METODA TRANSPORTASI TEKNIK RISET OPERASI Pertemuan 6b KHAMALUDIN, S.T, M.T “Least Cost Method”
Total
Supply
3 1 2 4 5
40
2 3 2 2 4
3 4 5 2 1
4 3 1 2 1
Total
Demand25050 40 45 75 40
A4
T2 T3 T4 T5
75
30
65
80
T1
TujuanSumber
A1
A2
A3
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
3 4 5 2 1
4 3 1 2 1
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
4 3 1 2 1
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
40
4 3 1 2 1
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
25 40
4 3 1 2 1
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
25 40
4 3 1 2 1
10
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
25 40
4 3 1 2 1
10 50
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
25 40
4 3 1 2 1
20 10 50
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Total
Supply
3 1 2 4 5
40 35
2 3 2 2 4
30
3 4 5 2 1
25 40
4 3 1 2 1
20 10 50
Total
Demand
A4 80
50 40 45 75 40 250
A1 75
A2 30
A3 65
SumberTujuan
T1 T2 T3 T4 T5
Z = (1.40) + (2.35) + (2.30) + (2.25) + (1.40) + (4.20) + (1.10) + (2.50) = 450
Total
Supply
3 2 7 6
7 5 2 3
2 5 4 5
Total
Demand135006000 4000 2000 1500
2500
Gudang Q Gudang R Gudang SGudang P
TujuanSumber
Pabrik A
Pabrik B
Pabrik C
5000
6000
Total
Supply
2 3 11 7
1 0 6 1
5 8 15 4
Total
Demand
Pabrik B
Pabrik C
6
1
Gudang P
TujuanSumber
Pabrik A
10
Gudang Q Gudang R Gudang S
177 5 3 2
Tentukan komposisi biaya minimal untuk data berikut ini dengan
Least Cost Method
1.
2.