Taking cube roots on a simple “scientific” calculator y x or using shift x y 27 y x.333333 = 2.99999 or 27 shift x y 3 = 3.

Taking cube roots on a simple “scientific” calculator

yx or using shift xy

27 yx .333333 = 2.99999 or 27 shift xy 3 = 3

A Problem using Kepler’s law

Review Kepler’s 3rd Law

End of Chapter 2 problem

Problem 6 using Kepler’s law from homework due Monday 4:30 PM

762 = 5776 yx .33333 = 17.94 = 18

Newton’s Universal Law of Gravity

Well, make that four significant figures!

http://www.chemie.fu-berlin.de/chemistry/general/constants_en.html

Newton’s third Law

Problem #1. Page 89 txt

How many times greater is the Earth’s gravitational force on the Moon than the Moon’s gravitational force on the Earth? Think about Newton’s third law of motion before answering this question.

The earth (designated as m) is in orbital motion nearly circular about the sun designated M. (masses in M.K.S. units) From a knowledge of Newton’s Universal law of gravitation and acceleration we can measure some parameters of the Earth Sun relation.

Modified form of Kepler’s Law!

Deduction of the Mass of the Sun from the Earth Sun distance and period.

Measurement of Surface Gravity

The Escape Velocity (not derived)