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Stoichiometry: Measurement of Elements
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Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Dec 24, 2015

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Page 1: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Stoichiometry: Measurement of

Elements

Page 2: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Formula Weights

Sum of the atomic weights (amu) of each atom in a chemical formula.

Called “molecular weight” or “molecular mass” for a molecule.

Use “formula weight” for ionic cmpds.

Page 3: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

The Mole

Chemists have derived a special counting unit for describing very large numbers of atoms or molecules.

Mole (mol) = the amount of matter that contains as many objects as the number of atoms in exactly 12g of isotopically pure carbon-12.

Page 4: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Mole, cont.

Avogadro’s number: 6.022 x 10^23

A mole of ANYTHING contains 6.022 x 10^23 objects!

I mole of marbles would cover the entire surface of the earth in a layer ________ thick.

Pennies placed side to side in a straight line would encircle the earth ________ times.

Page 5: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Representative Particles

Species present in a substance.Substance Type of

SpeciesRepresentative

Particles Representative

Particles in 1.00 mole

Lithium element atom 6.02 x 10^23

Nitrogen gas

molecular compound

molecule 6.02 x 10^23

Calcium fluoride

ionic compound

formula unit (f.u.)

6.02 x 10^23

Calcium ion

ion ion 6.02 X 10^23

Page 6: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Moles, cont., cont.

Remember:

1 mol of carbon = 6.022 X 10^23 atoms.

1 mol water = ____ molecules.

1 mol CN- ions = _____ ions.

1 mol NaCl = ____ formula units (f.u.’s).

1 mol elephants = _____ elephants.

Page 7: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Mole-Particle/Particle-Mole Problems

Use dimensional analysis!

How many moles of magnesium are

1.25 x 10^24 atoms of magnesium?

How many moles are 2.80 x 10^24 atoms Si?

How many molecules are in 3.60 mol water?

How many hydrogen atoms are in 3.60 mol water????

Page 8: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Molar Mass

A mole is always the same number but moles of different substances have different masses.

1 mol water = 18.02 g; 1 mol lead = 207.2 g

Molar mass: the mass in grams of 1 mole of a substance. Unit is g/mol.

Page 9: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Calculating Molar Mass

Calculate molar mass of CH4.

C: 1 atom x 12.01 g/mol = 12.01 g/molH: 4 atoms X 1.01 g/mol = 4.04 g/molAdd together: 12.01g/mol + 4.04 g/mol = 16.05 g/mol

Watch your sig figs!!!

Page 10: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Practice Calculating Molar Mass

Calculate the molar mass of NaCl.

Calculate the molar mass of calcium hydroxide.

Calculate the molar mass of Sr3(PO4)2.

Do you like this more than nomenclature?

Page 11: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Mass-Mole/ Mole-Mass Problems

Use dimensional analysis!Find the mass of 4.52 x 10^-3 mol water.

Find the mass of 0.342 mol nitrogen gas.

How many moles are in 72.96 g LiCl?

How many moles are in 12 28 g KOH?

Are we having fun yet?

Page 12: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Mole-Volume Relationship

Avogadro’s Hypothesis: equal volumes of gases at the same temp and pressure contain an equal number of particles.

Note: the size or mass of gas particles does NOT matter because particles are so far apart from each other.

Page 13: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Molar Volume of a Gas

STP = standard temp and pressureStandard temp for gases = 0°CStandard pressure = 1 atm “Molar volume of a gas” means that at

STP… I mole of ANY gas = 22.4L of gas

Page 14: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Mole-Volume Problems

We use molar volume to do mole-volume problems! Yeah!

Calculate the volume of 3.20 x 10^-3 mol carbon dioxide at STP.

0.0717 L carbon dioxideCalculate the volume of 3.70 mol nitrogen

gas at STP.82.9 L nitrogen gas

Page 15: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

More Molar Volume Calculations!

You have 0.200 L hydrogen gas at STP. How many moles?

8.93 x 10^-3 mol

Dan has 0.375 mol of oxygen gas at STP. What is its volume?

8.40 L oxygen

Page 16: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Density & Molar Volume at STP

The density of gases is in g/L, NOT g/mL. WHY?

You can use density along with molar volume to get molar mass! Hurrah!

Page 17: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Density & Molar Volume Problems

A gas has a density of 3.58 g/L at STP. What is the molar mass of the gas?

80.2 g/mol A gas has a density of 1.964 g/L at STP. What

is its molar mass? 43.99 g/mol What is the density of krypton gas at STP? 3.74 g/L

Page 18: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Percentage Composition from Chemical FormulaPercentage by mass of each element

in a substance.

% element = (# of atoms x molar mass of element/ molar mass of compound) x 100

Total % of each element = 100%

Page 19: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Calculating Percentage CompositionCalculate the % composition of C6H12O6.

% C = (6 x 12.01 g/mol/180.2 g/mol) x 100

= 40.00%

% H = (12 X 1.01 g/mol/180.2 g/mol) x 100

= 6.73%

% O = 100.00% - 40.00% - 6.73%

= 53.27%

Page 20: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Percent Composition Practice

Calculate the percent composition of C3H8.

C: 81.8 %; H: 18.2 %

Calculate the percent on nitrogen in NH3.

82.4% nitrogen

Page 21: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Percent Composition from Mass Data

Percent Composition = (mass of element in cmpd/mass of cmpd) x 100

Total %’s of all elements in cmpd = 100%

Page 22: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Percent Composition by Mass Practice

When a 13.60-g sample of a cmpd containing only Mg and O is decomposed, 5.40 g oxygen is obtained. What is the percent comp of the cmpd?

O: (5.40 g O/ 13.60 g) x 100 = 39.7%

Mg: [(13.60 g- 5.40 g)/ 13.60 g] x 100 = 60.3%

Page 23: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

More Percent Composition PracticeCalculate the number of grams of sulfur

in 3.54 g H2S.

First, find the % of sulfur in H2S.

94.1% S

Then, multiply .941 X 3.54 g H2S.

3.33 g

Page 24: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Empirical & Molecular FormulasEmpirical formula: gives the

lowest whole number ratio of atoms in a compound. PbO, not Pb2O2

Molecular formula: whole number multiples of the empirical formula.

Page 25: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Determining Empirical FormulasSing the Empirical Formula Song

(sung to tune of “Twinkle, Twinkle Little Star”):

“Percent to mass, mass to mole, divide by small, multiply ‘til whole.”

Page 26: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Empirical Formula Practice

A compound is analyzed and found to contain 25.9% nitrogen and 74.1% oxygen. What is the empirical formula of the compound?

N2O5

Page 27: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

More Empirical Formula Calculations!

Find the empirical formula for the following cmpd: Hg: 67.6%; S: 10.8%; O: 21.6%

HgSO4

Find the empirical formula for the following cmpd: H: 5.9%; O: 94.1%

HO

Page 28: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Molecular Formulas

Once you have determined the empirical formula (e.f.), you can determine the molecular formula (m.f.) if you know the compound’s molar mass.

Divide the molar mass of the cmpd by the molar mass of the e.f. and get a whole number. Multiply this number by each subscript in the e.f. to get the m.f..

Page 29: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Finding a Molecular Formula

You have the empirical formula HO. Find the molecular formula if its molar mass is 34.0 g/mol.

34.0 g/mol/ 17.0 g/mol = 2

The empirical formula HO becomes the molecular formula H2O2 !

Page 30: Stoichiometry: Measurement of Elements. Formula Weights Sum of the atomic weights (amu) of each atom in a chemical formula. Called “molecular weight”

Finding Molecular Formulas :-)

Find the molecular formula of a cmpd with a molar mass of 60.0 g/mol and an empirical formula of CH4N.

C2H8N2

Find the m.f. of a cmpd with a m.m of 62.0 g/mol and an e.f. of CH3O.

C2H6O2