Top Banner
Moles and Stoichiometry Ms. Randall
16
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: Stoic demo vod

Moles and Stoichiometry

Ms. Randall

Page 2: Stoic demo vod

I. Moles• 1 mole is 6.02 x 1023 of anything!!

• 6.02 x 1023 is called Avogadro's number.

• A mole can be 6.02 x 1023 atoms or molecules

A Mole is a UnitSing-a-long!!!

WRITEDOWN

Page 3: Stoic demo vod

II. Interpreting Chemical Formulas

Page 4: Stoic demo vod

A. Empirical Formula

• Simplest ratio of atoms in a compound (Ex. C2H5)

• The subscript tells you how many moles of each ion in the compound.

• Ex. Al2O3 = 2 mol Al+3 3 mol O-2

WRITEDOWN

Page 5: Stoic demo vod

B. Molecular Formula• Actual ratios of atoms in a molecule or

compound (Ex. C4H10)

• Molecular formulas are whole-number multiples of an empirical formula

• Ex: C4H10 molecular formula

C2H5 empirical formula

WRITEDOWN

WRITEDOWN

Page 6: Stoic demo vod

C. Structural Formula

• Shows the arrangement of the atoms in the actual compound

WRITEDOWN

Page 7: Stoic demo vod

III. Stoichiometry

• The study of quantitative relationships that can be derived from chemical formulas and equations

WRITEDOWN

Page 8: Stoic demo vod

• 1 mole of atoms has a mass equal to the atom’s atomic mass in grams.

• Atomic mass located on periodic table.

• Round to the nearest TENTH ( 0.1)

Example:

C= 12.0 amu = 12.0 g/mol

O= 16.0 amu = 16.0 g/mol

WRITEDOWN

Page 9: Stoic demo vod

B. Gram Formula Mass (GFM)

• the sum of all the atomic masses in the formula of the substance

1. add up the mass of each atom in the formula.

2. Multiply by the number of each atom if there is more than one of each atom.

WRITEDOWN

Element Atomic Mass # of Atoms in

Formula

Product

H 1 2 2

O 16 1 16

Total Mass = 18 g

Page 10: Stoic demo vod

Example: silver nitrate

Element # of atoms Mass Product

Ag = 1 × 108amu = 108 g

N = 1 × 14amu = 14 g

O = 3 × 16 amu = 48 g

170g/mol

Page 11: Stoic demo vod

11

Regents Practice

The gram formula mass of NH4Cl is

(1) 22.4 g/mole

(2) 28.0 g/mole

(3) 53.5 g/mole

(4) 95.5 g/mole

N 1 x 14.0 =

H 4 x 1.0 =

Cl 1 x 35.5 = _______

g/mole

Page 12: Stoic demo vod

1. Calculating Moles from Mass

Formula on table T in reference table

WRITEDOWN

given mass (g)

Gram formula mass

Mole =

Page 13: Stoic demo vod

2. Calculating Grams from Moles

• Rearrange the formula in

table T to solve for grams

given mass (g)

Gram formula mass

Mole =

Mole x GFMGrams =

WRITEDOWN

Page 14: Stoic demo vod

Grams Moles÷ gfm

x gfm

Summary

Page 15: Stoic demo vod

• Step1: Find the formula mass of the substance and express it in grams per mole

• Step 2: Apply the formula

mol =grams_

GFM

mol =390g__

110 g/mol

= 3.5 mol

CaCl2Ca = 40 × 1 = 40Cl = 35 × 2 = 70

110 g/mol

Page 16: Stoic demo vod

What is the mass of 2 moles of sodium thiosulfate?

Na2S2O3

Na = 23 × 2 = 46S = 32 × 2 = 64O = 16 × 3 = 48

158 g/mol= GFM

grams = moles × GFM

= 2 mol × 158 g/mol

= 316 g

step 1

step 2