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1 Stochastic Structural Dynamics Lecture-38 Dr C S Manohar Department of Civil Engineering Professor of Structural Engineering Indian Institute of Science Bangalore 560 012 India [email protected] Problem solving session-2
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Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

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Page 1: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

111

Stochastic Structural Dynamics

Lecture-38

Dr C S ManoharDepartment of Civil Engineering

Professor of Structural EngineeringIndian Institute of ScienceBangalore 560 012 India

[email protected]

Problem solving session-2

Page 2: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

2

1 2 3

Problem 17Consider the vector random variable given by

= . It is given that is normal with mean vector and correlation matrix given by

1 4 1 6= 2 and = 1 9 0 .

3 6 0 19We

t

t

Y

Y Y Y Y YR

R YY

21 2 3

now form the random process .

Find the mean, autocorrelations and cross correlationsof ( ) and .

X t Y Y t Y t

X t X t

Page 3: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

3

2

2 2

1 2 1 2

22 2

2 21 1 2 1 1 2

2 22 2

1 2

Define 1

11 2 1 2 3

3

2 2 6

4 1 6 1 4 61 1 9 0 1 1 9

6 0 19 6 19

,

t t

t

t t t

t t

XX

N t t t X t N t Y

X t N t Y t t t t

X t B Ct t

X t X t N t YY N t

t tt t t t t t

t t

R t t

2 2 2 21 2 1 2 1 2 1 2

2 2 4

4 9 6 6 19

4 2 21 19

t t t t t t t t

X t t t t

Page 4: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

4

2

2 2 2 21 2 1 2 1 2 1 2 1 2

2 2 4

22 2 4 2

2 4 2 4 2 3

2 3 4

1 2 3

, 4 9 6 6 19

4 2 21 19

4 2 21 19 1 2 3

4 2 21 19 (1 4 9 4 6 12 )4 6 11 12 19

XX

X

X t t t

R t t t t t t t t t t

X t t t t

t t t t t t

t t t t t t t tt t t t

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 20

50

100

150

200

250

time

varia

nce

x(t)

Page 5: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

5

2 2 2 21 2 1 2 1 2 1 2 1 2

21 2 1 2 1 2 1 2

2

21 2 1 2 1 3 1 2 3 2

22 1 1 2

2

1 2 1 2 1 21 2

, 4 9 6 6 19

, 1 9 12 38

Check

2

1 12 9 38

, 9 76

XX

XX

XX

R t t t t t t t t t t

X t X t R t t t t t tt

X t X t Y Y t Y t Y Y t

t t t t ok

X t X t R t t t tt t

Page 6: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

6

Problem 18

Consider the random process exp

where deterministic constant, 1, is a random variable with pdf and

characteristic function , and =a random variable that is indepen

X t a j t

a jp

dent of anddistributed uniformly in , . Show that

is proportional to , and

is proportional to XX

XX

R

S p

Page 7: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

7

*

2

2

2

2 2

exp

exp exp exp 0

exp exp

exp

exp

XX

XX

X t a j t

a j t a j t j

X t X t

a j t j t

a j

R a

S a j d a p

Page 8: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

8

2 2

Problem 19: A random process is given by

2 - - 2where ( ) is a zero mean stationary random processwith PSD function

Determine the PSD function of ( ).

XX

Y t

Y t X t X t X tX t

CS

Y t

Page 9: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

9

2 - - 2

2 - - 2 0

2 - - 2

2 2

2 4 2

2 2

6 4 4

2 2

XX XX XX

XX XX XX

XX XX XX

YY XX XX XX

XX XX

Y t X t X t X t

Y t X t X t X t

Y t X t X t X t

Y t Y t R R R

R R R

R R R

R R R R

R R

Page 10: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

10

exp

Consider exp

exp

exp exp exp UU

S R i d

R a i d

R u i u a d

i a R u i u d i a S

Page 11: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

11

2 2

exp

exp exp

6 4 4

2 2

6 4 exp exp

exp 2 exp 2

6 8cos 2cos 2

6 8cos 2cos 2

UU

YY XX XX XX

XX XX

YY XX XX

XX

XX

YY

R i d S

R a i d i a S

R R R R

R R

S S S i i

S i i

S

CS

Page 12: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

12

-100 -80 -60 -40 -20 0 20 40 60 80 10010

-20

10-15

10-10

10-5

100

105

w rad/s

psd

Sxx

Syy

Page 13: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

13

Problem 20Consider two independent random processes and which have zero mean and are stationary. Define

where is a deterministic constant.Determine PSD function of ( ).

X t Y t

Z t X t Y tZ t

0

XX

ZZ XX YY

ZZ YY

Z t X t Y t

Z t X t Y t X t Y t

Z t Z t X t Y t X t Y t

X t X t Y t Y t Y t

R R R

S S S d

Page 14: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

14

0

Problem 21A simply supported beam of span carries a distributed load ( ). The load is modeled as a segment of stationary

random process as ( ) 1 such that

0 and . Determine the

Lf x

f x F x

x x x

followingBending moment at midspanJoint pdf of reactions at the two supports.

Page 15: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

15

A B

f x

0

00 0

0 0

0

0 0 0

0

1 1 1

2

2 2

L

B

L L

B

L

L

B

R L xf x dx

R xf x dx xF x dxL L

F L F x x dxL

F L F F LR x x dxL

Page 16: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

16

0 0

0

2 20 0

1 2 1 2 1 20 0

20

1 2 0 1 2 1 20 0

2 2 220 0 0

00

2 20 0 0

2

2

3

~2 3

L

B

L L

B

L L

L

B

F L FR x x dxL

F L FR x x x x dx dxL

F x x I x x dx dxL

F F LIx I dxL

F L F LIR N

Page 17: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

17

0

00 0

0 0

0

2 2 20 0 0 0

2 20 0 0

1 1 1

2

&2 2 3

~2 3

L

A

L L

A

L

A A

B

R L L x f x dx

R L x f x dx L x F x dxL L

F L F L x x dxL

F L F L F LIR R

F L F LIR N

Page 18: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

18

0 0

2 20

1 2 1 2 1 220 0

2 20

1 2 0 2 1 1 220 0

2 2 2 20 0 0

020

2 2 2 20 0 0 00

2 2 2 20 0 0 0 0

2 2

6

3 62~

2 6 3

A B

L L

L L

L

A

B

F L F LR R

F L x x x x dx dxL

F L x x I x x dx dxL

F F I LI x L x dxL

F LI F LIF LR

NR F L F LI F LI

Page 19: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

19

2

00

2

00 0

2

00 0

0

Similarly one can study

( )2 2 2

1 ( )2 2

1 1 ( )2 2

Exercise: complete the characterization of

L

A

LL

LL

R LL LM M x f x dx

L LM L x f x dx x f x dxL

LL x F x dx x f x dx

M

Page 20: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

20

0

2 21 2 1 2

Problem 22A cantilever beam carries a randomly distributed loadas shown below. The load ( ) is modeled as

1 ; 0 &

1 1exp2 2

Determine the bending moment at a section m

q x

q x q f x f x

f x f x x x

x

easured from the free end.

x

q x

Page 21: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

21

0

00

2 22

0 0 00

22

0

2 20 1 2 1 2 1 2

0 0

2 2 2 20 1 2 1 2 1 2

0 0

1

2 2

2

1 1exp2 2

x

x

x

x x

x x

M x x q d

x q f d

x xM x x q d q x q

xM x q

q x x f f d d

q x x d d

Page 22: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

22

2 2 2 2 20 1 2 1 2 1 2

0 0

2 2 2 2 20 1 2 1 2

0 0

2 2 2 20 2 1 2 1 2

0 0

2 2 2 20 1 1 2 1 2

0 0

2 20 1 2

1 1exp2 2

1 1exp2 2

1 1exp2 2

1 1exp2 2

1 1exp2 2

x x

M

x x

x x

x x

x q x x d d

q x d d

q x d d

q x d d

q

2 21 2 1 2

0 0

x x

d d

Page 23: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

23

22 2 2 2 2 2 2

0 0

22 2 20

2

0

2 1 exp22

1 exp2 2

with

1 exp22

M

x

x xx q x x xq

q x

xx dx

Page 24: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

24

Problem 23A cantilever beam of span carries a series of concentrated loads. The point of application of theseloads are distributed as Poisson points on 0 to . The magnitude of the loads are modeled

L

L as a sequence

of iid-s with a common Rayleigh distribution withparamter . Determine the characteristic funciton of thereaction .R

Page 25: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

25

1w 2w 3w nw

R

M

1

2

2 2

exp ; 0,1, 2,!

exp ; 02

N L

nn

n

w

R w

aLP N L n aL n

nw wp w w

Page 26: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

26

1 1

1 1

1

0

2 2

exp exp

0 exp

exp exp!

exp exp 1!

: 1 exp 1 erf2

N L N L

n R in n

k

ik n

kk

wk

kk

w wk

w

R w i R i w

P N L i w N L k P N L k

aLaL i aL

k

aLi aL aL i

k

ii i

Note (prove)2

Page 27: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

27

1 2 2 1 2 1

Problem 24Verify if

, exp - - sin -

can be a valid autocovariance function of a zero meanrandom process. It is given that , , 0.

R t t t t t t

1 2 2 1

1 2 1 1 2 2

Required characteristics, ,

, 0

, , ,

No, since the function is not positive definite;notice , 0

R t t R t t

R t t

R t t R t t R t t

R t t

Page 28: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

28

2

Problem 25Consider to be a stationary random process with

zero mean. Define ( ) - where and ( ) are determinisitc. Determine autocovariance of( ). It is given that

exp 1XX

X t

Y t X t a t X ta t

Y t

R

Page 29: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

29

( ) -

( ) - 0

( )

- -

-

-

- -

-

Simplify using

XX XX XX

XX

n m

n m

Y t X t a t X t

Y t X t a t X t

Y t Y t

X t a t X t X t a t X t

X t X t X t a t X t

a t X t X t

a t X t a t X t

R a t R a t R

a t a t R

d X t d Y tdt dt

1n m

m XYn m

d Rd

Page 30: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

30

2

2

2

2

2

2

2

exp 1

exp sgn 1

exp sgn

exp sgn sgn sgn

exp sgn

Use

sgn &

and derive

XX

XX

XX

R

d Rd

dU tU U t

dtd Rd

Page 31: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

31

Problem 26An undamped sdof system is set into free vibrationby imparting random initial displacement and velocity.Characterize the system response. Determine the conditionsunder which the response can become stationary.

Page 32: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

32

2

2

2

2

0; 0 ; 0

cos sin

cos sin

cos sin

cos sin cos sin

, cos cos cos sin

sin cos sin sin

xx

x x x u x v

x t A t B tvx t u t t

vx t u t t

x t x t

v vu t t u t t

uvR t u t t t t

vuvt t t t

Page 33: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

33

2

2

2

22 2

2

2

2

, cos cos cos sin

sin cos sin sin

Take 0 &

, cos cos sin sin

, cosConditions for existence of stochastic steady state

xx

xx

xx xx

uvR t u t t t t

vuvt t t t

vuv u

R t t t t t

R t R

2

2 22

are

0, 0, 0 &v

u v uv u

Page 34: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

34

Problem 27An input ( ) 0 for 0 and ( ) exp(-2 ) for 0 to a linear system produces the output

1 exp 2 exp 4 . The system is now 2

excited by a Gaussian white noise excitation with unit stren

f t t f t t t

y t t t

gth. Determine the PSD of the steady state response.

Page 35: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

35

2

2

( ) exp(-2 ) 1

21 exp 2 exp 42

1 1 12 2 4

1 1 11 2 12 2 4 11 2 4 4

21

16YY

f t t U t

Fi

y t t t U t

Yi i

ii iHi i

i

S H

Page 36: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

36

exp ; 0 0

expexp

10 0

1 exp exp

1

x x t x

tx t A t

x A

x t t t

Hi

Notice

Page 37: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

37

Problem 28Consider a random process

sinwhere is determinstic, is a random variable distributed uniformly in 0 to 2 , and ( ) is azero mean stationary Gaussian random process.It may be a

X t P t Y tP

Y t

ssumed that ( ) and are independent.Determine the joint pdf of and .

Are and uncorrelated? independent?

Y tX t X t

X t X t

Page 38: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

38

2

2

sin

0

sin sin

sin sin

cos2

is wide sense stationary

YY

YY

X t F t Y t

X t

X t X t F t Y t F t Y t

F t t R

F R

X t

Page 39: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

39

sincos

2 2

2 2

2 2

2 2

sin

cos

, | ,

1 1exp sin cos2 2

, , |

1 1 1exp sin cos2 2 2

12

y x F tXX YYy x F t

XX XX

X t F t Y t

X t F t Y t

p x x p y y

x F t x F t

p x x p x x p d

x F t x F t d

2 22 2

1 1exp sin cos2 2

x F x F d

Page 40: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

40

2 22 2

2 2 22 2 2

2 2 2 2 202 2 2

,

1 1 1exp sin cos2 2 2

1 1 1exp exp sin cos2 2 2

1 1exp ; ,2 2

sin

1|2

XX

X

p x x

x F x F d

Fx x F x x d

Fx x F I x x x x

X t F t Y t

p x

2

2

1exp sin2

|

|

X X

XX

x F t

p x p x p d

p x p x p d

Page 41: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

41

It can be verified that,

and are uncorrelated because they are stationaryrandom processes.

and are not independent

XXX Xp x x p x p x

X t X t

X t X t

Remark

Page 42: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

42

2 2

2 22 2

Problem 29

Let ( ) be a random process with

and . Show that

P for some in

1 1 ; 02

Note: This is the generalization of Chebychev's

X

X X

X

b

X X X Xa

X t X t t

X t t t

X t t t a t b

a b t t dt

inequalityfor random processes.

Page 43: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

43

22

2 2

2

2 2 2

2

We have for a random process ( )1P sup E sup Prove this

Also,

2

2

12

1sup

a t b a t b

t

ab

tt

a

a t b

Y t

Y t Y t

dY t Y a Y u Y u dudu

dY b Y u Y u dudu

dY t Y a Y b Y u Y u dudu

Y t

[Hints]

2 2

2

t

a

dY a Y b Y u Y u dudu

Page 44: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

44

12 2 2

2 2 2

12 2

2

We have

E E E

1sup2

E E

Substitute in the above to getthe required result.

a t b

t

a

X

UV U V

E Y t E Y a Y b

d Y u Y u dudu

Y t X t t

Page 45: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

45

2

2

Problem 30Let ( ) be a stationary random process with zero meanand autocovariance function given by

1 exp22

How many times can we differentiate this process?

Determine 0.75 i

XX

X t

R

P X t

f it is given that the

process is Gaussian and =1.

Page 46: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

46

2

2

2 2

2 2

1 exp22

exp2

exp exist 1, 2,2

is differentiable at =0 forall orders.

is differentiable to any order (in the mean square

XX

XX

nn

XX

R

S

d n

R

X t n

sense)

Page 47: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

47

2

2

2

2 2

2 2

2 2 2

22

2 2

2

2 2

1 exp22

1 exp22

1 1 exp22

1 exp22

1 1 10 12 2

1exp 2 exp2

0

XX

XX

XX

XX

X

R

d Rd

d Rd

R

p x x x

P X t

0.75

2.75 exp 0.97x dx

Page 48: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

48

Problem 31Let ( ) be a Poisson random process with arrival rate .

Define 1 .Determine the mean and covariance of ( ).Note: is known as semi random telegraph signal.

N t

N t

X tX t

X t

1

1

t

X t

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49

2 4

3 5

1 .

1 if ( ) 0 or ( ) is even1 if ( ) is odd

1 0 or ( ) is even

exp 1 exp cosh2! 4!

1 ( ) is odd

exp exp s3! 5!

N tX t

N t N tX t

N t

P X t P N t N t

t tt t t

P X t P N t

t tt t t

inh

1 1 1 1

exp cosh sinh 2exp 2

t

X t P X t P X t

t t t t

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50

even odd

1 if there are even number of occurrences in to .

1 if there are odd number of occurrences in to .

1 exp 1 exp exp 2! !

, exp 2

n n

n n

XX XX

X t X tt t

X t X tt t

X t X t

n nR t t R

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51

Problem 32A random walk is performed on a two-dimensional plane with auniform step size of . At every step the direction is a randomvariable. -s can be taken to be an iid sequence with a common

i

i

pdf that is uniformly distributed in 0 to 2 . Find the distribution of the

-coordinate after steps.x n

X

x

y

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52

1

1

12

00

0

0

00

cos

exp exp cos

exp cos

1exp cos exp cos2

1 exp2

1 cos

N

ii

N

X jj

n

ji

j j j

nX

nX

n

X

i X i

i

i i d J

J

p x J i x d

J xd

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53

0

00

2 2 4 4

0 2 2 2

2 2 4 4

0 2 2 2 2

2 2 2 2

2

2

2

1 cos

12 2 4

Consider the limit such that .

12 2 4

1 exp2 4

1 exp

nX

nX

nn

nn

n

X

J

p x J xd

J

n n c

c cJn n

c cn

xp xcc

; x

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54

th

Problem 33Let the time interval 0 to be divided into a sequence of equal intervals of length . Consider a sequence

1of Bernoulli trials with P success = . Define2

1 if success on trial 1 if f

TT

n

nX t

th 1ailure on trial

Find mean and autocorrelation of ( ).

Furtheremore, let be a random variable distributeduniformly in 0 to and independent of ( ).Define - . Determine the me

n T t nTn

X t

eT X t

Y t X t e

an andautocorrelaiton of ( ).Y t

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55

th

th

22 2

1 21 2

1 if success on trial 1

1 if failure on trial1 11 1 02 2

1 11 1 12 2

1 if 1 ,0 otherwise

nX t n T t nT

n

X t

X t

n T t t nTX t X t

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56

1 2 1 1

1 2

1 2 1 2

1 2

1 21 2

E =E E E 0

E E

E E

E 0 if

If

1 if -E

0 otherwise

Y t X t

Y t Y t X t

Y t Y t X t X t

X t X t

X t X t t t T

t t T

e T t tX t X t

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57

1 2 1 2

1 2

E 1 -

1

Y t Y t P e T t t

t tT

T T

1

2 1t t

1 2E Y t Y t

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58

Problem 34Given a postive function ( ) find a stochastic process whose PSD is ( ). Existence theorem

SS

Determine a LTI system with H and

pass a zero mean stationary Gaussian white noise withunit strength through this system. The output processwould be a zero mean stationary process with PSD= .

i S

S

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59

22Determine and define .

Clearly, 0 & 1; also,

has the properties of a pdf of a random variable.

Let ( ) cos where and are random variables

with

Sa S d f

a

f f d f f

f

X t a t

Alternative

2

1 2 1 20

22

~ , ~ 0,2 ,& .

( ) 0 Prove it; start with finding mean conditioned on

( ) ( ) cos cos ,

cos OK2XX XX

f U

X t

X t X t a t a t p d d

aR f d S a f

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0 10 20 30 40 50 60 70 80-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

t s

x(t)

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61

0 10 20 30 40 50 60 70 80-2

-1.5

-1

-0.5

0

0.5

1

1.5

2

t s

x(t)

0 10 20 30 40 50 60 70 80-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

t s

x(t)

PSD is an ensemble propertyThese two time histories

represent samplesfrom two different processes having thesame mean and PSD function.

Remarks

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62

RemarkThe following three processes share the same form of PSDThe sample realizations are dramatically different.

1 ; ( ) : Poisson process with rate

cos ; ~ ; ~ 0,2 ;

Steady st

N tX t N t

SX t t U

S d

0ate response ; 0X X t X X

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63

1

1

t

X t

0 10 20 30 40 50 60 70 80-2

-1.5

-1

-0.5

0

0.5

1

1.5

2

t s

x(t)

0 10 20 30 40 50 60 70 80-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

t s

x(t)

Page 64: Stochastic Structural Dynamics Lecture-38 - NPTELnptel.ac.in/courses/105108080/module10/Lecture38.pdfStochastic Structural Dynamics Lecture-38 ... Bending moment at midspan ... exp

64

Discussion on properties of processes withIndependent increments