SRP325G Manual

8/19/2019 SRP325G Manual

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Ex 1

Example / Ejemplo / Exemplo / Beispiel / Exemple / Esempio / Voorbeeld /

Eksempel / / Przykùad / /

Contoh /

Example 1Change 123 x 456 as 12 x 457

Cambiar 123 x 456 como 12 x 457

Mude 123 x 456 como 12 x 457

Änderen Sie 123 x 456 wie 12 x 457

Changez 123 x 456 pour 12 x 457

Cambiare 123 x 456 come 12 x 457

Verander 123 x 456 naar 12 x 457

Ret 123 x 456 til 12 x 457

123 x 456 12 x 457

Zamie 123 x 456 na 12 x 457

123 x 456 12 x 457

Ubahlah 123 x 456 menjadi 12 x 457

123×45612×457

123 [ x ] 45 [ ]1 2 3 4 5

5535.DD

[ ] [ ] [ ] [ DEL ]1 2 4 5

DD

[ 2nd ] [ ]1 2 3 4 5

DD

[ ] [ ] 7 [ ]1 2 3 4 7 5

58425.DD

Example 2 After executing 1+ 2, 3 + 4, 5 + 6, use replay function to recall


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Ex 2

Después de ejecutar 1 + 2, 3 + 4, 5 + 6, use la función replay pararevocar

Depois de executar 1 + 2, 3 + 4, 5 + 6, use função replay pararechamar

Nach der Eingabe von 1 + 2, 3 + 4, 5 + 6, benutzen Sie dieReplay-Funktion zum Wiederholen

Après avoir exécuté 1 + 2, 3 + 4, 5 + 6, utilisez la fonction de

répétition pour rappeler Dopo avere eseguito 1 + 2, 3 + 4, 5 + 6, usa funzione ripetuta(replay) perrichiamare

Na het uitvoeren van 1 + 2, 3 + 4, 5 + 6, gebruikt u deherhaalfunctie om op te vragen

Når d u h ar u df ørt 1 + 2 , 3 + 4, 5 + 6, ka n d u b rugegentagelsesfunktionen til at hente

1 + 2, 3 + 4, 5 + 6,

Po wykonaniu 1 + 2, 3 + 4, 5 + 6, zastosuj funkcj replay abywywo a z pami ci

1 + 2, 3 + 4, 5 + 6 , 3

Setelah mengeksekusi 1 + 2, 3 + 4, 5 + 6, gunakan fungsi replayuntuk memanggil kembali

1+23+45+6

1 [ + ] 2 [ ] 3 [ + ] 4 [ ]5 [ + ] 6 [ ] 5 + 6

11.DD

[ ]5 + 6

DD

[ ]3 + 4

DD

[ ]1 + 2

DD

Example 3

14 ) 0 x 2.3 mistakenly input instead of 14 )10 x 2.3

14 ) 0 x 2.3 equivocadamente digitado en lugar de 14 )10 x 2.3


5/70

Ex 3

14 ) 0 x 2.3 eradamente digitada em vez de 14 )10 x 2.3

14 ) 0 x 2.3 irrtümlicherweise an Stelle von 14 )10 x 2.3eingegeben

Entrée erronée de14 ) 0 x 2.3 au lieu de 14 )10 x 2.3

14 ) 0 x 2.3 sbagliatamente entrato invece di 14 )10 x 2.3

In plaats van 14 ÷ 10 x 2.3, voerde u 14 ÷ 0 x 2.3 in

14 ÷ 0 x 2.3 indtastet ved en fejl i stedet for 14÷10 x 2.314 ÷ 0 x 2.3 14 ÷ 10 x 2.3

14 ) 0 x 2.3 omy kowo wprowadzono zamiast 14 )10 x 2.3

14 ) 10 x 2.3 14 ) 0 x 2.3

14 ÷ 0 x 2.3 telah keliru dimasukkan, padahal seharusnya 14 ÷ 10x 2.3

14÷0×2.314÷10×2.3

14 [ ) ] 0 [ x ] 2.3 [ ]D I V I D E B Y 0

DD

( 5 Seconds )1 4 / 0 2 . 3

DD

[ ] 1 [ ]1 4 / 1 0 2 . 3

3.22DD

Example 4

[ ( 3 x 5 ) + ( 56 ) 7 ) ( 74 8 x 7 ) ] = 5

3 [ x ] 5 [ M+ ]3 5

15.DD

M

56 [ ) ] 7 [ M+ ]5 6 / 7

8.DD

M

[ MRC ] [ ]M

23.DD

M


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Ex 4

74 [ ] 8 [ x ] 7 [ 2nd ] [ M ]74 8 * 7

18.DD

M

[ MRC ] [ ]M

5.DD

M

[ MRC ] [ MRC ] [ CL/ESC ]

DD

Example 5Put the value 30 into variable APonga el valor 30 en la variable APonha o valor 30 na variável ASetzen Sie den Wert 30 für die Variable APlacez la valeur 30 dans la variable AMetti il valore 30 nella variabile ASla de waarde 30 in de variabele A opMasukkan nilai 30 ke variabel A

30 AWarto 30 zapisz do rejestru pami ci A

A 30

Masukkan nilai 30 ke variabel A 30 A

[ 2nd ] [ CL-VAR ] 30 [ SAVE ] [ A ][ ] 3 0 A

DD

30.

Multiple 5 to variable A, then put the result into variable BMultiplicar 5 a la variable A, entonces ponga el resultado envariable BMultiplique 5 para variável A, depois ponha o resultado navariável BMultiplizieren Sie 5 mit der Variablen A und setzen Siedieses Ergebnis für die Variablen BMultipliez 5 par la variable A, puis placez le résultat dans lavariable BMoltiplicare 5 a variabile A, poi metti il risultato nellavariabile BVermenigvuldig 5 met de variabele A, en sla het resultaatvervolgens in de variabele B opGang 5 med variabel A, og placer resultatet i variabel B

5 A,B


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Ex 5

Z Zawarto rejestru pami ci A pomnó rpzez 5, a wynikzapisz do rejestru pami ci

A 5 BVariabel A dikalikan dengan 5, kemudian masukkanhasilnya ke variabel B

5 [ x ] [ 2nd ] [ VRCL ]3 0 A

DD

30.

[ ] [ ]5 3 0

150.DD

[ SAVE ] [ B ] [ ] A n s B

DD

150.

Add 3 to vari able B Agregue 3 a variable BSome 3 a variável BFügen Sie 3 der Variablen B zuPour clarifier le contenu de toutes les variables Addizionare 3 a vari abile BVoeg 3 aan de inhoud van variabele B toeLæg 3 til variabel B

3 BDo rejestru pami ci B dodaj 3

B 3Tambahkan 3 ke variabel B

3B

[ ALPHA ] [ B ]B

DD

[ + ] 3 [ ]B + 3

153.DD

To clear the contents of all variablesPara cancelar los contenidos de todas las variablesPara apagar os conteúdos de todas as variável BLöschen Sie den Inhalt aller VariablenPour clarifier le contenu de toutes les variablesPer sgombrare i contenuti di tutte le variabileWis de inhoud van alle variabelen


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Ex 6

For at rydde indholdet i alle variabler ,

Aby wyzerowa wszystkie rejestry pami ci

Menghapus isi dari seluruh variable

[ 2nd ] [ CL-VAR ] [ 2nd ] [ VRCL ] A B C D E F

DD

G H IJ K L

Example 6Set PROG 1 = cos (3A) + sin (5B), where A = 0, B = 0Fijar PROG 1 = cos (3A) + sin (5B), donde A = 0, B = 0Fixe PROG 1 = cos (3A) + sin (5B), onde A = 0, B = 0Einstellung PROG 1 = cos (3A) + sin (5B), wobie A = 0, B = 0Set PROG 1 = cos (3A) + sin (5B), où A = 0, B = 0Impostare PROG 1 = cos (3A) sin (5B), dove A = 0, B = 0Instellen van PROG 1 = cos (3A) + sin (5B), waarbij A = 0 enB = 0Sæt PROG 1 = cos (3A) + sin (5B), hvor A = 0, B = 0

PROG 1 = cos (3A) + sin (5B), A = 0, B = 0Zapisa program PROG 1 = cos (3A) + sin (5B), gdzie A = 0,B = 0

PROG 1 = cos (3A) + sin (5B), A = 0, B = 0Tetapkan PROG 1 = cos (3A) + sin (5B), di mana A = 0, B = 0

[ COS ] 3 [ ALPHA ] [ A ] [ ] [ + ][ SIN ] 5 [ ALPHA ] [ B ] [ ] 3 A ) + s i n ( 5 B )

DD

[ SAVE ] [ PROG ] 1( 5 B ) P RO G 1

DD

[ ]c o s ( 3 A ) + s i n

1.DD

Set A = 20,B = 18, get PROG 1 = cos (3A) + sin (5B) = 1.5Establecer A = 20,B = 18, obtener PROG 1 = cos (3A) + sin(5B) = 1.5Estabelecer A = 20,B = 18, obtenha PROG 1 = cos (3A) +sin (5B) = 1.5Setzen Sie A = 20,B = 18, Sie bekommen PROG 1 = cos

(3A) + sin (5B) = 1.5Définissez A = 20,B = 18, et vous obtenez PROG 1 = cos


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Ex 7

(3A) + sin (5B) = 1.5Regola A = 20,B = 18, ottieni PROG 1 = cos (3A) + sin (5B)= 1.5Geef A = 20 en B = 18 op, en verkrijg de oplossing PROG 1= cos (3A) + sin (5B) = 1.5Sæt A = 20,B = 18, get PROG 1 = cos (3A) + sin (5B) = 1.5

A = 20,B = 18, PROG 1 = cos (3A) +sin (5B) = 1.5

Nadaj warto ci A = 20,B = 18, jako wynik otrzymasz PROG 1= cos (3A) + sin (5B) = 1.5 A = 20,B = 18, PROG 1 = cos (3A) + sin (5B) = 1.5

Tetapkan A = 20,B = 18, untuk mendapatkan PROG 1 = cos(3A) + sin (5B) = 1.5

[ PROG ] 1 [ ] [ ][ CL/ESC ] 20

A = 20

DD

[ ] [ CL/ESC ] 18 B = 18

DD

[ ]c o s ( 3 A ) + s i n

1.5DD

Example 7To expand the number of memories by 2 to bring the total to28Para ampliar la cantidad de memorias en 2 y disponer de unotal de 28

Para ampliar o número de memórias por 2 para obter o totalde 28Um die Speicherzahl durch 2 zu erweitern, um die Gesamtzahlauf 28 zu bringenPour augmenter le nombre de mémoires par 2 et amener leotal à 28

Per espandere il numero di memorie di 2 per portare il totalea 28Het aantal geheugens met 2 uitbreiden zodanig dat hetotale aantal op 28 komt te staan

For at udvide antallet af hukommelser med 2, så detsamlede antal kommer op på 28

2,28.

Powi kszy liczb rejestrów pami ci o 2, tzn. do 28 ogó em2 28


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Ex 8

Memperluas banyaknya memori dua kali lipat sehinggaotalnya adalah 28

228

[ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r

DD

2 D e f m

[ ] 2 D e f m 2

DD

[ ]M 2 8 S 3 7 6

DD

Put the value 66 into variable A [ 27 ]Ponga el valor 66 en la variable A [ 27 ]Ponha o valor 66 dentro da variável A [ 27 ]Setzen Sie den Wert 66 in die Variable A [ 27 ]Inscrivez la valeur 66 dans la variable A [ 27 ]Mettere il valore 66 nella variabile A [ 27 ]Sla de waarde 66 in de variabele A [ 27 ] opPlacer værdien 66 i variabel A [ 27 ]

66 A [ 27 ]Zapisa warto 66 do rejestru A [ 27 ]

A [ 27 ] 66

Masukkan nilai 66 ke variabel A [ 27 ]66 A]27[

66 [ SAVE ] [ A ] [ ALPHA ] [ [ ] ]27 [ ] 6 6 A [ 2 7 ]

DD

66.

Recall variable A [ 27 ]Recupere la variable A [ 27 ]Rechame variável A [ 27 ]Rufen Sie Variable A [ 27 ]Rappelez la variable A [ 27 ] wieder auf Rechiamare la variabile A [ 27 ]Opvragen van variabele A [ 27 ]Hent variabel A [ 27 ]

, A[ 27 ]Wywo a zmienn A [ 27 ]

A [ 27 ]Panggilah variabel A [ 27 ]


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Ex 9

[ ALPHA ] [ A ] [ ALPHA ] [ [ ] ] 27[ ] A [ 2 7 ]

DD

66.

To return memory variable to the standard configurationPara volver la variable de memoria a la configuraciónestánder

Para retornar a variável de memória à configuração padrãoUm die Speichervariable zur Standkonfiguration zurückzubringenPour faire revenir la variable de mémoire à la configurationstandardPer riportare la variabile di memoria alla configurazionestandardHerstelt de geheugenvariabelen naar de standaardinstellingFor at bringe hukommelsesvariablen tilbage tilstandardkonfigurationen

Powróci do standardowej konfiguracji pami ci

Mengembalikan variabel memori ke konfigurasi standar

[ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r

DD

2 D e f m

[ ] 0 [ ]M 2 6 S 4 0 0

DD

Example 8

7 + 10 x 8 ) 2 = 47

7 [ + ] 10 [ x ] 8 [ ) ] 2 [ ]7 + 10 8 / 2

47.DD

Example 9

3.5 + 8 ) 4 = 0.5

[ ( ) ] 3.5 [ + ] 8 [ ) ] 4 [ ] 3 . 5 + 8 / 4

1.5DD

Example 10


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Ex 10

12369 x 7532 x 74103 = 6903680613000

12369 [ x ] 7532 [ x ] 74103[ ] 1 2 3 6 9 7 5 3 2

6.903680613x10 12

DD

Example 11

6 ) 7 = 0.857142857

6 [ ) ] 7 [ ] 6 / 7

0.857142857DD

[ 2 nd ] [ FIX ] [ ] [ ] [ ]F 0 1 2 3 4 5 6 7 8 9

DD

[ ]6 / 7

0.86DD FIX

[ 2nd ] [ FIX ] 46 / 7

0.8571DD FIX

[ 2nd ] [ FIX ] [ ]6 / 7

0.857142857DD

Example 12

1 ) 6000 = 0.0001666...

1 [ ) ] 6000 [ ] 1 / 6 0 0 0

0.000166667DD

[ 2nd ] [ SCI / ENG ] [ ]F L O S C I E N G

DD


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Ex 11

[ ]1 / 6 0 0 0

1.666666667DD SCI

x10 04


DD SCI

[ ]1 / 6 0 0 0

166.6666667DD ENG

x10 06


DD ENG

[ ]1 / 6 0 0 0

0.000166667DD

Example 130.0015 = 1.5 x 10 3

1.5 [ EXP ] [ () ] 3 [ ] 1 .5 E 3

0.0015DD

Example 1420 G byte + 0.15 K byte = 2.000000015 x 10 10 byte

20 [ 2nd ] [ ENG SYM ] [ ] [ ]0 K 1 M 2 G

DD

3 T 4 P5 E

[ ] [ + ] 0.15 [ 2nd ] [ ENGSYM ] 0 K 1 M 2 G

DD

3 T 4 P5 E


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Ex 12

[ ] [ ]2 0 G + 0 .1 5 K

2.000000015DD

x10 10

Example 15

( 5 2 x 1.5 ) x 3 = 6[ ( ) ] 5 [ ] 2 [ x ] 1.5 [ ] [ x ] 3[ ] ( 5 2 1 . 5 ) 3

6.DD

Example 162 x { 7 + 6 x ( 5 + 4 ) } = 122

2 [ x ] [ ( ) ] 7 [ + ] 6 [ x ] [ ( ) ] 5 [ + ]4 [ ] 2 ( 7 + 6 ( 5 + 4

122.DD

Example 17120 x 30 % = 36

120 [ x ] 30 [ 2nd ] [ % ] [ ]1 2 0 3 0 %

36 .DD

88 ) 55% = 160

88 [ ) ] 55 [ 2nd ] [ % ] [ ] 8 8 / 5 5 %

160.DD

Example 183 x 3 x 3 x 3 = 81

3 [ x ] 3 [ ]3 3

9.DD

[ x ] 3 [ ] A n s 3

27 .DD


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Ex 13

[ ] A n s 3

81.DD

To calculate ) 6 after 3 x 4 = 12Para calcular ) 6 después de 3 x 4 = 12Para calcular ) 6 depois de 3 x 4 = 12

Berechnen Sie ) 6 nach 3 x 4 = 12Pour calculer ) 6 aprés 3 x 4 = 12Per calcolare ) 6 dopo 3 x 4 = 12Voer ÷ 6 uit, na de bewerking 3 x 4 = 12For at beregne ÷ 6 efter 3 x 4 = 12

÷ 6 3 x 4 = 12 Aby obliczy ÷ 6 po 3 x 4 = 12

3 x 4 = 12 ) 6Menghitung ÷ 6 setelah 3 x 4 = 12

6÷3×4=12

3 [ x ] 4 [ ]3 4

12.DD

[ ) ] 6 [ ] A n s / 6

2.DD

Example 19123 + 456 = 579 789 579 = 210

123 [ + ] 456 [ ]1 2 3 + 4 5 6

579.DD

789 [ ] [ 2nd ] [ ANS ] [ ]7 8 9 A n s

210.DD

Example 20ln7 + log100 =3.945910149

[ LN ] 7 [ ] [ + ] [ LOG ] 100[ ] l n ( 7 ) + l o g ( 1

DD

3.945910149


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Ex 14

10 2 = 100

[ 2nd ] [ 10 x ] 2 [ ]1 0 ( 2 )

DD

100.

e 5 = 0.006737947

[ 2nd ] [ e x

] [ ( ) ] 5 [ ] e ( 5 )

DD

0.006737947

Example 21

7 [ A b/c ] 2 [ A b/c ] 3 [ + ] 14 [ A

b/c ]5 [ A b/c ] 7 [ ]

7 2 3 + 1 4 5

DD

22 U 8 21

Example 22

4 [ A b/c ] 2 [ A b/c ] 4 [ ] 4 2 4

DD

4 U 1 2

[ 2nd ] [ Ab/cd/e ] [ ] Ans Ab/c d/e

DD

9 2

[ 2nd ] [ Ab/cd/e ] [ ] Ans Ab/c d/e

DD

4 U 1 2

Example 23

4 [ A b/c ] 1 [ A b/c ] 2 [ 2nd ]

[ F D ] [ ] 4 1 2 F D

DD

4.5


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Ex 15

Example 24

8 [ A b/c ] 4 [ A b/c ] 5 [ + ] 3.75

[ ] 8 4 5 + 3.75

DD

12.55

Example 25

2 rad. = 360 deg.

[ DRG ]D E G R A D G R D

DD

[ ] 2 [ 2nd ] [ ] [ 2nd ][ DMS ] [ ] [ ] [ ]

º r g

DD

DMS

[ ] [ ]2 r

DD

360.

Example 261.5 = 1O 30 I 0 II ( DMS )

1.5 [ 2nd ] [ DMS ] [ ]º r g

DD

DMS

[ ] [ ]1.5 D M S

DD

1 30 I 0 II

Example 272 O 45 I 10.5 II = 2.752916667

2 [ 2nd ] [ DMS ]º r g

DD

DMS


18/70

Ex 16

[ ] 45 [ 2nd ] [ DMS ] [ ]º r g

DD

DMS

[ ] 10.5 [ 2nd ] [ DMS ] [ ][ ] º

r g

DD

DMS

[ ] [ ]2 º 4 5 1 0. 5

DD

2.752916667

Example 28sin30 Deg. = 0.5

[ DRG ]D E G R A D G R D

DD

[ ] [ SIN ] 30 [ ]s i n ( 3 0 )

DD

0.5

sin30 Rad. = 0.988031624[ DRG ] [ ]

D E G R A D G R D

DD

[ ] [ SIN ] 30 [ ]s i n ( 3 0 )

RR

0.9 880 316 24

sin 1 0.5 = 33.33333333 Grad.

[ DRG ] [ ]D E G R A D G R D

RR

[ ] [ 2nd ] [ SIN 1 ] 0.5[ ] s i n

1 ( 0 . 5 )

GG33.33333333


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Ex 17

Example 29cosh1.5+2 = 4.352409615

[ 2nd ] [ HYP ] [ COS ] 1.5 [ ][ + ] 2 [ ] c o s h ( 1 . 5 ) + 2

DD

4.352409615

sinh 1 7 = 2.644120761[ 2nd ] [ HYP ] [ 2nd ] [ SIN 1] 7[ ] s i n h

1 ( 7 )

DD

2. 644120761

Example 30

If x = 5, y = 30, what are r, ? Ans : r = 30.41381265, =80.53767779 °Six x = 5 , y = 30, lo que es r, ? Resp : r = 30.41381265, =80.53767779 °Sex x = 5 , y = 30, o que é r, ? Resp : r = 30.41381265, =80.53767779 °Falls x = 5, y = 30, was sind r, ? Antw : r = 30.41381265, =80.53767779 °Six x = 5 , y = 30, cobien vaut r, ? Rép : r = 30.41381265, =80.53767779 °Se x = 5 , y = 30, Che sono r, ? Risp : r = 30.41381265, =

80.53767779 °Indien x = 5 en y = 30, hoeveel is dan r en ? Antwoord : r =30.41381265 en = 80.53767779Hvis x = 5 , y = 30, hvad er så r, ? Svar : r = 30.41381265, =80.53767779 °

x = 5, y = 30, r, ? : r = 30.41381265,=80.53767779 °Jeli x = 5 , y = 30, to jakie s warto ci r , ? Odp : r =30.41381265, = 80.53767779 °

x = 5 , y = 30, r : r = 30.41381265, = 80.53767779 °Jika x = 5 , y = 30, berapakah r, ? Jawab : r = 30.41381265, =80.53767779 °

[ 2nd ] [ R P ]R P r R P

DD

P R xP R y


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Ex 18

[ ] 5 [ ALPHA ] [ ] 30[ ] R P r ( 5 , 30 )

DD

30.41381265

[ 2 nd ] [ R P ] [ ]R P r R P

DD

P R x

P R y

[ ] 5 [ ALPHA ] [ ] 30[ ] R P ( 5 , 30 )

DD

80.53767779

If r = 25, = 56°, what are x , y ? Ans : x = 13.97982259, y =20.72593931Six r = 25, = 56°, lo que es x , y? Resp : x = 13.97982259, y =20.72593931Sex r = 25, = 56°, o que é x , y? Resp : x = 13.97982259, y =20.72593931Falls r = 25, = 56°, was sind x , y? Antw : x = 13.97982259, y =20.72593931Six r = 25, = 56°, cobien vaut x , y? Rép : x = 13.97982259, y =20.72593931Se r = 25, = 56°, Che sono x , y ? Risp : x = 13.97982259, y =20.72593931Indien r = 25 en = 56? Hoeveel is dan x en y ? Antwoord : x =

13.97982259 en y = 20.72593931Hvis r = 25, = 56, hvad er så x , y ? Svar : x = 13.97982259, y =20.72593931

r = 25, = 56°, x , y? : x = 13.97982259, y= 20.72593931Je li r = 25, = 56°, to jakie s warto ci x , y? Odp : x =13.97982259, y = 20.72593931

r = 25, = 56°, x y : x = 13.97982259, y =20.72593931Jika r = 25, = 56? berapakah x , y ? Jawab : x = 13.97982259, y= 20.72593931

[ 2nd ] [ R P ] [ ]R P r R P

DD

P R xP R y


21/70

Ex 19

[ ] 25 [ ALPHA ] [ ] 56[ ] P R x ( 2 5 , 5 6 )

DD

13.97982259

[ 2nd ] [ R P ] [ ] [ ]R P r R P

DD

P R x

P R y

[ ] 25 [ ALPHA ] [ ] 56[ ] P R y ( 2 5 , 5 6 )

DD

20.72593931

Example 315 ! = 120

5 [ MATH ]0 ! 1 R A N D

DD

2 RA N D I3 R N D

[ ] [ ]5 !

DD

120.

Generates a random number between 0 and 1Generar un número aleatorio entre 0 y 1Gera um número randomico entre 0 e 1Erzeugt eine zufälligen Zahl zwischen 0 und 1Produisez un chiffre au hasard entre 0 et 1Genera un numero casuale tra 0 et 1Genereert een willekeurig getal tussen 0 en 1Genererer et tilfældigt tal mellem 0 og 1

0 1Generuje losow liczb ca kowit zawart mi dzy 0 i 1

0 1Menghasilkan sebuah bilangan acak antara 0 dan 1

01

[ MATH ] [ ]0 ! 1 R A N D

DD

2 RA N D I3 R N D

[ ] [ ]R A N D

DD0.103988648


22/70

Ex 20

Generates a random integer between 7 and 9Genera un entero aleatorio entre 7 y 9Gera um inteiro randomico entre 7 e 9Erzeugt eine Zufallszahl zwischen 7 und 9Génère un entier au hasard entre 7 et 9Genera un numero intero casuale fra 7 e 9Genereert een willekeurig getal tussen 7 en 9Genererer et tilfældigt heltal mellem 7 og 9

7 9Wygenerowa przypadkw liczb ca kowit z zakresu od 7 do 97 9

Menghasilkan sebuah bilangan bulat acak antara 7 dan 979

[ MATH ] [ ]0 ! 1 R A N D

DD

2 RA N D I3 R N D

[ ] 7 [ ALPHA ] [ ] 9[ ] R A N D I ( 7 , 9 )

DD

8.

RND ( sin 45 Deg. ) = 0.71 ( FIX = 2 )

[ MATH ] [ ] [ ]0 ! 1 R A N D

DD

2 RA N D I3 R N D

[ ] [ SIN ] 45 [ 2nd ] [ FIX ][ ] [ ] [ ] F 0 1 2 3 4 5 6 7 8 9

DD

[ ] [ ]R N D ( s i n ( 4 5 )

DD

0.71FIX

MAX ( sin 30 Deg. , sin 90 Deg. ) = MAX ( 0.5, 1 ) = 1

[ MATH ] [ MATH ]0 M A X 1 M I N

DD

2 S U M3 AV G

[ ] [ SI N ] 30 [ ] [ ALPHA ][ ] [ SIN ] 90 [ ] M A X ( s i n ( 3 0 )

DD

1

MIN ( sin 30 Deg., sin 90 Deg. ) = MIN ( 0.5, 1 ) = 0.5


23/70

Ex 21

[ MATH ] [ MATH ] [ ]0 M A X 1 M I N

DD

2 S U M3 AV G

[ ] [ SIN ] 30 [ ] [ AL PHA ][ ] [ SIN ] 90 [ ] M I N ( s i n ( 3 0 )

DD0.5

SUM (13, 15, 23 ) = 51

[ MATH ] [ MATH ] [ ]0 M A X 1 M I N

DD

2 S U M3 AV G

[ ] 13 [ ALPHA ] [ ] 15[ ALPHA ] [ ] 23 [ ] S U M ( 1 3 , 1 5 , 2

DD

51.

AVG (13, 15, 23 ) = 17

[ MATH ] [ MATH ] [ ] [ ]0 M A X 1 M I N

DD

2 S U M3 AV G

[ ] 13 [ ALPHA ] [ ] 15

[ ALPHA ] [ ] 23 [ ] A V G ( 1 3 , 1 5 , 2

DD

17.

Frac (10 ) 8 ) = Frac ( 1.25 ) = 0.25

[ MATH ] [ MATH ] [ MATH ]0 F r a c 1 I N T

DD

2 S G N3 AB S

[ ] 10 [ ) ] 8 [ ]F r a c ( 1 0 / 8 )

DD

0.25

INT (10 ) 8 ) = INT ( 1.25 ) = 1

[ MATH ] [ MATH ] [ MATH ] [ ]0 F r a c 1 I N T

DD

2 S G N3 AB S


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Ex 22

[ ] 10 [ ) ] 8 [ ] I N T ( 1 0 / 8 )

DD

1.

SGN ( log 0.01 ) =SGN ( 2 ) = 1

[ MATH ] [ MATH ] [ MATH ] [ ]0 F r a c 1 I N T

DD

2 S G N3 AB S

[ ] [ LOG ] 0.01 [ ]S G N ( l o g ( 0 . 0

DD

1.

ABS ( log 0.01) =ABS ( 2 ) = 2

[ MATH ] [ MATH ] [ MATH ] [ ][ ] 0 F r a c 1 I N T

DD

2 S G N3 AB S

[ ] [ LOG ] 0.01 [ ] A B S ( l o g ( 0 . 0

DD

2.

7 ! ) [ ( 7 4 ) ! ] = 840

7 [ MATH ] [ MATH ] [ MATH ][ MATH ] 0 n P r 1 n C r

DD

2 D e f m

[ ] 4 [ ]7 n P r 4

DD

840.

7 ! ) [ ( 7 4 ) ! x 3 ! ] = 35

7 [ MATH ] [ MATH ] [ MATH ][ MATH ] [ ] 0 n P r 1 n C r

DD

2 D e f m

[ ] 4 [ ]7 n C r 4

DD

35.


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Ex 23

Example 32

1.25 [ 2nd ] [ X 1 ] [ ]1 . 2 5 1

0.8DD

2 [ X 2 ] [ + ] [ ] 4 [ + ] 21 [ ][ + ] [ 2nd ] [ 3 ] 27 [ ] 2

2 + ( 4 + 21 ) +

12.DD

4 [ 2nd ] [ X ] 81 [ ] 4 x ( 8 1 )

3.DD

7 4 = 2401

7 [ 2nd ] [ ] 4 [ ] 7 4

2401.DD

Example 331yd 2 = 9 ft2 = 0.000000836 km 2

1 [ 2nd ] [ CONV ] [ 2nd ] [ CONV ][ ] f t

2 y d 2 m 2

DD

m i I e 2

k m 2

[ ]f t 2 y d 2 m 2

DD

m i I e 2

k m 2 1.

[ ]f t 2 y d 2 m 2

DD

m i I e 2

k m 2 9.


26/70

Ex 24

[ ] [ ]f t 2 y d 2 m 2

DD

m i I e 2

k m 2 0.000000836

Example 34

3 x G = 2.00177955 x 10

10

3 [ x ] [ 2nd ] [ CONST ] [ ] [ ]0 c 1 V m 2 N A

DD

3 g 4 m e5 G 6 m P 6.6725985

x10 11

[ ] [ ]3 G

2.00177955x10 10

DD

Example 35Use Multistatement function to the two statements : ( E = 15 )Use la función de multiinstrucción en las dos instrucciones:( E =15 )Use função Multi Sentença para as duas sentenças : ( E = 15 )Verwenden Sie die Mehrfachaussagefunktion für die zwei Aussagen : ( E = 15 )Utilisez une fonction Instructions multiples pour les deuxinstructions : ( E = 15 )

Usare la funzione Multistatement con le due frasi : ( E = 15 )Gebruik de Multistatement functie met de twee uitdrukkingen : ( E= 15 )Brug multisætningsfunktionen på de to sætninger : ( E = 15 )

:(E=15)Wykorzysta funkcj wielozadaniow do dwu instrukcji : ( E = 15 )

2 : ( E = 15 )Gunakan fungsi Multistatement untuk dua pernyataan di bawahini : ( E = 15 )

E x 13 = 195180 E = 12

15 [ SAVE ] [ E ] [ ]15 E

DD

15.


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Ex 25

[ ALPHA ] [ E ] [ x ] 13 [ ALPHA ][ ] 180 [ ) ] [ APLHA ] [ E ] E 1 3 1 8 0 / E

DD

195.

[ ]E 1 3 1 8 0 / E

DD12.

[ ]E 1 3 1 8 0 / E

DD

195.

Example 36Graph Y = e x

[ Graph ] [ 2nd ] [ e x ]r a p h Y = e ^ (

DD

[ ]

DD

Example 37Range : X min = 180, X max = 180, X scl = 90, Y min = 1.25,Y max = 1.25, Y scl = 0.5, Graph Y = sin (2 x)

[ Range ] [ () ] 180X m i n = 1 8 0

DD

[ ] 180 [ ] 90 [ ] [ () ] 1.25[ ] 1.25 [ ] 0.5 Y s c l = 0 . 5

DD

[ ] [ 2nd ] [ Factor ] 2X f a c t = 2

DD


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Ex 26

[ ] 2Y f a c t = 2

DD

[ ] [ Graph ] [ SIN ] 2[ ALPHA ] [ X ] p h Y = s i n ( 2 X

DD

[ ]

DD

[ G T ]

DD

[ G T ]

DD

Use Zoom function to enlarge and reduce Y = sin (2x)Use la función Zoom al para agrandar y reducir Y = sin (2x)Use função Zoom para ampliar e reduzir Y = sin (2x)Verwenden Sie die Zoomfunktion zur Vergrößerung oder reduzierung von Y = sin (2x)Utilisez la fonction Zoom pour agrandir et réduire Y = sin (2x)Usare la funzione dello zoom per allargare e ridurre Y = sin (2x)Teken de grafiek voor Y = cos (X) op de grafiek voor Y = sin ( x )Brug Zoom-funktionen til at forstørre og reducere Y = sin (2x)

ZoomY = sin (2x)

U y funkcj Zoom aby powi kszy i zmniejszy wykres Y = sin(2x)

Y = sin (2x)Gunakan fungsi Zoom untuk memperbesar atau memperkecil Y =sin (2x)

[ 2nd ] [ Zoom x f ]

DD


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Ex 27

[ 2nd ] [ Zoom x f ]

DD

[ 2nd ] [ Zoom Org ]

DD

[ 2nd ] [ Zoom x 1 / f ]

DD

[ 2nd ] [ Zoom x 1 / f ]

DD

Example 38Overdraw the graph for Y = X + 2 on the graph for Y = X 3 + 3 X 2 6 X 8Sobreponga el gráfico para Y = X + 2 sobre el gráfico Y = X 3 +3X 2 6 X 8Delinee o gráfico para Y = X + 2 sobre o gráficopara Y = X 3 +3X 2 6 X 8

Überziehen Sie den Graphen für Y = X + 2 auf dem Graphen fürY = X 3 + 3 X 2 6 X 8Superposez le graphique pour Y = X + 2 sur le graphique pour Y= X 3 + 3 X 2 6 X 8Sovrascrivere il grafico di Y = X + 2 sul grafico di Y = X 3 + 3 X2 6X 8Teken de grafiek voor Y = X + 2 op de grafiek voor Y = X 3 +3X2 6 X 8Tegn grafen for Y = X + 2 over grafen for Y = X 3 + 3 X 2 6 X 8

Y = X + 2 Y =X 3 + 3 X 2 6 X 8Na o y wykres funkcji Y = X + 2 na wykres funkcji Y = X 3 +3X2 6 X 8

Y = X + 2 Y = X 3 + 3 X 2 6 X 8Buatlah grafik Y = X + 2 pada grafik Y = X 3 + 3 X 2 6 X 8

[ Range ] [ () ] 8 [ ] 8 [ ] 2[ ] [ () ] 15 [ ] 15 [ ] 5 Y s c l = 5

DD


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Ex 28

[ ] [ Graph ] [ ALPHA ] [ X ][ 2nd ] [ x 3 ] [ + ] 3 [ ALPHA ] [ X ][ x 2 ] [ ] 6 [ ALPHA ] [ X ] [ ] 8

X 3 + 3 X 2 6 X 8

DD

[ ]

DD

[ Graph ] [ () ] [ ALPHA ] [ X ] [ + ]2 r a p h Y = X + 2

DD

[ ]

DD

Example 39Overdraw the graph for Y = cos (X) on the graph for Y = sin ( x )Sobreponga el gráfico para Y = cos (X) sobre el gráfico Y = sin( x )Delinee o gráfico para Y = cos (X) sobre o gráficopara Y = sin ( x )Überziehen Sie den Graphen für Y = cos (X) auf dem Graphen für Y = sin ( x )

Superposez le graphique pour Y = cos (X) sur le graphique pour Y = sin ( x )Sovrascrivere il grafico di Y = cos (X) sul grafico di Y = sin ( x )Teken de grafiek voor Y = cos (X) op de grafiek voor Y = sin ( x )Tegn grafen for Y = cos (X) over grafen for Y = sin ( x )

Y = cos (X) Y =sin ( x )Na o y wykres funkcji Y = cos (X) na wykres funkcji Y = sin ( x )

Y = cos (X) Y = sin ( x )Buatlah grafik Y = cos (X) pada grafik Y = sin ( x )

[ Graph ] [ SIN ] [ ]

DD

[ Graph ] [ COS ] [ ALPHA ] [ X ][ ]

DD


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Ex 29

Example 40Use la función Trace para analizar el gráfico para Y = cos ( x )Use la función Trace para analizar el gráfico para Y = cos ( x )Use função de traço Trace para analisar o gráfico para Y = cos( x )Verwenden Sie die Trace-Funktion, um den Graphen für Y = cos( x )

Utilisez la fonction Trace pour analyser le graphique pour Y = cos( x )Usare la funzione Trace per analizzare il grafico per Y = cos ( x )Gebruik de Trace functie om de grafiek voor Y = cos ( x ) teanalyserenBrug Trace-funktionen til at analysere grafen for Y = cos ( x )

Y= cos ( x )U y funkcj trasowania do analizy wykresu funkcji Y = cos ( x )

Y = cos ( x )Gunakan fungsi Trace untuk menganalisis grafik Y = cos ( x )

[ Graph ] [ COS ] [ ]

DD

[ Trace ]

DD

338.8235 294X =

[ ] [ ] [ ]

DD

X =

275.29411 76

[ 2nd ] [ X Y ]

DD

Y =

0.092268359

Example 41Draw and scroll the graph for Y = cos ( x )Represente y desplace el gráfico para Y = cos ( x )Desenhe e desloque o gráfico para Y = cos ( x )Zeichnen und scrollen Sie den Graphen für Y = cos ( x )Dessinez et faites défiler le graphique pour Y = cos ( x )Tracciare e far scorrere il grafico di Y = cos ( x )Teken en schuif door de grafiek voor Y = cos ( x )

Tegn og rul gennem grafen for Y = cos ( x )


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Ex 30

Y = cos ( x )

Narysowa wykres funkcji Y = cos ( x ) i przesun go na ekranieY = cos ( x )

Buatlah dan gulunglah grafik Y = cos ( x )

[ Graph ] [ COS ] [ ] [ ]

DD

[ ] [ ]

DD

[ ] [ ] [ ] [ ] [ ]

DD

Example 42Use Plot function to locate a point on ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ),( 18, 15 ), and then use Line function to connect.Use la función posicionar (PLOT) para posicionar un punto en ( 5 ,5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), y después use la función Linepara conectarlos.Use função tracejante plot para localizar um ponto em ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), e então use função linha Line paraconectar.Verwenden Sie die Plotfunktion, um einen Punkt auf ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), zu likalisieren und dann verwenden Siedie Zeilenfunktion zur Verbindung.Utilisez la fonction Plot (coordonnées) pour localiser un point sur ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), puis utilisez la fonctionLigne pour sy connecter.Usare la funzione Plot per individuare un punto su ( 5 , 5 ), ( 5 ,10 ), ( 15 , 15 ), ( 18, 15 ), ed allora usare funzione Line per collegare.Gebruik de Plot functie omeen punt op ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 )en ( 18, 15 ) te vinden en gebruik vervolgens de Line functie om teverbinden.Brug Plot-funktionen til at finde et punkt på ( 5 , 5 ), ( 5 , 10 ), ( 15 ,15 ), ( 18, 15 ), og brug derefter Line-funktionen til at forbinde.

( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ),.

Wyznaczy punkty o wspó rz dnych ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ),

( 18, 15 ), i po czy je lini aman .


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Ex 31

( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 )

Gunakan fungsi Plot untuk mementukan kedudukan titik-titik pada( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), dan kemudian gunakanfungsi Line untuk menghubungkan titik-titik itu.

[ Ran ge ] 0 [ ] 35 [ ] 5 [ ] 0[ ] 23 [ ] 5 Y s c l = 5

DD

[ ] [ 2nd ] [ Pl ot ] 5[ ALPHA ] [ ] 5 P L O T ( 5 , 5

DD

[ ]

X =

5.147058824DD

[ 2nd ] [ X Y ]

Y =

5.227272727DD

[ 2nd ] [ X Y ] [ 2nd ] [ Plot ] 5[ ALPHA ] [ ] 10 [ ]

DD

X =

5.147058824

[ 2nd ] [ Li ne ] [ ]

DD

[ 2nd ] [ Plot ] 15 [ ALPHA ] [ ]15 [ ] [ 2n d ] [ L in e ][ ]

DD

[ 2nd ] [ Plot ] 18 [ ALPHA ] [ ]15 [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] X =

25.73529412DD


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Ex 32

[ 2nd ] [ Li ne ] [ ]

DD

Example 43

Enter data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, then find out x = 7.5, S x =3.745585637, Cax = 0 , and Cpx = 0.503655401Entre datos : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, entonces encuentra x = 7.5, Sx =3.745585637, Cax = 0 , y Cpx = 0.503655401Entre dados : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, depois encontre x = 7.5, S x =3.745585637, Cax = 0 , e Cpx = 0.503655401Geben Sie ein : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, Sie sehen dann x = 7.5, S x =3.745585637, Cax = 0 , und Cpx = 0.503655401Entrez les données : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, puis trouvez x = 7.5, Sx =3.745585637, Cax = 0 , et Cpx = 0.503655401Entrare dato : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9 , X 3 = 12, FREQ3 = 7, poi trova x = 7.5, Sx =3.745585637, Cax = 0 , e Cpx = 0.503655401Voer de gegevens: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7 in, en vind de oplossing x =7.5, Sx = 3.745585637, Cax = 0 en Cpx = 0.503655401Indtast data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,

FREQ2 = 9, X 3 = 12, FREQ3 = 7, find så x = 7.5, Sx = 3.745585637,Cax = 0 , og Cpx = 0.503655401: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 =

5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, x =7.5, Sx = 3.745585637, Cax = 0 , Cpx = 0.503655401Wprowad dane : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, awwyniku otrzymasz x = 7.5, S x= 3.745585637, Cax = 0 , i Cpx = 0.503655401

: X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 , FREQ2= 9, X 3 = 12, FREQ3 = 7, x = 7.5, Sx = 3.745585637, Cax= 0 ,¥H¤ÎCpx = 0.503655401Masukkan data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 ,FREQ2 = 9, X 3 = 12, FREQ3 = 7, kemudian carilah x = 7.5, Sx =3.745585637, Cax = 0 , and Cpx = 0.503655401

[ MODE ] 11 - V A R 2 - V A R

DD

R E GD - C L

STAT


35/70

Ex 33

[ ] [ DATA ] [ ]D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 2X L S L= 2

DD STAT

[ ] 13 [ ]X U S L = 13

DD STAT

13.

[ DATA ]D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 3X 1 = 3

DD STAT

[ ] 2F R E Q 1 = 2

DD STAT

[ ] 5 [ ] 9 [ ] 12 [ ] 7F R E Q 3 = 7

DD STAT

[ 2nd ] [ STATVAR ]n x S x x

DD

R x X ma xCVx Xmin

STAT

18.

[ ]n x S x x

DD

R x X ma xCVx Xmin

STAT

7.5

[ ]n x S x x

DD

R x X ma xCVx Xmin

STAT

3.745585637


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Ex 34

[ Graph ] [ ]0 N D I S T

DD

1 H I S T2 S P C

STAT

[ ]

DD STAT

[ 2nd ] [ STATVAR ] [ ] [ ][ ] [ ] x x

2 Cpkx

DD

Cax Cpxppm

STAT

0.

[ ]x x 2 Cpkx

DD

Cax Cpxppm

STAT

0.503655401

[ Graph ]0 N D I S T

DD

1 H I S T2 S P C

STAT

[ ]

DD STAT

[ 2nd ] [ STATVAR ] [ Graph ] [ ][ ] 0 N D I S T

DD

1 H I S T2 S P C

STAT

[ ]

DD STAT

Example 44Enter data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4,X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, then find out x = 5, Sx = 2, Cax =0, Cay = 0.111111111Entre datos : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, entonces encuentra x = 5, Sx= 2, Cax = 0, Cay = 0.111111111


37/70

Ex 35

Entre dados : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, depois encontre x = 5, Sx = 2,Cax = 0, Cay = 0.111111111Geben Sie ein : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, Sie sehen dann x = 5, Sx =2, Cax = 0, Cay = 0.111111111Entrez les données : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 =3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, puis trouvez x = 5, Sx

= 2, Cax = 0, Cay = 0.111111111Entrare : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, poi trova x = 5, Sx = 2, Cax = 0, Cay= 0.111111111Voer de gegevens: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7 en Y 3 = 6 in, en vind de oplossingx = 5, Sx = 2, Cax = 0, Cay = 0.111111111Indtast data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 =4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, find så x = 5, Sx = 2, Cax = 0,Cay = 0.111111111

: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6,x = 5, Sx = 2, Cax = 0, Cay = 0.111111111Wprowad dane : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3,Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, awwyniku otrzymasz x =5, Sx = 2, Cax = 0, Cay = 0.111111111

: X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4,X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, x = 5, Sx = 2, Cax = 0,Cay = 0.111111111Masukkan data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, kemudian carilah x = 5, Sx= 2, Cax = 0, Cay = 0.111111111

[ MODE ] 1 [ ]1 - V A R 2 - V A R

DD

R E GD - C L

STAT

[ ] [ DATA ] [ ]D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 2 [ ] 8 [ ] 3 [ ] 9[ ] Y U S L = 9

DD STAT

9.


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Ex 36


DD

L I M I TD I S T R

STAT

[ ] 3 [ ] 4 [ ] 5 [ ] 7[ ] 7 [ ] 6 Y 3 = 6

DD STAT

[ 2nd ] [ STATVAR ] [ ]n x S x x

DD

Rx XmaxCVx Xmin

STAT

5.

[ ]n x S x x

DD

Rx XmaxCVx Xmin

STAT

2.

[ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] x x

2 x y

DD

y y 2

Cax CaySTAT

0.

[ ]x x 2 x y

DD

y y 2

Cax Cay STAT0.111111111

[ Graph ]

DD STAT

Example 45Based on Example 44, change Y1 = 4 as Y1 = 9 and X2 = 5 as X2 =8, then find Sx = 2.645751311Basado en el Ejemplo 44, cambia Y1 = 4 como Y1 = 9 y X2 = 5como X2 = 8, entonces encuentra Sx = 2.645751311Baseado no Exemplo 44, mude Y1 = 4 como Y1 = 9 e X2 = 5 comoX2 = 8, depois encontre Sx = 2.645751311 Auf Grund von Beispiel 44, ändem Sie Y1 = 4 zu Y1 = 9 und X2 = 5zu X2 = 8, Sie bekommen Sx = 2.645751311Sur lExemple 44, changez Y1 = 4 pour Y1 = 9 et X2 = 5 pour X2 = 8,puis trouvez Sx = 2.645751311Basarsi su Esempio 44, Cambia Y1 = 4 come Y1 = 9 e X2 = 5 comeX2 = 8, poi trova Sx = 2.645751311

Gebaseerd op voorbeeld 44, verander Y1 = 4 door Y1 = 9 en X2 =5 door X2 = 8, en vind vervolgens Sx = 2.645751311


39/70

Ex 37

Tag udgangspunkt i eksempel 44, ret Y1 = 4 til Y1 = 9 og X2 = 5 tilX2 = 8, og find så Sx = 2,645751311

44, Y1 = 4 Y1 = 9 X2 =5 X2 = 8, Sx = 2.645751311WPrzykadzie 44, zamie Y1 = 4 na Y1 = 9 i X2 = 5 na X2 = 8, awwyniku otrzyhmasz Sx = 2.645751311

44 Y1 = 4 Y1 = 9 X2 = 5 X2 = 8,Sx = 2.645751311

Berdasarkan Contoh 44, ubahlah Y1 = 4 menjadi Y1 = 9 dan X2 = 5menjadi X2 = 8, kemudian carilah Sx = 2.645751311


DD

L I M I TD I S T R

STAT

[ ] [ ] 9Y 1 = 9

DD STAT

[ ] 8X 2 = 8

DD STAT

[ 2nd ] [ STATVAR ] [ ] [ ]n x S x x

DD

R XmaxCVx Xmin

STAT

2.645751311

Example 46Enter data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 =12, FREQ 3 = 7, then find out t = 1.510966203, P ( t ) = 0.0654, Q( t ) = 0.4346, R ( t ) =0.9346Entre datos : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3= 12, FREQ 3 = 7, entonces encuentra t = 1.510966203, P ( t ) =0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Entre dados : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3= 12, FREQ 3 = 7, depois encontre t = 1.510966203, P ( t ) =0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Geben Sie ein : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X3 = 12, FREQ 3 = 7, Sie sehen dann t = 1.510966203, P ( t ) =0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Entrez les données : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2= 9, X 3 = 12, FREQ 3 = 7, puis trouvez t = 1.510966203, P ( t ) =0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346


40/70

Ex 38

Entrare dato : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3= 12, FREQ 3 = 7, poi trova t = 1.510966203, P ( t ) = 0.0654, Q( t ) = 0.4346, R ( t ) =0.9346Voer de gegevens: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 =9, X 3 = 12, FREQ 3 = 7 in, en vind de oplossing t = 1.510966203,P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Indtast data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3= 12, FREQ 3 = 7, og find så t = 1.510966203, P ( t ) = 0.0654, Q

( t ) = 0.4346, R ( t ) =0.9346: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, t = 1.510966203,P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346Wprowad dane : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, awwyniku otrzymasz t = 1.510966203, P ( t )= 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346

: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 = 12,FREQ 3 = 7, = 1.510966203, P ( t ) = 0.0654, Q ( t ) =0.4346, R ( t ) =0.9346Masukkan data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9,X 3 = 12, FREQ 3 = 7, kemudian carilah t = 1.510966203, P ( t ) =0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346

[ MODE ] 11 - V A R 2 - V A R

DD

R E GD - C L

STAT

[ ] [ DATA ] [ ] [ ] D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 2 [ ] a x = 2

DD STAT

2.

[ DATA ] [ ] 3 [ ] 2 [ ] 5[ ] 9 [ ] 12 [ ] 7 F R E Q 3 = 7

DD STAT

[ 2nd ] [ STATVAR ] [ ]P ( t ) Q ( t )

DD

R ( t ) t 1. 51096 620 3

STAT


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Ex 39

[ ]P ( t ) Q ( t )

DD

R ( t ) t0.9346

STAT

[ ]P ( t ) Q ( t )

DD

R ( t ) t

0.4346STAT

[ ]P ( t ) Q ( t )

DD

R ( t ) t0.0654

STAT

Example 47For the following data using linear regression and estimate x = ?for y = 573 and y = ? for x = 19

Para los datos siguientes usando regresión lineal y estimación x =? para y =573 e y = ? para x = 19

Para os dados seguintes usando regressão linear e estimativa x =? para y =573 e y = ? para x = 19

Für die folgenden Daten unter Verwendung der linearenRegression und Schätzung x = ? für y = 573 und y = ? für x = 19

Pour les données suivantes utilisez la Régression linéaire etestimez x =? pour y =573 et y = ? pour x = 19

Per i seguenti dati usando regressione lineare e stimare x = ?per y = 573 e y = ? per x = 19

Voor de volgende gegevens aan de hand van de lineaireregressie en voorspel x ' =? voor y =573 en y ' = ? voor x = 19

Brug lineær regression på de følgende data, og estimer x ' =? for y =573 og y ' = ? for x = 19

x =? y =573 y = ? x = 19

Zastosuj regresj liniow dla nast puj cych danych i znajd x = ?for y = 573 i y = ? for x = 19

y = 573, x ' = ? x =19 y ' = ?

Untuk data berikut ini gunakan regresi linear dan estimasikan x '= ? untuk y = 573 dan y ' = ? untuk x = 19

X 15 17 21 28

Y 451 475 525 678


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Ex 40

[ MODE ] 1 [ ]1 - V A R 2 - V A R

DD

R E GD - C L

STAT

[ ]L I N L O G e

DD

X 2 I N V

Q U A D STAT

[ ] [ DATA ]D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 15 [ ] 451 [ ] 17[ ] 475 [ ] 21 [ ] 525 [ ]28 [ ] 6 78

Y 4 = 6 7 8

DD STATL I N

[ 2nd ] [ STATVAR ] [ Graph ]

DD STAT

[ 2nd ] [ STATVAR ] [ ] [ ] [ ]a b r x y

DD STATL I N[ ] 573 [ ]

x ( 5 7 3 )

DD STAT

22.56700734

[ 2nd ] [ STATVAR ] [ ] [ ] [ ][ ] a b r x y

DD STATL I N

[ ] 19 [ ]y ( 1 9 )

DD STAT

510.2658228

Example 48For the following data using quadratic regression and estimate y = ? for x = 58 and x = ? for y =143


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Ex 41

Para los datos siguientes usando regresión cuadrática yestimación y = ? para x = 58 e x = ? para y = 143Para os dados seguintes usando regressão quadrática eestimativa y = ? para x = 573 e x = ? para y = 143Für die folgenden Daten unter Verwendung der quadratischenRegression und Schätzung y = ? für x = 573 und x = ? für y =143Pour les données suivantes utilisez la Régression quadratique et

estimez y = ? pour x = 573 et x = ? pour y = 143Per i seguenti dati usando regressione quadratica e stimare y = ?per x = 56 e x = ? per y = 143Voor de volgende gegevens aan de hand van de kwadratischeregressie en voorspel y ' = ? voor x = 58 en x ' =? voor y =143Brug kvadratregression på de følgende data, og estimer y ' = ? for x = 58 og x ' =? for y =143

y =? x = 573 x = ? y = 143Zastosuj regresj liniow dla nast puj cych danych i znajd y =?for x = 573 i x = ? for y = 143

x = 58, y ' = ? y =143 x ' = ?Untuk data berikut ini gunakan regresi kuadratik dan estimasikanx ' = ? untuk y 58 dan y ' = ? untuk x =143

X 57 61 67

Y 1 01 117 155

[ MODE ] 1 [ ]1 - V A R 2 - V A R

DD

R E GD - C L

STAT

[ ] [ ] [ ]L I N L O G e

DD

X 2 I N VQ U A D

STAT

[ ] [ DATA ]D A T A I N P U T

DD

L I M I TD I S T R

STAT

[ ] 57 [ ] 101 [ ] 61[ ] 117 [ ] 67 [ ] 155 Y 3 = 1 5 5

DD STATQ U A D


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Ex 42

[ 2nd ] [ STATVAR ] [ Graph ]

DD STAT

[ 2nd ] [ STATVAR ] [ ] [ ] [ ]a b c x y

DD STATQUAD

[ ] 143 [ ]x 1 x 2

DD STAT

65.36790453QUAD

[ ]x 1 x 2

DD STAT

35.48923833QUAD

[ 2nd ] [ STATVAR ] [ ] [ ] [ ][ ] a b c x y

DD STATQUAD

[ ] 58 [ ]y ( 5 8 )

DD STAT

104.3

Example 4931 10 = 1F16 = 11111 2 = 37 8[ MODE ] 2

d

31 [ ]d 3 1

d

31

[ dhbo ]D H B O

d

31


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Ex 43

[ ]D H B O

h

1F

[ ]D H B O

b

11111

[ ]D H B O

o

37

Example 504777 10 = 1001010101001 2[ MODE ] 2 [ dhbo ] [ ] [ ]

D E C H E X B I NO C T od h b

o

[ ] [ dhbo ] [ ] [ ]D E C H E X B I NO C T od h b

b

[ ] 4777 [ ] d 4 7 7 71b

10101001

[ ]d 4 7 7 7

2b

10010

[ ]d 4 7 7 7

3b

0

[ ]d 4 7 7 7

4b

0

Example 51


46/70

Ex 44

How is 3A 16 expressed as a nega ive ? Ans : FFFFFFC6Cómo se expresa 3A 16 comoun negativo ? Resp : FFFFFFC6Como se expressa 3A 16 como um negativo ? Resp : FFFFFFC6Wie wird 3A 16 negativ ausgedrückt ? An : FFFFFFC6Comment 3A 16 est-il exprimé en tant que négative ? Rép :FFFFFFC6Come è 3A 16 è espresso come un negativo ? Risp : FFFFFFC6Hoe wordt 3 A 16 voorgesteld als een negatief getal? Antwoord :

FFFFFFC6Hvordan udtrykkes 3A 16 som et negativt tal ? Svar : FFFFFFC63A 16 ? : F FFFFFC6

Wjaki sposób mo na przedstwi liczb 3A16 jako liczb ujemn ?Odp : FFFFFFC63A 16 : FFFFFFC6Bagaimanakah cara mengekspresikan negatif dari 3A 16 ? Jawab :FFFFFFC6

[ MODE ] 2 [ dhbo ] [ ]D E C H E X B I NO C T od h b

b

[ ] [ NEG ] 3 /A [ ]N E G h 3 / A

h

FFFFFFC6

Example 52

1234 10 + 1EF 16 ) 24 8 = 2352 8 = 1258 10

[ MODE ] 2 [ dhbo ] [ ]D E C H E X B I NO C T od h b

h


o

[ ] 1234 [ + ]d 1 2 3 4 +

o

[ dhbo ] [ ] [ ] [ ]D E C H E X B I NO C T od h b

o


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Ex 45

[ ] 1IEIF [ ) ] d 1 2 3 4 + h 1 IEIF /o

[ dhbo ] [ ] [ ]D E C H E X B I NO C T o

d h b

o

[ ] 243 4 + h 1IEIF / O 24

o

[ ]d 1 2 3 4 + h 1 IEIF /

o

2352

[ dhbo ] [ ] [ ] [ ]D H B O

d

1258

Example 531010 2 AND ( A 16 OR 7 16 ) = 1010 2 = 10 10

[ MODE ] 2 [ dhbo ] [ ] [ ] D E C H E X B I NO C T od h b

d

[ ] [ dhbo ] [ ] [ ] [ ][ ] D E C H E X B I N

O C T od h b

b

[ ] 1010 [ AND ] [ ( ) ]1 0 1 0 A N D (

b


b


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Ex 46

[ ] /A [ OR ] [ dhbo ] [ ][ ] [ ] D E C H E X B I N

O C T od h b

b

[ ] 7 [ ]b 1 0 1 0 AN D (

b

1010

[ dhbo ] [ ] [ ]D H B O

d

10

Example 54Create a program to preform arithmetic calculation for complexnumbersCree un programa para realizar el cálculo aritmético de númeroscomplejosCrie um programa para executar cálculo aritmético para númeroscomplexosErstellen Sie ein Programm, um arithmetische Berechnungen für komplexe ZahlenCréez un progeamme pour accomplir des calculs arithmétiquespour des nombres complexesGenerare un programma per effettuare calcoli aritmetici per numeri complessi (Descrizione)Creëer een programma om een wiskundige berekening metcomplexe nummers uit te voeren.Opret et program, der udfører aritmetiske beregninger for komplekse tal

Napisz program przeprowadzania oblicze arytmetycznych liczbzespolonych

Buatlah sebuah program untuk menjalankan perhitunganaritmetika untuk bilangan kompleks

Z 1 = A + B i, Z 2 = C + D i Sum : Z 1 + Z 2 = ( A + B ) + ( C + D ) i Difference : Z 1 Z 2 = ( A B ) + ( C D ) i Product : Z 1 x Z 2 = E + F i = ( AC BD ) + ( AD + BC ) i

Quotient : Z 1 Z 2 = E + F i =


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Ex 47

Program Type : MAIN

Line Program

1 L b l 0 :

2 P R I N T " C H O O S E T H E O P E R A T

O R " ; S L E E P ( 5 ;

3 P R I N T " 1 : + 2 : 3 : 4 : / " ;

4 I N P U T O ;5 I F ( O > 4 T H E N { G O T O 0 ; }

6 I N P U T A , B , C , D ;

7 I F ( O == 1 ) T H E N { G O T O 3 ; }

8 I F ( O == 2 T H E N { G O T O 2 ; }

9 I F ( O == 3 T H E N { G O T O 1 ; }

10 E L S E { E = ( A C + B D / ( C 2 + D 2

11 F = ( B C A D / ( C 2 + D 2 }

12 G O T O 4 ;

13 L b l 1 :

14 E = ( A C B D ; F = ( A D + B C

15 G O T O 4 ;

16 L b l 2 :

17 E = ( A C ; F = ( B D ; G O T O 4 ;

18 L b l 3 :

19 E = ( A + C ; F = ( B + D ; G O T O 4 ;

20 L b l 4 :

21 Q = A B S ( F

22 I F ( F > 0 T H E N { P R I N T E , " + " ,

Q , " I " ; }23 I F ( F < 0 T H E N { P R I N T E , " " ,

Q , " I " ; }

2 4 E N D

RUN

When the message 1: +, 2 : , 3 : x , 4 : / appears on thedisplay, you can input a O value to any of the foll owing valuesfor specifying the type of operation to be performed.Cuando aparezca el mensaje 1: +, 2 : , 3 : x , 4 : / en lapantalla, se puede introducir un valor O en cualquiera de losvalores siguientes para especificar el tipo de operación a realizar.Quando a mensagem 1: +, 2 : , 3 : x , 4 : / aparecer na tela,você pode entrar um valor O a quaisqer dos valores seguintespara especificar o tipo de operação a ser executado.Wenn die Meldung 1: +, 2 : , 3 : x , 4 : / Auf dem Bildschirmerscheint, können Sie einen O Wert zu jedem der folgendenWerte eingeben zur Spezifizierung der auszuführendenOperationsart.


50/70

Ex 48

Lorsque le message 1: +, 2 : , 3 : x , 4 : / saffiche, vouspouvez entrer une valeur O à chacune des valeurs suivantespour spécifier le type dopération à accomplir.Quando compare il messaggio 1: +, 2 : , 3 : x , 4 : / suldisplay, si può immettere un valore 0 ad uno dei seguenti valoriper specificare il tipo di operazione da effettuare.Wanneer het bericht 1: +, 2 : , 3 : x , 4 : / op het beeldschermverschijnt, Wanneer het bericht " 1: A(N), 2 :S(N) " op het

beeldscherm verschijnt, kunt u een "O" waarde toekennen aan devolgende waarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen 1: +, 2 : , 3 : x , 4 : / vises på displayet, kandu indtaste en værdi " O " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.

1: +, 2 : , 3 : x , 4 : / , O

, .Je li pojawi si komunikat 1: +, 2 : , 3 : x , 4 : / , to mo nanada warto O dowolnej z nast puj cych wielko ci, abywybra typ operacji, która ma by wykonana.

1: +, 2 : , 3 : x , 4 : / O

Jika pesan 1: +, 2 : , 3 : x , 4 : / muncul di layar, Anda dapatmemasukkan nilai "O " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.

1.... Z 1 + Z 2 2.... Z 1 Z 23.... Z 1 x Z 2 4.... Z 1 ) Z 2

Z 1 = A + B i = 17 + 5 iZ 2 = C + D i = ( 3 ) + 14 i

Z 1 + Z 2 =14 + 19 i

[ ] ( 5 Seconds )C H O O S E T H E

PROGDD

1 : + 2 : 3 :

PROGDD

[ ] 1O = 1

PROGDD


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Ex 49

[ ] 17 [ ] 5 [ ][ ( ) ] 3 [ ] 14 D = 1 4

PROGDD

[ ]1 4 + 1 9 I

PROGDD

Z 1 = A + B i = 10 + 13 iZ 2 = C + D i = 6 + 17 i

Z 1 Z 2 = 4 4 i


PROGDD

1 : + 2 : 3 :

PROGDD

[ ] 2O = 2

PROGDD

[ ] 10 [ ] 13 [ ][ ( ) ] 6 [ ]17 D = 1 7

PROGDD

[ ]4 4 I

PROGDD

Z 1 = A + B i = 2 + ( 5 ) iZ 2 = C + D i = 11 + 17 i

Z 1 x Z 2 = 107 21 i


PROGDD


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Ex 50

1 : + 2 : 3 :

PROGDD

[ ] 3O = 3

PROGDD

[ ] 2 [ ] [ ( ) ] 5[ ] 11 [ ] 17 D = 1 7

PROGDD

[ ]1 0 7 2 1 I

PROGDD

Z 1 = A+ B i = 6 + 5 iZ 2 = C + D i = ( 3 ) + 4 i

Z 1Z 2

= 0.08 1.56 i


PROGDD

1 : + 2 : 3 :

PROGDD

[ ] 4O = 4

PROGDD

[ ] 6 [ ] 5 [ ][ ( ) ] 3 [ ] 4 D = 4

PROGDD

[ ]0. 0 8 1. 5 6 I

PROGDD

Example 55


53/70

Ex 51

Create a program to determine solutions for quadratic equationCree un programa para determinar las soluciones de la ecuacioncuadráticaCrie um programa para determinar soluções para equaçãoquadráticaErstellen sie ein Programm, um die Lösungen für quadratischeGleichungen zu bestimmenCréez un programme pour déterminer les solutions pour une

équation quadratiqueGenerare un programma per determinare le soluzioni diunequazione quadraticaCreëer een programma om een kwadratische vergelijking op telossenOpret et program, der finder løsninger for andengradsligninger

Napisz program pozwalaj cy rozwi zywa równania kwadratowe

Membuat sebuah program untuk menentukan penyelesaian daripersamaan kuadratik

A X 2 + B X + C = 0, D = B 2 4AC

1) D > 0 ,

2) D = 0

3) D < 0 ,

Program Type : MAIN

Line Program1 I N P U T A , B , C ;

2 D = B 2 4 A C

3 E = B / 2 A ; F = ( A B S ( D / 2 A

4 G = E + F ; H = E F

5 I F ( D > 0 T H E N { P R I N T " X 1 = " ,

G , " X 2 = " , H ; }

6 I F ( D == 0 T H E N { P R I N T " X = " , E

; }

7 I F ( D < 0 T H E N { P R I N T " X 1 = " ,

E , " + " , F , " I " , " X 2 = " , E , " ", F , " I " ; }

8 E N D

RUN

2 X 2 7 X + 5 = 0 X 1 = 2.5 , X 2 = 1

[ ] A =

PROGDD


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Ex 52

2 [ ] [ () ] 7 [ ] 5C = 5

PROGDD

[ ]X 1 = 2 . 5 X 2 = 1

PROGDD

25 X 2 70 X + 49 = 0 X = 1.4

[ ] A =

PROGDD

25 [ ] [ () ] 70 [ ] 49C = 4 9

PROGDD

[ ]X = 1 . 4

PROGDD

X 2 + 2 X + 5 = 0 X 1 = 1 + 2 i, X 2 = 1 2 i

[ ] A =

PROGDD

1 [ ] 2 [ ] 5C = 5

PROGDD

[ ]X 1 = 1 + 2 I X 2

PROGDD

[ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] [ ] [ ][ ] [ ] [ ] [ ] [ ] [ ][ ] [ ]

2 I X 2 = 1 2 I

PROGDD

Example 56


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Ex 53

Create a program for common difference sequence and numbers( A : First item, D : Common difference, N : number )Cree un programa para la secuencia de progresión aritmética ynúmeros ( A : Primer elemento, D : Diferencia común, N :número )Crie um programa para sequências e números de diferençacomum ( A : Primeiro item, D : Diferença comum, N : número )Erstellen Sie ein Programm für normale Differenzsequenzen und

Zahlen ( A : Erster Punkt, D : Allgemeine Differenz, N : Zahl )Créez un programme pour une séquence de différence communeet les nombres ( A : Premier objet D : Différence commun, N :nombre )Generare un programma per numeri e sequenze di differenzecomuni / (Descrizione) : A : Primo oggetto, D : Differenza comune,N : numero,Creëer een programma voor het berekenen van het gemeenverschil en getallen ( A : eerste item, D : Gemeen verschil, N :getal)Opret et program for fælles differensfølger og tal ( A : førsteelement, D : fælles differens, N : tal )

( A : , D : , N :)

Napisz program do analizy post pu arytmetycznego ( A :Pierwszy wyraz, D : Ró nica post pu, N : wyraz ogólny )

(A : , D : , N : )Membuat sebuah program untuk urutan perbedaan umum danbilangan-bilangan ( A : Item pertama, D : Perbedaan umum, N :bilangan )

Sum : S ( N ) = A+(A+D)+(A+2D)+(A+3D)+...

=

Nth item : A ( N ) = A+ (N 1)D

Program Type : MAIN

Line Program

1 P R I N T " 1 : A ( N 2 : S N " ; S L

E E P ( 5 ;

2 I N P U T P , A , D , N ;

3 I F ( P == 1 T H E N { G O T O 1 ; }

4 S = N ( 2 A + ( N 1 D / 2

5 P R I N T " S ( N = " , S ;

6 G O T O 2 ;

7 L b l 1 :

8 T = A + ( N 1 D

9 P R I N T " A ( N = " , T ;

10 L b l 2 : E N D

RUN


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Ex 54

When the message 1: A(N), 2 :S(N) appears on the display,you can input a P value to any of the following values forspecifying the type of operation to be performed.Cuando aparezca el mensaje 1: A(N), 2 :S(N) en la pantalla, sepuede introducir un valor P en cualquiera de los valoressiguientes para especificar el tipo de operación a realizar.Quando a mensagem 1: A(N), 2 :S(N) aparecer na tela, vocêpode entrar um valor P a quaisqer dos valores seguintes para

especificar o tipo de operação a ser executado.Wenn die Meldung 1: A(N), 2 :S(N) Auf dem Bildschirmerscheint, können Sie einen P Wert zu jedem der folgendenWerte eingeben zur Spezifizierung der auszuführendenOperationsart.Lorsque le message 1: A(N), 2 :S(N) saffiche, vous pouvezentrer une valeur P à chacune des valeurs suivantes pourspécifier le type dopération à accomplir.Quando compare il messaggio 1: A(N), 2 :S(N) sul display, sipuò immettere un valore P ad uno dei seguenti valori perspecificare il tipo di operazione da effettuare.Wanneer het bericht 1: A(N), 2 :S(N) op het beeldschermverschijnt, kunt u een " P " waarde toekennen aan de volgendewaarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen 1: A(N), 2 :S(N) vises på displayet, kan duindtaste en værdi " P " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.

1: A(N), 2 :S(N) , P

, .Je li pojawi si komunikat 1: A(N), 2 :S(N) , to mo na nadawarto P dowolnej z nast puj cych wielko ci, aby wybra typoperacji, która ma by wykonana.

1: A(N), 2 :S(N) P

Jika pesan 1: A(N), 2 :S(N) muncul di layar, Anda dapatmemasukkan nilai " P " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.

1.... A(N) 2.... S(N)

A = 3 , D = 2, N = 4 A (N) = A (4) = 9

[ ] ( 5 Seconds )1 : A ( N ) 2 : S (

PROGDD

P =

PROGDD


57/70


58/70

Ex 56

Opret et program for fælles brøkfølger og tal ( A : første element,R : fælles brøk, N : tal )

( A : , R : , N :)

Napisz program do analizy post pu geometrycznego( A :Pierwszy wyraz, R : iloraz post pu, N : wyraz ogólny )

(A : , R : , N : )

Membuat sebuah program untuk urutan rasio umum danbilangan-bilangan ( A : Item pertama, R : rasio umum, N :bilangan )

Sum : S ( N ) = A+AR+AR 2+AR 3....

1) R 1

2) R =1 A ( N ) = AR (N 1)Nth item : A ( N ) = A (N 1)

Program Type : MAIN

Line Program

1 P R I N T " 1 : A ( N ) 2 : S ( N ) " ; S L

E E P ( 5 ;

2 I N P U T P , A , R , N ;

3 I F ( P == 1 T H E N { G O T O 1 ; }

4 I F ( R == 1 T H E N { S = A N }

5 I F ( R 1 ) T H E N { S = A ( R ^ N 1 ) / (R 1 }

6 P R I N T " S ( N = " , S ;

7 G O T O 2 ;

8 L b l 1 :

9 T = A R ^ ( N 110 P R I N T " A ( N = " , T ;

11 L b l 2 : E N D

RUN

When the message 1: A(N), 2 :S(N) appears on the display,you can input a P value to any of the following values forspecifying the type of operation to be performed.Cuando aparezca el mensaje 1: A(N), 2 :S(N) en la pantalla, sepuede introducir un valor P en cualquiera de los valoressiguientes para especificar el tipo de operación a realizar.Quando a mensagem 1: A(N), 2 :S(N) aparecer na tela, vocêpode entrar um valor P a quaisqer dos valores seguintes paraespecificar o tipo de operação a ser executado.Wenn die Meldung 1: A(N), 2 :S(N) Auf dem Bildschirmerscheint, können Sie einen P Wert zu jedem der folgendenWerte eingeben zur Spezifizierung der auszuführendenOperationsart.


59/70

Ex 57

Lorsque le message 1: A(N), 2 :S(N) saffiche, vous pouvezentrer une valeur P à chacune des valeurs suivantes pourspécifier le type dopération à accomplir.Quando compare il messaggio 1: A(N), 2 :S(N) sul display, sipuò immettere un valore P ad uno dei seguenti valori perspecificare il tipo di operazione da effettuare.Wanneer het bericht 1: A(N), 2 :S(N) op het beeldschermverschijnt, kunt u een " P " waarde toekennen aan de volgende

waarden om het type van bewerking op te geven die zaluitgevoerd worden.Når meddelelsen 1: A(N), 2 :S(N) vises på displayet, kan duindtaste en værdi " P " for hver af de følgende værdier for atangive, hvilken type operation der skal udføres.

1: A(N), 2 :S(N) , P

, .Je li pojawi si komunikat 1: A(N), 2 :S(N) , to mo na nadawarto P dowolnej z nast puj cych wielko ci, aby wybra typoperacji, która ma by wykonana.

1: A(N), 2 :S(N) P

Jika pesan 1: A(N), 2 :S(N) muncul di layar, Anda dapatmemasukkan nilai " P " ke salah satu dari nilai-nilai berikut iniuntuk menentukan tipe operasi yang akan dijalankan.

1.... A(N) 2.... S(N)

A = 5, R = 4, N = 7 A (N) = A (7) = 20480

[ ] ( 5 Seconds ) 1 : A ( N ) 2 : S (

PROGDD

P =

PROGDD

1 [ ] 5 [ ] 4 [ ]7 N = 7

PROGDD

[ ] A ( N ) = 2 0 4 8 0

PROGDD

A = 5, R = 4, N = 9 S (N) = S (9) = 436905


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Ex 58

[ ] ( 5 Seconds )1 : A ( N ) 2 : S (

PROGDD

P =

PROGDD

2 [ ] 5 [ ] 4 [ ]9 N = 9

PROGDD

[ ]S ( N ) = 4 3 6 9 0 5

PROGDD

A = 7, R = 1, N = 14 S (N) = S (14) = 98

[ ] ( 5 Seconds )1 : A ( N ) 2 : S (

PROGDD

P =

PROGDD

2 [ ] 7 [ ] 1 [ ]14 N = 1 4

PROGDD

[ ]S ( N ) = 9 8

PROGDD

Example 58Create a program to determine solutions for variable linear equation.Cree un programa para determinar las soluciones de unaecuación lineal variable.Crie um programa para determinar soluções para equação linear

variável.


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Ex 59

Erstellen Sie ein Programm, um Lösungen für eine variablelineare Gleichung zu bestimmen.Créez un programme pour déterminer les solutions pour uneéquation linéaire variableGenerare un programma per determinare le soluzioni diequazioni lineari variabiliCreëer een programma voor het berekenen van een variabelelineaire vergelijking.

Opret et program, der finder løsninger for variable lineæreligninger .

Napisz program pozwalaj cy rozwi zywa równania liniowe

Membuat sebuah program untuk menentukan penyelesaian daripersamaan kuadratik

Program Type : MAIN

Line Program

1 I N P U T A , B , C , D , E , F ;

2 G = A B S ( A / A B S ( D

3 D = D G ; E = E G ; F = F G

4 I F ( A == D T H E N { G O T O 1 ; }

5 H = ( C + F / ( B + E

6 G O T O 2 ;

7 L b l 1 :

8 H = ( C F / ( B E9 L b l 2 :

10 A = ( C B H / A

11 P R I N T " A N S = " ;

12 P R I N T " X = " , A , " Y = " , H ;

1 3 E N D

RUN

[ ] A =

PROGDD

4 A = 4

PROGDD


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Ex 60

[ ] [ ( ) ] 1 [ ] 30[ ] 5 [ ] 9 [ ]17

F = 1 7

PROGDD

[ ]X = 7 Y = 2

PROGDD

Example 59Create three subroutines to store the below formulas and useGOSUB-PROG command to write a mainroutine for executing.( Subroutine 1~3 )Cree tres subrutinas para almacenar las fórmulas de másadelante y use el comando GOSUB-PROG para escribir unarutina principal para ejecutar. ( Subrutina 1~3 )Crie três sub-rotinas para armazenar as fórmulas abaixo e usecomando GOSUB-PROG para escrever uma rotina pricipal paraexecução. ( Sub-rotina 1~3 )Erstellen Sie drei Unterprogramme zur Speicherung der untengenannten Formeln und verwenden Sie den GOSUB-PROGBefehl, um ein Hauptprogramm zur Ausführung. ( Unterprogramm1~3 zu schreiben )Créez trois sous-routines pour enregistrer les formulesci-dessous et utilisez la commande GOSUB-PROG pour écrireune routine principale pour lexécution. ( Sous-routine 1~3 )Generare tre sottoroutine per memorizzare le seguenti formule e

usare il comando GOSUB-PROG per scrivere un routineprincipale per esecuzione/sottoroutine 1~3Creëer drie subroutines om de onderstaande formules op te slaanen gebruik GOSUBSPROG opdrachten om een hoofdprogrammae creëren voor het uitvoeren van deze subroutines. ( Subroutine

1~3 )Opret tre subrutiner til at opbevare formlerne nedenfor, og brugkommandoen GOSUB-PROG til at skrive en hovedrutine, der står for afviklingen. ( Subrutine 1~3 )

GOSUB-PROG.

( 1~3 )Napisz trzy podprogramy do przechowywania poni szych wzorówi uæyj polecenia GOSUB-PROG do napisania programug ównego. ( Podprogram 1~3 )

GOSUB-PROG( 1~3)

Membuat tiga subrutin untuk menyimpan rumus-rumus di bawahini dan menggunakan perintah GOSUB-PROG sebagai tempatmenuliskan rutin utama untuk mengeksekusi. ( Subrutin 1~3 )


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64/70

Ex 62

[ ] ( 5 Seconds )C H A R G E = 4 . 5

PROGDD

486I = 4 8 6

PROGDD

[ ] 2 A = 2

PROGDD

[ ] ( 5 Seconds )P O W E R = 2 4 3

PROGDD

V O L TA G E = 2

PROGDD

Example 60

Create a program that draws Graph Y = and Graph Y

= 2 X with Range : X min = 3.4, X max = 3.4, X scl = 1, Y min = 3, Y max = 3, Y scl = 1Cree un programa que dibuje el Gráfico Y = elGráfico Y = 2 X con Rango: X min = 3.4, X max = 3.4, X scl = 1,Ymin = 3,Y max = 3, Y scl = 1Crie um programa que desenhe Gráfico Y = eGráfico Y = 2 X com Variação : X min = 3.4, X max = 3.4, X scl =1,Y min = 3,Y max = 3, Y scl = 1Erstellen Sie ein Programm, das den Graph Y = undGraph Y = 2 X mit Bereich : X min = 3.4, X max = 3.4, X scl = 1,Y min = 3, Y max = 3, Y scl = 1Créez un programme qui dessine un Graphique Y = et un Graphique Y = 2 X avec lÉtendue : X min = 3.4, X max =3.4, X scl = 1, Y min = 3, Y max = 3, Y scl = 1Generare un programma che disegni Grafico Y = eGrafico Y=2 x con Intervallo : X min = 3.4, X max = 3.4, X scl =1,Y min = 3, Y max = 3, Y scl =1Creëer een programma dat de grafiek Y = en degrafiek Y = 2 X tekent met een bereik van: X min = 3.4, X max =3.4, X scl = 1, Y min = 3, Y max = 3 en Y scl = 1


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66/70

Ex 64

Utilisez la commande FOR pour calculer 1 + 6 = ? , 1 + 5 = ? , 1 +4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?Usare il comando FOR per calcolare 1 + 6 = ? , 1 + 5 = ? , 1 + 4= ?, 2 + 6 = ?, 2 + 5 = ? , 2 + 4 = ?Gebruik een FOR-opdracht om een programma te creëren dat 1 +6 = ? , 1 + 5 = ? 1 + 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ? berekent.Brug FOR-kommandoen til at beregne 1 + 6 = ? , 1 + 5 = ? , 1 + 4= ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?

FOR 1 + 6 = ? , 1 + 5 = ? , 1 +4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?U yj polecenia FOR do obliczenia 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?,2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?

FOR 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2 + 6 = ?, 2 +5 = ? 2 + 4 = ?Gunakan perintah FOR untuk menghitung 1 + 6 = ? , 1 + 5 = ? , 1+ 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ?

Program Type : MAIN

Line Program

1 C L S ;

2 F O R ( A = 1 ; A 2 ; A ++ {

3 F O R ( B = 6 ; B 4 ; B

4 { C = A + B ; P R I N T A , " + " , B , " = ", C ; } }

5 E N D

RUN

[ ]1 + 6 = 7

PROGDD

1 + 5 = 6

PROGDD

1 + 4 = 5

PROGDD

2 + 6 = 8

PROGDD


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Ex 65

2 + 5 = 7

PROGDD

2 + 4 = 6

PROGDD

Example 62Set the program type of the program area as BaseN andcalculate the following question :Establezca el tipo de programa de la zona de programa como BaseN y calcule la siguiente cuestión :fixe o tipo de programa da área de programa como BaseN ecalcule a seguinte questão :Setzen Sie die Programmart des Programmbereichs als BaseN und berechnen Sie die folgende Frage :Spécifiez le type de programme de la zone de programme en tantque BaseN et calculez la question suivante :Regolare il tipo di programma della zona di programma come BaseN e calcolare la seguente domanda :Stel het programmatype van het programmageheugen in op "Basen " en creëer een programma dat de volgende vraag oplost:Indstil programområdet til " BaseN ", og beregn følgendespørgsmål :

BaseN :

Wejd do trybu BaseN i przeprowad nast puj ce obliczenia : BaseN :

Tetapkan tipe dari wilayah program sebagai BaseN danhitunglah soal di bawah ini :

ANS = 1010 2 AND ( Y OR 7 16 )Program Type : BaseN ( DEC )

Line Program

1 I N P U T Y ;

2 C = b 1 0 1 0 A N D ( Y O R h 7 )

3 P R I N T " A N S = " , C ;

4 E N D

RUN

If Y = /A 16 , Ans = 10 10

[ ]Y =

PROG

d


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Ex 66


d

PROG

[ ] / AY = h / A

PROG

d

[ ] A N S = 1 0

PROG

d

If Y =11011 8, Ans = 1010 2

[ ]I N P U T YE D I T :

D E C112

PROG


d

PROG

[ ]I N P U T Y

E D I T :B I N

112

PROG

RUN

If Y =11011 8, Ans = 1010 2

[ ]Y =

PROG

b

[ dhbo ] [ ] [ ]D E C H E X B I NO C T od h b

b

PROG

[ ] 11011Y = o 1 1 0 1 1

PROG

b


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Ex 67

[ ] A N S = 1 0 1 0

PROG

b

Example 63

Create a program to perform the following questions and checkhe content of the memory variable inserted a display resultcommand ( )Cree un programa para ejecutar las cuestiones siguientes yverificar el contenido de la variable de memoria insertando uncomando de presentación del resultado ( )Crie um programa para executar as questões seguintes e paraverificar o conteúdo da variável de memória inserida a umcomando de resultado de exibição ( )Erstellen Sie ein Programm zur Ausführung der folgendenFragestellungen und prüfen Sie den Inhalt der in einenBildschirmresultat-Befehl ( ) eingesetzten SpeichervariablenCréez un programme pour effectuer les questions suivantes etvérifiez le contenu de la variable de mémoire par linsertion de lacommande daffichage de résultat ( )Generare un programma per effettuare le seguenti domande econtrollare il contenuto della variabile di memoria inserito uncomando di risultato su display ( )Creëer een programma om de volgende vragen uit te voeren encontroleer of de inhoud van de geheugenvariabele eenresultaatopdracht ( ) invoegde.Opret et program, der udfører de følgende spørgsmål, og

undersøg indholdet i hukommelsesvariablen med en kommandoil visning af resultatet ( )

( )Napisz program do przeprowadzenia nast puj cych oblicze isprawd zawarto pami ci zmiennych ( ) uæywaj c poleceniawy wietlania wyniku ( )

( )

Membuat sebuah program untuk menjalankan perhitungansoal-soal dan mengecek isi dari variabel memori yang telahdisisipkan pada perintah hasil yang ditampilkan ( )

( )B = log ( A + 90 ), C = 13 x A, D = 51 ( A x B )


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Ex 68

Program Type : MAIN

Line Program

1 I N P U T A ;

2 B = l o g ( A + 9 0

3 C = 1 3 A ;

4 D = 5 1 / ( A B

5 P R I N T " D = " , D ;

6 E N D

RUN

A = 10 C = 130 , D = 2.55

[ ] A =

PROGDD

10 A = 1 0

PROGDD

[ ]C = 1 3 A ;

PROGP R O G

DD

[ 2nd ] [ VRCL ] [ ] [ ] A B C D E F

130.G H IJ K L

PROGDD

[ CL/ESC ] [ ] D = 2 . 5 5

PROGDD

SRP325G Manual

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