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Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin
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Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Mar 27, 2015

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Page 1: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Solving Systems of Equations

3 Approaches

Mrs. N. NewmanClick here to begin

Page 2: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Method #1

Graphically

Method #2

Algebraically Using Addition and/or Subtraction

Method #3

Algebraically Using Substitution

Door #1

Door #2

Door #3

Page 3: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

In order to solve a system of equations graphically you

typically begin by making sure both equations are in standard

form.

Where m is the slope and b is the y-intercept.

Examples:

y = 3x- 4

y = -2x +6

Slope is 3 and y-intercept is - 4.

Slope is -2 and y-intercept is 6.

bmxy

Page 4: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Graph the line by locating the appropriate

intercept, this your first coordinate. Then move to your next

coordinate using your slope.

Page 5: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Use this same process and graph the second line.

Page 6: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Once both lines have been graphed locate the point of

intersection for the lines. This point is your solution set.

In this example the solution set is [2,2].

Page 7: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

In order to solve a system of equations algebraically using addition first you must be sure that both equation are in the same chronological order.

Example: 2

4

yx

xy

2

4

xy

xyCould be

Page 8: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now select which of the two variables you want to eliminate.

For the example below I decided to remove x.

2

4

xy

xy

The reason I chose to eliminate x is because they are the additive inverse of each other.

That means they will cancel when added together.

Page 9: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now add the two equations together.

2

4

xy

xy

Your total is:

therefore 3

62

y

y

Page 10: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now substitute the known value into either one of the original equations.I decided to substitute 3 in for y in the second equation.

1

23

x

x

Now state your solution set always remembering to do so in alphabetical order.

[-1,3]

Page 11: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Lets suppose for a moment that the equations are in the same sequential order. However, you notice that neither coefficients are additive

inverses of the other.

1273

332

yx

yx

Identify the least common multiple of the coefficient you chose to

eliminate. So, the LCM of 2 and 3 in this example would be 6.

Page 12: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Multiply one or both equations by their

respective multiples. Be sure to choose numbers that

will result in additive inverses.

)1273(2

)332(3

yx

yx

24146

996

yx

yxbecomes

Page 13: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now add the two equations together.

24146

996

yx

yxbecomes 155 y

Therefore 3y

Page 14: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now substitute the known value into either one of the original equations.

3

62

392

3)3(32

3

x

x

x

x

y

Page 15: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now state your solution set always remembering to do so in alphabetical

order.

[-3,3]

Page 16: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

In order to solve a system equations algebraically using substitution you must have on variable isolated in one of the equations. In other words you will need to solve for y in terms

of x or solve for x in terms of y.

In this example it has been done for you in the first

equation.

2

4

yx

xy

Page 17: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now lets suppose for a moment that you are given a set of equations like this..

1273

332

yx

yx

Choosing to isolate y in the first equation the result is :

13

2 xy

Page 18: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

Now substitute what y equals into the second equation.

2

4

yx

xy

becomes24 xx

Better know as

Therefore 1

22

242

x

x

x

Page 19: Solving Systems of Equations 3 Approaches Mrs. N. Newman Click here to begin.

This concludes my presentation on simultaneous equations.

Please feel free to view it again at your leisure.