Review – Section 1 Solving Equations
Equation
Is a statement that two algebraic expressions are equal.
EXAMPLES
3x – 5 = 7, x2 – x – 6 = 0, and 4x = 4
To solve a equation in x means to find all real values of x for which the equation is true.
Domain
The set of real numbers for which an algebraic expression is defined.
Remember the real numbers are made up of the Natural, Whole, Integer, Rational and Irrational numbers. The real numbers can be represented on a number line with 0 as the origin.
Identity
An equation that is true for every real number in the domain of the variable
EXAMPLE
x2 – 9 =(x-3)(x+3) is an Identity, because it is a true statement for any real value of x
Conditional Equations
An equation that is true for some (or even none) of the real numbers in the domain of the variable.
EXAMPLE
x2 – 9 =0 is conditional because x =3 and x = -3 are the only values in the domain that satisfy the equation.
Linear Equation
An equation in one variable that can be written in the standard form:
ax + b = 0 where and a and b are real numbers and a ≠ 0
EXAMPLE
2x – 5 = 0
Solving Linear Equations
A linear equation has exactly one solution and the solution is found by isolating the variable on one side of the equation by a sequence of equivalent equations.
EXAMPLE2x – 4 = 102x – 4+ 4 = 10+ 42x = 14½(2x) = ½(14)X = 7
Extraneous Solution
A solution that does not satisfy the original equation.
EXAMPLE1/(x-2)= 3/(x+2) – 6x/(x2 -4)x = -2However, x = -2 yields a denominator of
zero, so the original equation has no solution.
Quadratic Equations
An equation in one variable written in the general form:
ax2 + bx + c = 0Where a, b, and c are real numbers and a ≠ 0
EXAMPLEx2 –x – 6 = 0
Solving Quadratic Equations
A quadratic equation has either one real solution, two real solutions or two conjugate imaginary solutions.
METHODS Factoring Square Root Principle Completing the Square Quadratic Formula
Completing the Square
EXAMPLEx2 + 6x = 5x + 6x + (6/2)2 = 5 + (6/2)2 (x+3) 2 = 5 + 32
x + 3 = ±14X = -3 ±14
Other Types of Equations Polynomials of Higher Degree
3x4 = 48x2
x3 – 3x2 – 3x + 9 = 0 Equations Involving Radicals
(2x +7) ½ - x = 2(x – 4)⅔ = 25
Equations with Absolute Values|x – 2| = 3|x2 – 3x| = -4x + 6
Solving Linear Inequalities
Solve as if it were an equality, but remember to reverse the sign of the inequality whenever you multiply or divide by a negative number. Write the answer using interval notation.
EXAMPLE5x – 7 > 3x + 9x > 8 so the solution set is (8, ∞) meaning 8 is
not part of the solution, but all real numbers larger than 8 to infinity is the solution
Solving a Double Linear InequalitySolve as if it were an equality, but isolate
the variable as the middle term or solve as two separate inequalities
EXAMPLE-3 ≤ 6x – 1 < 3-⅓ ≤ x <⅔Solution interval is [-⅓, ⅔)[ ] means closed interval; ( ) means open
interval
Inequalities Involving Absolute Values
Write equivalent inequalities and solve.EXAMPLE
|x + 3| ≥ 7 (a) x + 3 ≥ 7 or (b) – (x + 3) ≥7 x ≥ 4 or x ≤ - 10 The solution interval is (-∞, -10] [4, ∞)
Solving a Polynomial Inequality
Write equivalent inequalities and solve.EXAMPLE
x2 – x – 6 < 0 Solve as if equality and find the critical values(x -3) (x + 2) = 0 then x =3, or x = -2 are the critical
values Check intervals(- ∞, -2) if x = -3 then (-3)2 –(-3) – 6 is positive(-2, 3) if x = 0 then (0) 2 – (0) – 6 is negative(3, ∞) if x = 4 then (4) 2 - (4) – 6 is positive
The solution interval is (-2, 3)
Solving a Rational Inequality
Find the critical values which occur for values making the numerator 0 or the denominator undefined. (right hand side must be 0 first)
EXAMPLE(2x – 7) / (x – 5) ≤ 3 Simplify to (-x +8)/(x-5) ≤ 0, thus critical values are
8 and 5Check the intervals (-∞, 5) if x = 4 then inequality is negative(5,8) if x = 6 then inequality is positive(8, ∞) if x = 9 then inequality is negativeThe solution interval is (-∞, 5) [8, ∞)
Finding the Domain of an ExpressionRemember the domain is the set of all x
values for which the expression is defined
EXAMPLE
(64 -4x2)½ Since this is a square root expression, the expression must be larger than 0. So find the critical values for (64 -4x2)½ ≥ 0 and test each of the intervals to find the solution set. The critical numbers are 4 and - 4
Coordinate Plane
consists of two perpendicular number lines, dividing the plane into four regions called quadrants
Parts of the Coordinate Plane
X-AXIS - the horizontal number line
Y-AXIS - the vertical number line
ORIGIN - the point where the x-axis and y-axis cross
Ordered Pair
ORDERED PAIR - a unique assignment of real numbers to a point in the coordinate plane consisting of one x-coordinate and one y-coordinate
(-3, 5), (2,4), (6,0), (0,-3)
Verfiy a Right Triangle
Use the distance formula and Pythagorean Theorem to determine a right triangle.
EXAMPLE
(2,1), (4,0) and (5,7)
Midpoint Formula
Find the midpoint of a line segment that joins two points in a coordinate plane.
M = [(x1 + x2)/ 2 ,(y1 + y2)/2]
EXAMPLE(-5,-3) and (9,3) M = (2,0)
Intercepts of a Graph
Solutions points that have zeros as either the x-coordinate or the y-coordinate are called intercepts because they are the points where the graph intersects the x-axis or y-axis
Finding the Intercepts
To find the x-intercepts, let y be zero and solve the equation for x.
To find the y-intercepts, let x be zero and solve the equation for y
Symmetry – mirror images
Types of symmetry x – axis if (x,y) then (x,-y)
y – axisIf (x,y) then (-x, y)
OriginIf (x,y) then (-x, -y)
Tests for Symmetry
• If replacing y with –y yields an equivalent equation then symmetric about x-axis
• If replacing x with –x yields an equivalent equation then symmetric about y-axis
• If replacing x with –x and y with –y yields an equivalent equation then symmetric about the origin
Circles
The standard form of the equation of a circle is:
(x – h)2 +(y-k)2 = r2 where (x,y) is a point on the circle, (h,k) is the center and r is the radius
Example
Find the equation of a circle whose center is (-1,2) with point (3,4) on the circle.
Find the radius by using the distance formula
(x +1)2 + (y-2)2 = 20
Slope
is the ratio of vertical change to the horizontal change. The variable m is used to represent slope.
Slope Intercept formy= mx + b, where m is the slope, b is y-intercept
Point-Slope formy – y1 = m(x- x1)
Writing Linear Equations in Two Variables
Parallel Lines - are two distinct nonvertical lines having identical slopes; m1 = m2
Perpendicular Lines – are two nonvertical lines whose slopes are the negative reciprocal of each other
Parallel and Perpendicular Lines