Presenting Solving Absolute Value Equations
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PresentingSolving
Absolute Value Equations
Solving Absolute Value Equations
Howdy! I’m hoping you’ll help me
escape these bars!
An absolute value equation is one with a
variable trapped between the bars!
What does it mean to be
between bars?
It represents distance from a given value!
|x - 3| = 2The distance between a number and 3 is 2!
Check out these 2 examples! What is happening in each?
Example 1a|-4 + 5x| = 16
-4 + 5x = 16 or -4 + 5x = -16
5x = 16+ 4 5x = -16+45x = 20 5x = -12 x = 20/5 x = -12/5 x = 4 Solutions: {-12/5, 4}
Example 1b|1 - 5a| = 29
1 - 5a = 29 or 1 - 5a = -29
-5a = 29 - 1 -5a = -29 - 1-5a = 28 -5a = -30 a = -28/5 a = -30/-5 a = 6Solutions: {-28/5, 6}
Example 1a|-4 + 5x| = 16
-4 + 5x = 16 or -4 + 5x = -16
5x = 16+ 4 5x = -16+45x = 20 5x = -12 x = 20/5 x = -12/5 x = 4 Solutions: {-12/5, 4}
Example 1b|1 - 5a| = 29
1 - 5a = 29 or 1 - 5a = -29
-5a = 29 - 1 -5a = -29 - 1-5a = 28 -5a = -30 a = -28/5 a = -30/-5 a = 6Solutions: {-28/5, 6}
What do you notice? What steps occur in both examples?
Now it is your turn!Solve for x: |-2x - 1| = 11
Let’s look 2 more examples? What do you
notice?
Example 2a-5|3 + 4k| = -115-5(3 + 4k) = -115 or -5(3 + 4k) = 1153 + 4k = -115/-5 3 + 4k = 115/-53 + 4k = 23 3 + 4k = -23 4k = 23 - 3 4k = -23 - 3 4k = 20 4k = - 26 k = 5 k = -26/4 k = -13/2Solutions: {-13/2, 5}
Example 2b-8|3 - 8k| = 40-8|3 - 8k| = 40 or -8|3 - 8k| = -40 |3 - 8k| = -5 3 - 8k = 5 not possible -8k = 2 k = -2/8 k = -1/4 doesn’t workNo solution because one solution is extraneous and the other not possible.
What do you notice? What are key ideas you need in your notes?
Example 2a-5|3 + 4k| = -115-5(3 + 4k) = -115 or -5(3 + 4k) = 1153 + 4k = -115/-5 3 + 4k = 115/-53 + 4k = 23 3 + 4k = -23 4k = 23 - 3 4k = -23 - 3 4k = 20 4k = - 26 k = 5 k = -26/4 k = -13/2Solutions: {-13/2, 5}
Example 2b-8|3 - 8k| = 40-8|3 - 8k| = 40 or -8|3 - 8k| = -40 |3 - 8k| = -5 3 - 8k = 5 not possible -8k = 2 k = -2/8 k = -1/4 doesn’t workNo solution because one solution is extraneous and the other not possible.
Now it is your turn!Solve for x: 10|7x + 3| = 0
Last 2 examples! Again - what do you notice?
Example 3a3|3 - 5x| - 3 = 183(3 - 5x) = 21 or 3(3 - 5x) = -21 3 - 5x = 7 3 - 5x = -7 -5x = 4 -5x = -10 x = -4/5 x = 2
Solutions both check {-⅘, 2}
Example 3b5|9 - 5x| - 7 = 385(9 - 5x) = 45 or 5(9 - 5x) = -45 9 - 5x = 9 9 - 5x = -9 -5x = 0 -5x = -18 x = 0 x = 18/5
Solutions both check {0, 18/5}
What do you notice? What are key ideas you need to add to your notes?
Example 3a3|3 - 5x| - 3 = 183(3 - 5x) = 21 or 3(3 - 5x) = -21 3 - 5x = 7 3 - 5x = -7 -5x = 4 -5x = -10 x = -4/5 x = 2
Solutions both check {-⅘, 2}
Example 3b5|9 - 5x| - 7 = 385(9 - 5x) = 45 or 5(9 - 5x) = -45 9 - 5x = 9 9 - 5x = -9 -5x = 0 -5x = -18 x = 0 x = 18/5
Solutions both check {0, 18/5}
Now it is your turn! Three to move on!
1) Solve for x: |-5x| + 4 = -11
2) Solve for x: 3 - |8x - 6| = 3
3) Solve for x: 6|1 - 5x| - 9 = 57
{No solution}
{¾}
{-2, 12/5}
That’s a Wrap for Solving
Absolute Value Equations
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