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Solutions of the Conduction Equation P M V Subbarao Associate Professor Mechanical Engineering Department IIT Delhi An Idea Generates More Mathematics…. Mathematics Generate Mode Ideas…..
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Solutions of the Conduction Equation

Jan 23, 2016

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Solutions of the Conduction Equation. P M V Subbarao Associate Professor Mechanical Engineering Department IIT Delhi. An Idea Generates More Mathematics…. Mathematics Generate Mode Ideas…. The Conduction Equation. Incorporation of the constitutive equation into the energy - PowerPoint PPT Presentation
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Page 1: Solutions of the Conduction Equation

Solutions of the Conduction Equation

P M V Subbarao

Associate Professor

Mechanical Engineering Department

IIT Delhi

An Idea Generates More Mathematics….Mathematics Generate Mode Ideas…..

Page 2: Solutions of the Conduction Equation

The Conduction Equation

),(''. trgqt

H

),(.. trgTkt

TC p

Incorporation of the constitutive equation into the energy equation above yields:

Dividing both sides by Cp and introducing the thermal diffusivity of the material given by

s

mm

s

m

C

k

p

2

Page 3: Solutions of the Conduction Equation

Thermal Diffusivity

• Thermal diffusivity includes the effects of properties like mass density, thermal conductivity and specific heat capacity.

• Thermal diffusivity, which is involved in all unsteady heat-conduction problems, is a property of the solid object.

• The time rate of change of temperature depends on its numerical value.

• The physical significance of thermal diffusivity is associated with the diffusion of heat into the medium during changes of temperature with time.

• The higher thermal diffusivity coefficient signifies the faster penetration of the heat into the medium and the less time required to remove the heat from the solid.

Page 4: Solutions of the Conduction Equation

pp C

trgT

C

k

t

T

),(

..

This is often called the heat equation.

pC

trgT

t

T

),(

..

For a homogeneous material:

pC

txgT

t

T

),(2

Page 5: Solutions of the Conduction Equation

This is a general form of heat conduction equation.

Valid for all geometries.

Selection of geometry depends on nature of application.

Page 6: Solutions of the Conduction Equation

General conduction equation based on Cartesian Coordinates

xqxxq

yyq

yqzzq

zq

Page 7: Solutions of the Conduction Equation

),(. txgTkt

TC p

For an isotropic and homogeneous material:

),(2 txgTkt

TC p

):,,(2

2

2

2

2

2

tzyxgz

T

y

T

x

Tk

t

TC p

Page 8: Solutions of the Conduction Equation

General conduction equation based on Polar

Cylindrical Coordinates

):,,(1

2

2

2

2

2tzrg

z

TT

rr

Tr

rk

t

TC p

Page 9: Solutions of the Conduction Equation

General conduction equation based on Polar Spherical Coordinates

):,,(sin

1sin

sin

112

2

2222

2trg

T

r

T

rr

Tr

rrk

t

TC p

X

Y

Page 10: Solutions of the Conduction Equation

Thermal Conductivity of Brick Masonry Walls

Page 11: Solutions of the Conduction Equation

Thermally Heterogeneous Materials

zyxkk ,,

),(. txgTkt

TC p

),,,( tzyxgz

zT

k

y

yT

k

xxT

k

t

TC p

Page 12: Solutions of the Conduction Equation

),,,(2

2

2

2

2

2

tzyxgz

Tk

z

T

z

k

y

Tk

y

T

y

k

x

Tk

x

T

x

k

t

TC p

More service to humankind than heat transfer rate calculations

Page 13: Solutions of the Conduction Equation

Satellite Imaging : Remote Sensing

Page 14: Solutions of the Conduction Equation

Thermal Imaging of Brain

Page 15: Solutions of the Conduction Equation
Page 16: Solutions of the Conduction Equation
Page 17: Solutions of the Conduction Equation

One Dimensional Heat Conduction problems

P M V Subbarao

Associate Professor

Mechanical Engineering Department

IIT Delhi

Simple ideas for complex Problems…

Page 18: Solutions of the Conduction Equation

Desert Housing & Composite Walls

Page 19: Solutions of the Conduction Equation

Steady-State One-Dimensional Conduction

• Assume a homogeneous medium with invariant thermal conductivity ( k = constant) :

• For conduction through a large wall the heat equation reduces

to:

),,,(2

2

tzyxgx

Tk

x

T

x

k

t

TC p

),,,(2

2

tzyxgx

Tk

t

TC p

One dimensional Transient conduction with heat generation.

Page 20: Solutions of the Conduction Equation

Steady Heat transfer through a plane slab

02

2

dx

TdA

0),,,(2

2

tzyxgx

Tk

No heat generation

211 CxCTCdx

dT

Page 21: Solutions of the Conduction Equation

Isothermal Wall Surfaces

Apply boundary conditions to solve for constants: T(0)=Ts1 ; T(L)=Ts2

211 CxCTCdx

dT

The resulting temperature distribution is:

and varies linearly with x.

Page 22: Solutions of the Conduction Equation

Applying Fourier’s law:

heat transfer rate:

heat flux:

Therefore, both the heat transfer rate and heat flux are independent of x.

Page 23: Solutions of the Conduction Equation

Wall Surfaces with Convection

2112

2

0 CxCTCdx

dT

dx

TdA

Boundary conditions:

110

)0(

TThdx

dTk

x

22 )(

TLThdx

dTk

Lx

Page 24: Solutions of the Conduction Equation

Wall with isothermal Surface and Convection Wall

2112

2

0 CxCTCdx

dT

dx

TdA

Boundary conditions:

1)0( TxT

22 )(

TLThdx

dTk

Lx

Page 25: Solutions of the Conduction Equation

Electrical Circuit Theory of Heat Transfer

• Thermal Resistance• A resistance can be defined as the ratio of a

driving potential to a corresponding transfer rate.

i

VR

Analogy:

Electrical resistance is to conduction of electricity as thermal resistance is to conduction of heat.

The analog of Q is current, and the analog of the temperature difference, T1 - T2, is voltage difference.

From this perspective the slab is a pure resistance to heat transfer and we can define

Page 26: Solutions of the Conduction Equation

q

TR

R

Tq th

th

WKmW

Kmm

kA

L

L

TTkA

TT

q

TR

ss

ss

condth /

1.2

12

21

WKmW

Km

hATThA

TT

q

TR

s

s

convth /

1.12

2

Page 27: Solutions of the Conduction Equation

WKmW

Km

AhTTAh

TT

q

TR

rsurrsr

surrs

radth /

1.12

2

Page 28: Solutions of the Conduction Equation

The composite Wall

• The concept of a thermal resistance circuit allows ready analysis of problems such as a composite slab (composite planar heat transfer surface).

• In the composite slab, the heat flux is constant with x.

• The resistances are in series and sum to Rth = Rth1 + Rth2.

• If TL is the temperature at the left, and TR is the temperature at the right, the heat transfer rate is given by

21 thth

RL

th RR

TT

R

Tq

Page 29: Solutions of the Conduction Equation

Wall Surfaces with Convection

2112

2

0 CxCTCdx

dT

dx

TdA

Boundary conditions:

110

)0(

TThdx

dTk

x

22 )(

TLThdx

dTk

Lx

Rconv,1 Rcond Rconv,2

T1 T2

Page 30: Solutions of the Conduction Equation

Heat transfer for a wall with dissimilar materials

• For this situation, the total heat flux Q is made up of the heat flux in the two parallel paths:

• Q = Q1+ Q2

with the total resistance given by:

Page 31: Solutions of the Conduction Equation

Composite Walls

• The overall thermal resistance is given by

Page 32: Solutions of the Conduction Equation

Desert Housing & Composite Walls