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SOALAN 1 • kg m s -2 (mass x acceleration = force ) • kg m s -1 (mass x velocity = momentum ) • m s -1 •m ( Distance (m) = velocity x time )
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SOALAN 1

Feb 23, 2016

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SOALAN 1. kg m s -2 (mass x acceleration = force ) kg m s -1 (mass x velocity = momentum ) m s -1 m ( Distance (m) = velocity x time ). 760.3 cm. SOALAN 2. 759.6 cm. 760.3 cm - 759.6 cm = 0.7 cm. SOALAN 3. RV against MV. Responding Variable (RV) - PowerPoint PPT Presentation
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Page 1: SOALAN  1

SOALAN 1

• kg m s-2 (mass x acceleration = force )• kg m s-1 (mass x velocity = momentum )• m s-1

• m ( Distance (m) = velocity x time )

Page 2: SOALAN  1

SOALAN 2

760.3 cm - 759.6 cm = 0.7 cm

mercury

761

760

cm

barometer

759 0

mercury

761

cm

barometer

759 0

760

Figure 1a / Rajah 1a Figure 1b / Rajah 1b

759.6 cm760.3 cm

Page 3: SOALAN  1

SOALAN 3

Manipulated Variable (MV)

(Pembolehubah dimanipulasi)

Responding Variable (RV)

(Pembolehubah bersandar)

RV against MV

Gradient =1

1560

)10(5060

Ns

-10

Page 4: SOALAN  1

CATATAN

Y is increases linearly with X(Y bertambah secara linear

dengan x)

Y is inversely proportional to X

(Y berkadar songsang dengan x)

Y is directly proportional to X(Y berkadar terus

dengan x)

Page 5: SOALAN  1

SOALAN 4

• 0.5 cm + 0.05 cm = 0.55 cm

Vernier calliperAngkup vernier

0 cm

1 cm

0 10

2 cm0

Main scale reading = 0.5 cm

( 0.0 < 1.0 → 0.5cm )

→( 0.05cm )

Vernier scale reading = 0.05 cm

Page 6: SOALAN  1

SOALAN 5

32.0 mm

Red fringePinggir merah

Dark fringePinggir gelap

xx

x

SOALAN 8

Page 7: SOALAN  1

SOALAN 6

Constant Acceleration

(Pecutan seragam)

Increasing Acceleration

(Pecutan bertambah

tidak seragam)

Decreasing Acceleration

(Pecutan berkurang

tidak seragam)

Constant Velocity(Halaju

seragam)

Page 8: SOALAN  1

SOALAN 9

Inclined plane

Landasan condongBlockBongkah

Rough surface

Weight

Normal Reaction

SOALAN 10

Net force = 0 N (no movement/const. velocity)Net force = upward ( accelerate upwards)Net force = downward ( accelerate downwards)Net force = 500N – 400N

= 100NF = ma → a = 233.3

30100 ms

mF

233.330

100 msmF

233.330

100 ms

mF 22

50100 ms

mF

2250

100 msmF

Surface of contact

(satah sentuhan)

Page 9: SOALAN  1

SOALAN 12

Force parallel to distance moved = 10cos 40o

Distance moved = 5m

Work done = 10 cos 40o x 5 = 38.3 J

Page 10: SOALAN  1

SOALAN 13

Page 11: SOALAN  1

SOALAN 16

Very high air speed,Very low air pressure

Slightly high air speed,slightly low air pressure

Low air speed,High air pressure

Page 12: SOALAN  1

SOALAN 18

B.A. C.

Very high air speed,Very low air pressure(Pushes the water level down slightly)

Low air speed,High air pressure(Pushes the water down)

Slightly high air speed,slightly low air pressure

Page 13: SOALAN  1

Speed of wave, v = f = 25,000 Hz x 4.8 x 10-2 m

Distance, s = vt = 25,000 Hz x 4.8 x 10-2 m x 0.4s =

SOALAN 23

42o

SOALAN 24

Page 14: SOALAN  1

SOALAN 30