Slide 3- 1 Quick Quiz Sections 3.4 – 3.6 4 3 3 3 3 Y ou should solve the follow ing problem sw ithoutusing agraphing calculator. 1. W hich ofthefollow ing gives for sin 3 ? A 4sin 3 cos 3 B 12sin 3 cos 3 C 12sin 3 cos 3 D 12sin 3 E 12sin 3 cos 3 dy y x dx x x x x x x x x x
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Slide 3- 1
Quick Quiz Sections 3.4 – 3.6
4
3
3
3
3
You should solve the following problems without using a graphing calculator.
1. Which of the following gives for sin 3 ?
A 4sin 3 cos 3
B 12sin 3 cos 3
C 12sin 3 cos 3
D 12sin 3
E 12sin 3 cos 3
dyy x
dx
x x
x x
x x
x
x x
3.7
Implicit Differentiation
Slide 3- 3
What you’ll learn about
• Implicitly Defined Functions• Lenses, Tangents, and Normal Lines• Derivatives of Higher Order• Rational Powers of Differentiable Functions
… and why
Implicit differentiation allows us to find derivatives of functions that are not defined or written explicitly as a function of a single variable.
Slide 3- 4
Implicitly Defined Functions
An important problem in Calculus is how to find the slope when the
function can't conveniently be solved for . Instead, is treated as
a differentiable function of and both sides of the equation
y y
x are
differentiated with respect to , using the appropriate rules for sums,
products, quotients and the Chain rule. Then solve for in terms of
and together to obtain a formula that calculates
x
dyx
dxy
3 3
1 2
the slope at any
point , on the graph.
The process by which we find is called .
The phrase derives from the fact that the equation
9 0
defines the functions , a
x y
dy
dx
x y xy
f f
implicit differentiation
3nd implicitly (i.e., hidden inside the
equation), without giving us formulas to work with.
f
explicit
Slide 3- 5
Implicitly Defined Functions
This is not a function, but it would still be nice to be able to find the slope.
Do the same thing to both sides.
Note use of chain rule.
Slide 3- 7
Example Implicitly Defined Functions
2Find if 3 2 5dy
y y xdx
2
2 2
To find differentiate both sides of the equation with respect
to , treating as a differentiable function of and applying the
Chain Rule.
3 2 5
3 3
6 2 5
2 2
dy
dxx y x
y y x
d d dyy y
dx dy dxdy dyy
d d dydx dxy y
dx dy
6 2 5
5
6 2
dx
dyy
dxdy
dx y
Slide 3- 8
Implicit Differentiation Process
1. Differentiate both sides of the equation with respect to .
2. Collect the terms with on one side of the equation.
3. Factor out .
4. Solve for .
x
dy
dxdy
dxdy
dx
This can’t be solved for y.
This technique is called implicit differentiation.
1 Differentiate both sides w.r.t. x.
2 Solve for .
We need the slope. Since we can’t solve for y, we use
implicit differentiation to solve for .
Find the equations of the lines tangent and normal to the
curve at .
Note product rule.
Find the equations of the lines tangent and normal to the