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Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1: 2 ln(2 ) 5 xy x
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Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

Mar 26, 2015

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Lucas McElroy
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Page 1: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

Section 4.6 – Related Rates

5.5

I can use implicit differentiation to solve related rate word problems.

Day 1:

Find the slope the following at x = 1: 2ln(2 ) 5xy x

Page 2: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

2If , find wA r r 2d

hen andd

t

A

dt

r3

d

2A 2 A 4

2A r

2dA

t dtdr

dr

2dA

dt2 3

dA

dt12

Page 3: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A 2 rh r 2, hdh

2dt

If , fid

nd whA

16d

en , and .d

4r

t

d

t

A 2 2 4 A 16

A 2 r h

dr

d

dA

d

dh2

t tr

th 2

d

dr

dt1 2 2 26 4 2

dr1

dt

Page 4: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

If , find whenr h 4

r 2, h ,dh

dtand

d12

3 h

r 1

d.

t 2

11r 1 4h

3

214h

dh

d

dr

d3 tt

2

d1 4

3 t2

1

d1

h

2

dh6

dt

Page 5: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

2 2 2If , find when , , .A R h A 10, R 8dR 1

dt

dh 1

dt 3

A

2

d

dt

2 2 2 2 2 2A R h 10 8 h h 6

2 2 2A R h

dR

d

d

t

A

d2A 2R 2

t dth

dh

2 10 21

2

dA

d8

1

t 32 6

dA 3

dt 5

Page 6: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A 14 foot ladder is leaning against a wall. If the top of the ladder slips down the wall at a rate of 2 ft/s, how fast will the end be moving away from the wall when the top is 6 ft above the ground?

146

x

y L

dx

dt

2 2 2x y L dy

2dt

dL0

dt

2 2 2x 6 14 x 4 10

4 10dy

d

d

t

x

d2x 2y 2

t dtL

dL

2 4 10 2 6 2 1 0dx

d2 4

t

dx 3

dt 10

The ladder is moving away at a rate of 3

10

Page 7: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A man 6 ft tall is walking at a rate of 2 ft/s toward a street light 16 ft tall. At what rate is the size of his shadow changing?

616

x y

6 x

16 x y

dy2

dt

dx

dt

6x 6y 16x

10x 6y 0 dx

dt10 6

t0

dy

d

dx

dt10 6 2 0

dx 6

dt 5

The size of his shadow is reducing at a rate of 6/5.

Page 8: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A boat whose deck is 10 ft below the level of a dock, is being drawn in by means of a rope attached to a pulley on the dock. When the boat is 24 ft away and approaching the dock at ½ ft/sec, how fast is the rope being pulled in?

-10

24x

y R

dx 1

dt 2

dy0

dt

dR

dt

2 2 2

2 2 2

x y R

24 10 R

R 26

26

dy

d

d

t

x

d2x 2y 2

t dtR

dR

2 24 2 10 2 26dR

01

d2 t

dR 6

dt 13

The rope is being pulled in at a rate of 6/13

Page 9: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A pebble is dropped into a still pool and sends out a circular ripple whose radius increases at a constant rate of 4 ft/s. How fast is the area of the region enclosed by the ripple increasing at the end of 8 seconds.

dr4

dt

dA

dt

2A r

At t = 8, r = (8)(4) = 32

2A 32 1024

2dA

t dtdr

dr

2d

dt2

A43

dA256

dt

The area is increasing at a rate of 256

Page 10: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A spherical container is deflated such that its radius decreases at a constant rate of 10 cm/min. At what rate must air be removed when the radius is 5 cm?

5dr

10dt

dV

dt

34V r

3

34 500V 5 V

3 3

2d4 r

dt t

V

d

dr

2dV1004 5 0

t10

d

Air must be removed at a rate of 1000

Page 11: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

A ruptured pipe of an offshore oil platform spills oil in a circular pattern whose radius increases at a constant rate of 4 ft/sec. How fast is the area of the spill increasing when the radius of the spill is 100 ft?

dr4

dt

100

dA

dt

2A r

2A 100 10000

2dA

t dtdr

dr

2d

dt0 4

A10

dA800

dt

The area of the spill is increasing at a rate of 800

Page 12: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

Sand pours into a conical pile whose height is always one half its diameter. If the height increases at a constant rate of 4 ft/min, at what rate is sand pouring from the chute when the pile is 15 ft high?

21V r h

3

1h d

2

1h 2r

2

h r

31V h

3 dh

4dt

15

15

dV

dt

2hdV

dtdt

dh

2V

dt4

d15

dV900

dt

The sand is pouring from the chute at a rate of 900

Page 13: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

Liquid is pouring through a cone shaped filter at a rate of 3 cubic inches per minute. Assume that the height of the cone is 12 inches and the radius of the base of the cone is 3 inches. How rapidly is the depth of the liquid in the filter decreasing when the level is 6 inches deep?

dV3

dt

12

3

h

r

21V

3hr

r

3 2

h

1

r h1

4

2

V h1

3

1

4h

3V h1

48

23

48

dhh

d

dt

V

dt

236

48

h

dt3

d

4 dh

3 dt

The depth of the liquid is decreasing at a rate of 4

3

Page 14: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

2

rate

of 30 cu ft per hour.

Water is flowing into a spherical tank with at the constant

When the water is h feet deep, the volume of water

hin the tank is given by

6 f

V 18 h . What is the3

oot radius

rate at which the depth

of the water in the ta

when the watenk is increasing 2 ft dr is eep?

6

dV30

dt

dh

dt 2

32 h

V 6 h3

2dh dhh h

dt12

dV

dtdt

dh dh2 4

dt30

t2

d1

dh 3C

dt 2

Page 15: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

If and x is decreasing at the rate of 3 units per second,the rate at which y is changing when y = 2 is nearest to:

2xy 20

a. –0.6 u/s b. –0.2 u/s c. 0.2 u/s d. 0.6 u/s e. 1.0 u/s

2xy 20

2x 2 20

x 5

2y 2ydy

d

dx

dt0

tx

2 dy

dt2 2 2 53 0

Page 16: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

When a wholesale producer market has x crates of lettuce available on a given day, it charges p dollars per crate as determined by the supply equation If the daily supply is decreasing at the rate of 8 crates per day, at what rate is the price changing when the supply is 100 crates?

px 20p 6x 40 0

px 20p 6x 40 0

p 20p 6100 10 400 0 p 7

dp dp

dt dt

dx dx

dt dx p 2 6

t0 0

8d

100 7 2p dp

dt dt0 6 8 0

dp0.1 B

dt

Page 17: Section 4.6 – Related Rates 5.5 I can use implicit differentiation to solve related rate word problems. Day 1: Find the slope the following at x = 1:

2

dy8

d

A particle moves along a curve x y 2 at time t 0.

If when , what is the value of at that timdx

dtx 1

te?

2x y 2

2y 2-1 y 2

2dyd

d

x

d t2 0x y x

t

2dx

dt1 2 8 02 1

dx2 E

dt