Sebastian Böser [email protected] Acoustic sensor and transmitter development Amanda/IceCube Collaboration Meeting Berkeley March 2005
Dec 27, 2015
Sebastian Bö[email protected]
Acoustic sensor and transmitter development
Amanda/IceCube Collaboration Meeting
Berkeley
March 2005
Acoustic sensors and transmitters – 2 [email protected]
Overview
Motivation
Sensors calibration Methods Results Equivalent noise level
Transmitters Ringtransmitter HV signal generator
Acoustic sensors and transmitters – 4 [email protected]
Calibration
Problem interesting frequency ≈ 20 kHz
λwater = 7.5 cm λice = 20 cm
Oscillating signal reflections distort signal need container with xcont » λ
Setup at HSVA water tank 12m × 3m × 70m deep section 12m × 5m × 10m
Sensors Reference Hydrophone
Sensortech SA03
-163.3±0.3 dB re 1 V/µPa (5 to 65 kHz) Glass Ball, Iron Ball
Transmitter piezoceramic in epoxy
arbitrary signal generator
Acoustic sensors and transmitters – 5 [email protected]
Speed of sound
Method compare arrival times of
direct signal reflection at the surface reflection at the walls
Result vwater = 1409.7 ± 4.5 m/s
Theory vwater = 1411.2 m/s
good agreement
Acoustic sensors and transmitters – 6 [email protected]
Sensitivity: Method
Method transmit same signal to
reference sensor to calibrate
compare response relative calibration
Transmitted signals gated burst
precisely measuresingle frequency limited by
system relaxation time reflections
pulse in one shot measure full spectrum limited by
noise level
Acoustic sensors and transmitters – 7 [email protected]
Sensitivity: Gated burst
Time window start: after initial excitation stop: before 1st reflection
Fit
A(t) = A0sin(2πf·t + φ) + bt +c free phase and amplitude fixed frequency linear offset term
very good χ2
But: low-f and DC background
large error for small signals
probably overerstimated
Acoustic sensors and transmitters – 8 [email protected]
Sensitivity: pulse method
Transmitted signal
P ∞ ∂2Uin/ ∂t2 “soft” step function
Received signal
Fourier transform compare spectral components
Errors and noise
A(t) = Σf s(f)ei (2πft + φs) + n(f)ei (2πft + φn)
coherent signal: φs(f) = const
random noise: φs(f) = random
Noise spectrum from
average fourier transform
fourier transform average
define signal dominated regions
Acoustic sensors and transmitters – 9 [email protected]
Comparison of methods
Results high sensitivity and S/N
Glass ball: factor ≈ 20 Iron ball: factor ≈ 50
very good agreement strongly structured
many different resonance modes only valid for water
Acoustic sensors and transmitters – 10 [email protected]
Equivalent noise level
Method fourier transform
scaling, frequency range
backward transform
Problem noise recording from water tank lab self noise higher due to EM coupling
Equivalent Noise Level [mPa]
Frequency range [kHz]
5 - 120 5 - 65
Hydrophone 50.1± 0.7 40.3 ± 8.3
Glass Ball 17.1 ± 1.7 15.9 ± 1.7
Iron Ball 6.6 ± 0.6 4.7 ± 0.7
Acoustic sensors and transmitters – 11 [email protected]
How to do it for ice ?
Theoretical use formula for transmission in media
Problem temperature dependence
resonance modes amplifier gain× bandwidth
solid state vs. liquid
Practical use large ice volume (glacier, pole) use small ice block with changing boundary conditions
(e.g. air, water) determine reflections from comparison
Acoustic sensors and transmitters – 12 [email protected]
Transmitters
Large absorption length
Need high power transmitter
Piezoceramics can be driven with kV signals easy to handle cheap well understood
Ring-shaped piezo ceramic azimuthal symmetry larger signals than cylinders more expensive
Acoustic sensors and transmitters – 13 [email protected]
Transmitter: Ringtransmitter
Linearity tested from 100 mV to 300 V
perfect linearity
Frequency response three resonance modes
width, thickness and diameter
wide resonance at lower frequencies
Testing frequency sweep
dominated by reflections
resonance modes of container
white noise signal
reflections not in phase
resonance modes of transmitter
Acoustic sensors and transmitters – 14 [email protected]
Power supply
Problem build a HV generator for
arbitrary signals
Imax = 2πf Ctot Umax
Cring = 16 nF f = 100 kHz Umax = 1kV k33 = 0.34
Imax = 16 A, P ≈ 5.4 kW too large
Solution large capacity at low duty cycles
100 cycle burst 1ms 16 W large inductivity
discharge via capacitance shortcut after N cycles
Acoustic sensors and transmitters – 15 [email protected]
Next talk