Series of real numbers Group 814 November 2019 Lecture no.5 ● Deinition 1 Each order of two sequences ((x n ),(s n )) n≥1 with the property that S k = x k S k+1 = x k + x k+1 … S n =x k + x k+1 + … + x n is called a series of real numbers. It is denoted by x n ∑ n≥k Terminology ❖ (x n ) is the generating sequence and ∀ n∈ ℕ x n is the general term of degree n ❖ ∀ n∈ ℕ (s n ) ∈ ℝ is called a partial sum of degree n ❖ (s n ) the sequence of the partial sums ● Deinition 2 Let (x n ) let x n be a series of real numbers. If there exists , ∑ n≥k ∈ ℝ lim n→∞ s n = l then l is said to be THE SUM of the series and is denoted by (= ) ∑ ∞ n=k x n l ● Deinition 3 The series (x n ) is said to be convergent if . It is divergent ∑ n≥k ∃) ∈ℝ ( ∑ ∞ n=k x n otherwise.
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Series of real numbers Group 814
November 2019 Lecture no.5
● De�inition 1
Each order of two sequences ((x n ),(s n )) n≥1 with the property that S k = x k S k+1 = x k + x k+1
… S n =x k + x k+1 + … + x n
is called a series of real numbers .
It is denoted by x n ∑
n≥k
Terminology ❖ (x n ) is the generating sequence and ∀ n∈ ℕ x n is the general term of degree n ❖ ∀ n∈ ℕ (s n ) ∈ ℝ is called a partial sum of degree n ❖ (s n ) the sequence of the partial sums
● De�inition 2
Let (x n ) let x n be a series of real numbers. If there exists , ∑
n≥k∈ ℝlim
n→∞sn = l
then l is said to be THE SUM of the series and is denoted by (= )∑∞
n=kxn l
● De�inition 3
The series (x n ) is said to be convergent if . It is divergent ∑
n≥k∃) ∈ℝ( ∑
∞
n=kxn
otherwise.
Remark❕ A series ⅀ x n is divergent in two cases:
1. ∃ { 士 ∞} limn→∞
sn =
2. ∄ limn→∞
sn
Examples:
❏ Studying the series we get that =1 so this series has a ∑
n≥1
1n(n+1) ∃ ∑
∞
n=1
1n(n+1)
sum and this is convergent
❏ Studying the series we get that ∑
n≥1( )− 1 n
the series is divergent and it doesn’t have a sum . ∄ limn→∞
sn ⇒
Geometric series
● De�inition
Let q≠0, then q n-1 is called the geometric series . ∑
n≥1
For k=1 and the sequence x n =q n-1 ,∀ n∈ℕ the sequence of the partial sums is: ● s n =x 1 =q 0 =1 ● s 2 =x 1 +x 2 =q 0 +q 1 =1+q
... ● s n =x 1 +x 2 +...+x n =q 0 +q 1 +...+q n-1
which is equal to either , for q≠1 or n , for q=1. 1 q−1 q − n
Case 1: q=1 ⇒ s n = =+∞ ⇒the geometric series is divergent and it has limn→∞
limn→∞
n
the sum =∞ ∑∞
n=11n
Case 2: q≠1(≠0)⇒ is equal to: ∑∞
n=1qn 1−
● ∞ ,q≥1 ● , 0< <1 1
1 q− q∣ ∣ ● ∄, q≤-1
The geometric series has a sum ∀ q∈(-1,∞)/{0} and it’s convergent ⇔0< <1 q∣ ∣
Telescopic series
● De�inition
Let x n such that ∀ n≥k x n =a n -a n+1 where (a n ) n ⊆R ∑
n≥kk ≥
● s k =x k =a k -a k+1 ● s k+1 =x k +x k+1 =a k -a k+2
... ● s n =x k +x k+1 +...+x n = a k -a n+1
(a k -a n+1 )=a k - a n ⇒if ∃ a n ⇒ x n =a k - a limn→∞
sn = limn→∞
limn→∞
limn→∞
∑∞
n=klimn→∞
The series is covergent ⇔ the sequence is convergent. A different starting index alters the sum , but keeps the nature ( convergent
remains convergent, divergent remains divergent) Classical operations such as multiplication with a scalar, addition, etc... can
be performed on series, but you have to pay attention to the non determined cases .
Let x n and y n be two series of real numbers and a,b from R. Then: ∑
n>k∑∞
n>k
(ax n +by n )=a x n +b y n ∑∝
n=k∑∞
n=k∑∞
n=k
Remark❕ Let x n be a series which has a sum. Then
x n =x k +x k+1 +...+x k+p-1 + x n ∑∞
n=k∑∞
n=k+p
Realizat de: Spatar Bogdan, So�ian Razvan, Timerman Alina, Solcan Cezar