Sample13_Spreadsheet.pdf

Pressure Vessel Engineering, Ltd.120 Randall Dr. Waterloo, Ontario N2V 1C6

Date Printed: 11/12/2009

CUSTOMERPressure Vessel Engineering Ltd

120 Randall Drive, Suite BWaterloo, Ontario N2V 1C6

VESSEL LOCATIONPressure Vessel Engineering Ltd

120 Randall Drive, Suite BWaterloo, Ontario N2V 1C6

VESSEL DESCRIPTIONSample Tower

Vessel designed per the ASME Boiler & Pressure Vessel Code, Section VIII, Division 1,2007 Edition, 2008 Addenda

with Advanced Pressure Vessel, Version: 10.1.5Vessel is ASME Code Stamped

Wind Analysis performed in accordance with IBC 2006Seismic Analysis performed in accordance with IBC 2006

Job No: PVE-3602 Sample 13Vessel Number: Sample 13

NAMEPLATE INFORMATIONVessel MAWP: 250.00 PSI and Full Vacuum at 550 F

M D M T : -20 F at 250.00 PSI

Serial Number(s): __________________________________

National Board Number(s): __________________________________Year Built: 2009

R a d i o g r a p h y : RT 2Postweld Heat Treated: PHT

Construction Type: W

Signatures

_______________________________________________________________ Date: ____/____/____

P.Eng:_______________________________________________________________ Date: ____/____/____ Laurence Brundret



Project Description

Sample Tower for website posting - stored under sample jobs in Engineering directory

Pressure Vessel Design Summary

CustomerVesselJob & RevCalculations byReviewed by

UG-22 Loadings ConsideredYes (a) Internal pressureNo (a) External pressureNo (b) Vessel weight full, empty and at hydro testNo (c) Weight of attached equipment and pipingNo (d)(1) Attachment of internalsNo (d)(2) Attachment of vessel supportsNo (d) Cyclic or dynamic reactionsYes (f) WindNo (f) SnowYes (f) SeismicNo (g) Fluid impact shock reactionsNo (h) Temperature gradientsNo (h) Differential thermal expansionNo (i) Abnormal pressures like deflagrationNO (j) Hydrotest Loads

Sample 13Sample 13

Brian MunnLaurence Brundrett P. Eng.

Pressure Vessel Engineering, Ltd.Shell 1

C u s t o m e r : Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13

N u m b e r : 1 Mark Number: S1


Cylindrical Shell Design Information

Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Long. Joint Efficiency: 85 %

Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI

Shell Length: 98.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 11431 PSI

Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 16286 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 7976 PSI

Outside Diameter (new): 86.0000 in.Outside Diameter (corroded): 86.0000 in. Specific Gravity: 1.00

Shell Surface Area: 183.87 Sq. Ft. Weight of Fluid: 19643.09 lb.Shell Estimated Volume: 2351.32 Gal. Total Flooded Shell Weight: 26970.54 lb.

Circ. Joint Efficiency: 85 % Shell Weight: 7327.45 lb.

Minimum Design Metal Temperature Data

Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F

External Pressure Data

Design Pressure (Pa): 15.00 PSI Design Temperature: 550 FDimension L: 294.0000 in.

Ext. Minimum t: 0.5830 in. Ext. Nominal t: 1.0000 in.Minimum L/Do: 3.4186 Nominal L/Do: 3.4186Minimum Do/t: 187.7730 Nominal Do/t: 98.2857

Minimum Factor A:0.0001627 Nominal Factor A:0.0004162Minimum Factor B: 2112 PSI Nominal Factor B: 5414 PSI

Design Thickness Calculations

Longitudinal Stress Calculations per Paragraph UG-27(c)(2)

t = PR

2SE + 0.4P =

284.00 * 42.1250

2 * 19700 * 0.85 + 0.4 * 284.00 = 0.3560 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) = minimum of 0.4810 i n .

Circumferential Stress Calculations per Appendix 1-1(a)(1)

t = PRo

SE + 0.4P=

284.00 * 43.0000

19700 * 0.85 + 0.4 * 284.00 = 0.7244 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) = minimum of 0.8494 i n .

Maximum External Pressure Calculation per Paragraph UG-28

Pa ( u s i n g nominal t ) = 4B

3(Do / t) =

4 * 5414

3 * ( 86.0000 / 0.8750 ) = maximum external pressure of 73.45 P S I

Extreme Fiber Elongation Calculation per Paragraph UCS-79

Elongation = 50t

Rf=

50 * 1.0000

42.5000 = elongation of 1.18 %

External loads do not control design.

Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddendaPage 1 of 95


Job No: PVE-3602 Sample 13 Vessel Number: Sample 13 N u m b e r : 1 Mark Number: S1


Nominal Shell Thickness Selected = 1.0000 i n .






















t = PR

2SE + 0.4P =

267.00 * 60.1250



t = PRo

SE + 0.4P=

267.00 * 61.1250




3(Do / t) =

4 * 5573



Elongation = 50t

Rf=

50 * 1.1250
























t = PR

2SE + 0.4P =

284.00 * 42.1250



t = PRo

SE + 0.4P=

284.00 * 43.0000




3(Do / t) =

4 * 5414



Elongation = 50t

Rf=

50 * 1.0000
























t = PR

2SE + 0.4P =

267.00 * 60.1250



t = PRo

SE + 0.4P=

267.00 * 61.1250




3(Do / t) =

4 * 5573



Elongation = 50t

Rf=

50 * 1.1250
























t = PR

2SE + 0.4P =

253.50 * 17.7500



t = PRo

SE + 0.4P=

253.50 * 18.6250




3(Do / t) =

4 * 8458



Elongation = 50t

Rf=

50 * 1.0000

















Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F







t = PR

2SE + 0.4P =

253.50 * 18.1250



t = PRo

SE + 0.4P=

253.50 * 18.6250




3(Do / t) =

4 * 3184



Elongation = 50t

Rf=

50 * 0.6250




Pressure Vessel Engineering, Ltd.Ring Stiffener 1


N u m b e r : 1 Mark Number: RS1


Stiffener Design Information

D e s c r i p t i o n : Ring 1Q u a n t i t y : 1

Stiffener Is: Outside Design Temperature: 550 FMaterial: SA-36 Factor B Chart: CS-2

S t r e s s ( h o t ) : 16600 PSI S t r e s s ( c o l d ) : 16600 PSIA s : 5.0000 sq. in. L s : 294.0000 in.d 1 : 5.0000 in. d 2 : 1.0000 in.

Corrosion Allowance: 0.0000 in.

Cylindrical Shell Design InformationShell 5

External Pressure: 15.00 PSI Shell Factor B Chart: CS-2Shell Thickness: 1.0000 in. Shell Outside Diameter: 86.0000 in.



Job No: PVE-3602 Sample 13 Vessel Number: Sample 13 N u m b e r : 1 Mark Number: RS1


FLATBAR Stiffener CalculationsAvailable Moments of Intertia

Available Stiffening Ring Moment of Inertia (I)

y = d12

= 5.0000

2= 2.5000 i n .

I = d2 * d1

12 =

1.0000 * 5.0000

12= 10.4167 i n . ^4

Lsh = 1.1 * Do * t = 1.1 * 86.0000 * 0.8750 = 9.5421 i n .

Ash(Shell Area) = Lsht = 9.5421 * 0.8750 = 8.3493 sq. in.

Ish(Shell Moment of Inertia) = Lsht

12 =

9.5421 * 0.8750

12 = 0.5327 i n . ^4

X(Neutral Axis) = As(t + y) + (Ash * t)

As + Ash =

5.0000 * (0.8750 + 2.5000) + (8.3493 * * 0.8750)

5.0000 + 8.3493 = 1.5377 i n .

I' = I + Ish + As * ((t + y) - X) + Ash * (X - t) = 10.4167 + 0.5327 + 5.0000 * ((0.8750 + 2.5000) - 1.5377) + 8.3493 * (1.5377 - ( * 0.8750)) = 37.9341 i n . ^4

Required Moments of Inertia

Factor B = PDo

t + AsLs

= 15.00 * 86.0000

0.8750 + 5.0000

294.0000

= 1085 P S I

From Factor B Table Factor A = 0.0000840

Ring Moment(Is) =

Do * Ls t +

AsLs

* A

14 =

86.0000 * 294.00000.8750 + 5.0000

294.0000 * 0.0000840

14 = 11.6376 i n . ^4

Combined Moment(Is') =

Do * Ls t +

AsLs

* A

10.9 =

86.0000 * 294.00000.8750 + 5.0000

294.0000 * 0.0000840

10.9 = 14.9474 i n . ^4

I' greater than or equal to Is'Stiffener Ring PASSES the requirements of UG-29







D e s c r i p t i o n : Ring 2Q u a n t i t y : 1












y = d12

= 5.0000

2= 2.5000 i n .

I = d2 * d1

12 =

1.0000 * 5.0000

12= 10.4167 i n . ^4

Lsh = 1.1 * Do * t = 1.1 * 122.2500 * 1.0000 = 12.1623 i n .



12 =

12.1623 * 1.0000

12 = 1.0135 i n . ^4


As + Ash =

5.0000 * (1.0000 + 2.5000) + (12.1623 * * 1.0000)

5.0000 + 12.1623 = 1.3740 i n .



Factor B = PDo

t + AsLs

= 15.00 * 122.2500

1.0000 + 5.0000

294.0000

= 1352 P S I


Ring Moment(Is) =

Do * Ls t +

AsLs

* A

14 =

122.2500 * 294.00001.0000 + 5.0000

294.0000 * 0.0001050

14 = 33.5143 i n . ^4


Do * Ls t +

AsLs

* A

10.9 =

122.2500 * 294.00001.0000 + 5.0000

294.0000 * 0.0001050

10.9 = 43.0459 i n . ^4








D e s c r i p t i o n : Q u a n t i t y : 1












y = d12

= 5.0000

2= 2.5000 i n .

I = d2 * d1

12 =

1.0000 * 5.0000

12= 10.4167 i n . ^4

Lsh = 1.1 * Do * t = 1.1 * 122.2500 * 1.0000 = 12.1623 i n .



12 =

12.1623 * 1.0000

12 = 1.0135 i n . ^4


As + Ash =

5.0000 * (1.0000 + 2.5000) + (12.1623 * * 1.0000)

5.0000 + 12.1623 = 1.3740 i n .



Factor B = PDo

t + AsLs

= 15.00 * 122.2500

1.0000 + 5.0000

294.0000

= 1352 P S I


Ring Moment(Is) =

Do * Ls t +

AsLs

* A

14 =

122.2500 * 294.00001.0000 + 5.0000

294.0000 * 0.0001050

14 = 33.5143 i n . ^4


Do * Ls t +

AsLs

* A

10.9 =

122.2500 * 294.00001.0000 + 5.0000

294.0000 * 0.0001050

10.9 = 43.0459 i n . ^4



Pressure Vessel Engineering, Ltd.Conical Reducer 1


N u m b e r : 1 Mark Number: R1


Conical Reducer Design Information

Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Joint Efficiency: 85 %

Conical Reducer Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Conical Reducer Stress: 18226 PSISmall End of Cone Located at: Bottom Outside Ds : 86.0000 in.

Outside Diameter : 122.2500 in. Cone Height (h) : 120.0000 in.angle a (): 8.59

Conical Reducer Surface Area: 275.69 Sq. Ft. Specific Gravity: 1.00Conical Reducer Estimated Volume: 4256.50 Gal. Weight of Fluid: 35499.18 lb.

Conical Reducer Weight: 13726.15 lb. Total Flooded Conical Reducer Weight: 49225.33 lb.




Design Pressure (Pa): 15.00 PSI Design Temperature: 550 FExt. Minimum t: 0.5053 in. Ext. Nominal t: 1.2500 in.

Minimum te: 0.3760 in. Nominal te: 1.1124 in.Minimum Factor A:0.0002814 Nominal Factor A:0.0014486Minimum Factor B: 3657 PSI Nominal Factor B: 10066 PSI


Design Thickness Calculations per Appendix 1-4(e)

t = PDo

2 cos (SE + 0.4P) =

284.00 * 122.2500

2 * 0.9888 * (19700 * 0.85 + 0.4 * 284.00 ) = 1.0414 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion)

= minimum of 1.1664 i n .


Pa ( u s i n g nominal t) = 4B

3Dlte

= 4 * 10066

3122.2500

1.1124

= = maximum external pressure of 122.13 P S I


elongation = 50t

Rf =

50 * 1.2500


Nominal Conical Reducer Thickness Selected = 1.2500 i n .


Pressure Vessel Engineering, Ltd.Conical Reducer 2


N u m b e r : 2 Mark Number: R2


Conical Reducer Design Information


Conical Reducer Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Conical Reducer Stress: 19688 PSISmall End of Cone Located at: Top Outside Ds : 37.2500 in.

Outside Diameter : 122.2500 in. Cone Height (h) : 100.0000 in.angle a (): 23.03

Conical Reducer Surface Area: 189.05 Sq. Ft. Specific Gravity: 1.00Conical Reducer Estimated Volume: 2236.83 Gal. Weight of Fluid: 18655.18 lb.

Conical Reducer Weight: 8443.82 lb. Total Flooded Conical Reducer Weight: 27099.00 lb.





Minimum te: 0.3105 in. Nominal te: 0.9203 in.Minimum Factor A:0.0003408 Nominal Factor A:0.0018060Minimum Factor B: 4431 PSI Nominal Factor B: 10518 PSI


Design Thickness Calculations per Appendix 1-4(e)

t = PDo

2 cos (SE + 0.4P) =

253.50 * 122.2500

2 * 0.9203 * (19700 * 0.85 + 0.4 * 253.50 ) = 0.9995 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion)

= minimum of 1.1245 i n .


Pa ( u s i n g nominal t) = 4B

3Dlte

= 4 * 10518

3122.2500

0.9203

= = maximum external pressure of 105.57 P S I


elongation = 50t

Rf =

50 * 1.1250


Nominal Conical Reducer Thickness Selected = 1.1250 i n .


Pressure Vessel Engineering, Ltd.Head 1


N u m b e r : 1 Mark Number: H1


Ellipsoidal Head Design Information


Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 13701 PSI

Head Location: Bottom Straight Flange : 1.5000 in.Outside Diameter : 86.0000 in. Head Depth (ho) : 22.1250 in.

Thin Out : 0.2500 in.

K = 1

6 [2 + (D/2h) ] : 1.00

Head Surface Area: 57.14 Sq. Ft. Specific Gravity: 1.00Head Estimated Volume: 365.50 Gal. Weight of Fluid: 3048.30 lb.

Head Weight: 2879.93 lb. Total Flooded Head Weight: 5928.22 lb.





Minimum t - Ca - ext. Ca - Thin Out: 0.2273 in. Nominal t - Ca - ext. Ca. - Thin Out: 0.8750 in.Minimum Factor A:0.0003797 Nominal Factor A:0.0014618Minimum Factor B: 4939 PSI Nominal Factor B: 10083 PSI


Design Thickness Calculations per Appendix 1-4(c)

t = PDoK

2SE + 2P(K - 0.1) =

284.00 * 86.0000 * 1.00

2 * 19700 * 1.00 + 2 * 284.00 * (1.00 - 0.1)

= 0.6120 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.2500(thin out) = minimum of 0.9870 i n .



Job No: PVE-3602 Sample 13 Vessel Number: Sample 13 N u m b e r : 1 Mark Number: H1



Pa ( u s i n g nominal t) = B

Rot

= 10083

74.82000.8750

= maximum external pressure of 117.92 P S I


elongation = 75tRf

= 75 * 1.2500


tmin(external) = 1.67PDo K

2SE + 2(1.67P)(K - 0.1) =

1.67 * 15.00 * 86.0000 * 1.00 2 * 19700 * 1.0 + 2(1.67 * 15.00) * (1.00 - 0.1 )

= Greater of(0.0546(Calc),0.0938(MinT)) + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.2500 ( T h i n o u t )= minimum of 0.4688 in.

Nominal Head Thickness Selected = 1.2500 i n .Minimum Thickness after forming, ts (uncorroded) = 1.0000 i n .




N u m b e r : 2 Mark Number: H2


Ellipsoidal Head Design Information


Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 12070 PSI

Head Location: Top Straight Flange : 1.5000 in.Outside Diameter : 37.2500 in. Head Depth (ho) : 9.5938 in.

Thin Out : 0.0625 in.

K = 1

6 [2 + (D/2h) ] : 0.99

Head Surface Area: 11.39 Sq. Ft. Specific Gravity: 1.00Head Estimated Volume: 33.37 Gal. Weight of Fluid: 278.34 lb.

Head Weight: 258.30 lb. Total Flooded Head Weight: 536.64 lb.





Minimum t - Ca - ext. Ca - Thin Out: 0.0985 in. Nominal t - Ca - ext. Ca. - Thin Out: 0.3750 in.Minimum Factor A:0.0003799 Nominal Factor A:0.0014464Minimum Factor B: 4941 PSI Nominal Factor B: 10064 PSI


Design Thickness Calculations per Appendix 1-4(c)

t = PDoK

2SE + 2P(K - 0.1) =

250.00 * 37.2500 * 0.99

2 * 19700 * 1.00 + 2 * 250.00 * (0.99 - 0.1)

= 0.2314 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.0625(thin out) = minimum of 0.4189 i n .



Job No: PVE-3602 Sample 13 Vessel Number: Sample 13 N u m b e r : 2 Mark Number: H2



Pa ( u s i n g nominal t) = B

Rot

= 10064

32.40750.3750

= maximum external pressure of 116.45 P S I


elongation = 75tRf

= 75 * 0.5625


tmin(external) = 1.67PDo K

2SE + 2(1.67P)(K - 0.1) =

1.67 * 15.00 * 37.2500 * 0.99 2 * 19700 * 1.0 + 2(1.67 * 15.00) * (0.99 - 0.1 )

= Greater of(0.0234(Calc),0.0938(MinT)) + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.0625 ( T h i n o u t )= minimum of 0.2813 in.

Nominal Head Thickness Selected = 0.5625 i n .Minimum Thickness after forming, ts (uncorroded) = 0.5000 i n .


Pressure Vessel Engineering, Ltd.N1


N u m b e r : 1 Mark Number: N1ID Number: N1


Nozzle Design Information

Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 2.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle Pipe Size: 8 Nozzle Pipe Schedule: 80Nozzle ID (new): 7.6250 in. Nozzle Wall Thickness(new): 0.5000 in.

Nozzle ID (corroded): 7.8750 in. Nozzle Wall Thickness(corroded): 0.3750 in.Outer "h" Limit: 1.6875 in. Upper Weld Leg Size(Weld 41): 0.3750 in.

Internal "h" Limit: 0.6250 in. Internal Weld Leg Size(Weld 43): 0.0000 in.OD, Limit of Reinforcement: 15.7500 in. Outside Groove Weld Depth: 1.2500 in.

Minimum Design Metal Temperature

Min. Temp. Curve: B Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -125 F

Reinforcing Pad Information

Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 19700 PSIAllowable Stress at Ambient Temperature: 20000 PSI

Reinforcing Plate Thickness(te): 0.7500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.OD, Reinforcing Plate(Dp): 10.0000 in. Repad to Nozzle Groove Weld Depth: 0.7500 in.

Host Component: Head 1 - Head 1

Material: SA-516 Gr. 70 Head wall thickness(new): 1.2500 in.Material Stress(Sv): 19700 PSI Head wall thickness - thin out (corroded): 0.8750 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3750 in.

Nozzle Wall Thickness(tn): 0.5000 in.

Outside Groove Weld Depth: 1.2500 in.

Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.

Repad Thickness(te): 0.7500 in.

Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 8 Schedule: 80

Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.

Weld Strength Paths are adequate.



Job No: PVE-3602 Sample 13 Vessel Number: Sample 13N u m b e r : 1 Mark Number: N1

ID Number: N1


Required Head Thickness per Paragraph UG-37(a)

tr = P K1 Do

(2SE + 0.8P) =

250.00 * 0.9000 * 86.0000

(2 * 19700 * 1 + 0.8 * 250.00) = 0.4886 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

250.00 * 3.9375

17100 * 1 - 0.6 * 250.00 = 0.0581 i n .

Required Nozzle Thickness for External Pressure per Paragraph UG-37(a)

trn = 3 * Do * Pa

4B =

3 * 8.6250 * 15.00

4 * 6410 = 0.0152 i n .

Strength Reduction Factors

fr1 = min Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680 fr2 = min

Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680

fr3 = min Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680 fr4 = min

Sp

Sv, 1.0000 = min

19700

19700, 1.0000 = 1.0000

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion) per Paragraph UG-45(a)

t = PRn

SE - 0.6P + Ca + ext. Ca =

250.00 * 3.9375

17100 * 1.00 - 0.6 * 250.00 + 0.1250 + 0.0000 = 0.1831 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) per Paragraph UG-45(b)(1)

t = P K Do

(2SE + 2P(K - 0.1)) + Ca + ext. Ca =

250.00 * 1.0000 * 86.0000

(2 * 19700 * 1 + 2 * 250.00 * (1.0000 - 0.1)) + 0.1250 + 0.0000 = 0.6645 i n .

Nozzle Thickness for External Pressure (plus corrosion) per Paragraph UG-45(b)(2)

t = P K Do

(2SE + 2P(K - 0.1)) + Ca + ext. Ca =

15.00 * 1.0000 * 86.0000

(2 * 19700 * 1 + 2 * 15.00 * (1.0000 - 0.1)) + 0.1250 + 0.0000

= Greater Of (0.0327(Calculated), 0.0938(Minimum Allowed)) + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) = 0.2188 i n .Minimum Thickness for Internal and External Pressure per Paragraph UG-45(b)(3)

t = Greater of the thicknesses determined by UG-45(b)(1) or UG-45(b)(2) = 0.6645 i n .

Minimum Thickness of Standard Wall Pipe (plus corrosion) per Paragraph UG-45(b)(4)t = minimum thickness of standard wall pipe + Ca + ext. Ca = 0.4067 i n .

Nozzle Minimum Thickness per Paragraph UG-45(b)t = Smallest of UG-45(b)(3) or UG-45(b)(4) = 0.4067 i n .

Wall thickness = tn * 0.875(pipe) = 0.4375 is greater than or equal to UG-45 value of 0.4067




ID Number: N1


Nozzle Reinforcement Calculations

Area Required for Internal PressureA = d tr F + 2 tn tr F (1 - fr1) = (7.8750 * 0.4886 * 1.00) + (2 * 0.3750 * 0.4886 * 1.00 * (1 - 0.8680)) = 3.8961 sq. in.

Area Available - Internal PressureA1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) = 7.8750 * (1.00 * 0.8750 - 1.00 * 0.4886) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.4886) * (1 - 0.8680) = 3.0047 sq. in.A1 Formula 2 = 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) = 2 * (0.8750 + 0.3750)(1.00 * 0.8750 - 1.00 * 0.4886) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.4886) * (1 - 0.8680) = 0.9278 sq. in.A1 = Larger value of A1 Formula 1 a n d A1 Formula 2 = 3.0047 sq. in.

A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.3750 - 0.0581) * 0.8680 * 0.8750 = 1.2035 sq. in.A2 Formula 2 = 2(tn - trn) fr2 (2.5 tn + te ) = 2(0.3750 - 0.0581) * 0.8680 * (2.5 * 0.3750 + 0.7500) = 0.9284 sq. in.A2 = Smaller value of A2 Formula 1 a n d A2 Formula 2 = 0.9284 sq. in.

A3 = Smaller value of the following : 5 * t * ti * fr2 = 5 * 0.8750 * 0.2500 * 0.8680 = 0.9494 sq. in.5 * ti * ti * fr2 = 5 * 0.2500 * 0.2500 * 0.8680 = 0.2713 sq. in.2 * h * ti * fr2 = 2 * 0.0000 * 0.2500 * 0.8680= 0.0000 sq. in.

= 0.0000 sq. in.

A41 = (leg) * fr3 = (0.3750) * 0.8680 = 0.1221 sq. in.

A42 = (leg) * fr4 = (0.6250) * 1.0000 = 0.3906 sq. in.

A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq. in.

A5 = (Dp - d - 2tn) te fr4 = (10.0000 - 7.8750 - 2 * 0.3750) * 0.7500 * 1.0000 = 1.0313 sq. in.

Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 5.4771 sq. in., which is greater than A (3.8961)




ID Number: N1



Area Required for External Pressure

A = * (d tr F + 2 tn tr F (1 - fr1)) = * ((7.8750 * 0.2273 * 1.0) + (2 * 0.3750 * 0.2273 * 1.0 * (1 - 0.8680))) = 0.9062 sq. in.Area Available - External Pressure

A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) = 7.8750 * (1.00 * 0.8750 - 1.00 * 0.2273) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.2273) * (1 - 0.8680) = 5.0365 sq. in.A1 Formula 2 = 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) = 2 * (0.8750 + 0.3750)(1.00 * 0.8750 - 1.00 * 0.2273) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.2273) * (1 - 0.8680) = 1.5551 sq. in.A1 = Larger value of A1 Formula 1 a n d A1 Formula 2 = 5.0365 sq. in.



= 0.0000 sq. in.

A41 = (leg) * fr3 = (0.3750) * 0.8680 = 0.1221 sq. in.

A42 = (leg) * fr4 = (0.6250) * 1.0000 = 0.3906 sq. in.

A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq. in.

A5 = (Dp - d - 2tn) te fr4 = (10.0000 - 7.8750 - 2 * 0.3750) * 0.7500 * 1.0000 = 1.0313 sq. in.

Area Available (External Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 7.6346 sq. in., which is greater than A (0.9062)




ID Number: N1


Nozzle Weld Strength Calculations

Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)

Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 0.7500, or 0.3750 = 0.3750 i n .

Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA

0.7 =

0.2500

0.7 = 0.3571 i n .

Weld 41, actual weld leg = 0.3750 i n .

Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 0.8750, or 0.7500 = 0.7500 i n .

Weld 42 Leg min. = 0.5 * tmin + ext. CA

0.7 =

0.5 * 0.7500 + 0.0000

0.7 = 0.5357 i n .


Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 P S IUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 P S IVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 P S IOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 19700 = 9653 P S IRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 P S I

Strength of Connection ElementsNozzle wall in shear = * * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * * 8.2500 * 0.3750 * 11970 = 58100 l b .Upper fillet in shear = * * Nozzle OD * weld leg * upper fillet in shear unit stress = * * 8.6250 * 0.3750 * 8379 = 42500 l b .Groove Weld in Tension = * * Nozzle OD * groove depth * groove weld tension unit stress = * * 8.6250 * 0.8750 * 12654 = 149900 l b .Outer fillet in shear = * * Plate OD * weld leg * outer fillet in shear unit stress = * * 10.0000 * 0.6250 * 9653 = 94700 l b .Repad groove weld = * * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * * 8.6250 * 0.7500 * 12654 = 128500 l b .

Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [3.8961 - 3.0047 + 2 * 0.3750 * 0.8680 * (1.00 * 0.8750 - 1.0000 * 0.4886)] * 19700 = 22500 l b .W1-1 = (A2 + A5 + A41 + A42) * Sv = (0.9284 + 1.0313 + 0.1221 + 0.3906) * 19700 = 48700 l b .W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (0.9284 + 0.0000 + 0.1221 + 0.0000 + 2 * 0.3750 * 0.8750 * 0.8680) * 19700 = 31900 l b .W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (0.9284 + 0.0000 + 1.0313 + 0.1221 + 0.3906 + 0.0000 + 2 * 0.3750 * 0.8750 * 0.8680) * 19700 = 59900 l b .

Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 94700 + 58100 = 152800 l b .Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 42500 + 128500 + 149900 + 0 = 320900 l b .Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 94700 + 0 + 149900 = 244600 l b .




ID Number: N1


Plate Strength = A5 * Sp = 1.0313 * 19700 = 20317 l b .

Outer fillet weld strength(94700) is greater than plate strength(20317).




N u m b e r : 2 Mark Number: N2ID Number: 2




Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2




Nozzle ID (corroded): 5.4390 in. Nozzle Wall Thickness(corroded): 0.5930 in.Outer "h" Limit: 1.4825 in. Upper Weld Leg Size(Weld 41): 0.3750 in.

Internal "h" Limit: 1.1700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.OD, Limit of Reinforcement: 10.8780 in. Outside Groove Weld Depth: 1.0000 in.



Host Component: Shell 1 - Shell 1

Material: SA-516 Gr. 70 Shell wall thickness(new): 1.0000 in.Material Stress(Sv): 19700 PSI Shell wall thickness(corroded): 0.8750 in.





Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 6 Schedule: 160






ID Number: 2


Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

250.00 * 43.0000

19700 * 1 + 0.4 * 250.00 = 0.5429 i n .



trn = PRn

SE - 0.6P =

250.00 * 2.7195

17100 * 1 - 0.6 * 250.00 = 0.0401 i n .


trn = 3 * Do * Pa

4B =

3 * 6.6250 * 15.00

4 * 3548 = 0.0212 i n .


fr1 = min Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680 fr2 = min

Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680

fr3 = min Sn

Sv, 1.0000 = min

17100

19700, 1.0000 = 0.8680



t = PRn

SE - 0.6P + Ca + ext. Ca =

250.00 * 2.7195

17100 * 1.00 - 0.6 * 250.00 + 0.1250 + 0.0000 = 0.1651 i n .


t = PRo

SE + 0.4P + Ca + ext. Ca =

250.00 * 43.0000

19700 * 1 + 0.4 * 250.00 + 0.1250 + 0.0000 = 0.6679 i n .


t = PRo

SE + 0.4P + Ca + ext. Ca =

15.00 * 43.0000

19700 * 1 + 0.4 * 15.00 + 0.1250 + 0.0000









ID Number: 2





A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.5930 - 0.0401) * 0.8680 * 0.8750 = 2.0997 sq. in.A2 Formula 2 = 5(tn - trn) fr2 tn = 5(0.5930 - 0.0401) * 0.8680 * 0.5930 = 1.4230 sq. in.A2 = Smaller value of A2 Formula 1 a n d A2 Formula 2 = 1.4230 sq. in.


= 0.0000 sq. in.

A41 = (leg) * fr2 = (0.3750) * 0.8680 = 0.1221 sq. in.

A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq. in.

Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A43 = 3.2994 sq. in., which is greater than A (3.0378)





A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.5930 - 0.0212) * 0.8680 * 0.8750 = 2.1715 sq. in.A2 Formula 2 = 5(tn - trn) fr2 tn = 5(0.5930 - 0.0212) * 0.8680 * 0.5930 = 1.4716 sq. in.A2 = Smaller value of A2 Formula 1 a n d A2 Formula 2 = 1.4716 sq. in.


= 0.0000 sq. in.

A41 = (leg) * fr2 = (0.3750) * 0.8680 = 0.1221 sq. in.

A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq. in.

Area Available (External Pressure) = A1 + A2 + A3 + A41 + A43 = 3.7965 sq. in., which is greater than A (1.2814)








Nozzle Material: SA-105 Joint Efficiency (E1): 1.00Factor B Chart: CS-2



Nozzle ID (new): 2.0000 in. Nozzle Wall Thickness(new): 0.6600 in.Nozzle ID (corroded): 2.2500 in. Nozzle Wall Thickness(corroded): 0.5350 in.

Outer "h" Limit: 1.3375 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal "h" Limit: 1.0250 in. Internal Weld Leg Size(Weld 43): 0.5625 in.

OD, Limit of Reinforcement: 5.0700 in. Outside Groove Weld Depth: 1.0000 in.



Host Component: Shell 4 - Shell 4

Material: SA-516 Gr. 70 Shell wall thickness(new): 1.0000 in.Material Stress(Sv): 19700 PSI Shell wall thickness(corroded): 0.8750 in.



Internal Weld Leg Size(Weld 43): 0.5625 in.



Nozzle passes through the vessel, attached by a groove weld.Nozzle is adequate for UG-45 requirements.

Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.

Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.




ID Number: 3


Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

250.00 * 43.0000

19700 * 1 + 0.4 * 250.00 = 0.5429 i n .



trn = PRn

SE - 0.6P =

250.00 * 1.1250

19000 * 1 - 0.6 * 250.00 = 0.0149 i n .


trn = 3 * Do * Pa

4B =

3 * 3.3200 * 15.00

4 * 2717 = 0.0138 i n .


fr1 = min Sn

Sv, 1.0000 = min

19000

19700, 1.0000 = 0.9645 fr2 = min

Sn

Sv, 1.0000 = min

19000

19700, 1.0000 = 0.9645

fr3 = min Sn

Sv, 1.0000 = min

19000

19700, 1.0000 = 0.9645



t = PRn

SE - 0.6P + Ca + ext. Ca =

250.00 * 1.1250

19000 * 1.00 - 0.6 * 250.00 + 0.1250 + 0.0000 = 0.1399 i n .


t = PRo

SE + 0.4P + Ca + ext. Ca =

250.00 * 43.0000

19700 * 1 + 0.4 * 250.00 + 0.1250 + 0.0000 = 0.6679 i n .


t = PRo

SE + 0.4P + Ca + ext. Ca =

15.00 * 43.0000

19700 * 1 + 0.4 * 15.00 + 0.1250 + 0.0000





Wall thickness = tn = 0.6600 is greater than or equal to UG-45 value of 0.3140








Nozzle Material: SA-312 TP316L, High Joint Efficiency (E1): 1.00Factor B Chart: HA-4




Nozzle ID (corroded): 3.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.Developed Opening: 3.6240 in. Tangential Dimension L: 4.0000 in.




Minimum Design Metal Temperature: -20 FMaterial is exempt from impact testing per UHA-51(d)




Host Component: Cone 2 - Conical Reducer 2

Material: SA-516 Gr. 70 Conical Reducer wall thickness(new): 1.1250 in.Material Stress(Sv): 19700 PSInical Reducer wall thickness - thin out (corroded): 1.0000 in.

Distance from small end of cone: 50.0000 in. Diameter of Cone at Nozzle: 79.7500 in.



Internal Weld Leg Size(Weld 43): 0.5000 in.





tangential to the vessel wall, attached by a groove weld.Pipe Size: 4 Schedule: 120






ID Number: 4


Required Conical Reducer Thickness per Paragraph UG-37(a)

tr = PDo

(2 * cos (SE + 0.4P)) =

250.00 * 79.7500

(2 * 0.9203 * (19700 * 1 + 0.4 * 250.00)) = 0.5471 i n .



trn = PRn

SE - 0.6P =

250.00 * 1.9370

14400 * 1 - 0.6 * 250.00 = 0.0340 i n .


trn = 3 * Do * Pa

4B =

3 * 4.5000 * 15.00

4 * 3051 = 0.0167 i n .


fr1 = min Sn

Sv, 1.0000 = min

14400

19700, 1.0000 = 0.7310 fr2 = min

Sn

Sv, 1.0000 = min

14400

19700, 1.0000 = 0.7310

fr3 = min Sn

Sv, 1.0000 = min

14400

19700, 1.0000 = 0.7310 fr4 = min

Sp

Sv, 1.0000 = min

19700

19700, 1.0000 = 1.0000



t = PRn

SE - 0.6P + Ca + ext. Ca =

250.00 * 1.9370

14400 * 1.00 - 0.6 * 250.00 + 0.1250 + 0.0000 = 0.1590 i n .


t = PDo

(2 * cos (SE + 0.4P)) + Ca + ext. Ca =

250.00 * 79.7500

(2 * 0.9203 * (19700 * 1 + 0.4 * 250.00)) + 0.1250 + 0.0000 = 0.6721 i n .


t = PDo

(2 * cos (SE + 0.4P)) + Ca + ext. Ca =

15.00 * 79.7500

(2 * 0.9203 * (19700 * 1 + 0.4 * 15.00)) + 0.1250 + 0.0000









ID Number: 4







= 0.1292 sq. in.

A41 = (leg) * fr3 = (0.3750) * 0.7310 = 0.1028 sq. in.

A42 = Allowable Weld 42 area * fr4 = 0.3276 * 1.0000 = 0.3276 sq. in.

A43 = (leg) * fr2 = (0.3214) * 0.7310 = 0.0755 sq. in.

A5 = (Dp - d - 2tn) te fr4 = (7.0000 - 3.8740 - 2 * 0.3130) * 0.7500 * 1.0000 = 1.8750 sq. in.

Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 4.8135 sq. in., which is greater than A (2.2116)




ID Number: 4








= 0.1292 sq. in.

A41 = (leg) * fr3 = (0.3750) * 0.7310 = 0.1028 sq. in.

A42 = Allowable Weld 42 area * fr4 = 0.3276 * 1.0000 = 0.3276 sq. in.

A43 = (leg) * fr2 = (0.3214) * 0.7310 = 0.0755 sq. in.

A5 = (Dp - d - 2tn) te fr4 = (7.0000 - 3.8740 - 2 * 0.3130) * 0.7500 * 1.0000 = 1.8750 sq. in.

Area Available (External Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 5.6292 sq. in., which is greater than A (0.6820)




ID Number: 4


Nozzle Weld Strength Calculations

Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)

Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 0.7500, or 0.3130 = 0.3130 i n .

Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA

0.7 =

0.2191

0.7 = 0.3130 i n .


Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.0000, or 0.7500 = 0.7500 i n .

Weld 42 Leg min. = 0.5 * tmin + ext. CA

0.7 =

0.5 * 0.7500 + 0.0000

0.7 = 0.5357 i n .


Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.0000, or 0.3130 = 0.3130 i n .

Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca

0.7 =

(smaller of 0.25 or (0.3130 * 0.7)) + 0.1250

0.7 =

0.3441

0.7 = 0.4916 i n .


Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 14400 = 10080 P S IUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 14400 = 7056 P S IVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 14400 = 10656 P S IInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 14400 = 7056 P S IOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 19700 = 9653 P S IRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 14400 = 10656 P S I

Strength of Connection ElementsNozzle wall in shear = * * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * * 4.1870 * 0.3130 * 10080 = 20700 l b .Upper fillet in shear = * * Nozzle OD * weld leg * upper fillet in shear unit stress = * * 4.5000 * 0.3750 * 7056 = 18700 l b .Groove Weld in Tension = * * Nozzle OD * groove depth * groove weld tension unit stress = * * 4.5000 * 1.1250 * 10656 = 84700 l b .Inner fillet in shear = * * Nozzle OD * weld leg * inner fillet in shear unit stress = * * 4.5000 * 0.3214 * 7056 = 16000 l b .Outer fillet in shear = * * Plate OD * weld leg * outer fillet in shear unit stress = * * 7.0000 * 0.6250 * 9653 = 66300 l b .Repad groove weld = * * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * * 4.5000 * 0.7500 * 10656 = 56500 l b .




ID Number: 4


Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [2.2116 - 1.6783 + 2 * 0.3130 * 0.7310 * (1.00 * 1.0000 - 1.0000 * 0.5471)] * 19700 = 14600 l b .W1-1 = (A2 + A5 + A41 + A42) * Sv = (0.6251 + 1.8750 + 0.1028 + 0.3276) * 19700 = 57700 l b .W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (0.6251 + 0.1292 + 0.1028 + 0.0755 + 2 * 0.3130 * 1.0000 * 0.7310) * 19700 = 27400 l b .W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (0.6251 + 0.1292 + 1.8750 + 0.1028 + 0.3276 + 0.0755 + 2 * 0.3130 * 1.0000 * 0.7310) * 19700 = 70800 l b .

Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 66300 + 20700 = 87000 l b .Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 18700 + 56500 + 84700 + 16000 = 175900 l b .Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 66300 + 16000 + 84700 = 167000 l b .

Plate Strength = A5 * Sp = 1.8750 * 19700 = 36938 l b .

Outer fillet weld strength(66300) is greater than plate strength(36938).


Pressure Vessel Engineering, Ltd.M2


N u m b e r : 5 Mark Number: M2ID Number: M2




Nozzle Material: SA-240 Gr. 316L, High Joint Efficiency (E1): 1.00Factor B Chart: HA-4



Nozzle ID (new): 22.0000 in. Nozzle Wall Thickness(new): 1.0000 in.Nozzle ID (corroded): 22.2500 in. Nozzle Wall Thickness(corroded): 0.8750 in.Developed Opening: 22.0000 in. Tangential Dimension L: 22.0000 in.




Minimum Design Metal Temperature: -20 FMaterial is exempt from impact testing per UHA-51(d)




Host Component: Cone 2 - Conical Reducer 2

Material: SA-516 Gr. 70 Conical Reducer wall thickness(new): 1.1250 in.Material Stress(Sv): 19700 PSInical Reducer wall thickness - thin out (corroded): 1.0000 in.

Distance from small end of cone: 50.0000 in. Diameter of Cone at Nozzle: 79.7500 in.







tangential to the vessel wall, attached by a groove weld.Nozzle is adequate for UG-45 requirements.

Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.



Pressure Vessel Engineering, Ltd.M2

Job No: PVE-3602 Sample 13 Vessel Number: Sample 13N u m b e r : 5 Mark Number: M2

ID Number: M2


Required Conical Reducer Thickness per Paragraph UG-37(a)

tr = PDo

(2 * cos (SE + 0.4P)) =

250.00 * 79.7500

(2 * 0.9203 * (19700 * 1 + 0.4 * 250.00)) = 0.5471 i n .


Required Nozzle Thickness for Internal Pressure per Paragrap

Sample13_Spreadsheet.pdf

Documents

vessel number

advanced pressure vessel

shell material

psi design temperature

ontario n2v 1c6date

sample jobs

weight of fluid

temperature curve