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7-8 Populations and Samples Course 2 Warm Up Warm Up Problem of the Day Problem of the Day Lesson Presentation Lesson Presentation
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Page 1: Sample and population

7-8 Populations and Samples

Course 2

Warm UpWarm Up

Problem of the DayProblem of the Day

Lesson PresentationLesson Presentation

Page 2: Sample and population

Warm UpSolve.

n = 0.0625

Course 2

7-8 Populations and Samples

1. 12 =

2. 8n = 0.5

3. n – 9 = 14

2 5

n 9

n = 1113 5

4. –16 = n – (30)

n = 5

n = 46

Page 3: Sample and population

Problem of the Day

Why are both products the same?26 51 = 1,326 39 34 = 1,326

26 51 = (2 13) (3 17);

39 34 = (3 13) (2 17);

They have the same factors: 2, 3, 13, and 17

Course 2

7-8 Populations and Samples

Page 4: Sample and population

Learn to compare and analyze sampling methods.

Course 2

7-8 Populations and Samples

Page 5: Sample and population

Vocabularypopulationsamplerandom sampleconvenience samplebiased sample

Course 2

7-8 Populations and Samples

Page 6: Sample and population

In 2002, there were claims that Chronic Wasting Disease (CWD), or Mad Elk Disease, was spreading westward across North America. In order to verify claims such as these, the elk population had to be tested.

When information is gathered about a group, such as the elk in North America, the entire group is called the population. Because testing each member of a large group can be difficult or impossible, researchers often study a part of the population, called a sample.

Course 2

7-8 Populations and Samples

Page 7: Sample and population

Course 2

7-8 Populations and Samples

For a random sample, members of the population are chosen at random. This gives every member of the population an equal chance of being chosen. A convenience sample is based on members of the population that are readily available, such as 30 elk in a wildlife preservation area.

A random sample is more likely to be representative of a population than a convenience sample is.

Helpful Hint

Page 8: Sample and population

Determine which sampling method will better represent the entire population. Justify your answer.

Additional Example 1: Analyzing Sampling Methods

Course 2

7-8 Populations and Samples

Sampling methodMaria surveys only the band students she knows personally.

Results84% want blue uniforms

Jon writes each band student’s name on a card. He questions those students whose name he draws.

61% want blue uniforms

Jon’s sample is a random sample, giving every band member equal chance to be surveyed, so it is the better method.

Page 9: Sample and population

Determine which sampling method will better represent the entire population. Justify your answer.

Check It Out: Example 1

Course 2

7-8 Populations and Samples

Sampling methodFerdinand surveys every other swimmer on the team.

Results72% want practice early

Anna-Maria questions the swimmers who are in her Biology class.

50% want practice early

Ferdinand’s sample is a random sample, giving results that better represent the entire swimming team, so it is the better method.

Page 10: Sample and population

A biased sample does not fairly represent the population. A study of 50 elk belonging to a breeder could be biased because the breeder’s elk might be less likely to have Mad Elk Disease than elk in the wild.

Course 2

7-8 Populations and Samples

Page 11: Sample and population

Determine whether each sample may be biased. Explain.

Additional Example 2: Identifying Potentially Biased Samples

A. The mayor surveys 100 supporters at a rally about the most important issues to be addressed by the city council.

Course 2

7-8 Populations and Samples

The sample is biased. The supporters may have different ideas than those not at the rally.

B. The principal sends out questionnaires to all of the students to find out what kind of music students prefer at dances.The sample is random. The students all have a chance to respond.

Page 12: Sample and population

Determine whether each sample may be biased. Explain.

Check It Out: Example 2

Course 2

7-8 Populations and Samples

A. The owner of a record shop surveys only customers over the age of 18 who shop at his store.This is not random. Customers under the age of 18 do not have a chance of being chosen.

B. The teacher writes the name of each student on a piece of paper and questions the students whose names are drawn.

This sampling method is random. Each student has an equal chance of being chosen.

Page 13: Sample and population

A principal of a school with 1,500 students estimates that about 400 students will attend a band festival on Saturday. A random sample of 25 students showed that 6 of them will attend. Determine whether the principal’s estimate is likely to be accurate.

Additional Example 3: Verifying Claims Based on Statistical Data

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7-8 Populations and Samples

Set up a proportion to predict the total number of students that will attend.

Students attending sample # of Students sampled

Students attending Student Population

=

Page 14: Sample and population

Additional Example 3 Continued

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7-8 Populations and Samples

Let x represent the number of actual students attending the band festival.

6 25

x 1500

=

6 • 1500 = 25 • x The cross products are equal.

9000 = 25x Multiply.

9000 25

25x 25

= Divide each side by 25 to isolate x.

360 = x

The estimate is not accurate because the data shows that 360 students are likely to attend.

Page 15: Sample and population

The owner of a large chain restaurant with 1,200 employees estimates that about 250 employees will ask for winter vacation. A random sample of 40 employees showed that 8 of them will ask for the time off. Determine whether the owner’s estimate is likely to be accurate.

Check It Out: Example 3

Course 2

7-8 Populations and Samples

Set up a proportion to predict the total number of students that will attend.

Employees surveyed for time off # of Employees surveyed

Employees asking for time off Total # of Employees

=

Page 16: Sample and population

Check It Out: Example 3 Continued

Course 2

7-8 Populations and Samples

Let x represent the number of actual employees asking for time off.

8 40

x 1200

=

8 • 1200 = 40 • x The cross products are equal.

9600 = 40x Multiply.

9600 40

40x 40

= Divide each side by 40 to isolate x.

240 = x

The estimate is accurate because the data shows that 240 employees will ask for time off.

Page 17: Sample and population

a. A TV ratings service is surveying residents of Orlando who bought TVs in the last month about their favorite TV show.

b. A TV ratings service called residents of Orlando randomly selected from the phone directory to conduct a survey about their favorite show.

Lesson Quiz: Part I

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7-8 Populations and Samples

b1. Determine which sample better represents the

entire population.

Page 18: Sample and population

2. Determine whether each sample may be biased. Explain.

Lesson Quiz: Part II

Course 2

7-8 Populations and Samples

Biased; at other times of the day, customers may have different preferences.

a. A convenience store surveys customers one morning to determine what products they may like the store to stock.

b. Each student’s name is written on a slip of paper and placed in a box. One slip of paper is selected to determine the student to be the homeroom representative.Not biased; the sample is random.

Page 19: Sample and population

3. A local middle school has 2500 students. Morgan interviewed 75 of the students about their library habits. She found that 45 of the students checked out a book weekly. Predict the number of students likely to check out books weekly.

Lesson Quiz: Part III

Course 2

7-8 Populations and Samples

1500