1. [Jan 2009 Q(4) ] Ans : median = 53 , LQ = 35, UQ = 60 2. [Jan 2009 Q(5) ] Ans : (a) w = 5 , h= 0.75 (b) 10.2 , IQR = 9 , (c) 12.8 , Sd = 9.88 (d) Median < mean, So positive skew (e) Use median and IQR, since data is skewed or not affected by extreme values or outliers PAST PAPER QUESTIONS S1 – Data Location, Measures of dispersion and
1. MATHEMATICAL MODELLING 2. DATA LOCATION. 3. MEASURES OF DISPERSION. 4.REPRESENTATION OF DATA STEM LEAF DIAGRAMS INTERPOLATION METHOD BOX PLOTS HISTOGRAMS
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1. [Jan 2009 Q(4) ] Ans : median = 53 , LQ = 35, UQ = 60
2. [Jan 2009 Q(5) ] Ans : (a) w = 5 , h= 0.75 (b) 10.2 , IQR = 9 , (c) 12.8 , Sd = 9.88 (d) Median < mean, So positive skew (e) Use median and IQR, since data is skewed or not affected by extreme values or outliers
PAST PAPER QUESTIONS
S1 – Data Location, Measures of dispersion and Representation of data
3. [ June 2009 Q(3) ] Ans : (a) 1 cm (b) 6 cm
4. [ June 2009 Q(4) ] Ans : (a) 17.1 (b) mean = 17.1 , Sd = 3.28 (c) -0.00802 No skew/slightly skew.
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9. [ Jan 2011 Q(3) ] Ans : (a) Outlier=25 , (b) negatively skewed since Q3−Q3 ¿Q2−Q1 (c) not true since the lower quartile is 7000 and therefore 75% above 7000 not 10000
10. [ Jan 2011 Q(5) ] Ans : (a) 41.3 (b) 44.1875 , 14.7 (c) mean > median therefore positive skew
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