RELATED RATES PROBLEMS
Nov 27, 2014
RELATED RATES PROBLEMS
If a particle is moving along a straight line according to the equation of motion , since the velocity may be interpreted as a rate of change of distance with respect to time, thus we have shown that the velocity of the particle at time “t” is the derivative of “s” with respect to “t”.
)t(fs
There are many problems in which we are concerned with the rate of change of two or more related variables with respect to time, in which it is not necessary to express each of these variables directly as function of time. For example, we are given an equation involving the variables x and y, and that both x and y are functions of the third variable t, where t denotes time.
Since the rate of change of x and y with respect to t is given by and , respectively, we differentiate both sides of the given equation with respect to t by applying the chain rule.
When two or more variables, all functions of t, are related by an equation, the relation between their rates of change may be obtained by differentiating the equation with respect to t.
dx
dt
dy
dt
A Strategy for Solving Related Rates Problems (p. 205)
Example 1A 17 ft ladder is leaning against a wall. If the bottom of the ladder is pulled along the ground away from the wall at the constant rate of 5 ft/sec, how fast will the top of the ladder be moving down the wall when it is 8 ft above the ground?
wallthe fromaway
ground the along pulled is ladder the of bottom the sincesec time t
instantany at ground the from ladder the of top the of ft distance y
instantany at wallthe from ladder the of bottom the of ft distance x Let
sec
ft5
dt
dx
x
17 ft. ?dt
dy
ft8y
y
Note: • Values which changes as time changes are denoted by variable.• The rate is positive if the variable increases as time increase and is negative if the variable decreases as time increases.
sec
ft375.9
8
515
dt
dy
15817x8y when
ydtdx
x
y2dtdx
x2
dt
dy
0dt
dyy2
dt
dxx2
Equation Working 17yx
22
222
Example 2A balloon leaving the ground 60 feet from an observer, rises vertically at the rate 10 ft/sec . How fast is the balloon receding from the observer after 8 seconds?
ground the from rise to startsballoon the sincesec time t
instantany at observer the from balloon the of ft distance L
instantany at ground the from balloon the of ft height h Let
Viewer60 feet
h L
sec
ft10
dt
dh
?dt
dL
sec8t
Equation Working 3600hL
60hL :figure the In
2
222
3600h
dtdh
h
dt
dL
3600h2
dtdh
h2
dt
dL
2
2
.ft 808sec sec
ft10h
8sect and sec
ft10
dt
dh ,Since
sec
ft 8
100
800
dt
dL
000,10
800
36006400
800
dt
dL
360080
1080
dt
dL2
Example 3As a man walks across a bridge at the rate of 5 ft/sec , a boat passes directly beneath him at 10 ft/sec. If the bridge is 30 feet above the water, how fast are the man and the boat separating 3 seconds later?
secft
5
secft
10
instantany at boat the and
man the between ft distance s
bridge the cross to
startsman the sec time t Let
2
22
222
t125 L
t10t5 L
t10t5L
sec3 t whendt
ds :Find
2
2
2
22
22
222
t125900
t125
dt
dSt1259002
t2125
dt
dS
:t time wrtWE the of sidesboth ateDifferenti
Equation Working 125t900S
125t900S
125tL but L900 S
L30S
sec
ft8.33 or
sec
ft
3
25
45
3125
dt
dS
3125900
3125
dt
ds
sec3t when
2
S
L5t
30’
30’ 10t
secft
10
secft
5
R
secft
4dtdR
x
20ft
Example 4A man on a wharf of 20 feet above the water pulls in a rope, to which a boat is attached, at the rate of 4 ft/sec. At what rate is the boat approaching the wharf when there is 25 feet of rope out?
instantany at out rope the of ft length R
instantany at wharfthe from boat the of ft distance x
wharfthe approach to startsboat the sincesec time t Let
)Equation Working( 400R x
400Rx
20xR
ft25R when dt
dx Find
2
22
222
400RdtdR
R
400R2dtdR
R2
dt
dx
400Rx
22
2
sec
ft
3
20
dt
dx
15
425
40025
425
dt
dxsec
ft4
dt
dR and
ft25R When
2
Example 5Water is flowing into a conical reservoir 20 feet deep and 10 feet across the top, at the rate of 15 ft3/min . Find how fast the surface is rising when the water is 8 feet deep?
5 feet20
feet
h
r
10 feet
min
ft15
dt
dV 3
instantany at waterthe of (ft) heighth
instantany at surface waterthe of (ft) radius r
reservoir the oint flows water the cesin min time t Let
h r 3
1 Bh
3
1 V
deep ft 8 is waterthe whendt
dh Find
2 h4
1r
h
r
20
5
proportion and ratio By
min
ft1.194 or
min
ft
4
15
8
1516
hdtdV
16
dt
dh
dt
dhh
16dt
dhh3
48dt
dV Equation Working h
48V
hh4
1
3
1V ,Thus
22ft8h
223
2
Example 6Water is flowing into a vertical tank at the rate of 24 ft3/min . If the radius of the tank is 4 feet, how fast is the surface rising?
h
4 feet
min
ft24
dt
dV 3
instantany at waterhet of ft volume V
instantany at waterthe of ft heighth
tank the into flows waterthe sincemin time t Let
3
Equation Working h 16h4V
ft 4r constant, is r But
hr h r V
BhV From
ft. 4 is tank the of radius the whendt
dh Find
2
22
min
ft
2
3
16
24
16dt
dV
dt
dh
dt
dh16
dt
dV
ft4r
Example 7A triangular trough is 10 feet long, 6 feet across the top, and 3 feet deep. If water flows in at the rate of 12 ft3/min, find how fast the surface is rising when the water is 6 inches deep?
min
ft12
3
h
6 feet
10 feet3 fe
et x
instantany at waterhet of ft volume V
instantany at end
triangular the at waterthe of ft widthhorizontal x
instantany at waterthe of ft heighth
trough the into flows waterthe sincemin time t Let
3
Equation Working 10hh2h55xhV Thus,
h2x3
6
h
x ,proportion and ratioy B
h5x10h x2
1V
BhV From
deep. inches 6 is waterthe whendt
dh Find
2
min
ft2.1
in12
ft1in620
12
h20dt
dV
dt
dh
dt
dhh20
dt
dV
in6h
Example 8A train, starting at noon, travels at 40 mph going north. Another train, starting from the same point at 2:00 pm travels east at 50 mph . Find how fast the two trains are separating at 3:00 pm.
80 m
iles
x2pm
B
C
DA
L
y
3pm
3pm
hr
mi40
dt
dy
hr
mi50
dt
dx
12pm
2pm
miles 80240BA
mph 40dt
dy and mph 50
dt
dx Since
1hr. t enwh dt
dL Find
Equation Working y80x L
y80xL :figure the From
22
222
22 )y80(x2dtdy
)y80(2dtdx
x2
dt
dL
miles 40hr1mph40y
miles 50hr150mphx hr 1 After
22 )4080()50(
)40)(4080(())50)(50(
dt
dL
400,14500,2
800,4500,2
dt
dL
22 )y80(xdtdy
)y80(dtdx
x
dt
dL
130
300,7
900,16
300,7
dt
dL
hr
mi15.56
dt
dL
Example 9A billboard 10 feet high is located on the edge of a building 45 feet tall. A girl 5 feet in height approaches the building at the rate of 3.4 ft/sec . How fast is the angle subtended at her eye by the billboard changing when she is 30 feet from the billboard?
x
sec.ft
43
45’
10’
5’
x40
x50
1
x40
x50
tan
x
40 tan and
x
50 tan ,but
tan tan1
tan tan tan
tan tan
:gsinU
:figure the In
ft 30 x enwh dt
d Find
ationWorkingEqu 2000x
x10tan
2000x
x10
x2000xx
10
tan
21
2
2
2
22
2
2
2
2000xdtdx
)x2(x10dtdx
)10)(2000x(
2000xx10
1
1
dt
d
Equation Working 2000x
x10tan
21
222
22
x1002000xdtdx
x20000,20x10
dt
d
222
2
x1002000xdtdx
x10000,20
dt
d
222
2
30 100 200030
4.3 30 10000,20
dt
d
000,500,8
4.3 000,11
dt
d
sec
rad0044.0
dt
d
1. What number exceeds its square by the maximum amount?2. The sum of two numbers is “K”. find the minimum value of the sum of their squares.3. A rectangular field of given area is to be fenced off along the bank
of a river. If no fence is needed along the river, what are the dimensions of the rectangle that will require the least amount of fencing?
4. A Norman window consists of a rectangle surmounted by a semicircle. What shape gives the most light for a given perimeter?
5. A cylindrical glass jar has a plastic top. If the plastic is half as expensive as the glass per unit area, find the most economical
proportions for the glass.6. Find the proportions of the circular cone of maximum volume inscribed in a sphere.7. A wall 8 feet high and 24.5 feet from a house. Find the shortest ladder which will reach from the ground to the house when leaning over the wall
EXERCISES: