Waves and our Universe Quantum Phenomena 1. Electrons and photons appear to exhibit either particle or wave behaviour in different situations. Complete the tables by briefly outlining an observation and its explanation which provide evidence for the particle or wave behaviour in the situation given. Electrons Photons (Total 6 marks)
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Waves and our Universe Quantum Phenomena
1. Electrons and photons appear to exhibit either particle or wave behaviour in different situations.
Complete the tables by briefly outlining an observation and its explanation which provide evidence for the particle or wave behaviour in the situation given.
Electrons Photons
(Total 6 marks)
2. (a) The following equation describes the release of electrons from a metal surface illuminated by electromagnetic radiation.
hf = k.e.max
+ φ
Explain briefly what you understand by each of the terms in the equation.
3. The graph shows how the maximum kinetic energy T of photoelectrons emitted from the surface of sodium metal varies with the frequency f of the incident radiation.
Why are no photoelectrons emitted at frequencies below 4.4 × 1014 Hz?
Add a line to the graph to show the maximum kinetic energy of the photoelectrons emitted from a metal which has a greater work function than sodium.
(2)
(Total 9 marks)
4. Experiments on the photoelectric effect show that the kinetic energy of photoelectrons released depends upon the frequency of the incident light and not on its intensity,
• light below a certain threshold frequency cannot release photoelectrons.
How do these conclusions support a particle theory but not a wave theory of light?
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(6)
Calculate the threshold wavelength for a metal surface which has a work function of 6.2 eV.
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Threshold wavelength = ………………………………………….
To which part of the electromagnetic spectrum does this wavelength belong?
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(4)(Total 10 marks)
5. (a) Describe briefly how you would demonstrate in a school laboratory that different elements can be identified by means of their optical spectra
6. Experiments on the photoelectric effect show that the kinetic energy of photoelectrons released depends upon the frequency of the incident light and not on its intensity.
• light below a certain threshold frequency cannot release photoelectrons.
How do these conclusions support a particle theory but not a wave theory of light? You may be awarded a mark for the clarity of your answer.
Two beams of monochromatic electromagnetic radiation, A and B, have equal intensities. Their wavelengths are:
Beam A 300 nm
Beam B 450 nm
In the table below, E denotes the energy of a photon and N denotes the number of photons passing per second through unit area normal to the beam. The subscripts A and B refer to the two beams. In the second column of the table, state the value of each ratio, and in the third column explain your answer.
Ratio Value Explanation
EA / E
B
NA / N
B
The table below gives the work functions of four metals.
A metal plate made from one of these metals is exposed to beams A and B in turn. Beam A causes electrons to be emitted from the plate, but beam B does not. Calculate the
photon energies in each beam and hence deduce from which metal the plate is made.
8. Read the passage and then answer the questions at the end.
Spontaneous and stimulated emission of radiation
An atom in an excited state emits radiation by dropping to a state of lower energy, often the ground state. This is a random process in which each atom has an average lifetime in the excited state. The diagram shows this random process of spontaneous emission.
Einstein proposed that in addition to this process, the transition from an excited state could also be triggered by radiation of the correct frequency. This type of emission is known as stimulated emission. In stimulated emission an incoming photon, which is not absorbed, triggers a transition to the lower energy state, thus producing a second identical photon.
The emitted photons in both spontaneous and stimulated emission have clearly defined frequencies determined by the atom’s energy levels. However, other effects, such as Doppler shifts caused by the motion of the atoms, broaden what should be a very sharp line in the emission spectrum into a narrow band.
When a large number of gas atoms are in thermal equilibrium at an absolute temperature T, the number of atoms in each of the energy levels depends only on the temperature. The higher the energy level, the smaller the number of atoms raised to that energy by thermal agitation. If N
1 is the number of atoms at level E
1, the ground state, and N
2 the
number of atoms at level E2, then
N2 = N
1e–∆E/kT
where ∆E = E2 – E
1 and k is a constant. Similar equations relate N
3 to N
2 and N
4 to N
3
etc. An incoming photon may be absorbed and excite an atom in the ground state E1, a
process which subsequently results in spontaneous emission. However, an incoming photon is hardly ever going to interact with an atom already in an excited state such as E
2 to give rise to stimulated emission. This is because N
2 << N
1, even at high
temperatures, and is why the emission of visible light from excited atoms is usually regarded as a completely random process.
In certain circumstances, however, it is possible to arrange for N2 > N
1, a situation
known as population inversion. In this case the gas atoms are not in thermal equilibrium, indeed the ‘temperature’ of the gas can be thought of as being negative. Each photon now entering the gas is more likely to produce stimulated emission than to be absorbed. In these circumstances the photon flux is increased – a situation described as light amplification by the stimulated emission of radiation or as laser action.
[This passage is adapted from Masers and lasers by R A Smith in Endeavour, April 1962.]
(a) Explain the meaning of the following phrases as used in the passage:
(i) absolute temperature (paragraph 4),
(ii) Doppler shifts (paragraph 3),
(iii) a random process (paragraphs 1 and 4).(5)
(b) The diagram above illustrates the spontaneous emission of a photon when an atom has a transition from an excited state E
2 to the ground state E
1.
(i) Calculate the wavelength of the emitted photon when E2 – E
1 = 2.0 eV. To
which region of the electromagnetic spectrum does this radiation belong?
(ii) Sketch an energy level diagram showing the ground state and three possible excited states for an atom. Explain, using your diagram, why there can be six possible wavelengths for photons emitted from atoms occupying such a set of excited states.
(7)
(c) (i) Draw a diagram, similar to the diagram above, to illustrate what happens in the stimulated emission of a photon.
(ii) Explain in your own words how light amplification is achieved in a laser.(4)
(d) State the circumstances under which the ‘temperature’ of a gas can be thought of as being negative.
(2)
(e) The average kinetic energy of helium atoms of mass 6.7 × 10–27 kg at room temperature is6.0 × 10–22 J.
(i) Calculate the average speed of helium atoms at room temperature.
(ii) Show that these helium atoms produce a Doppler shift ∆λ of less than 10–12 m for photons of wavelength 600 nm.
(iii) Suggest why the spectral line at 600 nm is found to be broader than 10–12 m.(6)
(f) The diagram shows the number of atoms in some energy levels for a gas in thermal equilibrium at a temperature T.
(i) What determines the number of atoms in each energy level?
(ii) State how atoms are raised to higher energy levels.(2)
(g) Suppose that a very large number of hydrogen atoms are in thermal equilibrium at a temperature of 1150 K and that two million of these atoms are raised to level E
3,
i.e. E3 = 2.00 × 106.
(i) Use N4 = N
3e–∆E/kT to show that the number of atoms N
4 in level E
4 is just
over 2500, given that
∆E = E4 – E
3 = 1.06 × 10–19 J and k = 1.38 × 10–23 J K–1
Show all your working.
(ii) Calculate the number of atoms N5 in level E
5 given that
E5 – E
4 = 0.49 × 10–19 J
(5)(Total 31 marks)
9. The diagram shows some of the outer energy levels of the mercury atom.
Calculate the ionisation energy in joules for an electron in the -10.4 eV level.
10. Four of the energy levels of a lithium atom are shown below.
Draw on the diagram all the possible transitions which the atom could make when going from the –3.84 eV level to the –5.02 eV level.
(2)
Photons of energy 3.17 eV are shone onto atoms in lithium vapour. Mark on the diagram, and label with a T, the transition which could occur.
(1)
One way to study the energy levels of an atom is to scatter electrons from it and measure their kinetic energies before and after the collision. If an electron of kinetic energy 0.92 eV is scattered from a lithium atom which is initially in the –5.02 eV level, the scattered electron can have only two possible kinetic energies.
State these two kinetic energy values, and explain what has happened to the lithium atom in each case. (You should assume that the lithium atom was at rest both before and after the collision.)
Kinetic energy 1 ...................................................................................................................
Show this change in energy levels on the diagram.(1)
The spectrum of white light that has been passed through hot hydrogen gas is observed in the laboratory. The continuous spectrum is seen to have a few dark lines across it. One of these dark lines occurs in the blue region of the spectrum at a wavelength of 490 nm.
The spectrum of a distant star is observed. It too shows the same pattern of dark lines, but all at longer wavelengths. The line measured at 490 nm in the laboratory occurs at 550 nm in the star’s spectrum. What can be deduced about the star?
17. The graph shows how the maximum kinetic energy T of photoelectrons emitted from the surface of sodium metal varies with the frequency f of the incident electromagnetic radiation.
Use the graph to find a value for the Planck constant.
Ionisation energy = ...................................... J(2)
A proton of kinetic energy 9.2 eV collides with a mercury atom. As a result, an electron in the atom moves from the –10.4 eV level to the –1.6 eV level. What is the kinetic energy in eV of the proton after the collision?
20. A 60 W light bulb converts electrical energy to visible light with an efficiency of 8%. Calculate the visible light intensity 2 m away from the light bulb.
The average energy of the photons emitted by the light bulb in the visible region is 2 eV. Calculate the number of these photons received per square metre per second at this distance from the light bulb.