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+Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of

Apr 17, 2018

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Page 1: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 2: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 3: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 4: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 5: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 6: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of
Page 7: +Q2 +2pQ (P+Q)2 R=P+Q when e-1800 ; cos 180--1 ; Sin 180 = o = p2 +Q2 _2PQ = (p-Q)2 R=P-Q a = or 1800 a) Define moment of force about a point. State the condition of equilibrium of