SULIT 2 3472/1 [Lihat halaman sebelah 3472/1 SULIT Untuk Kegunaan Pemeriksa For Exeminer’s Use The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. ALGEBRA 1 a ac b b x 2 4 2 8 a b b c c a log log log 2 a m x a n = a m + n 9 Tn = a + (n -1)d 3 a m a n = a m – n 10 S n = 2 ( 1) 2 n a n d 4 ( a m ) n = a m n 11 T n = 1 n ar 5 n m mn a a a log log log 12 ( 1) (1 ) , 1 1 1 n n n ar a r S r r r 6 n m n m a a a log log log 13 , 1 1 a S r r 7 log a m n = n log a m CALCULUS 1 dx du v dx dv u dx dy uv y , 4 Area under a curve= b a y dx or b a x dy 2 2 , v dx dv u dx du v dx dy v u y 3 dx du du dy dx dy 5 Volume generated = 2 b a y dx or = 2 b a x dy
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SULIT 2 3472/1
[Lihat halaman sebelah
3472/1 SULIT
Untuk
Kegunaan
Pemeriksa
For
Exeminer’s
Use The following formulae may be helpful in answering the questions. The symbols given are
the ones commonly used.
ALGEBRA
1 a
acbbx
2
42 8
a
bb
c
ca
log
loglog
2 am x a
n = a
m + n 9 Tn = a + (n -1)d
3 am
an = a
m – n 10 Sn = 2 ( 1)
2
na n d
4 ( am
)n = a
m n 11 Tn = 1nar
5 nmmn aaa logloglog 12 ( 1) (1 )
, 11 1
n n
n
a r a rS r
r r
6 nmn
maaa logloglog 13 , 1
1
aS r
r
7 log a mn = n log a m
CALCULUS
1 dx
duv
dx
dvu
dx
dyuvy ,
4 Area under a curve=
b
a
y dx or
b
a
x dy
2
2 ,
v
dx
dvu
dx
duv
dx
dy
v
uy
3 dx
du
du
dy
dx
dy
5 Volume generated
= 2
b
a
y dx or
= 2
b
a
x dy
SULIT 3 3472/1
[Lihat halaman sebelah
3472/1 SULIT
Untuk
Kegunaan
Pemeriksa
For
Exeminer’s
Use
STATISTICS
1 N
xx
8 !
( )!
nr
nP
n r
2 f
fxx
9 !
( )! !
nr
nC
n r r
3 2
22
xN
x
N
xx
10 ( ) ( ) ( ) ( )P A B P A P B P A B
4 2
22
xf
fx
f
xxf
11 P(X = r) = , 1n r n rrC p q p q
5 Cf
FN
Lmm
2
1
12 Mean = np
6 1
0
100Q
IQ
13 npq
7 i
ii
W
IWI
14
XZ
GEOMETRY
1 Distance = 2 22 1 2 1( ) ( )x x y y
5 22
~yxr
2 Midpoint =
2,
2
2121 yyxx
6 22
~~
~
^
yx
jyix
r
3 A point dividing a segment of a line
(x , y ) =
nm
myny
nm
mxnx 2121 ,
4 Area of a triangle =
1
21 2 2 3 3 1 2 1 3 2 1 3( ) ( )x y x y x y x y x y x y
SULIT 4 3472/1
[Lihat halaman sebelah
3472/1 SULIT
Untuk
Kegunaan
Pemeriksa
For
Exeminer’s
Use
TRIGONOMETRY
1 Arc length, s =r
8 sin( ) sin cos cos sinA B A B A B
2 Area of a sector, 21
2A r 9 cos( ) cos cos sin sinA B A B A B
3 . 2 2sin cos 1A A
10
tan tantan( )
1 tan tan
A BA B
A B
4 2 2sec 1 tanA A
11 2
2tantan 2
1 tan
AA
A
5 2 2cos 1 cotec A A 12 sin sin sin
a b c
A B C
6 sin 2A = 2 sin A cos A 13 2 2 2 2 cosa b c bc A
7 cos 2A = 2 2cos sinA A
= 22cos 1A
= 21 2sin A
14 Area of triangle = 1
sin2
ab C
SULIT 5 3472/1
[Lihat halaman sebelah
3472/1 SULIT
Untuk
Kegunaan
Pemeriksa
For
Exeminer’s
Use Answer all questions.
Jawab semua soalan.
1. Fungsi f memetakan unsur dari set P = { m – 3, 4, 9,16, 25 } kepada
set Q = { 0, 3, 8, 15, 24 }, ditunjukkan dalam bentuk pasangan tertib:
A function f maps the elements from set P = { m – 3, 4, 9,16, 25 } to
set Q = { 0, 3, 8, 15, 24 } as shown below in ordered pairs: