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Page 1: Pythagoras theorem ppt

a

b

c

222 cba

Page 2: Pythagoras theorem ppt

Pythagorean Theorem Essential Questions

How is the Pythagorean Theorem used to identify side lengths?

When can the Pythagorean Theorem be used to solve real life patterns?

Page 3: Pythagoras theorem ppt

This is a right triangle:

Page 4: Pythagoras theorem ppt

We call it a right triangle because it contains a right angle.

Page 5: Pythagoras theorem ppt

The measure of a right angle is 90o

90o

Page 6: Pythagoras theorem ppt

The little square

90o

in theangle tells you it is aright angle.

Page 7: Pythagoras theorem ppt

About 2,500 years ago, a Greek mathematician named Pythagorus discovered a special relationship between the sides of right triangles.

Page 8: Pythagoras theorem ppt

Pythagorus realized that if you have a right triangle,

3

4

5

Page 9: Pythagoras theorem ppt

and you square the lengths of the two sides that make up the right angle,

24233

4

5

Page 10: Pythagoras theorem ppt

and add them together,

3

4

5

2423 22 43

Page 11: Pythagoras theorem ppt

22 43

you get the same number you would get by squaring the other side.

222 543 3

4

5

Page 12: Pythagoras theorem ppt

Is that correct?

222 543 ?

25169 ?

Page 13: Pythagoras theorem ppt

It is. And it is true for any right triangle.

8

6

10222 1086

1006436

Page 14: Pythagoras theorem ppt

The two sides which come together in a right angle are called

Page 15: Pythagoras theorem ppt

The two sides which come together in a right angle are called

Page 16: Pythagoras theorem ppt

The two sides which come together in a right angle are called

Page 17: Pythagoras theorem ppt

The lengths of the legs are usually called a and b.

a

b

Page 18: Pythagoras theorem ppt

The side across from the right angle

a

b

is called the

Page 19: Pythagoras theorem ppt

And the length of the hypotenuse

is usually labeled c.

a

b

c

Page 20: Pythagoras theorem ppt

The relationship Pythagorus discovered is now called The Pythagorean Theorem:

a

b

c

Page 21: Pythagoras theorem ppt

The Pythagorean Theorem says, given the right triangle with legs a and b and hypotenuse c,

a

b

c

Page 22: Pythagoras theorem ppt

then

a

b

c

.222 cba

Page 23: Pythagoras theorem ppt

You can use The Pythagorean Theorem to solve many kinds of problems.

Suppose you drive directly west for 48 miles,

48

Page 24: Pythagoras theorem ppt

Then turn south and drive for 36 miles.

48

36

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How far are you from where you started?

48

36?

Page 26: Pythagoras theorem ppt

482

Using The Pythagorean Theorem,

48

36c

362+ = c2

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Why? Can you see that we have a right triangle?

48

36c

482 362+ = c2

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Which side is the hypotenuse? Which sides are the legs?

48

36c

482 362+ = c2

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22 3648

Then all we need to do is calculate:

12962304

3600 2c

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And you end up 60 miles from where you started.

48

3660

So, since c2 is 3600, c is 60.So, since c2 is 3600, c is

Page 31: Pythagoras theorem ppt

Find the length of a diagonal of the rectangle:

15"

8"?

Page 32: Pythagoras theorem ppt

Find the length of a diagonal of the rectangle:

15"

8"?

b = 8

a = 15

c

Page 33: Pythagoras theorem ppt

222 cba 222 815 c 264225 c 2892 c 17c

b = 8

a = 15

c

Page 34: Pythagoras theorem ppt

Find the length of a diagonal of the rectangle:

15"

8"17

Page 35: Pythagoras theorem ppt

Practice using The Pythagorean Theorem to solve these right triangles:

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5

12

c = 13

Page 37: Pythagoras theorem ppt

10

b

26

Page 38: Pythagoras theorem ppt

10

b

26

= 24

(a)

(c)

222 cba 222 2610 b

676100 2 b1006762 b

5762 b24b

Page 39: Pythagoras theorem ppt

Check It Out! Example 2

A rectangular field has a length of 100 yards and a width of 33 yards. About how far is it from one corner of the field to the opposite corner of the field? Round your answer to the nearest tenth.

Page 40: Pythagoras theorem ppt

Check It Out! Example 2 Continued

11 Understand the Problem

Rewrite the question as a statement.

• Find the distance from one corner of the field to the opposite corner of the field.

• The segment between the two corners is the hypotenuse.

• The sides of the fields are legs, and they are 33 yards long and 100 yards long.

List the important information:

• Drawing a segment from one corner of the field to the opposite corner of the field divides the field into two right triangles.

Page 41: Pythagoras theorem ppt

Check It Out! Example 2 Continued

22 Make a Plan

You can use the Pythagorean Theorem towrite an equation.

Page 42: Pythagoras theorem ppt

Check It Out! Example 2 Continued

Solve33

a2 + b2 = c2

332 + 1002 = c2

1089 + 10,000 = c2

11,089 = c2

105.304 c

The distance from one corner of the field to the opposite corner is about 105.3 yards.

Use the Pythagorean Theorem.

Substitute for the known variables.

Evaluate the powers.

Add.

Take the square roots of both sides.

105.3 c Round.

Page 43: Pythagoras theorem ppt

The Pythagorean Theorem

“For any right triangle, the sum of the areas of the two small squares is equal to the area of the larger.”

aa22 + b + b22 = c = c22

Page 44: Pythagoras theorem ppt

Proof

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a

a

a2

bb

cc

b2

c2

Let’s look at it this way…

Page 46: Pythagoras theorem ppt

Baseball Problem

A baseball “diamond” is really a square.

You can use the Pythagorean theorem to find distances around a baseball diamond.

Page 47: Pythagoras theorem ppt

Baseball Problem

The distance between

consecutive bases is 90

feet. How far does a

catcher have to throw

the ball from home

plate to second base?

Page 48: Pythagoras theorem ppt

Baseball Problem

To use the Pythagorean theorem to solve for x, find the right angle.

Which side is the hypotenuse?

Which sides are the legs?

Now use: aa22 + b + b22 = c = c22

Page 49: Pythagoras theorem ppt

Baseball ProblemSolution

• The hypotenuse is the distance from home to second, or side x in the picture.

• The legs are from home to first and from first to second.

• Solution:

x2 = 902 + 902 = 16,200

x = 127.28 ft

Page 50: Pythagoras theorem ppt

Ladder Problem

A ladder leans against a second-story window of a house. If the ladder is 25 meters long, and the base of the ladder is 7 meters from the house, how high is the window?

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Ladder ProblemSolution

• First draw a diagram that shows the sides of the right triangle.

• Label the sides: – Ladder is 25 m

– Distance from house is 7 m

• Use a2 + b2 = c2 to solve for the missing side.

Distance from house: 7 meters

Page 52: Pythagoras theorem ppt

Ladder ProblemSolution

72 + b2 = 252

49 + b2 = 625 b2 = 576 b = 24 m

How did you do? A = 7 m