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PROJECTILE MOTION by: JANET BRIGIDA A. CATIPON MHS Science 9 Teacher
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PROJECTILE MOTION

Apr 09, 2017

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Page 1: PROJECTILE MOTION

PROJECTILE MOTION

by: JANET BRIGIDA A. CATIPONMHS Science 9 Teacher

Page 2: PROJECTILE MOTION

LEARNING OBJECTIVES

• Define Projectile Motion• Explain Projectile Motion• Identify the types of Projectile Motion• Differentiate the types of Projectile Motion• Explain and summarize all the kinematics

equation in solving Projectile Motion problems• Solve problems involving the types of Projectile

Motion

Page 3: PROJECTILE MOTION

WHAT IS PROJECTILE?Projectile -Any object which projected by some means and

continues to move due to its own inertia (mass).

Page 4: PROJECTILE MOTION

PROJECTILES MOVE IN TWO DIMENSIONS

A projectile moves in 2 - dimensions, therefore, it has 2 components just like a resultant vector.

Page 5: PROJECTILE MOTION

HORIZONTAL “VELOCITY” COMPONENT

• It NEVER changes, covers equal displacements in equal time periods. This means the initial horizontal velocity equals the final horizontal velocity

In other words, the horizontal velocity is CONSTANT. BUT WHY?

Gravity DOES NOT work horizontally to increase or decrease the velocity.

Page 6: PROJECTILE MOTION

VERTICAL “VELOCITY” COMPONENT

• Changes (due to gravity), does NOT cover equal displacements in equal time periods.

Both the MAGNITUDE and DIRECTION change. As the projectile moves up the MAGNITUDE DECREASES and its direction is UPWARD. As it moves down the MAGNITUDE INCREASES and the direction is DOWNWARD.

Page 7: PROJECTILE MOTION

COMBINING THE COMPONENTS

These components produce what is called a TRAJECTORY or path. This path is PARABOLIC in nature.

Component Magnitude Direction

Horizontal Constant Constant

Vertical Changes Changes

Page 8: PROJECTILE MOTION

HORIZONTALLY LAUNCHED PROJECTILES

Projectiles which have NO upward trajectory and NO initial VERTICAL velocity.

0 /oyv m s

constantox xv v

Page 9: PROJECTILE MOTION

HORIZONTALLY LAUNCHED PROJECTILESTo analyze a projectile in 2 dimensions we need 2

equations. One for the “x” direction and one for the “y” direction. And for this we use kinematic #2.

oxx v t

Remember, the velocity is CONSTANT horizontally, so that means the acceleration is ZERO!

212y gt

Remember that since the projectile is launched horizontally, the INITIAL VERTICAL VELOCITY is equal to ZERO.

Page 10: PROJECTILE MOTION

HORIZONTALLY LAUNCHED PROJECTILESExample:

A plane traveling with a horizontal velocity of 100 m/s is 500 m above the ground. At some point the pilot decides to drop some supplies to designated target below. (a) How long is the drop in the air? (b) How far away from point where it was launched will it land?

What do I know?

What I want to know?

vox=100 m/s t = ?y = 500 m x = ?voy= 0 m/s

g = -9.8 m/s/s2 2

2

1 1500 ( 9.8)2 2102.04

y gt t

t t

10.1 seconds(100)(10.1)oxx v t 1010 m

Page 11: PROJECTILE MOTION

VERTICALLY LAUNCHED PROJECTILES

Component Magnitude DirectionHorizontal Constant ConstantVertical Decreases up, 0

@ top, Increases down

Changes

Horizontal Velocity is constant

Vertical Velocity decreases on the way upward

Vertical Velocity increases on the way down,

NO Vertical Velocity at the top of the trajectory.

Page 12: PROJECTILE MOTION

VERTICALLY LAUNCHED PROJECTILES

Since the projectile was launched at a angle, the velocity MUST be broken into components!!! cos

sinox o

oy o

v vv v

vo

vox

voy

Page 13: PROJECTILE MOTION

VERTICALLY LAUNCHED PROJECTILES

There are several things you must consider when doing these types of projectiles besides using components. If it begins and ends at ground level, the “y” displacement is ZERO: y = 0

Page 14: PROJECTILE MOTION

VERTICALLY LAUNCHED PROJECTILES

You will still use kinematic #2, but YOU MUST use COMPONENTS in the equation.

cossin

ox o

oy o

v vv v

vo

vox

voy

oxx v t 212oyy v t gt

Page 15: PROJECTILE MOTION

EXAMPLE

A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees.

(a) How long is the ball in the air?(b) How far away does it land?(c) How high does it travel?

cos20cos53 12.04 /sin

20sin53 15.97 /

ox o

ox

oy o

oy

v vv m sv v

v m s

v o=20

.0 m/s

53

Page 16: PROJECTILE MOTION

EXAMPLEA place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees.

(a) How long is the ball in the air?

What I know What I want to know

vox=12.04 m/s t = ?voy=15.97 m/s x = ?y = 0 ymax=?g = - 9.8 m/s/s

2 2

2

1 0 (15.97) 4.9215.97 4.9 15.97 4.9

oyy v t gt t t

t t tt

3.26 s

Page 17: PROJECTILE MOTION

EXAMPLE

A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees.

(b) How far away does it land?

What I know What I want to know

vox=12.04 m/s t = 3.26 svoy=15.97 m/s x = ?y = 0 ymax=?g = - 9.8 m/s/s

(12.04)(3.26)oxx v t 39.24 m

Page 18: PROJECTILE MOTION

SAMPLE PROBLEM:

A place kicker kicks a football with a velocity of 20.0 m/s and at an angle of 53 degrees.

(c) How high does it travel?

CUT YOUR TIME IN HALF!

What I know What I want to know

vox=12.04 m/s t = 3.26 svoy=15.97 m/s x = 39.24 my = 0 ymax=?g = - 9.8 m/s/s

2

2

12

(15.97)(1.63) 4.9(1.63)

oyy v t gt

yy

13.01 m

Page 19: PROJECTILE MOTION

BASICS STUDENTS SHOULD KNOW

1. What is a Projectile Motion?2. What is a Projectile?3. What is aTrajectory?4. Why is Horizontal Velocity is constant all throughout in

Projectile Motion?5. Why is Vertical velocity is zero at maximum height?6. What is changing in Projectile Motion?7. What is the difference between Half Projectile Motion

and Full Projectile Motion?8. What is the difference Half-Time and Hang-Time?9. Is there an acceleration along the horizontal in

Projectile Motion?10. Is there an acceleration along the vertical in Projectile

Motion? What is it?

Page 20: PROJECTILE MOTION

HALF PROJECTILE MOTION

Page 21: PROJECTILE MOTION

FULL PROJECTILE MOTION

Page 22: PROJECTILE MOTION

PROJECTILE MOTIONHORIZONTALax = o, Vox=Vx = constantHalf projectile:R= VoxtFull Projectile:X = Xo + VoxtR = VoxT

VERTICALHalf Projectile:Voy=0Y=1/2 ag t², use ag = -9.8 m/s²Full Projectile:@max pt/ht:Vy=0, use ag = -9.8 m/s²Y = Yo + Voyt + ½ agt²

Page 23: PROJECTILE MOTION

OTHER KINEMATICS EQUATIONS TO BE USED IN PROJECTILE MOTION1. Vox = Vo cos ø2. Voy = Vo sin ø3. V = √Vx² + Vy²4. Ø = tanˉ ¹ (Voy/Vox) or Vy/Vx5. Vy² = Voy² + 2 agY6. Vy = Voy + agt

Page 24: PROJECTILE MOTION

MORE EXAMPLES

1. A slingshot is used to launch a stone horizontally from the top of a 20.0 meter cliff. The stone lands 36.o meters away.

a. At what speed was the stone launched? (17.82 m/s)

b. What is the speed and angle of impact? ( 26.64 m/s, -47.98 degrees)2. A cannon fires a cannonball 500.0m downrange when set at 45 degree angle. At what velocity does the cannonball leave the cannon? (Answer: 70.0m/s)

Page 25: PROJECTILE MOTION

EVALUATION

1. A punter in a football game kicks a ball from the goal line at 60 degrees from the horizontal at 25.0 m/s

a. What is the hang time of the punt? (Ans: 4.41 s)

b. How far downfield does the ball land? (Ans: 55.2m)

2. A skier leaves the horizontal end of a ramp with a velocity of 25.0m/s and lands 70.0 m from the base of the ramp. How high is the end of the ramp from the ground? (Answer: 38.5 m)

Page 26: PROJECTILE MOTION

ASSIGNMENT

1. What is a Momentum2. What is an Impulse3. Bring the following

a. Block of Woodb. Masking Tapec. Protractord. Ruler/Meter Stick

Page 27: PROJECTILE MOTION

QUOTE TO LIVE BY…

“Project, launch yourself and be discovered…”

- YOURS TRULY-