FS 1.16 C 4.5 KPa ψp 20 ° ψs 15 ° ψf 80 ° Φ 20 ° H 10 m b 5 m z 4 m 1 Zw 2 m 2.2 A 21.46 U 21.46 t V 2 t W 1586.49 t 1 KPa= 0,1019716212978 t/m 2 ɤw t/m 3 ɤr t/m 3 m 2
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
SIN REFUERZOFS1.16C4.5KPa1 KPa= 0,1019716212978 t/m2p20s15f8020H10mb5mz4mw1t/m3Zw2mr2.2t/m3
A21.46m2U21.46tV2tW1586.49t
CON REFUERZO-CASO GENERALFS1.16C4.5KPa1 KPa= 0,1019716212978 t/m2p20s15f8020H10mb5mz4mw1t/m3Zw2mr2.2t/m3T0tt15t+p35
A21.46m2U21.46tV2tW1586.49t
PROBLEMA DE CLASEFSERROR:#NAME?1 KPa= 0,1019716212978 t/m2DATOS DE ENTRADAC25kPagw9.8kN/m3yp35gr26kN/m3ys0z4.35myf60Zw3mf37b4mH12mDATOS DE SALIDAyT2T0tt15t+p50AERROR:#NAME?m2UERROR:#NAME?tV44.1tWERROR:#NAME?tLa Cua Es estable, no necesita del perno
Related Documents
