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Problem Set 2 Derivatives
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Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Dec 30, 2015

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Allison Willis
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Page 1: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem Set 2

Derivatives

Page 2: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 1

C(S,X,t) + B(X,t) = S + P(S,X,t)

$12 + $89 $95 + $2.50

$101 $97.50

Profit = $3.50

Page 3: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 2

C(S,X,t) + B(X,t) = S + P(S,X,t)

$11 + $42.70 $50 + $3$53.70

$53Build a Box!

$2 + $47.44 $50 + $5

$49.44$55

Page 4: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

So, what comes from building the box?

Problem 2

Initially: $55–$49.44 –$53 + $53.70= $6.26

At expiration you will pay $5 (option portion) and receive $5 (bond portion) so net zero

S5045

$45–$50 = –$5

Profit: $6.26

Page 5: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 3

C(S,X,t) + B(X,t) = S + P(S,X,t)

$14.50 + $80.75

$91.50 + $3.75

$95.25 $95.25

Use a box to borrow

$11.875 + $85.50

$91.50 + $5.875

$97.375 $97.375

Page 6: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

So, what comes from building the box?

Problem 3

S9085

Initially: $5.875 – $11.875 + $14.50 – $3.75= $4.75

$85–$90 = –$5

At expiration you will pay $5 no matter what

Borrow at T-bill rate

Page 7: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problems 4, 5, 6, 7

Page 8: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Keys for using OPT as an analytical tool

C(S,X,t) = S - B(X,t) + P(S,X,t)C(S,X,t) = S - B(X,t) + P(S,X,t)

Stock

Cal

l

B(X,t) Stock

Cal

l

B(X,t)

S C

X C

t C

C

R C

P

P

P

P

P

Page 9: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.
Page 10: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 8

New York• $10 buys a put to sell

£120 in exchange for $200 (exchange at the forward rate)

London• £5.58 buys a call to buy

$200 in exchange for £120 (exchange at the forward rate)

• Answer:$10 * .62 = £6.20, so buy the

calls in London & sell puts in New York

$1 = £0.62 spot$1 = £0.60 forward

Page 11: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 9

New York• Find equilibrium price

for a call to buy €100 in exchange for $135 (exchange at the forward rate)

• Answer:€5 * 1.32 = $6.60

Frankfurt• €5 buys a put to sell

$135 in exchange for €100 (exchange at the forward rate)

€ 1 = $1.32 spot€ 1 = $1.35 forward

Page 12: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problems for Discussion

10. Will the premium for a currency option be higher when there is greater uncertainty about the inflation differential in the two countries?

11. Explain the factors that determine the value of currency options such as the ones in problems 8 and 9.

12. Suppose a corporate treasurer complains that currency options are too expensive? Explain the advantages of currency options compared with forward contracts. Why do options command a premium?

Page 13: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

PENsSCPERS

BT

Counterpary

PEFCO

$5 mm

$5mm + Appreciat

ion

1% Coupon Fixed Undisclosed Flow

AppreciationAppreciation

Page 14: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.
Page 15: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Warm-up: Problem 2

NY

LON

ZUR

$1=£0.40

$1=CHF 1.30

£1=CHF 2.60

$1,000,000

£ 500,000

CHF 1,300,000

$1,250,000

Profit = $250,000

Page 16: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 6 (Basis too big)

$1,050,000 500,000 bu

$1,150,000 500,000 bu

Profit = $84,350.92

Moneytoday

Wheattoday

$2.00 per bushel

$2.30 per bushelWheatlater

Storage 10¢

$1,065,649.08 Moneylater

3%

Lend @ 18.45%

Page 17: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 7 (Basis too small)

$1,000,000 500,000 bu

$1,010,000 500,000 bu

Profit = $4,903.88

Moneytoday

Wheattoday

$2.00 per bushel

$2.02 per bushelWheatlater

Storage 10¢

$1,014,903.88 Moneylater

3%

Borrowing @ 2.02%

Page 18: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 9

Net for RRNB: extra 1% each year

This is includes a Floating/Floating Swap

RRNBT-Bill + 1%

CitiCorpLIBOR + 1%

CounterpartyT-Bill

LIBOR

BW Homes

T + 2%

Midland Bank

LIBOR + 1%

$10,000 per year profit!

Page 19: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 10

• Breakup Value$750,000,000 from Shug’s Restaurants

$600,000,000 from Betty’s Boutiques

$200,000,000 from airline liquidation

$1,550,000,000 Total

• Market Value of Package: $1,000,000,000

• Value of airline as going concern:$550,000,000

Page 20: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

Problem 12

C(S,X,t) + B(X,t) = S + P(S,X,t)

$10 + $89 $95 + $1.75$99

$96.75Build a Box!

$12 + $84.06 $95 + $1.25

$96.06$96.25

Page 21: Problem Set 2 Derivatives. Problem 1 C(S,X,t) + B(X,t) = S + P(S,X,t) $12 + $89$95 + $2.50 $101 $97.50 Profit = $3.50.

So, what comes from building the box?

Problem 12

S9085

Initially: $10 – $1.75– $12 + $1.25= – $2.50

$90 – $85 = $5

At expiration you will receive $5 no matter what

Double your money!