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Principles of Technology Waxahachie High School Resistance in Mechanical Systems PIC Chapter 4.1 PT TEKS
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Principles of Technology Waxahachie High School

Jan 11, 2016

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Principles of Technology Waxahachie High School. Resistance in Mechanical Systems PIC Chapter 4.1. PT TEKS. Resistance in Mechanical Systems. Objectives : State Newton’s second law of motion and use it to solve problems involving force, mass, and acceleration. - PowerPoint PPT Presentation
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Page 1: Principles of Technology Waxahachie High School

Principles of TechnologyWaxahachie High School

Principles of TechnologyWaxahachie High School

Resistancein

Mechanical Systems

PIC Chapter 4.1

Resistancein

Mechanical Systems

PIC Chapter 4.1

PT TEKS PT TEKS

Page 2: Principles of Technology Waxahachie High School

Resistance in Mechanical SystemsResistance in Mechanical Systems

Objectives:

State Newton’s second law of motion and use it to solve problems involving force, mass, and acceleration.

Calculate an object’s weight, given its mass.Explain the difference between static and kinetic friction.Use the linear model to calculate the force of friction

between two surfaces.Explain how lubrication and rolling reduce friction.

Objectives:

State Newton’s second law of motion and use it to solve problems involving force, mass, and acceleration.

Calculate an object’s weight, given its mass.Explain the difference between static and kinetic friction.Use the linear model to calculate the force of friction

between two surfaces.Explain how lubrication and rolling reduce friction.

Page 3: Principles of Technology Waxahachie High School

Newton’s 1st law - Every object will remain at rest, or will continue to move in a straight line with constant speed unless the object is acted on by a net force.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 4: Principles of Technology Waxahachie High School

A book sitting on a table is in equilibrium. The weight of the book is the force of gravity acting downward. The table pushes upward on the book with an equal and opposite force. The vector sum of the two forces is zero and it remains at rest.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 5: Principles of Technology Waxahachie High School

If you push and exert a net force in a horizontal direction from left to right the book will begin to move, or be accelerated, in the direction of the net force. If you push it with twice the force the acceleration will double, triple the force, acceleration will triple.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 6: Principles of Technology Waxahachie High School

In other words, the acceleration of the book is directly proportional to the force acting on the book.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 7: Principles of Technology Waxahachie High School

Suppose you use the same net force to accelerate more than one book. For an equal force, two books are accelerated at one-half rate of one book. Three books are accelerated at one-third the rate, and so on. The acceleration of the books is inversely proportional to the mass.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 8: Principles of Technology Waxahachie High School

The relationship between acceleration, net force, and mass is:

Newton’s 2nd law - The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the mass of the object.

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 9: Principles of Technology Waxahachie High School

Newton’s 2nd law equation =

Net force = mass x acceleration

Fnet = m x a

Units of Force = Newtons (N)

1N = (1 kg) (1 m/s2) = 1kg.m/s2

Resistance in Mechanical SystemsResistance in Mechanical Systems

Page 10: Principles of Technology Waxahachie High School

A 1200 kg race car accelerates 0 to 100 m/s in 5 seconds. What is the average force on the car?

First find the Acceleration = (vf - vi) / t

aave = (100 m/s – 0 m/s) / 5 s

aave = 100 m/s / 5 s = 20 m/s2

Fave = m x aave

Fave = 1200 kg x 20 m/s2

Fave = 24,000 kg.m/s2 or N

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Page 11: Principles of Technology Waxahachie High School

You can use Newton's second law to relate an object's weight to its mass. In this case, the acceleration is that experienced by the object in the Earth's gravitational field. We use the symbol Fg to represent gravitational force, or weight.

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Page 12: Principles of Technology Waxahachie High School

You have experienced gravitational acceleration if you have ever stepped off a diving board. While standing on the board, your weight Fg acting downward is balanced by an upward force exerted on you by the board.

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Page 13: Principles of Technology Waxahachie High School

When you step off, the upward force is removed and a net force Fg is acting downward. You accelerate in the direction of this force, toward the surface of the pool.

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Page 14: Principles of Technology Waxahachie High School

When an object is in a gravitational field and gravity is the only force acting on the object, it accelerates in the direction of the force. This acceleration is called gravitational acceleration (g).

Force of gravity = Fg

Force of gravity = mass x gravity

Fg = m x g

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Page 15: Principles of Technology Waxahachie High School

A 65 kg person stands on a scale, what is the force of gravity on the person?

Fg = m x g

g = 9.8 m/s2 (gravitational acceleration)

Fg = 65 kg x 9.8 m/s2

Fg = 637 kg.m/s2 or N

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Page 16: Principles of Technology Waxahachie High School

When you push an object across a surface, the opposing force is called friction.

To accelerate an object, the force must be greater than the frictional force.

The force of friction resists movement.

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Page 17: Principles of Technology Waxahachie High School

Friction is a result of irregularities in the surfaces of objects.

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Page 18: Principles of Technology Waxahachie High School

The force required to overcome friction is called the static friction force.

The force needed to keep a constant speed is called the kinetic friction force.

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Page 19: Principles of Technology Waxahachie High School

Imagine your car broke down and you have to push it. Which takes the most force?

To get it started rolling or to keep it rolling?

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Page 20: Principles of Technology Waxahachie High School

To get it started

Static friction is greater than kinetic friction.

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Page 21: Principles of Technology Waxahachie High School

Friction depends on 3 things:

1. The friction force depends on whether or not the surfaces are moving.

2. The friction force depends on the materials of which the surfaces are made of.

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Page 22: Principles of Technology Waxahachie High School

3. The friction force depends on how hard the surfaces are pressed together. This is called the Normal Force between the surfaces.

Friction opposes motion. In other words, the direction of the friction force is opposite the direction of the applied force.

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Page 23: Principles of Technology Waxahachie High School

The magnitude of the friction force is proportional to the normal force (N). The constant of proportionality is called the coefficient of friction (μ, the Greek letter mu).

The coefficient of static friction is μs and the coefficient of kinetic friction is μk.

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Page 24: Principles of Technology Waxahachie High School

Coefficients of Friction Equations

Static force =

Coefficient of static x Normal Force (Weight)

Fs = μs x N

Kinetic Force =

Coefficient of kinetic x Normal Force (Weight)

Fk = μk x N

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Page 25: Principles of Technology Waxahachie High School

The crate below is made of wood and weighs 85 lb. To slide the crate across a concrete floor: What force is required to get it moving? What force is required to keep the crate moving?

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Page 26: Principles of Technology Waxahachie High School

A crate made of wood weighs 85 lb is on a concrete floor. What force is required to get it moving?

Fs = μs x N

μs = .6

Fs = .6 x 85 lb = 51 lb

To get the crate moving, the applied force must exceed 51 lb.

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Page 27: Principles of Technology Waxahachie High School

The same crate is now moving, what force is needed to keep it moving at a constant speed?

Fk = μk x N

μk = .4

Fk = .4 x 85 lb = 34 lb

To keep the crate moving at a constant speed, the applied force must equal 34 lb.

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Page 28: Principles of Technology Waxahachie High School

Lubricants reduce friction by keeping the two sliding surfaces apart with a thin layer of fluid.

Friction is no longer rubbing the irregularities of the surfaces, but instead rubbing the lubricant.

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Page 29: Principles of Technology Waxahachie High School

For example, in a car engine, a piston ring and a cylinder wall do not touch each other when moving because they are lubricated with oil.

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Page 30: Principles of Technology Waxahachie High School

Another way to reduce friction is to roll an object over a surface, instead of sliding it.

This is called rolling frictional force instead of kinetic frictional force.

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Page 31: Principles of Technology Waxahachie High School

The force of rolling friction is much less than the force of sliding friction because there is less movement between surfaces.

The surfaces don’t scrape past one another as they do in sliding friction.

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