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Potential Energy Curves

Jun 04, 2018

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Kenny Fernando
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    S O F A R W E H A V E D E A L T W I T H T W O

    K I N D S O F P O T E N T I A L E N E R G Y :G R A V I T A T I O N A L ( U = M G H )

    E L A S T I C ( U = 1 / 2 K X 2)

    S O M E T I M E S I T I S M O R E H E L P F U L W H E NY O U H A V E P O T E N T I A L E N E R G Y A S A

    F U N C T I O N O F P O S I T I O N T O F I N DP O T E N T I A L E N E R G Y F I R S T A N D D E R I V E

    T H E F O R C E F R O M T H E R E .

    Potential Energy Curves

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    Force and Potential Energy

    We established last class that the relationshipbetween work and potential energy was:

    which leads toW U

    F x U

    UFx

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    Force and Potential Energy

    which leads to.

    A conservative force always acts to push the systemtoward a lower potential energy.

    dUF

    dx

    21

    2

    g

    s

    dF mgh mgdx

    dF kx kx

    dx

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    A FORCE PARALLEL TO THE X -A XIS

    ACTS ON A PARTICLE MOVING ALONGTHE X-AXIS. THE FORCE PRODUCESA POTENTIAL ENERGY: U(X) = 1 .2X 4.

    WHAT IS THE FORCE WHEN THE

    PARTICLE IS AT X=-0.8M?

    Example

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    Force and Potential Energy

    This analysis can be extended to apply to threedimensions:

    U U UF i j k

    x y x

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    A P A R T I C L E M O V I N G A L O N G T H E X - A X I S I S

    A C T E D O N B Y A C O N S E R V A T I V E F O R C E . A T AC E R T A I N P O I N T , T H E F O R C E I S Z E R O .

    W H A T D O E S T H I S T E L L Y O U A B O U T T H EV A L U E O F T H E P O T E N T I A L E N E R G Y

    F U N C T I O N A T T H I S P O I N T ?

    Check Point

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    Potential Energy Curves for a Spring

    Note: When the spring is either in a

    state of maximum extension orcompression its potential energyis also a maximum

    When the spring's displacementis DOWN the restoring force is

    UP When the potential energy

    function has a negative slope, therestoring force is positive and

    vice-versa When the restoring force is zero,

    the potential energy is zero At any point in the cycle, the total

    energy is constant:U + K = Umax= Kmax

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    Potential Energy Curve for a function

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    Points of Equilibrium

    When the force acting on the object is zero, the objectis said to be in a state of EQUILIBRIUM!

    STABLE EQUILIBRIUM located at minimums, if

    the object is displaced slightly it will tend backtothis location.

    UNSTABLE EQUILIBRIUM located at maximums,if the object is displaced slightly it will tendaway

    from this location. STATIC EQUILIBRIUM located at plateaus, where

    the net force equals zero.

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    Points of Equilibrium

    Stable Equilibriumat x3and x5.

    UnstableEquilibrium at x4.

    Static Equilibriumat x1and x6.

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    Turning Points

    Define the boundariesof the particlesmotion.

    We know that E=K+U,so where U=E, K=0Jand the particlechanges direction.

    For instance, if E=4J,there would be turning

    point at x2.

    .

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    If E = 1J, why isthe grey areareferred to as an

    energy well?

    Turning Points

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    What is the value of U(0)?

    What are the values of x1and x2?

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    How much potential energy does theparticle have at position x1?

    If the object was initially releasedfrom rest, how fast is it moving as it

    passes through position x1?

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    How much potential energy doesthe mass have at x2?

    How fast is it moving throughposition x2?

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    Which position, x1or x2, is aposition of stable equilibrium?

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    How fast is the particle movingwhen its potential energy, U(x) =0J?

    If x3= x1, then how fast is theparticle moving as it passes throughposition x

    3?

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    ExampleA particle of mass 0.5 kg obeys the

    potential energy function:

    U(x) = 2(x - 1) - (x - 2)3

    Sketch the graph of the particle's

    acceleration as a function of x.Indicate positions x1and x2onyour graph.

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    ExampleA particle of mass 0.5 kg obeys the potential energy

    function:U(x) = 2(x - 1) - (x - 2)3

    At what value of x does the particle experience itgreatest negative acceleration?

    What is the value of its potential energy at thisposition?

    How much kinetic energy does it have at thisposition?

    What force is being exerted upon it at thisposition?

    What is the value of its acceleration at thisposition?