1 SECTION I No UNDERSTANDING Total mark 1 1. runner has Inertia 2. to continue moving forward 3. the legs stop, body continue moving forward 4. Unstable and fall 4 2 1. When the ball on one end is pulled up and let to fall, it strikes the second ball which is at rest and comes to a dead stop. 2. The momentum of the ball becomes zero as its velocity is zero. 3. The Principle of Conservation of Momentum states that in a collision between two objects the total momentum of the objects in the system remains unchanged. 4. The energy and momentum from the first ball is transferred to the second ball and then transmitted through the balls at rest to the ball on the other end. 5. Because the momentum and energy is maintained in this system, the ball on the opposite side will move at the same velocity as the ball that were in initial motion [Any four] 4 3 1. The boat floats, so Weight of the boat = Weight f the water displaced = Buoyant force 2. As the weigh of the boat is the same so the weight of water displaced in the river and the sea water also the same 3. Density of sea water is higher than river water 4. Volume of water displaced in the sea is less than in the river, Level of the boat is higher in the sea than in the river 4 4 1. When the boiled water is poured onto the ping pong ball, The temperature of the air/gas will increase/ the kinetic energy increase 2. The rate of collision between molecules and wall of the ball will increase so the pressure will increase, 3. the ball will expand, so the volume will increase 4. when the volume increased, area of collision increased, so lastly the pressure will remain the same 4 5 1. When water in tube pass through the engine it can absorb large amount of heat energy 2 Once water reach the radiator, the heat of the water absorbed by the fin blade of the radiator 3 The same time the fan in the radiator push the heat out of the car. 4 Water has high specific heat capacity 4 6 1. For the fish, the light is refracted / change direction at B. 2. the light is refracted away from normal, towards the observer’s eyes 3. For the dragon-fly, the light is reflected by water surface at A. 4. Reflected angle = incidence angle, reflected towards the observer’s eyes 4 7 1. the air close to the surface is much colder than the air above it. 2. Light travels from denser to less dense medium 3. Light rays refracted away from normal line and bent downward toward the surface 4. thus tricking our eyes into thinking an object is located higher in appearance than it actually is - the observer will see the image of the ship due to light travels in a straight line 4 8 From the ray diagram [1.different medium (water/air), fish and observer 2.Light refracted away from normal 3. Extrapolation to show position of the observing image] 4. so, he should shoot the target at the lower position of the image 4
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1
SECTION I
No UNDERSTANDING Total
mark
1
1. runner has Inertia
2. to continue moving forward
3. the legs stop, body continue moving forward
4. Unstable and fall
4
2
1. When the ball on one end is pulled up and let to fall, it strikes the second ball which is at
rest and comes to a dead stop.
2. The momentum of the ball becomes zero as its velocity is zero.
3. The Principle of Conservation of Momentum states that in a collision between two objects
the total momentum of the objects in the system remains unchanged.
4. The energy and momentum from the first ball is transferred to the second ball and then
transmitted through the balls at rest to the ball on the other end.
5. Because the momentum and energy is maintained in this system, the ball on the opposite
side will move at the same velocity as the ball that were in initial motion
[Any four]
4
3
1. The boat floats, so Weight of the boat = Weight f the water displaced = Buoyant force
2. As the weigh of the boat is the same so the weight of water displaced in the river and the
sea water also the same
3. Density of sea water is higher than river water
4. Volume of water displaced in the sea is less than in the river, Level of the boat is higher in
the sea than in the river
4
4
1. When the boiled water is poured onto the ping pong ball,
The temperature of the air/gas will increase/ the kinetic energy increase
2. The rate of collision between molecules and wall of the ball will increase so the pressure
will increase,
3. the ball will expand, so the volume will increase
4. when the volume increased, area of collision increased, so lastly the pressure will remain
the same
4
5
1. When water in tube pass through the engine it can absorb large amount of heat energy
2 Once water reach the radiator, the heat of the water absorbed by the fin blade of the
radiator
3 The same time the fan in the radiator push the heat out of the car.
4 Water has high specific heat capacity
4
6
1. For the fish, the light is refracted / change direction at B.
2. the light is refracted away from normal, towards the observer’s eyes
3. For the dragon-fly, the light is reflected by water surface at A.
4. Reflected angle = incidence angle, reflected towards the observer’s eyes
4
7
1. the air close to the surface is much colder than the air above it.
2. Light travels from denser to less dense medium
3. Light rays refracted away from normal line and bent downward toward the surface
4. thus tricking our eyes into thinking an object is located higher in appearance than it
actually is - the observer will see the image of the ship due to light travels in a straight line
4
8
From the ray diagram
[1.different medium (water/air), fish and
observer
2.Light refracted away from normal
3. Extrapolation to show position of the
observing image]
4. so, he should shoot the target at the lower position of the image
4
2
No UNDERSTANDING Total
mark
9
1 - parallel ray between the condenser lens
2 - Two rays from condenser lens touching the end of the object
3 - two rays comes out from the convex lens reflected by the mirror
4 - image formed on the screen
5 - magnified, real, inverted
5
10
1. waves move from deeper to shallow area
2. the speed decreases
3. the wave refracted towards the normal line
4. the wave front which perpendicular to the direction of propagation of waves resulting the
wave front following the shape of the beach
4
11
1. waves move from deeper to shallow area
2 the speed decreases // the wave refracted towards normal line
3. the depth at cape decreases abruptly resulting waves focused at cape
4. the depth at bay decreases slowly resulting waves spread out
5. the energy of waves is smaller at bay resulting calmer region compared to at cape
4
12
1. Use ultrasound, ultrasound is transmitted to the sea bed
2. a receiver will then detect the reflected pulses
3. the time taken by the pulse to travel to the seabed and return to the receiver being
recorded, t
4. the depth of the sea can be calculated using the formula, d = vt/2
4
13
1. Wave length depends on depth of water
2. Increasing/decreasing of depth will cause the wave to refract
3. Refraction will increase/decrease the length of wavelength
4. The nodal/antinodal line will be affected
4
14
1. A parallel circuit can run several devices using the full voltage of the supply.
2. If one device fails, the others will continue running normally
3 A failure of one component does not lead to the failure of the other components.
4 More components may be added in parallel without the need for more voltage.
5. Each electrical appliance in the circuit has it own switch
6. Less effective resistance of the circuit
[any 4]
4
15
1. The lighted candle / the heat from the candle causes the air molecules to be ionized.
2. The positive charges would be attracted to the negative plate and/or the negative charges
would be attracted to the positive plate
3. The flame of the candle would be dispersed (flattened) into two parts // suitable diagram
4. Positive charges are heavier than negative charges
5. More of the flame is attracted to the negative plate //diagram
(any 4 correct)
4
3
No UNDERSTANDING Total
mark
16
[ show structure diagram of transformer]
1. An alternating current flows through primary coil
2. The soft iron core is magnetised
3. The magnetic field produced varies in magnitude and direction
4. This causes a changing magnetic flux to pass through the secondary coil
5 An induced emf across the secondary coil is produced
4
17
1. When a high current flow, the magnetic field becomes stronger
2. Electromagnet attracts the soft iron armature.
3. spring P pulls the wire and break the contact, the current does not flow // the circuit is
disconnected.
4. When reset button is pressed, spring Q pulls the soft iron armature back to its original
Position
4
18
1. Magnetic field produced by the current in the coil
2. interact with the magnetic field of the permanent magnet
3. producing the catapult field
4. produces resultant force
4
19
1. intrinsic semiconductor such as silicon atom
2. doped with pentavalent atom such as phosphorous
3. each pentavalent atom contributes one free electron and there is an excess electron
4. the excess free electrons become negative charge carrier in n-type semiconductor
4
20
1. Anode of diode (p- type) connected to positive terminal of battery/ vice versa
2. Electron from n-type drift to p-n junction towards positive terminal
3. Holes from p-type drift across p-n junction towards negative terminal
4. Movement of electrons and holes produced current, thus the bulb lights up
4
21
1. Radioactive ray enter the tube through the mica window
2. ionizes argon gas under low pressure
3. The ions accelerate towards respective electrodes
4. Produce a current pulses
5. Pulses are recorded by rate meter
[Any 4]
4
4
SECTION II
Question 1 [Force and Pressure]
Characteristics Explanation
Streamlined shape To reduce water resistance
High strength of metal To withstand high water pressure
Wide base cross section area So that ship can float//prevent from overturn // ship more stable // ship not
sink deeper
High volume of air space in the ship Increase buoyant force
Structure U
Because it has streamlined shape, high strength of metal, wide base
cross section area, high volume of air space in the ship
Question 2 [Force and Pressure]
Characteristics Explanation
Material made from glass Glass does not corrode with acid
Small diameter of stem To increase the sensitivity of the hydrometer
High density of shot Makes the hydrometer stays upright
Big diameter of bottom bulb To obtaine a bigger upthrust.
Choose N N is made from glass, has small diameter of capillary tube, high density of
shots and a big diameter of bottom bulb.
Question 3 [Force and Pressure]
Specification Explanation
With ABS To reduce jerking when it is stopped immediately / can be controlled if
direction changes/ does not move side ways
Wide tyres Better support / more stable /safer when turn
Low mass Lighter, can move faster / low inertia.
Low seat height Lower centre of gravity/ more stable
C It has ABS, wide tyres, low mass, low seat height.
Question 4 [Force and Pressure]
Specification Explanation
High specific heat capacity The rate of temperature increased caused by friction is low
High melting point Does not easily change in shape when the temperature is high
Difficult to compress Pressure will be transmitted uniformly in all directions
Use ceramic Can withstand high temperature // less dust produced
S Because it has high specific heat capacity, high melting point, difficult to be compressed and use ceramic.
5
Question 5 [Heat]
Characteristics Explanation
High boiling point It will not easily change into gas when absorb heat from the engine
Low viscosity It will not freeze during cold weather//can flow at low temperature
High specific heat capacity It can absorb a big quantity of heat with small rise in temperature
A low ability to react with metals The metal parts of the engine will not corrode easily
K is the most suitable liquid
Because of its low freezing point, high boiling point, high specific of heat capacity and low ability to react with metals
Question 6 [Light]
Specification Reason
Type of objective lens is convex lens To converge the light and produce real image
Focal length of the objective lens is
big To get higher magnification power
D < fo + fe To get virtual and magnified image
Diameter of the objective lens is
large More light can be captured , the image formed is brighter
Lens S Because lens used is convex lens, focal length of the objective lens is big,
D < fo + fe and diameter of the objective lens is large
Question 7 [Electromagnetism]
Characteristic Explanation
Low resistivity To reduce heat loss in the cables
Low density The cables will be lighter
Low rate of oxidation Not easily rust / corrode
Low rate of thermal expansion The cables will not expand under hot weather
Cable Q Low resistivity, low density, low rate of oxidation, low rate of thermal
Expansion
Question 8 [Electromagnetism/Electronic]
Characteristic Reason
Low density of the coil Lighter / less mass
High frequency of rotation The rate of change of magnetic field is higher, more current induced
Use 4 diodes Full wave rectification to get a d.c.
Has capasitor in the circuit To smooth the direct current obtained
Circuit I Because it has low density coil, high frequency of rotation, consist 4
diodes and has capasitor in the circuit.
6
Question 9 [Electronic]
Characteristics Explanation
The valency of the intrinsic
semiconductor is 4 When it is doped, the conductivity of the semiconductor increase
The valency of the doping substance
are 3 or 5
Valency of 3 is used to produce hole as majority charge carrier (P type)
and valency of 5 is used to produce electron as majority charge carrier (N
type)
Size of the atom of the doping
substance is almost same as the
size of the substance
Can maintain the crystalline structure of the substance/ Give good effect
in the doping process
Substance T
Because the valency of the intrinsic semiconductor is 4, The valency of
the doping substance are 3 or 5 and the size of the doping substance is
almost the same as the size of the substance
Type of pure semiconductor is Silicon
Because it has greater power handling (its not easy to get overheated)
Question 10 [Radioactivity]
Properties Reason
Type of radiation is gamma Has high penetrating power
Long half-life Long lasting
Solid Easy to handle
Low ionizing power Does not ionize healthy cells / does not cause cell mutation
K Because it radiates gamma ray, the half-life is long, the state of matter is
solid and it has low ionizing power
7
SECTION III - CONCEPTUALIZATION
Question Answer Mark
1
(a) 1.17 cm , 1.173 cm 2
(b) (i) The reading in Diagram 1.1 is less accurate than the reading in Diagram 1.2 1
(ii) The smallest scale in Diagram 1.1 is larger than the smallest scale in Diagram 1.2 1
(iii) The smaller the smallest scale of an instrument, the more accurate the measurement 1
(iv) The smaller the smallest scale of an instrument, the more sensitive the instrument 1
(v) The higher the sensitivity the instrument, the more accurate of the measurement 1
TOTAL 7
Question Answer Mark
2
(a)(i) F1 = F2, F3 = F4 1
(ii) The direction of the two forces involved in both diagrams are opposite to each other 1
(iii) For any action, there is a reaction
which has the same magnitude but acts in the opposite direction.
1
1
(iv) Newton third Law of Motion 1
TOTAL 5
Question Answer Mark
3
(a) (i) The total mass of the lorry and the load in Q is larger than in P 1
(ii) The difficulties in stopping the lorry Q is more than lorry P 1
(b)
When the mass of the lorry and the load is larger, the more difficult to stop it.
The difficulties in stopping the lorry is due to the inertia which tend to maintain the
state of motion.
When the mass of the object larger, the inertia is greater.
1
1
1
TOTAL 7
Question Answer Mark
4
(a)(i) Density of salt solution is higher than density of water 1
(ii) The portion of the block immersed in salt solution is less than in water 1
(iii) Buoyant force acted in both liquid are same 1
(b)
Factors affect the buoyant force in diagram 4 are density and volume of liquid displaced
For the same buoyant force, when the density of the liquid is higher, the volume of liquid
displaced is less
1
1
(c) Archimedes’ Principle 1
TOTAL 6
Question Answer Mark
5
(a) Temperature is the measurement of the average kinetic energy of the molecules in an
object / system
1
(b)(i)
(ii)
(iii)
Temperature of trap air in diagram 5.2 is higher than in diagram 5.1
Pressure of trap air in diagram 5.2 is higher than in diagram 5.1
Volume of trap air in diagram 5.2 and 5.1 are equal
1
1
1
(c) When the temperature of the air increase, the volume is also increase 1
(d) Pressure Law 1
TOTAL 6
8
Question Answer Mark
6
(a)(i) Real image is the image that can form on the screen. 1
(ii) The object distance is longer than the focal length to form real image 1
(iii) Object distance in Diagram 6.1 is shorter than that in Diagram 6.2
Image distance in Diagram 6.1 is longer than that in Diagram 6.2
Size of image in Diagram in 6.1 is larger than that in Diagram 6.2
When the object distance is longer, the image distance is shorter
When the image distance is shorter, the size of image is smaller
1
1
1
1
1
TOTAL 7
Question Answer Mark
7
(a)(i)
(ii)
(b)
In diagram 7.1, light propagates from low density medium to high density medium
In diagram 7.2, light propagates from high density medium to low density medium
In diagram 7.1 direction of light travel towards normal but in diagram 7.2 direction of
light is away from normal
When light travels from low density medium to high density medium, light bends towards
normal and when light travels from high density medium to low density medium, it will
bend away from normal
1
1
1
1
1
(b) Refraction of light 1
TOTAL 6
Question Answer Mark
8
(a)(i)
In diagram 8.1, density of layer of air close to ground is lower than density of layer of air
at upper part. In diagram 8.2, density of layer of air close to ground is higher than layer
of air upper part.
1
(ii) Direction of propagation of sound waves in diagram 8.1 is away from the earth (upward)
but in diagram 8.2 it propagates toward the earth (downward) 1
(iii) The loudness of sound that can be heard in diagram 8.2 is greater than that in Diagram
8.1 1
(b)
If the density of air close to the ground is higher than the air at the upper part, the
direction of propagation of the sound is directed towards the ground,
therefore the sound can be heard louder / vice versa
1
TOTAL 4
9
Question Answer Mark
10
(a) Negative 1
(b)(i)
(ii)
(iii)
In Diagram 10.1, there is no electric field while in diagram 10.2, the electric field exist
between the plates
The voltage of EHT between two plates in diagram 10.2 (a) is smaller than that in
Diagram 10.2 (b)
The angle of deflection of the cathode ray in diagram 10.2 (a) is smaller than that in
Diagram 10.2 (b)
1
1
1
(c) (i)
(ii)
When the voltage between EHT is higher, the strength of electric field is stronger
The stronger the electric field, the bigger the deflection of the cathode ray.
1
1
TOTAL 6
SECTION IV – PROBLEM SOLVING (QUALITATIVE)
QUESTION 1
Characteristics Explanation
The valency of the intrinsic
semiconductor is 4 When it is doped, the conductivity of the semiconductor increase
The valency of the doping substance
are 3 or 5
Valency of 3 is used to produce hole as majority charge carrier (P type)
and valency of 5 is used to produce electron as majority charge carrier (N
type)
Size of the atom of the doping
substance is almost same as the
size of the substance
Can maintain the crystalline structure of the substance/ Give good effect
in the doping process
Substance T
Because the valency of the intrinsic semiconductor is 4, The valency of
the doping substance are 3 or 5 and the size of the doping substance is
almost the same as the size of the substance
QUESTION 2
No Answer Mark
7(a)(i)
(ii)
(b)
c
(d)(i)
(ii)
Interference
Constructive interference
λ = 340
2000
= 0.17 m
Increase
f α 1/f and x α λ // x α 1/f
speaker
to convert and produce wave which has same frequency and amplitude
destructive interference
1
1
1
1
1
1
1
1
1
1 +
10
QUESTION 3
suggestion reason
Thin fuse has high resistance
low specificheat capacity It take shorter time to heat up/ to reach melting point /blow the fuse
Ceramic catridge Can withstand higher temperature
Fuse rating 13 A Normal current of device is 2400/240 = 10 A. Maximum rating must be
higher than normal current
Melting point must be low Easy to melt (blow faster)
QUESTION 4
suggestion reason
Attach one fuse to the live wire in the consumer unit/ fuse box.
To break /switch off the circuit when large current before the wire become hotter and produce fire.
Using the insulating wires // thicker wires
To prevent short circuit // To reduce resistance, improve efficiency
Attach switch for each lamp To allows each lamp to be switched on and off independently
Connect the metal fitting lamp to the earth wire/cable
To flows electron (extra) to earth to avoid lethal shock
Using only 240 V light bulb. To ensure the bulbs light up with normal brightness
QUESTION 5
suggestion reason
Handle made from insulator The rate of heat flow to the handle is less, does not easily heated
The body is made from low density
material Reduce mass, iighter
Coiled wire for the filament Can fit longer wire inside, more heat is released
Material for heating filament is
nichrome High melting point
Connection to earth // fuse Flow the excess /overload current to earth if there is a short circuit / blown
when it is excess of current flow
QUESTION 6
suggestion reason
Soft spring Give a greater sensitivity/ can detect small changes
Small density Small mass / ligh
Curve in shape of the magnet Radial magnetic field, create uniform strength of magnetic field around the
coil
Low resistance material of the coil To reduce energy loss
Place the seismometer in direct
contact with the earth to convert very small motions of the earth into electrical signals
11
QUESTION 7
suggestion reason
use thin diaphragm Easy to vibrate
Use strong material Not easy to break
More number of turns of coil Increase the rate of change of magnetic flux linkage // The magnitude of
the induced current or is also increased
Thicker diameter of wire of coil reduce the resistance of the coil
Using more powerful magnet to
increase the strength of the
magnetic field
Increase the rate of change of magnetic flux linkage //The magnitude of
the induced current or induced electromotive force is also increased
QUESTION 8
suggestion reason
OR gate The gate's output is ON if either one sensor is ON
One of the input X is connected to
+6 V
To supply an ON signal to gate X, so the current flow into the base of the
transistor
Place the resistor in base circuit To limit the current flow in the base circuit, The current amplification of the
transistor is higher
Use buzzer in the collector circuit It converts the electrical signal into sound energy
Relay switch To switch on the buzzer which is use a greater voltage
12
SECTION V – PROBLEM SOLVING (QUANTITATIVE)
QUESTION ANSWER MARK
1
(a)
a =
=
= -2 m s
-2
2
(b) s = ½ (0+4) x 2 = 4 m
2
2
(a)
m1u1+ m2u2= m1v1 + m2v2 (0.05)(0.8) + (0.03)(0) = 0 + (0.03) v2 v2 = 1.33 m s
-1
2
(b) m1v1 - m2u2 = 0 – (0.05)(0.8) = -0.04 kg m s
-1
2
(c) Impulsive force = -0.04 / 0.05 = 0.8 N
1
3
1 mark for correct parallelogram lines (measurement & angle). 1 mark for correct diagonal line. 1 mark for direction of the resultant force. 1 mark for magnitude with correct unit : 13.8cm X 2.5 = 34.5N
4
4
(a)
=
B = 375 N
2
(b) 2 x 21 = B x 15 B = 2.8 cm
2
5
(a)
P = F / A F = 400 x 50 F = 20000 N
2
(b)
Resultant Force = 20 000 – 900(10) = 11000 N Direction of force : upwards
3
6 (a)
Mass = density x volume Mass = 0.169 kg m
-3 x 1.2 m
3 = 0.20 kg
2
13
QUESTION ANSWER MARK
(b)
m = 1.3 kg m-3
x 1.2 m3 =1.56kg
Weight of displaced air = bouyant force = mg = 1.56 x 10 = 15.6 N
3
7
(a) V = 0.2 x 0.8 = 0.16 m
3
2
(b) B = Vρg = 0.16 x 1000 x 10 = 1600 N
2
(c) mass = 1600 ÷ 10 = 160 kg
1
8
=
x 100
= 35 oC = 308 K
4
9
(a)
Q = Pt = 48 x 5 x 60 // 14 400 J
Q = m c 14 400 = 500 x 10
-3 ( c ) ( 80 – 40 )
c = 720 J kg-1 o
C-1
(with unit )
3
(b)
Heat supplied by liquid = Heat received by water
( 500 x 10-3
)(720)(80 - ) = (1) ( 4200)( - 25 )
= 29.34 oC (with unit)
2
10
= 90o – 30
o
= 60o
1.33 = o40sin
sin
= 58.75o
4
11
(a)
1 = 1 + 1 f u v 1 = 1 – 1 v 5 400 v = 5.063 cm
2
(b)
h2 = v2 h1 v1 h2 = 5.063 100 400 h2 = 1.27 cm
2
12
I =
= 0.83 A R = V
2
P = 240
2 = 288 Ω
200
4
13
(a) 10A or 13 A
1
(b)
V = IR = 9 x 26.7 = 240.3 V P = IV = 9 x 240.3 = 2162.7 W
4
14
QUESTION ANSWER MARK
14
(a) 2 = I(1 +5) I = 0.33 A
2
(b)
R = ( 1/5 + 1/12)-1
= 3.53 Ω 2 = I( 1 + 3.53) I = 0.44 A
3
15
(a) 12 V
1
(b)
Np = Vp Ns Vs Np = 240 x 200 12 = 4000
2
(c)
Efficiency = Po x 100 Pi = 240 x 0.2 x 100 48 = 100 %
2
16
(a) I = 24/12 = 2A (with unit)
(b)
Efficiency = Output power x 100 % Input power Input power = 24 x 100 40 = 60W
17
v = 3.75 x 107
m s-1
3
18
(a)
The bulb not light up
3
(b)
R1 = 5500
2
19
(a)
+
1
(b) 3 alpha particles 2 beta particles
2
(c) t = 33.5 /6.7 = 5 T1/2 32 → 16 → 8 → 4 → 2 → 1 g
2
20 (a) M = (230.0331) - (226.0254 + 4.0026) = 0.0051 u = 0.0051 x l.66 x 10
-27 kg = 8.466 x 10
-30 kg
2
VQ = 500 = 0.48 V
12 12000 + 500
1 = 500
12 R1 + 500
15
QUESTION ANSWER MARK
(b)
E = mc 2
= 8.466 x 10-30
x (3 X 10 8
) 2
= 7.619 x 10-13
J
2
21
(a)
E = mc2
2.9 x 10 -11
= m x (3.0 x 108)2
m = 3.22 x 10-28
kg
2
(b)
Power obtained P = E/t = 2.9 x 10
-11 /1.5 x 10
-3
= 1.93 x 10-8
W
2
SECTION VI – PAPER 3
QUESTION 1
NO MARKING CRITERIA MARK REMARK
a
i Height, h 1
ii Acceleration, a 1
iii The frequency of the ticker timer, f 1
b
Calculate the acceleration, a
2
h = 20.0 cm a = 9.0/0.1 – 7.8/0.1 0.1
= 120 cms-2
h = 30.0 cm a = 9.8/0.1 – 7.4/0.1 0.1
= 240 cms-2
h = 40.0 cm a = 10.2/0.1 – 6.6/0.1 0.1
= 360 cms-2
h = 50.0 cm a = 11.0/0.1 – 6.2/0.1 0.1
= 480 cms-2
h = 60.0 cm a = 11.4/0.1 – 5.4/0.1 0.1
= 600 cms-2
Note: 1. All 5 values correct – 2 marks 2. 3 or 4 values correct – 1 mark
16
NO MARKING CRITERIA MARK REMARK
Height, h (cm)
Initial velocity, u (cm s
-1)
Final velocity, v (cm s
-1)
Acceleration, a (cm s
-2)
20.0 78.0 90.0 120.0
30.0 74.0 98.0 240.0
40.0 66.0 102.0 360.0
50.0 62.0 110.0 480.0
60.0 54.0 114.0 600.0
Give a tick () based on the following:
A a table which has h, u, v and a
B state name, symbol and correct unit for each column
C All values of h are correct
D All values of u are correct
E All values of v are correct
F All the values are consistent in 1 d.p or 2 d.p.
Marks awarded : Number of Marks
6 4
4 – 5 3
2 – 3 2
1 1
4
17
NO MARKING CRITERIA MARK REMARK
c
Give a tick () based on the following:
A Title of the graph
B a at the y-axis, h at the x-axis
C Name, symbol and unit for a
D Name, symbol and unit for h
E Uniform scale at both axis
F 5 points plotted correctly
[Note : 4 points plotted correctly : ]
G Straight line of best fit is drawn
H Size of the graph is ≥ ¾ size of the graph paper
Marks awarded : Number of Marks
9 6
8 5
6 - 7 4
4 - 5 3
2 - 3 2
1 1
6
d a increases linearly with h 1
e Avoid parallax error by making sure eyes are perpendicular to the scale of metre rule when measuring the height.
1
TOTAL 16
18
QUESTION 2
NO MARKING CRITERIA MARK REMARK
a T2 is directly proportional to m 1
b i
Draw line from m = 25 g to the given line and from the given line to the T2- axis