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Perfect Score Physic f4-Answer

Apr 05, 2018

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Hulwan Mukhlis
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    ANSWER SCHEME

    TOPIC : INTRODUCTION TO PHYSICS

    SKILL 1 : KNOWLEDGE

    What is meant by Statement

    1. Physical quantity Physical characteristic that can be measured

    2. Base quantities Quantities that cannot be defined in terms of other base quantities

    3. Derived QuantitiesQuantities that obtained by combining base quantities by

    multiplication, division or both these operations

    4. Scalar quantities Quantities that have magnitude but no direction

    5. Vector quantities Quantities that have both magnitude and direction

    6. Accuracy How close the measurement made is to the actual value

    5. Sensitivity Ability to detect a small change in the quantity to be measured

    6. ConsistencyHow little deviation there is among the measurements made when a

    quantity is measured several times

    7. Zero error Error due to the pointer does not return to zero when not in use

    SKILL 2 : UNDERSTANDING

    Question 1

    Accuracy is the ability of the instrument to give readings close to the actual value.

    The value determined is accurate if it is near to the actual value

    The consistency of a measuring instrument is the ability of instrument to record consistent readings for

    each measurement with little deviation among readings.

    The measurement is consistent if the values determined are close to each other.

    Question 2

    (a) To transfer heat faster from surroundings to the mercury

    (b) mercury does not vaporize/ conducts heat well/ does not wet the sides of the tube/ thread

    opaque

    Question 3

    (i) No

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    SKILL 5 : PROBLEM SOLVING QUANTITATIVE

    Question 1

    (i) volume = 15cm x 20cm x 30 cm

    = 9000 cm3

    [2 marks]

    = 9.0 x 103 cm3

    (ii) volume = 9.0 x 103 cm3

    = 9.0 x 10-3

    m3. [2 marks]

    (iii) Density = mass / volume

    = 15 kg / 9.0 x 10-3 m3

    = 1.67 x 103 kg m-3 [2 marks]

    Question 2

    (i) Thickness = 0.06 mm

    = 0.06 x 10-3 m [1 mark]

    (ii) Area = 20 cm x 10 cm

    = 20 cm2

    = 20 x 10-4 m2 [3marks]

    SKILL 6 : DECISION MAKING

    Question 1.

    Characteristic Reason

    Small range of measurement The estimate measurement is within a few mm only

    Small division on scale Can give accurate reading

    High sensitivity Can detect small change in measurement

    No parallax error To obtain more accurate reading

    Decision : M It has small range of measurement, small division

    on scale, high sensitivity, and no parallax error

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    Question 2

    - The length of the rope is approximately same as the length needed

    so that the length is not too long or too short.

    - The density of the rope has to be smallto make it light

    - The snapping force is larger

    to ensure that the rope is not easily break.

    - The diameter of the rope must smallerOccupy a smaller space

    - The best choice is K because the length is approximately the same as

    needed, low density, snapping force is bigger than the load and

    Smaller diameter

    2

    2

    2

    2

    2

    TOPIC 2 : FORCE AND MOTION

    SKILL 1 : KNOWLEDGE

    TOPIC : Force and Motion

    What is meant by Statement

    1. Linear motion Motion along a straight line

    2. Scalar quantity A physical quantity which has only magnitude

    3. Vector quantity A physical quantity which has both magnitude and direction

    4. Velocity The rate of change of displacement

    5. Speed The rate of change of distance

    6. Acceleration The rate of change of velocity

    7. Distance The total length of the path travelled

    8. Displacement Displacement is the shortest distance from one point to anotherpoint along a specific direction

    9. Inertia The tendency of an object to resist change to its state of rest or

    motion.

    10.Newtons First law An object will remain at rest or motion with uniform velocityalong a straight line unless it is acted upon by an external

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    What is meant by Statement

    force.

    11.Newtons Second law The net force on an object is proportional to the rate of changein momentum.

    12.Newtons Third law To every action there is an equal and opposite reaction.13.Momentum The product of mass and velocity of an object

    14.Principle ofconservation of

    momentum

    The total momentum of a system is constant if no external

    forces act on the system.

    15.Force A push or a pull that can change the size, shape or velocity ofan object.

    16. Impulse Change of momentum.

    17. Impulsive force A large force that acts for a short period of time during acollision or explosion

    18.Weight The force of gravity which is exerted on it by earth.

    19.Mass The amount of matter in the object.

    20.Free fall Free fall occurs when an object falling under the force ofgravity only without being affected by any other external

    forces.

    .21.Work The product of force and the displacement along the direction

    of the force

    22.Energy The capacity to do work.

    23.Gravitational field The region in which an object experiences a force due togravitational attraction.

    24.Potential energy The Potential Energy of an object is the energy stored in theobject because of itsposition orstate.

    25.Elastic potential energy The energy of an object when it is stretched or compressed

    26.Kinetic energy The energy of an object due to its motion

    27.The principle ofconservation of energy

    Energy cannot be created or destroyed. It can be transformed

    from one form to another, but the total energy in a closed

    system is constant.

    Power The rate at which work is done or energy is transferred.

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    What is meant by Statement

    28.Elasticity The property of an object that enables it to return to its originalshape and dimensions (size) after an applied external force is

    removed.

    29.Hookes law The extension of a spring is directly proportional to thestretching force provided the elastic limit is not exceeded.

    30.Elastic limit The elastic limit of a spring is the maximum stretching forcewhich can be applied to the spring before it ceases to be

    elastic.

    31.Force constant (springconstant)

    The force constant of a spring is the force per unit extension.

    SKILL 2 : UNDERSTANDING

    No Answers Mark

    1

    When the boy jumps onto the river bank, his momentum is forward. 1Using the Principle of conservation of momentum, 1

    the total momentum before and after jumping is equal. 1

    The boat moves backward to balance the forward momentum. 1

    2

    - Fuel burns in the combustion chamber

    - Hot gases expelled at high speed backwards

    - A large backwards momentum is produced

    - In accordance to the principle of conservation of momentum, The rocket

    gains forwards momentum of equal magnitude

    1

    1

    1

    1

    3 - There are two types of force- Attraction and repulsive force between the particles of the solid.

    - When the solid is stretched, the molecules displaced away from each other

    - Attractive forces are acting to oppose the stretching

    - When the solid is compressed, the molecules displaced closer to each other

    - Repulsive forces are acting to oppose the compression

    1

    1

    1

    1

    1

    4 - The inertia of lorry and load is very big when it is moving

    - The separate compartments make the load divided into smaller mass, thusreducing the ineatia of each unit.- The momentum of lorry and load is very big when it is moving and

    produce abigger impulsive force.

    - The steel structure will prevent the loads from smashing into the driverscompartment during emergency braking.

    1

    1

    1

    1

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    SKILL 5 : PROBLEM SOLVING QUANTITATIVE

    QUESTION ANSWER MARK

    1

    (i)Distance = 20 x 5

    = 100 m2

    (ii) 500 N 2

    (iii)a = F / m = -500

    800= -25 ms

    -2

    2

    2

    (a)The spring constant = gradient of the graphFor P , spring constant = 8 / 0.5 = 16 N cm

    -1

    For Q , spring constant = 3 / 0.5 = 6 Ncm-1

    3

    (b) Elastic potential energy = x 8 x 0.5 x 10-2

    =0.02 J

    2

    3 (i)

    Elastic potential energy 1

    (ii) x

    Fk ,

    4

    6.3k

    k= 0.9 N cm-1

    1

    (iii)E = Fx

    = x 3.6 x 4/100= 0.072 J

    2

    (iv) 9.0

    5x

    l = 12 5.56 = 6.44 cm

    2

    4

    i

    72 kmh-1 = 3600

    100072x

    = 20 ms-1

    Impulse = mvmu= 0 (800 x 20)= 16000 Ns Ans + unit

    1

    1

    1

    ii.

    Impulsive force = 2.0

    16000

    = 80000 N

    11

    5

    (a)

    (b)

    (d)

    (e)

    500N

    (i) 200 sin 300 N (ii) 200 cos 300 N

    (i) 200 cos 300 = 173.2N

    (ii) 173.2N = 50 aa = 3.464 m s-2

    500 + 200sin 300

    = 600 N

    Because the total force acting perpendicular to the floor is smaller.

    1

    1 + 1

    1

    1

    1

    1

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    QUESTION ANSWER MARK

    6

    (a)

    (b)

    (c)

    (i) 400 N(ii) 40 N

    In situation (i)

    the longer the time of impact, the bigger the impulsive force.

    1

    1

    1

    1

    SKILL 6 : DECISION MAKING

    QUESTION

    NO.ANSWER

    MA

    RK

    1

    (i)

    Q is chosen because it has the highest spring constant, it is made of steel and has

    the most number of coiled spring.

    Characteristics Explanation

    High spring constant Stiffer, more potential energy stored and

    converted to kinetic energy. The kinetic energy

    provided pushes the competitors higher up in

    the air.

    Steel frame Stronger, can support the competitor

    More coiled springs Allows for higher bounces and morecomplicated stunts.

    2

    2

    2

    2

    (ii)1. Jump harder/ push harder

    2. To increase reactive force/ to store more energy

    1

    1

    Total 10

    2

    Characteristic Reasons

    Density of the material must be small To make the landing pad lighter /

    easier to carry

    Elasticity must be high Lengthen the time of impact to reduce

    the impulsive force

    Thickness must be thick Better absorb the impact // to reduce

    the impulsive force

    Air absorption must be high Release and absorb the air easily

    - the most suitable material is R

    Because its density is low, elasticity is high, it is thick and high absorption of air

    1 + 1

    1 + 1

    1 + 1

    1 + 1

    1

    1

    3

    suitability Reason

    smalldiameter

    enough space for the spring to beinstalled

    High elastic

    limit can support motorcylist up to 100kg

    1

    1

    1

    1

    1

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    higher spring

    constant small compression of the spring

    small natural

    frequency

    to reduce bumping

    D , because has a small diameter , highest elastic limit ,highest spring constant and

    small natural frequency

    1

    1

    1

    1

    1

    4 (a)

    (b)

    (c)

    5N

    (i) T1 = 4.16N(ii) T2 = 3.13 N

    Picture in figure (a) because, the tension of the string is higher

    1

    22

    2

    Miscellaneous

    1 F2 = 10 cos 30oN= 10 (0.866) N= 8.66 N

    2

    3 The trolleys move off separately in opposite directions.

    F

    x

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    SKILL 6 : DECISION MAKING

    1

    Characteristics Reason

    Streamlined shape To reduce water resistance

    High strength of metal To withstand high water pressure

    Wide base cross section

    area

    So that ship can float//prevent from

    overturn // ship more stable // shipnot sink deeper

    High volume of air spacein the ship

    Produce air buoyant force// ship canfloat

    Structure P Streamlined shape, High strength of

    metal, Wide base cross section area,

    High volume of air space in the ship

    TOPIC : HEAT

    SKILL 1 : KNOWLEDGE

    What is meant by Statement

    1. HeatHeat is a form of energy

    2. Temperature Temperature is the degree.of hotness of a body

    3. Thermal

    equilibrium

    Thermal equilibrium is reach when the net rate of heat transfer between the

    two bodies is zero and its reach the same temperature.

    4. Specific heat

    Capacity , c

    Specific heat capacity is defined as the amount of heat required to increase

    the temperature of a mass of 1 kg by 1 C or 1 K.

    c = Q , SI unit for c = J kg-1 C-1

    m

    5. Specific latent

    Heat of fusion

    Specific latent heat of fusion is defined as the quantity of heat energy

    required to change 1 kg of a substance from the solid state to the liquid state,

    without a change in temperature

    Lf= Q , SI unit for L= J kg-1

    m

    6. Specific latent

    heat of

    vaporization

    Specific latent heat of vaporization is defined as the quantity of heat energy

    required to change 1 kg of a substance from the liquid state to the gaseous

    state, without change in temperature

    Lw= Q , SI unit for L= J kg-1

    m

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    7. Boyles LawBoyles Law states that for a fixed mass, at constant temperature, thepressure of gas is inversely proportional to its volume.

    8.Charles LawCharles Law states that for a fixed mass at constant presure, the volume ofgas is directly proportional to its absolute temperature.

    9. Pressure Law Pressure Law states that for a fixed mass at constant volume, the pressure ofgas is directly proportional to its absolute temperature. .

    SKILL 2 : UNDERSTANDING

    No Answers Mark

    1

    Thermometer is placed in the mouth of patient, 1

    Heat is transferred from patients body to the thermometer 1

    Thermal equilibrium between the thermometer and patients body is reached whenthe net rate of heat transfer is zero.

    1

    The thermometer reading shows the temperature of the patients body. 1

    No Answers Mark

    2

    During the day,the land and the sea receive the same amount of heat from the sun.

    1

    Water has a higher specific capacity than the land 1

    The land is heated to a higher temperature than the sea/The density of the air above

    the sea is higher than the density of the air above the land.

    1

    The air above the land flows up and the air above the sea flows towards the land. 1

    SKILL 3 : CONCEPTUALIZATION

    QUESTION ANSWER MARK

    1

    (a)

    1. Air molecules are in continuous random motion.

    2. Air molecules collide with the wall of the glass tube and

    bounces back.

    3. This result in change in momentum and a force is exerted on the

    wall.

    4. Force per unit area is the pressure of the air.

    4

    (b) i Length of trapped air in condition Q is higher than in condition P. 1

    ii Volume of trapped air in condition Q is higher than in condition P 1

    iii Pressure in condition P is bigger than that in condition Q. 1

    (c) i Length of trapped air is directly proportional to the volume of trapped air. 1

    ii The volume of trapped air is inversely proportional with pressure 1

    (d) Boyles law. 1

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    QUESTION ANSWER MARK

    2

    (a)i The quantity of heat in water and cooking oil is equal 1

    Ii The temperature of the water is lower than the temperature of the cooking oil 1

    (b) i Specific heat capacity 1

    iiThe higher the specific heat capacity of a material,the rate of increase of

    temperature slower.

    1

    SKILL 4 : PROBLEM SOLVING QUALITATIVE

    QUESTION

    1

    (i)

    Lower fixed point

    The thermometer is placed in pure melting ice

    When the mercury level is steady, its position in glass stem of

    the thermometer is marked as 0oC .

    Upper fixed point

    The thermometer is placed in a container that is surrounded by steam of boilingwater at ordinary atmospheric pressureWhen the mercury level is steady, its position on the glass stem of the thermometer

    is marked as 100oC .

    The distance on the stem of the thermometer between 0oC and 100

    oC is measured,

    then divided equally into 100 parts. (Each part represents 1oC)

    1

    1

    1

    1

    1

    1

    (ii)

    L - Lo x 100oC

    L100 - Lo

    = 10.0 - 2.5 x 100 oC

    13.82.5

    = 66.37oC

    1

    1

    1

    2

    (i)Heat is absorbed by the metal block

    1

    (ii)

    The rate of heat flows between metal block and the water is the same.

    The water and the metal block achieve thermal equilibrium.

    1

    1

    (iii)

    mwater x cwater x water = mmetal blockx cmetal blockx metal blockcmetal block= 0.1 x 4200 x (48-28)

    0.5 x (48-28)

    = 840 J kg-1

    C-1

    1

    1

    QUESTION

    NO.

    ANSWERMA

    RK

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    3

    (i)

    Modifications Reason

    thermometer is made from

    transparent glass that is strong

    so that it is not easily broken

    the thermometric liquid chosen ismercury

    because it easily expandsuniformly

    the capillary tube is made narrowand thin

    so that it is more sensitive

    the shape of the thermometer is

    round

    so that it has a magnifying effect

    the thermometer is placed in

    melting ice to obtain the lower

    point

    the thermometer is placed in

    steam from boiling water to

    obtain the upper point

    2

    2

    2

    2

    2

    Total 10

    SKILL 5 : PROBLEM SOLVINGQUANTITATIVE

    QUESTIO

    NANSWER

    MAR

    K

    1

    (i)P = Patm + Pwater

    = 10 + 0.5

    = 10.5 m water

    1

    (ii)

    P1V1 = P2V2V

    1=

    P

    2V

    2P1= 10.5 x 0.5

    10

    = 0.525 cm3

    1

    1

    2

    (a)

    L =m

    Pt

    = 0.1 x 103

    x 156

    0.05

    = 312000 J kg-1

    1

    1

    (b)

    t = 72 s (from graph)

    c = Pt

    m = 0.1 x 10 3 x 72

    0.05 x 140

    = 1028.57 J kg-1

    C

    1

    1

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    QUESTIO

    NANSWER

    MAR

    K

    1

    SKILL 6 : DECISION MAKING

    QUESTIO

    N

    NO.

    ANSWERMA

    RK

    1

    (i)

    K is the most suitable liquid

    Because of its low freezing point, high boiling point, high specific of heat capacity

    and low ability to react with metals

    Characteristics Explanation

    High boiling point It will not boil easily when absorbing heat

    from the engine

    Low freezing point It will not freeze during cold weather//can flow

    at low temperature

    High specific heat

    capacity

    It can transfer a big quantity of heat with small

    rise in temperature

    A low ability to react

    with metals

    The metal parts of the engine will not corrode

    easily

    2

    2

    2

    2

    1

    1

    Total 10

    QUESTIO

    N

    NO.

    ANSWERMA

    RK

    2 (i) R ischosen

    because

    Low

    specific heat capacity of ice cream box, Smaller size of ice cream box, Plastic PVC,

    Bright color of outer box

    Characteristics Explanation

    Low specific heat capacity

    of ice cream box

    Easy get cold // becomes cool quickly

    Smaller size of ice cream

    box

    Easier to carry // easy too become cool

    Plastic PVC Poor conductor of heatBright colour of outer box Does not absorb heat from surrounding

    quickly

    2

    2

    2

    2

    1

    1

    Total 10

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    Miscellaneous

    1 Rate of change of momentum of the molecules increases

    2

    3 Aluminium contains more heat energy than Copper

    p

    1