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Pembahasan Mtk UN 2013 Paket 01

Jun 03, 2018

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  • 8/11/2019 Pembahasan Mtk UN 2013 Paket 01

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    SMPN 3 KALIBAGOR

    Alfa Kristanti1

    PAKET 1

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    SMPN 3 KALIBAGOR

    Alfa Kristanti2

  • 8/11/2019 Pembahasan Mtk UN 2013 Paket 01

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    SMPN 3 KALIBAGOR

    Alfa Kristanti3

    23 + 43 =1

    23+

    1

    43=

    1

    8+

    1

    64=

    8

    64+

    1

    64=

    9

    64

    Pelangi Matematika Viandre

    Al4-kristanty.blogspot.com

    28 3 = 28 3 = 224 = 24 6 = 226 = 46

    41

    4+ 6

    2

    3 2 1

    2= 4

    1

    4+

    20

    3 5

    2= 4

    1

    4+

    20

    3

    2

    5

    = 4

    1

    4 +

    8

    3 =

    17

    4 +

    8

    3 =

    51

    12 +

    32

    12

    =83

    12= 6

    11

    12

    Selisih =5 35 + 3

    64.000 =2

    8 64.000= 16.000

    Bunga 9 bln =9

    12 12% = 9%

    Tabungan setelah 9 bln = 100% T + 9% T = 109% T

    109% T = 3.815.000T =3.815.000

    109%=

    3.815.000

    109

    100

    = 3.815.000 100

    109

    = 3.500.000

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    SMPN 3 KALIBAGOR

    Alfa Kristanti4

    b = 5252 =

    31193

    = 123

    = 4

    U2= a + b19 = a + 4a = 194a = 15

    Sn=

    2( 2a + (n1)b )

    S24=24

    2( 2(15) + (241) 4 ) = 12 (30 + (23)4 ) = 12 (30 + 92)

    = 12 (122) = 1.4.64

    a = U1= 7

    b = U2U1= 157 = 8

    Un = a + (n1)b

    U50= 7 + (501)8 = 7 + (49) 8 = 7 + 392 = 399

    r = 21=

    3

    9=

    1

    3

    a = U1= 9

    Un= a rn1

    = 9 13

    1

    = 32 311

    Un= 32 3+ 1= 32 + 1= 33

    5x5 1 + 2x

    5x2x 1 + 53x 6

    x 2

    I. 4x 9 = (2x) 3 = (2x+ 3)(2x3)II. 2x

    2+x3 = (2x+ 3)(x1)

    III. x2+x6 = (x+ 3)(x2)

    IV. x2+ 4x5 = (x+ 5)(x1)

    m =

    212 1

    =2 1

    23=

    35

    yy1= m (xx1)

    y1 =35

    (x(3))

    y1 =35

    (x+ 3)

    5(y1) =3(x+ 3)

    5y5 =3x9

    5y + 3x =9 + 5

    3x + 5y =4

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    SMPN 3 KALIBAGOR

    Alfa Kristanti5

    ax+ by + c = 0a = 2 ; b = 4

    m = =

    24 =

    1

    2

    Jumlah bilangan terbesar dan terkecil

    =2

    3jml ketiga bilangan

    =2

    396 = 64

    M = { 3, 5, 7 }N = { 4, 6, 8 }

    M N = { 3, 4, 5, 6, 7, 8 }

    g(2) = 7

    2q + r = 7

    g(5) = 7

    5q + r = 7

    2q + r = 7

    5q + r = 7

    7q = 14q = 2

    2q + r = 7

    2(2) + r = 7

    4 + r =

    7r = 7 + 4

    r = 3

    g(4) = 2(4) + (3)

    = 8 3

    = 11

    Misal :Harga gunting = p

    Harga spidol = q

    2p + 3q = 18.000 5 10p + 15q = 90.000

    3p + 5q = 29.000 3 9p + 15q = 87.000

    p = 3.000

    10 10

    1010

    6 6A

    B

    C

    D

    E

    S = 4

    =40

    4= 10

    DE = 2 2 = 102 62 = 100 36 = 64 = 8BD = 2 DE = 2 8 = 16

    Lbelahketupat ABCD=1

    2 d1 d2=

    1

    2 AC BD = =

    1

    2 12 16 = 96

    2p + 3q = 18.0002(3000) + 3q = 18.000

    6.000 + 3q = 18.0003q = 12.000q = 4.000

    4p + 2q = 4(3000)+2(4000)= 12.000 + 8.000= 20.000

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    SMPN 3 KALIBAGOR

    Alfa Kristanti6

    Pada gambar di samping:ABC PQR makaAB = PQ, BC = PR,

    AC = QRQ

    P

    R65

    o

    80o

    A

    B

    C65o

    80o

    Q

    28

    16

    8

    P RM

    L

    K

    12 6

    21

    =

    12

    16=

    3

    4 ,

    =

    21

    28=

    3

    4 ,

    =

    6

    8=

    3

    4

    KL =4 27 + 2 12

    4 + 2

    =108 + 24

    6=

    132

    6= 22

    L daerah tdk diarsir = LKLMN+ LPQRS2 Ldaerah diarsir

    = 16 12 + 822 40= 192 + 6480

    = 176

    Banyak lampu = =

    4 30

    6= 20

    DE

    F

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    SMPN 3 KALIBAGOR

    Alfa Kristanti7

    (6x+ 4) + (5x+ 9) = 90

    11x+ 13 = 9011x= 901311x= 77

    x= 7 PenyikuAOC = COB = 5x + 9 = 5(7) + 9 = 35 + 9 = 44

    Sudut keliling menghdpbusur yg sama maka

    ABE = ACE =ADE

    ABE =96

    3= 32

    AOE = 2 ABE= 2 32

    = 64

    = 676 100 = 576 = 24luar = 262 13 32 = 676 102

    LORS=

    =75

    105 21

    = 15

    Panjang rusuk balok = 4 (p + l + t) = 4 (30 + 12 + 18)= 4 (60) = 240 cm

    Kawat untuk kerangka 2 balok = 2 240 = 480 cm

    Sisa kawat = 5 m480 cm = 500 cm480 cm = 20 cm

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    SMPN 3 KALIBAGOR

    Alfa Kristanti8

    BC = 4

    =72

    4= 18

    t

    9

    15t = 152 92 = 225 81t = 144 = 12

    Vlimas=1

    3La t =

    1

    3 18

    2 12 = 324 4 = 1.296

    dbola= rusuk kubusdbola= 12, maka :

    r =12

    2= 6

    Vbola=4

    3 r

    3=

    4

    3 6

    3=

    4

    3 216

    = 4 72 = 288

    Ldinding= 2 (pt + lt) = 2(6 5 + 10 5)= 2(30 + 50) = 2(80) = 160

    Biaya = 160 Rp 40.000,- = Rp 6.400.000,-

    s2+ s

    2= 4

    2

    2 s2= 16

    s2= 8

    s = 8 = 4 2 = 22

    4 s

    s

    Lkubus= 6 s2

    = 6 222= 6 8

    = 48

    d = 14r = 7

    Ltabung= 2r (r + t) = 2 22

    7 7 (7 + 34)

    = 44 (41) = 1.804

    Siswa dgn nilai 72 = 4028 = 12 anakJml nilai siswa = 28 80 + 12 72 = 2.240 + 864 = 3.104

    Rata-rata nilai = =

    3.104

    40= 77,6

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    SMPN 3 KALIBAGOR

    Alfa Kristanti9

    Data 5 6 7 8 9frekuensi 2 3 2 4 1

    Modus

    32 30

    Jumlah hasil panen 2010 dan 2011 = 3 + 4 = 7

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    SMPN 3 KALIBAGOR

    Alfa Kristanti10

    n(S) = 2 2 2 = 82 angka 1 gambar = AAG, AGA, GAA

    P (2 angka 1 gambar) =3

    8

    6

    5 5

    22

    4

    3 3

    Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30Kelereng merah = 6

    P ( 1 merah) =6

    30 100 % = 20 %