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Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose. Date : 05-12-2010 Duration : 3 Hours Max. Marks : 258 PAPER - 1 PART TEST-4 (PT-4) TARGET : IIT-JEE 2011 INSTRUCTIONS A. General : 1. This Question Paper contains 63 questions. 2. The question paper CODE is printed on the right hand top corner on this sheet of this booklet. 3. No additional sheets will be provided for rough work. 4. Blank paper, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgets in any form are not allowed. 5. The answer sheet, a machine-gradable Objective Response Sheet (ORS), is provided separately. 6. Do not Tamper / mutilate the ORS or this booklet. 7. Do not break the seals of the question-paper booklet before instructed to do so by the invigilators. 8. Write your Name, Roll No. and Sign in the space provide on the back page of this booklet. B. Filling the bottom-half of the ORS : 9. The ORS has CODE printed on its lower and upper Parts. 10. Make sure the CODE on the ORS is the same as that on this booklet. If the Codes do not match, ask for a change of the Booklet. 11. Write your Roll No., Name and Name of centre and sig with pen in appropriate boxes. Do not write these anywhere else. 12. Darken the appropriate bubbles below your registration number with HB Pencil. 13. Fill the test cities code in ORS Sheet and for details of cities code see last page this test paper booklet. C. Question paper format and Marking scheme : 14. The question paper consists of 3 parts (Chemistry, Mathematics & Physics). Each part consists of five Sections. 15. For each question in SectionI , you will be awarded 3 marks if you darken the bubble corresponding to the correct answer and zero marks if no bubble is darkened. There is no negative marking for incorrect answer(s) for this this section. 16. For each question in SectionII , you will be awarded 4 marks if you darken the bubble(s) corresponding to the correct choice(s) for the answer and zero mark if no bubbled is darkened. There is no negative marking for incorrect answer(s) for this this section. 17. For each question in SectionIII, you will be awarded 3 marks if you darken the bubble corresponding to the correct answer, and zero mark if no bubble is darkened. In case of bubbling of incorrect answer. There is no negative marking for incorrect answer(s) for this this section. 18. For each question in SectionIV, you will be awarded 3 marks for each row in which you have darkened the bubble(s) corresponding to the correct answer. Thus, each question in this section carries a maximum of 12 marks. There is no negative marking for incorrect answer(s) for this this section. 19. For each question in SectionV, you will be awarded 3 marks if you darken the bubble corresponding to the correct answer, and zero mark if no bubble is darkened. There is no negative marking for incorrect answer(s) for this this section. DO NOT BREAK THE SEALS WITHOUT BEING INSTRUCTED TO DO SO BY THE INVIGILATOR CODE 0 CLASS-XII/XIII COURSE : ALL INDIA TEST SERIES (VIKALP)
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Page 1: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

Date : 05-12-2010 Duration : 3 Hours Max. Marks : 258

PAPER - 1

PART TEST-4 (PT-4)TARGET : IIT-JEE 2011

INSTRUCTIONSA. General :

1. This Question Paper contains 63 questions.

2. The question paper CODE is printed on the right hand top corner on this sheet of this booklet.

3. No additional sheets will be provided for rough work.

4. Blank paper, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgets

in any form are not allowed.

5. The answer sheet, a machine-gradable Objective Response Sheet (ORS), is provided separately.

6. Do not Tamper / mutilate the ORS or this booklet.

7. Do not break the seals of the question-paper booklet before instructed to do so by the invigilators.

8. Write your Name, Roll No. and Sign in the space provide on the back page of this booklet.

B. Filling the bottom-half of the ORS :

9. The ORS has CODE printed on its lower and upper Parts.

10. Make sure the CODE on the ORS is the same as that on this booklet. If the Codes do not match, ask for a

change of the Booklet.

11. Write your Roll No., Name and Name of centre and sig with pen in appropriate boxes. Do not write these

anywhere else.

12. Darken the appropriate bubbles below your registration number with HB Pencil.

13. Fill the test cities code in ORS Sheet and for details of cities code see last page this test paper booklet.

C. Question paper format and Marking scheme :

14. The question paper consists of 3 parts (Chemistry, Mathematics & Physics). Each part consists of five Sections.

15. For each question in Section�I , you will be awarded 3 marks if you darken the bubble corresponding to the

correct answer and zero marks if no bubble is darkened. There is no negative marking for incorrect

answer(s) for this this section.

16. For each question in Section�II , you will be awarded 4 marks if you darken the bubble(s) corresponding

to the correct choice(s) for the answer and zero mark if no bubbled is darkened. There is no negative

marking for incorrect answer(s) for this this section.

17. For each question in Section�III, you will be awarded 3 marks if you darken the bubble corresponding to

the correct answer, and zero mark if no bubble is darkened. In case of bubbling of incorrect answer. There

is no negative marking for incorrect answer(s) for this this section.

18. For each question in Section�IV, you will be awarded 3 marks for each row in which you have darkened the

bubble(s) corresponding to the correct answer. Thus, each question in this section carries a maximum of

12 marks. There is no negative marking for incorrect answer(s) for this this section.

19. For each question in Section�V, you will be awarded 3 marks if you darken the bubble corresponding to the

correct answer, and zero mark if no bubble is darkened. There is no negative marking for incorrect

answer(s) for this this section.

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INV

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CODE

0CLASS-XII/XIII COURSE : ALL INDIA TEST SERIES (VIKALP)

Page 2: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-1

PART-I

Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,

Al = 27, Si = 28, P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5,

Zn = 65, As = 75, Br = 80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207]

SECTION - I

Straight Objective TypeThis section contains 10 multiple choice questions. Each question has choices (A), (B), (C) and (D),

out of which ONLY ONE is correct.

1. What volume of 2 10�4 M Ba(OH)2 must be added to 300 mL of a 1 10�4 M HCl solution to get a solution

in which the molarity of hydronium (H3O+) ions is 5 10�11 M ?

(A) 375 mL (B) 300 mL (C) 225 mL (D) 450 mL

2. X ml of H2 gas effuses through a hole in a container in 5 sec. The time taken for the effusion of the same

volume of the gas specified below under identical conditions is

(A) 10 sec. He (B) 20 sec. O2 (C) 25 sec. CO2 (D) 55 sec. CO2

3. An ideal gas obeying kinetic gas equation can be liquified if .

(A) It temperature is more than critical temperature

(B) It's pressure is more than critical pressure

(C) It's pressure is more than critical pressure but its temperature is less than critical temperature.

(D) It can not be liquified at any value of P & T.

4. For a real gas with very large value of molar volume, which of the following equation can most suitably be

applied ?

(A) Z = 1 � RTVa

m(B) PV

m = RT (C) Z = 1 +

RTPb

(D) PVm � RT =

mVa

Page 3: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-2

5. A chloride dissolves appreciably in cold water. When placed on a platinum wire in Bunsen flame, no distinctive

colour is noticed. The cation of chloride is :

(A) Pb2+ (B) Ba2+ (C) Mg2+ (D) Ca2+

6. Wilkinson's catalyst [Rh Cl(PPh3)

3] react with H

2 to form an octahedral complex in which Rh(Z = 45) has the

following electronic configuration in the ligand field 2,2,2g2t , e

g0,0

Then which of the following is correct about this new complex.

(A) Complex is paramagnetic.

(B) Its IUPAC name is chloridodihydridotris(triphenylphosphine)rhodium().

(C) The oxidation state of central metal ion in complex is +2.

(D) Hybridisation of central metal ion is sp3d2.

7. When cold NaOH reacts with Cl2, which of the following is formed ?

(A) NaClO (B) NaClO2

(C) NaClO3

(D) None

8. /NaOH P ; the major product 'P' is :

(A) (B) (C) (D)

Page 4: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-3

9. MgBrCH3 (A)

(A) (B) (C) (D)

10.

Above compound contains four functional group the rate of reaction with RMg-X will be :

(A) I > III > III > IV (B) I > II > III > IV (C) IV > I > II > III (D) I > IV > III > II

SECTION - II

Multiple Correct Answers TypeThis section contains 5 multiple correct answer(s) type questions. Each question has 4 choices (A),

(B), (C) and (D), out of which ONE OR MORE is/are correct.

Page 5: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-4

11. Which of the following statements is/are correct ?

(A) Ozone reacts with dry KOH forming a deep red coloured compound and liberating oxygen gas at low

temperature.

(B) KO2 is better oxidant than K

2O

2 both in aqueous and acidic medium.

(C) KOH is better absorber of CO2 than NaOH.

(D) Quick lime on heating with carbon in an electric furnace forms CaCO3.

12. 0.56 gm CaO lime is dissolved in 100 ml water and made a saturated solution. (Kw = 10�13). The correct

statements are

(A) Concentration of OH� in solution is 0.2 M

(B) Concentration H+ ion would be 5 10�13

(C) Solution is basic because pH > 6.5.

(D) At 25ºC Kw = 10�14, so in above problem for K

w = 10�13 temperature should be less than 25ºC.

13. Choose correct option(s)

(A) If vanderWaal's constants of two gases 'A' and 'B' are a1, b

1 and a

2, b

2 respectively such that a

1 = a

2 but

b1 > b

2, then gas B possess higher compressibility than that of A under similar conditions.

(B) No gas can be liquefied above its critical temperature.

(C) Critical temperature of methane is greater than that of ammonia.

(D) The intercept of the plot dP

Vs P for any gas at constant temperature is M

RT.

[P � pressure, d� density of gas, T � temp in kelvin, M � molar mass of gas].

Page 6: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-5

14. In the following reaction sequence, product I, J and L are formed. K represents a reagent.

Hex-3-ynal I J L

(A) The product I is .

(B) The structure of compound J is .

(C) The structure of product L is .

(D) The reagent K is thionyl chloride.

15. CH2 = CH � Br

OH)iii(X)ii(

ether/Mg)i(

3

Y 4LiAlH Z

Zn,OH/O)ii(

HBr)i(

23

Final Products

3OCBa*

+ H2SO4 X + H2O + BaSO4.

(A) The product Z is . (B) The final products are only..

(C) The product Y is . (D) X is CO2.

SECTION - IIITrue & False Statement Type

This Section Contains 2 questions. Each question contains 3 or 4 statements S1, S

2, S

3 or S

4. Each

statement is either true (T) or false (F). Each question has 4 choices (A), (B), (C) and (D) each of whichcontains whether S

1, S

2, S

3 or S

4 are true or false. Exactly one choice contains the correct order of

truthness or falseness of S1, S

2, S

3 or S

4 respectively and is the correct choice.

Page 7: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-6

16. S1 : The heats of hydration of the dipositive alkaline earth metal ions decrease with an increase in their ionic size.

S2 : The low solubility of LiF is due to its high lattice energy whereas low solubility of CsI is due to smaller

hydration energy .

S3 : Stability of peroxides and superoxides of alkali metals increases with increase in size of the cation.

(A) T T T (B) T F F (C) T T F (D) F T F

17. Select the true/false statements.

S1 : The rate of catalytic hydrogenation of 2�butyne is greater than trans�2�butene.

S2 : The rate of reduction of CH2= O is slower than (CH

3)

2C=O by LiAlH

4.

S3 : The aqueous solution of CH3MgBr is used for SN2 reaction with primary alkyl halides.

S4 : is reduced to by using Zn(Hg)/HCl on heating.

(A) F F F F (B) T F T F (C) T F F F (D) T F T T

SECTION - IV

Matrix - Match TypeThis section contains 2 questions. Each question contains statements given in two

columns, which have to be matched. The statements in Column-I are labelled

A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any

given statement in Column-I can have correct matching with ONE OR MORE

statement(s) in Column-II. The appropriate bubbles corresponding to the answers

to these questions have to be darkened as illustrated in the following example.

If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening of

bubbles will look like the following :

Page 8: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-7

18. Column�I Column�II(A) [Cu(NO

2)6]4� (p) Outer orbital complex

(B) [Ni(NH3)

6] 2+ (q) Inner orbital complex.

(C) K2[Cr(CN)

4(NH

3)NO] (n = 1) (r) 'Spin only' magnetic moment = 1.73 B.M

(D) K4[Co(NO

2)6] (s) Central metal oxidation state + 2

(t) During hybridisation d-orbital electron(s) jump(s)

to higher energy orbital (s).

'n' represents number of unpaired electrons.

19. Match the column-I and II.Column-I Column-II(Reaction) (Type of reaction)

(A) (p) SN1

(B)

KOH.Alc

(q) SN2

(C) 4SO2H

(r) E1

(D)

/OHHC

OH

52

2 (s) E2

(t) Stereospecific

Page 9: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

RESONANCE

(SPACE FOR ROUGH WORK)

P1R051210C0-8

SECTION - V

Integer Answer Type

This section contains 2 questions. The answer to each of the questions is

a single digit integer, ranging from 0 to 9. The appropriate bubble below the

respective question number in the ORS have to be darkened.

20. How many total number of isomers are formed (including geometrical and optical) by octahedral complex

[Rh(en)2(NO

2)Cl]+ ?

21. If root mean square speed of CH4 at 48 K is same as the most probable speed of H

2 at T K, then T is.

Page 10: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-9

PART- II

SECTION - IStraight Objective Type

This section contains 10 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for itsanswer, out of which ONLY ONE is correct.

22. For any matrix A of order 3 × 3, if A (adj A) =

500

050

005

, then |A| is equal to

(A) 125 (B) 5 (C) 0 (D) 25

23. If b,a

are two unit vectors such that cbaa

, where |c|

= 2, then value of cba

is :

(A) 0 (B) ± 1 (C) �3 (D) 3

24. The shortest distance of a point

225

,0 from the curve y = x2 is

(A) 29

(B) 27

(C) 2

25(D)

25

25. If |x|

|2x|log)x(f k (where 0 < k < 1) and

}x{

xnn2xxlog)x(g 2

21

x , then common

domain of f(x) and g(x) is

(A)

�3,

2

3(B)

5,

2

3(C)

5,

2

3(D)

3,

2

3

(SPACE FOR ROUGH WORK)

Page 11: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-10

(SPACE FOR ROUGH WORK)

26. The set of all possible values of x for which 1 + x n (x + 1x2 ) 2x1 is given by

(A) (� 0] (B) [0, 1] (C) [0, ) (D) R

27. In a regular tetrahedron let be the angle between any edge and a face not containing the edge. If cos2 = ba

where a, b + , a and b are coprime, then the value of 10a + b is(A) 41 (B) 21 (C) 23 (D) 13

28. Number of integral value(s) of for which vectors k�xj�i�x2 , k�j�2i�)1( and k�j�i� , in the order,,

form right handed system x R, is(A) 0 (B) 2 (C) 4 (D) 6

29. A new tetrahedron is formed by joining the centriods of the faces of a given tetrahedron. The ratio of thevolume of given tetrahedron to that of new tetrahedron is(A) 3 (B) 9 (C) 27 (D) 81

Page 12: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-11

(SPACE FOR ROUGH WORK)

30. If A is an involutory matrix of order 2 × 2 ; B =

10

21 and C = ABA, then (C)2009 =

(A) A

10

220091 AA (B) A

10

220091 AA

(C) A

20090

21 AA (D) A

20090

220091 AA

31. If (u, v) are the co-ordinates of the point of local minimum on the curve x3 = y (x � 4)2, then uv is equalto.(A) 275 (B) 250 (C) 325 (D) 324

SECTION - II

Multiple Correct Answer Type

This section contains 5 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its

answer, out of which ONE OR MORE is/are correct.

32. A line passes through a point A with position vector k��j�i�3 and is parallel to the vector k�2�j�i�2 . If P is

a point on this line such that AP = 15 units, then the position vector of the point P is/are

(A) k�11�j�6i�13 (B) k�9j�4�i�13 (C) k�9j�4�i�7� (D) k�11j�6i�7�

Page 13: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-12

(SPACE FOR ROUGH WORK)

33. If the edges of a rectangular parallelopiped are 3, 2, 1, then angle between a pair of diagonals may be

(A) cos�1 76

(B) cos�1 73

(C) cos�1

72

� (D) cos�1

76

34. g(x) = f(x2) + f(1 � x2) and f(x) < 0 for 0 x 1, then

(A) g(x) decreases in

2

1,0 (B) g(x) increases in

2

1,0

(C) g(x) decreases in

1,

2

1(D) g(x) increases in

1,

2

1

35. The function y = f(x) is defined as x = 2t � |t| , y = t2 + t | t |, t R. If for x 0, f(x) is intersected by anothercurve y2 = 32x, the angle between the two curves at the point of intersection is

(A) 2

(B) tan�1 4

17(C) tan�1

174

(D) tan�1 176

36. If the matrix A =

cba

cba

cb20

is an orthogonal matrix. Then which of the following option(s) is/are

correct?

(A) b = ± 6

1(B) c = ±

3

1(C) a = ±

2

1(D) a = ± 2

Page 14: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-13

(SPACE FOR ROUGH WORK)

SECTION - IIITrue & False Statement Type

This Section Contains 2 questions. Each questions contains 3 or 4 statements S1, S

2, S

3 or S

4. Each

statement is either true (T) or false (F). Each questions has 4 choices (A), (B), (C) and (D) each ofwhich contains whether S

1, S

2, S

3 or S

4 are true or false. Exactly one choice contains the correct order

of truthness or falseness of S1, S

2, S

3 or S

4 respectively and is the correct choice.

37. Consider the following statements :A,B,P,Q are square matrices of order 3 × 3.

S1 : If |P| = |Q| = 1 and adj B = A then adj(Q�1BP�1) = PAQ.S2 : If A and P are skew symmetric matrices then PAP is symmetric matrix.S3 : If |Q| = 1 and adjA = B and |adj(Q�1A)| = k|B| then k = 1.State, in order, whether S

1, S

2, S

3 are true or false

(A) T F T (B) F T F (C) T T F (D) F T T

38. Consider the following statements :S1 : e

is smaller than e.S2 : Number of solutions of the equation sin�1x + 2x = 3 is one.S3 : If f(x) is increasing with concavity upwards, then concavity of f �1(x) is also upwards.State, in order, whether S

1, S

2, S

3 are true or false

(A) F F T (B) F T F (C) T T F (D) T FT

SECTION - IV

Matrix - Match TypeThis section contains 2 questions. Each question contains statements given in two

columns, which have to be matched. The statements in Column-I are labelled

A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any

given statement in Column-I can have correct matching with ONE OR MORE

statement(s) in Column-II. The appropriate bubbles corresponding to the answers

to these questions have to be drakened as illustrated in the following example.

If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening of

bubbles will look like the following :

Page 15: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-14

(SPACE FOR ROUGH WORK)

39. Column � I Column � II

(A) Let A and B are square matrices of order 3 × 3, (p) 2which satisfy AB = A and BA = B.If (A � B)5 = k (A � B), then k =

(B) If A =

aba

bab2

2

, a 0, b 0 and AAn =

00

00, n N, (q) 7

then the least value of n is equal to

(C) The distance of the point (1, 0, �3) from the plane x � y � z = 9 (r) 4

measured parallel to the line 2

2x =

32y

= 66z

is

(D) If A = 31

y2x

212

221

is orthogonal matrix, then the value (s) 3

of �x � y is

(t) 0

Page 16: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-15

(SPACE FOR ROUGH WORK)

40. Column � Column �

(A) If x2 + y2 = 1, then minimum value of x + y is (p) � 3

(B) If a local maximum value of y = a cos x � 31

cos 3x occurs (q) 0

when x = 6

, then the value of 'a' is

(C) If f(x) = x � 2 sin x, 0 x 2 is increasing in the interval (r) 3[a, b], then a + b is

(D) If equation of the tangent to the curve y = � e�x/2 where it (s) 2

crosses the y-axis is px

+ qy

= 1, then p � q is

(t) � 2

Page 17: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(SPACE FOR ROUGH WORK)

RESONANCE P1R051210C0-16

(SPACE FOR ROUGH WORK)

SECTION - VInteger Answer Type

This section contains 2 questions. The answer to each of the questions isa single digit integer, ranging from 0 to 9. The appropriate bubble below therespective question number in the ORS have to be darkened.

41. Let f(x) = 2x1

x

, then find the total number of points of inflection on the curve y = f(x).

42. A particle moves along the parabola y = x2 in the first quadrant in such a way that its x-coordinate (measuredin meters) increases at a rate of 10m/sec. If the angle of inclination of the line joining the particle to theorigin changes, when x = 3m, at the rate of k rad/sec., then find the value of k.

Page 18: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

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RESONANCE P1R051210C0 - 17

PART - III

SECTION - IStraight Objective Type

This section contains 10 multiple choice questions. Each question has choices (A), (B), (C) and (D),

out of which ONLY ONE is correct.

43. For a prism kept in air it is found that for an angle of incidence 'i', A = e = , where notations have their

usual meaning. If the refractive index of the prism is 3 then the value 'i' is :(A) 60º (B) 45º (C) 30º (D) 90º

44. Charges 2Q and �Q are placed as shown in figure. The potential at a point

at a finite distance where electric field is zero, will be :(A) positive (B) negative(C) zero (D) Not defined if the potential at the infinity to be taken as zero

45. A non�conducting uniformly charged thin spherical shell having potential of 10 volts at its surface is cut

into two equal parts then the electric potential at the edge of the hemisphere in the absence of theother part is :(A) 5 volt (B) 10 volt (C) zero volt (D) between 5 v and 10 v

46. For the given graphs (a) and (b) find the value of electric field at point(1m,2m) :

(A) j�i�2 V/m (B) j�2i� V/m (C) j�2i�2 V/m (D) j�2i� V/m

(SPACE FOR ROUGH WORK)

Page 19: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

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RESONANCE P1R051210C0 - 18

47. Figure (i) shows an imaginary cube of edge length L. A uniformly charged rod of length 2L movestowards left at a small but constant speed v. At t = 0, the left end of the rod just touches the centre ofthe face of the cube opposite to it. Which of the graphs shown in fig.(ii) represents the flux of theelectric field through the cube as the rod goes through it ?

(i) (ii)

b d a

c

time

Flux

(A) a (B) b (C) c (D) d

48. A positively charged body 'A' has been brought near a neutral brass sphere Bmounted on a glass stand as shown in the figure. The potential only due toinduced charged at the centre of the brass sphere will be :

(A) Zero (B) Negative

(C) Positive (D) Infinite

49. A point charge q = 1C is brought from infinity (slowly so that heat developed inthe shell is negligible) and is placed at the centre of a conducting neutralspherical shell of inner radius a = 1m and outer radius b = 2m, then work doneby external agent is:

(A) 0 (B) 41

× 10�3 J

(C) 49

× 10�3 J (D) �49

× 10�3 J

50. A body starts from rest at a point, distance R0 from the centre of the earth of mass M, radius R. The

velocity acquired by the body when it reaches the surface of the earth will be (R0 > R)

(A) GM

0R1

R1

(B) 2 GM

0R1

R1

(C)

0R1

R1

GM2 (D) 2GM

0R1

R1

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Page 20: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

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RESONANCE P1R051210C0 - 19

51. A spherical hollow cavity is made in a lead sphere of radius R, such thatits surface touches the outside surface of the lead sphere and passesthrough its centre. The mass (uniformly distributed) of the sphere beforehollowing was M. A particle of mass � m �, which lies at a distance d from

the centre of the lead sphere on the straight line connecting the centres ofthe spheres and that of the hollow, if d = 2R then find the interactiongravitational potential energy of the particle and hollowed sphere :

R

d

m

(A) R 12

GMm7 (B)

R 12GMm5

(C) R 2

GMm (D)

R 3GMm7

52. If internal resistance of a cell is constant. Then the best representation of terminal potential differenceof a cell with current drawn from cell will be:

(A) (B) (C) (D)

SECTION - IIMultiple Correct Answers Type

This section contains 5 multiple correct answer(s) type questions. Each question has 4 choices (A),(B), (C) and (D), out of which ONE OR MORE is/are correct.

(SPACE FOR ROUGH WORK)

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RESONANCE P1R051210C0 - 20

53. A uniform disc of mass m and radius R is rotating freely about a fixed vertical axis passing through itscentre with angular velocity . A particle of same mass m and having velocity 2

R towards centre of

the disc collides with the disc moving horizontally and sticks to its rim.(A) The angular velocity of the disc will become /3.(B) The angular momentum of the disc about the fixed axis of rotation will remain conserved becauseforce due to particle on the disc is passing through fixed axis of disc

(C) Magnitude of change in momentum of the particle is 37

3m R just after collision

(D) The change in momentum of the particle and change in momentum of system is same

54. Two point charges a & b, whose magnitudes are same are positioned at acertain distance from each other with a at origin. Graph is drawn betweenmagnitude of electric field strength at points between a & b and distancex from a. From the graph, it can be decided that : (A) a is positive, b is negative (B) a and b both are positive(C) a and b both are negative (D) a is negative, b is positive

55. The net charge given to a solid insulating sphere:(A) must be distributed uniformly in its volume(B) may be distributed uniformly in its volume(C) must be distributed uniformly on its surface(D) the distribution will depend upon whether other charges are present or not.

56. A negatively charged drop of mass 1.6 × 10�15 gm is allowed to fall. Due to air resistance force it attains aconstant velocity. Then if a uniform electric field is to be applied vertically to make the oil drop ascend upwith the same constant speed, which of the following are correct. (g = 10 ms-2) (Assume that the magnitudeof resistance force is same in both the cases)(A) The electric field is directed upward(B) The electric field is directed downward(C) Electrostatic force on the oil drop is 3.2 × 10�17 N(D) Electrostatic force on the oil drop is 1.6 × 10�17 N

Page 22: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

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RESONANCE P1R051210C0 - 21

57. Which of the following statements are correct about a planet rotating around the sun in an elliptic orbit.(The gravitation force due to other objects on this planet is to be neglected) :(A) its mechanical energy is constant(B) its angular momentum about the sun is constant(C) its areal velocity about the sun is constant(D) If the mass of planet is doubled for the same orbit then areal velocity will be halved

SECTION - IIITrue & False Statement Type

This Section Contains 2 questions. Each question contains 3 or 4 statements S1, S

2, S

3 or S

4. Each

statement is either true (T) or false (F). Each question has 4 choices (A), (B), (C) and (D) each of whichcontains whether S

1, S

2, S

3 or S

4 are true or false. Exactly one choice contains the correct order of

truthness or falseness of S1, S

2, S

3 or S

4 respectively and is the correct choice.

58. S1 : There are two point charges q1 and q2 kept at a separation such that q1 + q2 is not equal to zerothen there exist only one point there at a finite distance from them where there resultant electric fieldbe zero electric field will be zero for the given system except infinity.

S2: For the given system as shown in the figure net electric force onthe dipole due to point charge is parallel to dipole moment but the nettorque about the point charge is zero.

S3: For a planet moving along the shown elliptical. orbit the time taken by it forthe right half ABC will be equal to time taken by it for left half CDA.

(A) F T F (B) T T F

(C) F T T (D) T T T

Page 23: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

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RESONANCE P1R051210C0 - 22

59. S1 : For a given resistor current will always be greater for a cell of emf 6v then cell of emf 3v.

S2: The direction of electric current in a conducting wire will always be from higher potential to lowerpotential.

S3 : For the shown circuit potentiometer, the potential difference in portion 'AC' will be equal to potentialdifference across the cell 1 (having internal resistance r) even when null deflection is not obtained.

(A) T F T (B) F F F (C) T T F (D) F T T

SECTION - IV

Matrix - Match TypeThis section contains 2 questions. Each question contains statements given in twocolumns, which have to be matched. The statements in Column-I are labelledA, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Anygiven statement in Column-I can have correct matching with ONE OR MOREstatement(s) in Column-II. The appropriate bubbles corresponding to the answersto these questions have to be darkened as illustrated in the following example.If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening ofbubbles will look like the following :

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RESONANCE P1R051210C0 - 23

60. In each situation of column�I, two short electric dipoles having dipole moments 1p

and 2p

of same magnitude

(that is |p| 1

= |p| 2

) are placed on the axis symmetrically about the origin in different orientations asshown. In column�II, certain inferences are drawn for these two electric dipoles. Then, match the different

orientations of dipoles in column�I with the corresponding results in column�II.

Column�I Column�II

(A) (p) The torque on one dipole due to other dipole is zero about its

centre of mass

(B) (q) The potential energy of one dipole in electric field of the other

dipole is negative

(C) (r) There is one straight line in x�y plane (not at infinity) which is

equipotential.

(D) (s) Electric field at origin is zero.

(t) Electric potential at origin is zero.

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RESONANCE P1R051210C0 - 24

61. To create uniform electric field, two infinitely large plates are usedhaving uniform surface charge density as shown in the figure. Particlesin column- are projected horizontally from the middle with same kineticenergy. Neglect force acting between the particle and also neglectgravity. Match the column.

Column- Column-

(A) -particle (p) Particles which will move along path�(1)

(B) 23

Na+1 (q) Particles which will move along path�(2)

(C) 6Li+1 (r) Particles which will strike the negative plate in

minimum time

(D) 2D+1 (s) Particles which will strike the negative plate in

maximum time

(t) Particles which will strike the plate with lowest kinetic energy

SECTION - VInteger Answer Type

This section contains 2 questions. The answer to each of the questions isa single digit integer, ranging from 0 to 9. The appropriate bubble below therespective question number in the ORS have to be darkened.

62. A particle is released from height 'R' from the surface of earth where 'R' is radius of the earth. If the acceleration

of particle at that height is given by ng

. Then find the value of 'n'.

63. Electric field in a region is given by j�y6i�x4E

. If the charge

enclosed by the cube is n0 in the cube of side 1m oriented as shown in

the figure. Find the value of 'n'.

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Page 26: PAPER - 1 - WordPress.com electronic configuration in the ligand field2,2,2 t2g , e g 0, Then which of the following is correct about this new complex. (A) Complex is paramagnetic.

(Space for rough work)

Name of the Candidate Roll Number

I have read all the instructions andshall abide by them.

-------------------------------- Signature of the Invigilator

I have verified all the informationfilled in by the Candidate.

-------------------------------- Signature of the Candidate

Example for Filling Test Cities Code in ORS :If your Test centre is Bhatinda and test code is 06 then fill in ORS :

(a)

(b)

Test Code Test Centre Test Code Test Centre Test Code Test Centre

01 AHMEDABAD 02 AGRA 03 BENGALURU04 BIKANER 05 BHOPAL 06 BHATINDA07 BHUBNESHWAR 08 BOKARO 09 CHANDIGARH10 DHANBAD 11 DEHRADUN 12 GUWAHATI13 HYEDRABAD 14 INDORE 15 JAIPUR16 KANPUR 17 KOLKATA 18 KOTA19 LUCKNOW 20 MUMBAI- Andheri 21 MUMBAI- Thane22 MUMBAI- Nerul 23 MUMBAI- Dadar 24 MANGLURU25 MUZAFFARPUR 26 NAGPUR 27 NEW DELHI- East28 NEW DELHI- North West 29 NEW DELHI- South 30 PATNA31 RAIPUR 32 RANCHI 33 SRI GANGANAGAR34 SHAKTI NAGAR 35 UDAIPUR 36 UDUPI37 VARANASI 38 BHAGALPUR 39 GWALIOR40 PATHANKOT 41 RAJKOT 42 GORAKHPUR43 BHILAI