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Optimal Control Lecture 1 Solmaz S. Kia Mechanical and Aerospace Engineering Dept. University of California Irvine [email protected] 1 / 13
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Optimal Control Lecture 1 - Solmaz S. Kia

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Page 1: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control

Lecture 1

Solmaz S. Kia

Mechanical and Aerospace Engineering Dept.

University of California Irvine

[email protected]

1 / 13

solmazsajjadikia
Typewritten Text
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Page 2: Optimal Control Lecture 1 - Solmaz S. Kia

Objective of control theory

Control theory is a branch of applied mathematics that involves basic principles

underlying the analysis and design of (control) systems/processes.

The objective in control theory

stabilization, regulation, tracking

Impose performance on system behavior.

2 / 13

Page 3: Optimal Control Lecture 1 - Solmaz S. Kia

Objective of control theory

Control theory is a branch of applied mathematics that involves basic principles

underlying the analysis and design of (control) systems/processes.

The objective in control theory

stabilization, regulation, tracking

Impose performance on system behavior.

2 / 13

Page 4: Optimal Control Lecture 1 - Solmaz S. Kia

Objective of control theory

Control theory is a branch of applied mathematics that involves basic principles

underlying the analysis and design of (control) systems/processes.

The objective in control theory

stabilization, regulation, tracking

Impose performance on system behavior.

2 / 13

Page 5: Optimal Control Lecture 1 - Solmaz S. Kia

Objective of control theory

Control theory is a branch of applied mathematics that involves basic principles

underlying the analysis and design of (control) systems/processes.

The objective in control theory

stabilization, regulation, tracking

Impose performance on system behavior.

2 / 13

Page 6: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal control

I Performance measures considering step or ramp response:

• rise-time (tr)

• settling time (ts)

• peak overshoot (MP)

• gain and phase margin and

bandwidth

• steady state error

mostly for SISO systems

I In this course:

• more complex performance measures, perhaps more closely related to the

physical aspects of the system

minimum fuelminimum control effortminimum time

• satisfy some constraints on control and states of the system while optimizing

performance measure

3 / 13

Page 7: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal control

I Performance measures considering step or ramp response:

• rise-time (tr)

• settling time (ts)

• peak overshoot (MP)

• gain and phase margin and

bandwidth

• steady state error

mostly for SISO systems

I In this course:

• more complex performance measures, perhaps more closely related to the

physical aspects of the system

minimum fuelminimum control effortminimum time

• satisfy some constraints on control and states of the system while optimizing

performance measure

3 / 13

Page 8: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal control

I Performance measures considering step or ramp response:

• rise-time (tr)

• settling time (ts)

• peak overshoot (MP)

• gain and phase margin and

bandwidth

• steady state error

mostly for SISO systems

I In this course:

• more complex performance measures, perhaps more closely related to the

physical aspects of the system

minimum fuelminimum control effortminimum time

• satisfy some constraints on control and states of the system while optimizing

performance measure

3 / 13

Page 9: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal control

The objective of optimal control is to determine the control signals that will

cause a process to satisfy the physical constraints and at the same time minimize

(or maximize) some performance criterion.

The following three elements constitute the optimal control formulation|:

model (a mathematical description) of the process/system to be controlled

mathematical description of the (physical) constraints of the system

a performance measure and its mathematical description

4 / 13

Page 10: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-time problem: To transfer a system from arbitrary initial state

x(t0) = x0 to a specified target set S in minimum time

J = tf - t0 =

Ztf

t0

dt, (1)

where tf is the first instant of time when x(t) and S intersect.

For discrete-time systems, minimum-time performance can be cast as

J =N =XN-1

k=01.

5 / 13

Page 11: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-time problem: To transfer a system from arbitrary initial state

x(t0) = x0 to a specified target set S in minimum time

J = tf - t0 =

Ztf

t0

dt, (1)

where tf is the first instant of time when x(t) and S intersect.

For discrete-time systems, minimum-time performance can be cast as

J =N =XN-1

k=01.

5 / 13

Page 12: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 13: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 14: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 15: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 16: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 17: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Terminal control problem: to minimize the deviation of the final state of a system

from its desired value r(tf) 2 Rn

J =Xn

i=1(xi(tf)- ri(tf))

2 = (x(tf)- r(tf)>(x(tf)- r(tf)) = kx(tf)- r(tf)k2.

Both positive and negative deviations are undesirable.

Given the system model and the constrains, x(tf) = r(tf) may not be

accomplished.

A ballistic missile aimed at target S.

In this case, we may wish to put more weight or penalty on the deviation of

certain state more than others.

J = (x(tf)- r(tf))>H (x(tf)- r(tf)) = kx(tf)- r(tf)k2H, H > 0,

6 / 13

Page 18: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 19: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 20: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 21: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 22: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 23: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 24: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Minimum-control-effort problems: to transfer a sys. from an arbitrary initial state

x(t0) = x0 to a specified target S, with a minimum expenditure of control effort.

Form of “ minimum control effort” cost depends on physical application:

For a space craft (u(t): thrust of the engine), the minimum-control-effort

J =

Ztf

t0

|u(t)| dt.

For a discrete-time system

J =XN-1

k=0|uk|.

For an electric network without energy storage element (u(t): voltage source)

J =

Ztf

t0

u2(t) dt.

For several control inputs, we can write the cost function as

J =

Ztf

t0

u>(t)Ru(t) dt =

Ztf

t0

ku(t)k2R

dt, R >

For a discrete-time system:

J =1

2

XN-1

k=0u>kRuk.

7 / 13

Page 25: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

8 / 13

Page 26: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

| {z }8><

>:

reasonable if constraints includes |ui(t)| 6 1, i 2 {1, . . . ,m}

Otherwise may result in impulses in control and its derivatives

8 / 13

Page 27: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

| {z }8><

>:

reasonable if constraints includes |ui(t)| 6 1, i 2 {1, . . . ,m}

Otherwise may result in impulses in control and its derivatives

J =

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt,

| {z }remove the hard control bounds from problem formulation or conserve energy while maintaining tracking

8 / 13

Page 28: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

| {z }8><

>:

reasonable if constraints includes |ui(t)| 6 1, i 2 {1, . . . ,m}

Otherwise may result in impulses in control and its derivatives

J =

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt,

| {z }remove the hard control bounds from problem formulation or conserve energy while maintaining tracking

J = kx(tf)- r(tf)k2H| {z }states be close to their desired value at final time

+

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt.

8 / 13

Page 29: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

| {z }8><

>:

reasonable if constraints includes |ui(t)| 6 1, i 2 {1, . . . ,m}

Otherwise may result in impulses in control and its derivatives

J =

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt,

| {z }remove the hard control bounds from problem formulation or conserve energy while maintaining tracking

J = kx(tf)- r(tf)k2H| {z }states be close to their desired value at final time

+

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt.

J =1

2x>NHxN +

1

2

XN-1

k=0((xk - rk)

>Q(xk - rk) + u

>kRuk)

| {z }for a discrete-time system

.

8 / 13

Page 30: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

Tracking problem: to maintain the system state x(t) as close as possible to the

desired state r(t) in the interval [t0, tf]:

J =

Ztf

t0

(x(t)- r(t))>(t)Q(x(t)- r(t)) dt =

Ztf

t0

kx(t)- r(t)k2Q

dt, Q > 0

| {z }8><

>:

reasonable if constraints includes |ui(t)| 6 1, i 2 {1, . . . ,m}

Otherwise may result in impulses in control and its derivatives

J =

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt,

| {z }remove the hard control bounds from problem formulation or conserve energy while maintaining tracking

J = kx(tf)- r(tf)k2H| {z }states be close to their desired value at final time

+

Ztf

t0

(kx(t)- r(t)k2Q(t) + ku(t)k2

R(t)) dt.

J =1

2x>NHxN +

1

2

XN-1

k=0((xk - rk)

>Q(xk - rk) + u

>kRuk)

| {z }for a discrete-time system

.

Regulation problem: r(t) = 0 for all t 2 [t0, tf]8 / 13

Page 31: Optimal Control Lecture 1 - Solmaz S. Kia

Performance measures

All the performance measures discussed above are special cases of the general form

Continuous-time

J = h(x(tf), tf)| {z }terminal cost

+

Ztf

t0

g(x(t),u(t), t)dt

| {z }running cost

.

Discrete-time

J = �(xN,N)| {z }terminal cost

+XN-1

k=0Lk(xk,uk)dt

| {z }running cost

.

9 / 13

Page 32: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control Problem

Find admissible u?

which cause x = f(x(t),u(t), t) to follow admissible x?

that minimize

J = h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt.

- u?: optimal control x

?: optimal trajectory

J? = h(x?(tf), tf) +

Ztf

t0

g(x?(t),u?(t), t)dt

6 h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt, u 2 U, x 2 X.

We are looking for global minimum

Find all local minimum, and pick the smallest as global minimum

Solution is not unique

con: complicates computational procedures

pro: choose among multiple possibilities accounting for other measures

10 / 13

Page 33: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control Problem

Find admissible u?

which cause x = f(x(t),u(t), t) to follow admissible x?

that minimize

J = h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt.

- u?: optimal control x

?: optimal trajectory

J? = h(x?(tf), tf) +

Ztf

t0

g(x?(t),u?(t), t)dt

6 h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt, u 2 U, x 2 X.

We are looking for global minimum

Find all local minimum, and pick the smallest as global minimum

Solution is not unique

con: complicates computational procedures

pro: choose among multiple possibilities accounting for other measures

10 / 13

Page 34: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control Problem

Find admissible u?

which cause x = f(x(t),u(t), t) to follow admissible x?

that minimize

J = h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt.

- u?: optimal control x

?: optimal trajectory

J? = h(x?(tf), tf) +

Ztf

t0

g(x?(t),u?(t), t)dt

6 h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt, u 2 U, x 2 X.

We are looking for global minimum

Find all local minimum, and pick the smallest as global minimum

Solution is not unique

con: complicates computational procedures

pro: choose among multiple possibilities accounting for other measures

10 / 13

Page 35: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control Problem

Find admissible u?

which cause x = f(x(t),u(t), t) to follow admissible x?

that minimize

J = h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt.

- u?: optimal control x

?: optimal trajectory

J? = h(x?(tf), tf) +

Ztf

t0

g(x?(t),u?(t), t)dt

6 h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt, u 2 U, x 2 X.

We are looking for global minimum

Find all local minimum, and pick the smallest as global minimum

Solution is not unique

con: complicates computational procedures

pro: choose among multiple possibilities accounting for other measures

10 / 13

Page 36: Optimal Control Lecture 1 - Solmaz S. Kia

Optimal Control Problem

Find admissible u?

which cause x = f(x(t),u(t), t) to follow admissible x?

that minimize

J = h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt.

- u?: optimal control x

?: optimal trajectory

J? = h(x?(tf), tf) +

Ztf

t0

g(x?(t),u?(t), t)dt

6 h(x(tf), tf) +

Ztf

t0

g(x(t),u(t), t)dt, u 2 U, x 2 X.

We are looking for global minimum

Find all local minimum, and pick the smallest as global minimum

Solution is not unique

con: complicates computational procedures

pro: choose among multiple possibilities accounting for other measures

10 / 13

Page 37: Optimal Control Lecture 1 - Solmaz S. Kia

Parameter static optimization: when time is not a parameter in the problem

Unconstrained optimization

Constrained optimization

11 / 13

Page 38: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2Rm

F(u),

where F : Rm ! R is differentiable

Local (weak) minimum point: A point u? 2 Rm

is said to be a (weak) localminimum point of F over Rm

if

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point:

9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

(a) strong minimum, (b) weak minimum

12 / 13

Page 39: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2Rm

F(u),

where F : Rm ! R is differentiable

Local (weak) minimum point: A point u? 2 Rm

is said to be a (weak) localminimum point of F over Rm

if

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point:

9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

(a) strong minimum, (b) weak minimum

12 / 13

Page 40: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2Rm

F(u),

where F : Rm ! R is differentiable

Local (weak) minimum point: A point u? 2 Rm

is said to be a (weak) localminimum point of F over Rm

if

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point:

9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

(a) strong minimum, (b) weak minimum

12 / 13

Page 41: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2Rm

F(u),

where F : Rm ! R is differentiable

Local (weak) minimum point: A point u? 2 Rm

is said to be a (weak) localminimum point of F over Rm

if

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point:

9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

(a) strong minimum, (b) weak minimum12 / 13

Page 42: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2RmF(u),

where F : Rm ! R is differentiable

A point u? 2 Rm

is said to be a Local (weak) minimum point of F over Rmif

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point: 9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

Global minimum: (weak) F(u?) 6 F(u) 8,u 2 Rm, (strong) F(u?) < F(u) 8,u 2 Rm

f(x) = 2+ cos(x) + 0.5 cos(2 x- 0.5) has multiple local and global minimizer.

13 / 13

Page 43: Optimal Control Lecture 1 - Solmaz S. Kia

Unconstrained optimization

u? = argmin

u2RmF(u),

where F : Rm ! R is differentiable

A point u? 2 Rm

is said to be a Local (weak) minimum point of F over Rmif

9✏ > 0 s.t. F(u?) 6 F(u) 8u 2 Rm, ku- u?k < ✏

Local (strong) minimum point: 9✏ > 0 s.t. F(u?) < F(u) 8u 2 Rm, ku- u?k < ✏

Global minimum: (weak) F(u?) 6 F(u) 8,u 2 Rm, (strong) F(u?) < F(u) 8,u 2 Rm

x-10 -5 0 5 10

f(x)

1

1.5

2

2.5

3

3.5

X: -1.93Y: 1.476

X: -4.02Y: 1.045

f(x) = 2+ cos(x) + 0.5 cos(2 x- 0.5) has multiple local and global minimizer. 13 / 13