On the analysis of unsteady flows of implicitly constituted incompressible fluids Miroslav Bul´ ıˇ cek Mathematical Institute of the Charles University Sokolovsk´ a 83, 186 75 Prague 8, Czech Republic P. Gwiazda, J. M´ alek and A. ´ Swierczewska-Gwiazda Krak´ ow July 3, 2012 Bul´ ıˇ cek (Charles University in Prague) Implicit fluids & Analysis Krak´ow July 3, 2012 1 / 25
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On the analysis of unsteady ows of implicitly constituted ...prusv/ncmm/conference/...Steady case (DDD) + (SSS) dx C Unsteady case sup t kvk2 2 + T 0 (DDD) + (SSS) dx dt C Bul cek
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On the analysis of unsteady flows of implicitlyconstituted incompressible fluids
Miroslav Bulıcek
Mathematical Institute of the Charles UniversitySokolovska 83, 186 75 Prague 8, Czech Republic
P. Gwiazda, J. Malek and A. Swierczewska-Gwiazda
Krakow July 3, 2012
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 1 / 25
Equation
Balance equations
We consider flow of a homogeneous incompressible fluid under constanttemperature
div v = 0
v ,t + div(v ⊗ v)− divSSS = −∇p + f
SSS = SSST
• v is the velocity of the fluid• p is the pressure• f external body forces ( ≡ 0)• SSS is the constitutively determined part of the Cauchy stressThe Cauchy stress is given as TTT = −pIII + SSS
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 2 / 25
Constitutive equations
Point-wisely given constitutive equations
We denote by DDD(v) the symmetric part of the velocity gradient, i.e.,2DDD(v) := ∇v + (∇v)T .
We assume for simplicity only point-wise relation between DDD and SSS.
We add to balance equations some implicit (constitutive) formula:
Let ψ(DDD) := ψ(|DDD|) and ψ and ψ∗ satisfy ∆2 condition. Assume thatenergy space is compactly embedded into L2. Then there exists a weaksolution for Navier’s bc.
The same result also holds for Dirichlet bc. by using the Wolfdecomposition of the pressure.
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 14 / 25
Results
The key result
Theorem (Easier case; Gwiazda, Swierczewska-Gwiazda et al)
If energy equality “holds” and ψ∗ satisfies ∆2 conditions then there existsa weak solution for any relevant boundary conditions.
Let ψ(DDD) := ψ(|DDD|) and ψ and ψ∗ satisfy ∆2 condition. Assume thatenergy space is compactly embedded into L2. Then there exists a weaksolution for Navier’s bc.
The same result also holds for Dirichlet bc. by using the Wolfdecomposition of the pressure.
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 14 / 25
Results
The key result
Theorem (Easier case; Gwiazda, Swierczewska-Gwiazda et al)
If energy equality “holds” and ψ∗ satisfies ∆2 conditions then there existsa weak solution for any relevant boundary conditions.
Let ψ(DDD) := ψ(|DDD|) and ψ and ψ∗ satisfy ∆2 condition. Assume thatenergy space is compactly embedded into L2. Then there exists a weaksolution for Navier’s bc.
The same result also holds for Dirichlet bc. by using the Wolfdecomposition of the pressure.
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 14 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Byproducts-increase the citation report
Byproduct
Theory for the laplace equation with Neumann bc, i.e., for ψ and ψ∗ satisfying ∆2
condition, we have ˆΩ
ψ(|∇2u|) ≤ C
(1 +
ˆΩ
ψ(|f |))
for any u solving homogeneous Neuman problem with right hand side f .
Byproduct
Improvement of the Minty method =⇒ no use of the Vitali theorem =⇒ no strictmonotonicity required
Byproduct
Improvement of the Lipschitz approximation method =⇒ no need of ∆2 for ψ =⇒nothing to our case due to the pressure =⇒ but may be use for generalparabolic/elliptic problems
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 15 / 25
Results
Power-law like fluid - Explicit
Compact embedding is available if r > 65
r = 2 Lerray (1934)
r ≥ 115 for unsteady, r ≥ 9
5 steady; Ladyzhenskaya 60’s
r ≥ 95 unsteady; Malek. Necas, Ruzicka 90’s
r ≥ 85 unsteady; Frehse, Malek, Steinahuer (2000)
r > 65 steady; Frehse, Malek, Steinahuer (2002)
r > 65 unsteady; Diening, Ruzicka, Wolf (2009)
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 16 / 25
Results
Power-law like fluid - implicit (discontinuous)
r ≥ 115 - strict monotonicity - Gwiazda, Malek, Swierczewska
(2007)
r > 95 - Herschel-Bulkley model - Malek, Ruzicka, Shelukhin(2005)
r > 65 unsteady; Bulıcek, Gwiazda, Malek, Swierczewska (2010)
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 17 / 25
Results
Novelties
Fully Orlicz setting
Fully implicit setting
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 18 / 25
Results
Novelties
Fully Orlicz setting
Fully implicit setting
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 18 / 25
Methods
Methods
subcritical case - energy equality; Minty methodsmall problems if ψ does not satisfy ∆2 condition
supercritical case -Lipschitz approximation in Orlicz spaces;generalized Minty method
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 19 / 25
Methods
Methods
subcritical case - energy equality; Minty methodsmall problems if ψ does not satisfy ∆2 condition
supercritical case -Lipschitz approximation in Orlicz spaces;generalized Minty method
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 19 / 25
Methods
Lipschitz approximation
sequence of solutions vn; vn − v is not possible test function
introduce a Lipschitz function (vn − v)λ that is “closed” to to original
previous work are based on the continuity of the Hardy-Littelwoodmaximal function in Lp- In Orlicz space setting one needs that ∆2
conditions are satisfied and log continuity w.r.t. x
Goal is to avoid use continuity of Hardy-Littelwood maximal function;enough is just weak (1, 1) estimates
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 20 / 25
Methods
Lipschitz approximation
sequence of solutions vn; vn − v is not possible test function
introduce a Lipschitz function (vn − v)λ that is “closed” to to original
previous work are based on the continuity of the Hardy-Littelwoodmaximal function in Lp- In Orlicz space setting one needs that ∆2
conditions are satisfied and log continuity w.r.t. x
Goal is to avoid use continuity of Hardy-Littelwood maximal function;enough is just weak (1, 1) estimates
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 20 / 25
Methods
Lipschitz approximation
sequence of solutions vn; vn − v is not possible test function
introduce a Lipschitz function (vn − v)λ that is “closed” to to original
previous work are based on the continuity of the Hardy-Littelwoodmaximal function in Lp- In Orlicz space setting one needs that ∆2
conditions are satisfied and log continuity w.r.t. x
Goal is to avoid use continuity of Hardy-Littelwood maximal function;enough is just weak (1, 1) estimates
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 20 / 25
Methods
Lipschitz approximation
sequence of solutions vn; vn − v is not possible test function
introduce a Lipschitz function (vn − v)λ that is “closed” to to original
previous work are based on the continuity of the Hardy-Littelwoodmaximal function in Lp- In Orlicz space setting one needs that ∆2
conditions are satisfied and log continuity w.r.t. x
Goal is to avoid use continuity of Hardy-Littelwood maximal function;enough is just weak (1, 1) estimates
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 20 / 25
Methods
Lipschitz approximation
Lemma
un∞n=1 tends strongly to 0 in L1 and SSSn∞n=1 such thatˆ
Ω
ψ∗(|SSSn|) + ψ(|∇un|) dx ≤ C∗ (C∗ > 1).
Then for arbitrary λ∗ ∈ R+ and k ∈ N there exists λmax <∞ and there exists sequenceof λk
n∞n=1 and the sequence unk (going to zero) and open sets E k
n := unk 6= un such
that λkn ∈ [λ∗, λmax] and for any sequence αn
k
unk ∈W 1,p, ‖DDD(un
k)‖∞ ≤ Cλkn ,
|Ω ∩ E kn | ≤ C
C∗
ψ(λkn),
ˆΩ∩Ek
n
|SSSn ·DDD(unk)| dx ≤ CC∗
(αkn
k+αknψ(λk
n/αkn)
ψ(λkn)
)
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 21 / 25
Methods
Use of Lipschtiz approximation
We have approximative problem (vn,SSSn) and weak limits (v ,SSS), we need to showthat (SSS,DDD(v)) ∈ ATest the approximative n- problem by Lipschitz approximation of vn − v , i.e.,unk := (vn − v)k
One gets (here SSS is such that (SSS,DDD) ∈ A
limn→∞
ˆunk
=un(SSSn − SSS) : DDD(un
k) ≤ CC∗(αkn
k+αknψ(λk
n/αkn)
ψ(λkn)
)Holder inequality gives
limn→∞
ˆΩ
|(SSSn − SSS) : DDD(vn − v)|ε ≤ˆun=un
k
+
ˆun 6=un
k
≤ small terms→ 0
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 22 / 25
Methods
Use of Lipschtiz approximation
We have approximative problem (vn,SSSn) and weak limits (v ,SSS), we need to showthat (SSS,DDD(v)) ∈ ATest the approximative n- problem by Lipschitz approximation of vn − v , i.e.,unk := (vn − v)k
One gets (here SSS is such that (SSS,DDD) ∈ A
limn→∞
ˆunk
=un(SSSn − SSS) : DDD(un
k) ≤ CC∗(αkn
k+αknψ(λk
n/αkn)
ψ(λkn)
)Holder inequality gives
limn→∞
ˆΩ
|(SSSn − SSS) : DDD(vn − v)|ε ≤ˆun=un
k
+
ˆun 6=un
k
≤ small terms→ 0
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 22 / 25
Methods
Use of Lipschtiz approximation
We have approximative problem (vn,SSSn) and weak limits (v ,SSS), we need to showthat (SSS,DDD(v)) ∈ ATest the approximative n- problem by Lipschitz approximation of vn − v , i.e.,unk := (vn − v)k
One gets (here SSS is such that (SSS,DDD) ∈ A
limn→∞
ˆunk
=un(SSSn − SSS) : DDD(un
k) ≤ CC∗(αkn
k+αknψ(λk
n/αkn)
ψ(λkn)
)Holder inequality gives
limn→∞
ˆΩ
|(SSSn − SSS) : DDD(vn − v)|ε ≤ˆun=un
k
+
ˆun 6=un
k
≤ small terms→ 0
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 22 / 25
Methods
Use of Lipschtiz approximation
We have approximative problem (vn,SSSn) and weak limits (v ,SSS), we need to showthat (SSS,DDD(v)) ∈ ATest the approximative n- problem by Lipschitz approximation of vn − v , i.e.,unk := (vn − v)k
One gets (here SSS is such that (SSS,DDD) ∈ A
limn→∞
ˆunk
=un(SSSn − SSS) : DDD(un
k) ≤ CC∗(αkn
k+αknψ(λk
n/αkn)
ψ(λkn)
)Holder inequality gives
limn→∞
ˆΩ
|(SSSn − SSS) : DDD(vn − v)|ε ≤ˆun=un
k
+
ˆun 6=un
k
≤ small terms→ 0
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 22 / 25
Methods
Use of generalized Minty
point-wise convergence of (SSSn − SSS) : DDD(vn − v) to 0; strict monotonicity finishesthe proof
only monotonicity; Use Biting lemma; Since (SSSn − SSS) : DDD(vn − v) is bounded in L1
there is sequence of non-increasing sets Ak+1 ⊂ Ak , limk→∞ |Ak | = 0 such that
monotonicity of the graph implies (assume that A is x-independent) for anynonnegative ϕ, and any (SSS1,DDD1) ∈ A fixed matrixes
0 ≤ limn→∞
ˆΩ\Ak
(SSSn − SSS1) : (DDD(vn)−DDD1)ϕ =
ˆΩ\Ak
(SSS− SSS1) : (DDD(v)−DDD1)ϕ
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 23 / 25
Methods
Use of generalized Minty
ϕ arbitrary nonnegative implies
0 ≤ (SSS− SSS1) : (DDD(v)−DDD1) for a.a. x ∈ Ω \ Ak
Using maximality of the graph one gets
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω \ Ak
Using smallness of Ak we get
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 24 / 25
Methods
Use of generalized Minty
ϕ arbitrary nonnegative implies
0 ≤ (SSS− SSS1) : (DDD(v)−DDD1) for a.a. x ∈ Ω \ Ak
Using maximality of the graph one gets
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω \ Ak
Using smallness of Ak we get
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 24 / 25
Methods
Use of generalized Minty
ϕ arbitrary nonnegative implies
0 ≤ (SSS− SSS1) : (DDD(v)−DDD1) for a.a. x ∈ Ω \ Ak
Using maximality of the graph one gets
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω \ Ak
Using smallness of Ak we get
(SSS,DDD(v)) ∈ A for a.a. x ∈ Ω
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 24 / 25
Methods
Future?????
• Extension to whole N- function setting, i.e., ψ depends on whole DDD andnot only on |DDD|, very hard• Extension to “real” x-dependent setting, i.e., the growth estimatesdepends crucially on x , i.e., for models
SSS ∼ (1 + |DDD|)r(c(x))−2DDD,
where c satisfy convection diffusion problem.
Bulıcek (Charles University in Prague) Implicit fluids & Analysis Krakow July 3, 2012 25 / 25