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Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 www.nucastro.ph.tum .de
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Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Dec 15, 2015

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Page 1: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Nuclear Astrophysics

1

Lecture 3Thurs. Nov. 3, 2011

Prof. Shawn Bishop, Office 2013, Ex. 12437

www.nucastro.ph.tum.de

Page 2: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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Summary of Results Thus Far

Page 3: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

If species “z” can be ionized, the number of particles can be where is the number of free particles produced by species “z” (nucleus + free electrons). If fully ionized, and

Mass fraction, in volume V, of species “z” is just And clearly,

Alternative expressions for Pressures

3

is the number of atoms of atomic species with atomic number “z” in the volume V

Mass density of each species is just: where are the atomic mass of species “z” and Avogadro’s number, respectively

Collect the algebra to write

And so we have for :

Page 4: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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The mean molecular weight is defined by the quantity:

We can write it out as:

is the average of for atomic species Z > 2

For atomic species heavier than helium, average atomic weight is and if fullyionized,

Fully ionized gas:

Same game can be played for electrons:

Page 5: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Temp. vs Density Plane

5

Rela

tivis

tic

Non

-Rel

ativi

stic

g cm-3

Page 6: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Thermodynamics of the Gas

6

1st Law of Thermodynamics:

Thermal energy of the system (heat)

Total energy of the system

Assume that , then

Substitute into dQ:

Heat capacity at constant volume:

Heat capacity at constant pressure:

We finally have:

Page 7: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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For an ideal gas:

Therefore,

And,

So,

Let’s go back to first law, now, for ideal gas:

using

For an isentropic change in the gas, dQ = 0

This leads to, after integration of the above with dQ = 0, and

Page 8: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Use

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First Law for isentropic changes:

Take differentials of

but

Finally

Because is constant, we can integrate the last equation over the star:

Total energy of Star is gravitational binding energy and internal energy U

4/3 if star is to remain bound! (Ideal gas: = 5/3, so it’s safe)

Page 9: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

AGB Pulsation

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University of Minnesota's Laboratory for Computational Science & Engineering (LCSE)

Page 10: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Carinae (Southern Hemisphere)

Hubble Space Telescope10

• Eta Carinae: star of ~ 100 Solar masses • Radiation pressure dominant over gas pressure• Radiation luminosity is tearing star apart• A case where < 4/3 in most regions of the star!

Page 11: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Polytrope: First Stellar Structure Model

11

We have seen, under adiabatic/isentropic conditions that:

Deg. and Rel. Deg. electron gas

Lane-Emden Equation results:

Rearrange

Differentiate:

Let’s go back to hydrostatic equilibrium equation:

Page 12: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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Motivated by these P- relationships, the polytrope model adopts a pressure profile:

And the density function is given by where is a dimensionless function of radial coordinate .

Put these into the Lane-Emden equation:

Clean it up by setting and

Finally, we have:

Page 13: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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Boundary conditions for function : ,

Homework: Show that the case n=0, solution to the Lane-Emden equation is:

Mass:

Page 14: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Polytrope Solutions

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n = 0

n = 2n = 1

n = 5

n = 3n = 4

Page 15: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Case n = 3: Relativistic Deg. Electron Gas and White Dwarfs

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Therefore, we have:

Page 16: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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When n = 3

Substitute in for K from previous page:

Where is in grams.

This is Chandrasekhar’s mass relation for White Dwarf’s, and now you’ve seen how it is derived!

Page 17: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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C = 48%, O = 48%, Ne = 2%

Chandra X-ray Spectrum of WD H1504+65

What is a mass estimate of this Oxygen-Neon WD?

Page 18: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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Central Pressure: Use equations on page 29 for and , along with and the result for Mass on page 30.

Exercise for student: Show that the ratio of mean to central density is (for any index n):

Exercise for student: show that

For n = 3:

Page 19: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

Suppose gas pressure contributes a fraction to the total pressure . Then the photon pressure is . And

Total Pressure:

Case n = 3: “Main Sequence”

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Main sequence stars have both particle pressure and photon pressure acting within their interiors.

In thermodynamic equilibrium, both gases must have the same temperature . Eliminating the common temperature, we have (exercise for student)

Polytrope index of 3 again!

From

Page 20: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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This value of K can be used in mass expression (page 13) to determine Main sequence masses. For you to show that the Mass is given by:

Finally, let’s get the central temperature of this Main Sequence model:

(From previous page )

Page 21: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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In terms of the mean density, using from page 35and table on page 31:

Page 22: Nuclear Astrophysics 1 Lecture 3 Thurs. Nov. 3, 2011 Prof. Shawn Bishop, Office 2013, Ex. 12437 .

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Homework: A certain star has the following properties:

Using these values, graph below, and the previous equation, estimate the central temperature using the previous result for the polytrope Standard Model.

Parametric plot of versus

Refer to page 37 for the final mass formula of the Main Sequence Star model to understand why the plot is parameterized. (We do not Isolate in the mass formula. We isolate and plot its values for values of ) And this is what we see in the graph.