Noble Gases and Valence e - Ionization Energy and Bonding
Mar 15, 2016
Noble Gases and Valence e- Ionization Energy and Bonding
A look back at the Periodic Table
• Halogens, group 7A or 17: F, Cl, Br, I– Nonmetals– Element form is diatomic F2 Cl2 Br2 I2
– At room temperature, F2 and Cl2 are gases, Br2 is liquid, I2 is solid
– Reactivity decreases down group• F2 is the most reactive of all elements
• I2 is the least reactive halogen
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Trends in Element Families
• Alkali metals, group 1A or 1: Li, Na, K, Rb, Cs– Metals• stored under oil to keep them from reacting with O2
– Impart bright, characteristic colors to flames• Li = red Na = orange K, Rb, Cs = lavender
– All react with water to produce H2
– Reactivity increases down group• Cs is most reactive alkali metal• Li is least reactive alkali metal
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Trends in Element Families
• Noble gases, group 8A or 18: He, Ne, Ar, Kr, Xe– Nonmetals– Element form is monatomic– At room temperature, all are gases– Most significant property is that they are almost
completely unreactive• Compounds of Xe, Kr, and recently Ar have been made
with F and O, but they decompose very easily• No compounds of He have ever been prepared
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How do Atoms Join?
• The behavior of the noble gas, alkali metal, and halogen families is key to understanding bonding– Noble gases generally do not form compounds– Alkali metals form compounds by losing one
electron to form a +1 ion (cation)– Halogens form compounds by gaining one
electron to form a –1 ion (anion)
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Ion sizes
• A cation is always smaller than its parent atom
• An anion is always larger than its parent atom
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Let’s Practice…
• Which ion is larger?– Se or Se-2
• Which ion is smaller?– Al or Al+3
Ionization energy
• Ionization energy (IE) is the energy needed to remove the outermost electron from an atom– Low IE electron is easier to remove– High IE electron is harder to remove
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Ionization energy• IE decreases down a group
(easier to remove e– as you go down a group)
• IE generally increases across a period from left to right (harder to remove e– as you go across a period)
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Ionization Energy
Let’s Practice…
• Which has a larger ionization energy?– Cs or F
• Which has a smaller ionization energy?– Be or Mg
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2He
10Ne
18Ar
17Cl
9F
19K
11Na
3Li
Group 8ANoble gases
“happy to be me”
Group 7AHalogens“just one
more electron . . .”
Group 1AAlkali metals
“just oneless electron . . .”
Valence electrons
• This behavior suggests that– The number of electrons in a noble gas is
especially stable– That number of electrons forms a noble gas core
of stable electrons unavailable for bonding– Only electrons outside the noble gas core
participate in the formation of chemical bonds between atoms
– Those electrons are called VALENCE ELECTRONS
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Valence electrons
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1H
2He
3Li
11Na
19K
4Be
12Mg
20Ca
5B
6C
7N
8O
9F
10Ne
13Al
14Si
15P
16S
17Cl
18Ar
31Ga
32Ge
33As
34Se
35Br
36Kr
1A 2A 3A 4A 5A 6A 7A 8A
FOR MAIN-GROUP ELEMENTS:number of valence electrons = group number
Depicting Valence Electrons• Show the valence electrons for a main-group
element using a LEWIS DOT STRUCTURE
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Li Li
•
LithiumGroup 1A
1 valence electron
C C••
•
•
CarbonGroup 4A
4 valence electrons
O O•
••
•••
OxygenGroup 6A
6 valence electrons
Lewis Dot Structures• Dot number is important, positions are not
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••••
•
N
NitrogenGroup 5A
5 valence electrons
••
•
••
N
•
•
••• N•
••
N ••
Lewis Dot Structures• All the atoms in the same family have the same dot
structure
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HalogensGroup 7A
7 valence electrons
•••
••
••
F •
••
••
Cl •• •
••
••
Br
••
•
••
••
I ••
Let’s Practice…
• Draw the Lewis Dot Structure for:– Si – Rb – As– Br
Chemical Bonding
• The stability of the noble gases suggests that for main group elements,
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Atoms form chemical bonds bylosing, gaining, or sharing valence electrons
in order to achievethe same number of valence electrons as
the nearest noble gas
Octet Rule
• Noble gases have 8 valence shell electrons (except He)
–Atoms lose, gain, or share valence electrons in order to achieve 8 valence shell electrons– This is the OCTET RULE
• Atoms near He (H and Li) will try to achieve just 2 valence shell electrons
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Let’s Practice…
• Octet rule predicts that an atom of Flourine will try to _____(gain/lose) _____(1,2,3,4) electron(s) when forming a compound.
• Octet rule predicts that an atom of Calcium will try to _____(gain/lose) _____ (1,2,3,4) electron(s)when forming a compound.
Three Types of Chemical Bonding• Chemical Bonds can be classified into 3 broad categories, based on how
valence electrons are arranged:
Atoms Bond Character PropertiesMetal + nonmetal
ionic e- transferred Forms a salt= crystal of cations and anionsBrittleSolid does not conduct electricity, but conducts electricity when melted or dissolved in water
Nonmetal + nonmetal
covalent e- shared Composed of neutral moleculesBrittleDoes not conduct electricity in any state (solid, liquid, or dissovled in water)
Metal + metal
metallic e- pooled Lattice of cations embedded in “sea of electrons”MalleableSolid and liquid both conduct electricity
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Ionic bonds
• Ionic bonds form between metals and nonmetals– Metal gives up electrons– Nonmetal accepts electrons– Ions form– Because of opposite charges,
ions stick together to form a crystal– Resulting compound is a SALT
NaCl, saltNaCl, salt
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Ionic bonds: electron transfer• Metals transfer electrons to nonmetals to form ions:– Na has 1 valence e–, wants to lose it to attain a Ne core– Cl has 7 valence e–, wants to gain 1 to attain an octet, like Ar
• Solution is to transfer 1 electron from Na to Cl
– Electron transfer forms ions– Ions stick together because of opposite charges
••• Cl••
••Na
•
••
••
••
Cl
••
1–Na
1+
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Dot structures for ionic compounds
• Draw dot structures for these ionic compounds– Show the atoms before and ions after e– transfer– Use an arrow to show e– transfer– Show charges on ions after e– transfer– Write ions near each other but not together (they
are not sharing the electrons)
• MgO Na2O CaCl2
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Electronegativity
• Electronegativity is the ability to attract bond e–
• The higher the EN, the “greedier” the atom
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Electronegativity
• Electronegativity increases across a period and decreases down a group
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Covalent bonds: electron sharing• Nonmetals share electrons to form covalent bonds:– Each Cl has 7 valence e–, wants to gain 1 e– to get an
octet like Ar– Neither atom is willing to give up an electron– Solution is to share their unpaired electrons
– The shared pair of e– is a single covalent bond
•
••
••
Cl••
•
••
••
Cl ••
••
••Cl ••
••
••
Cl
•• ••
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Covalent bonds
• Covalent bonds form between nonmetals– Nonmetals share unpaired valence electrons– Each atom “owns” all of its bond electrons– Each atom achieves an octet (or 2, for hydrogen)– One shared pair of electrons is shown with a single line
••
••Cl ••
••
••
Cl••
•• or
••
••Cl ••
••
••
Cl••
––
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Bonding in O2
• Oxygen is a diatomic element
– Each unpaired electron must get into a bond– The atoms cannot achieve a filled valence level with a
single bond, so a double bond forms: they share two pairs of electrons
O
•
••
•• • O
•
••••• O
••
•• O
••
•• O
••O
••
••or ••••
=
••
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How to draw a dot structure
• Count valence e– • Put atom with lowest EN in center• Arrange other atoms around it symmetrically• Form single bonds between atoms (1 line = 2 e–)• Put lone pairs around terminal atoms to give each an
octet (2 for H), then finish central atom octet• If central atom does not get octet, move in lone pairs
to make double or triple bonds
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Lewis dot structures
• Draw a Lewis dot structure for each species– NH3 HBr CO2
– OH1– NH41+ HCN
– H2CO NO31– PF3
– SO2 C2H4 Cl2O
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How equally do atoms share e– ?• Hydrogen and fluorine share one pair
of e– in a single covalent bond• In the Lewis dot structure, they appear
to share the electrons equally, but do they?
H F
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How equally do atoms share e– ?• When you put HF in an
electric field, the molecules line up, as if the F end were negative and the H end positive.
• The electrons are shared unequally.
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How equally do atoms share e– ?• When bond e– are shared unequally, the bond is said to
be a polar covalent bond.
• A polar covalent bond has a dipole: one end is more negative than the other end
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Electronegativity and bond polarity
• Bond polarity depends on the difference in EN
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Evaluating bond type
• H–Br– H = 2.1, Br = 2.8– ∆EN = 0.7– Bond is polar covalent with Br end more negative
H–Br –
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Evaluating bond type
• C = O– C = 2.5, O = 3.5– ∆EN = 1.0– Bond is polar covalent with O end more negative
– Doesn’t matter whether bond is single or double
C=O –
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Evaluating bond type
• KCl– K = 0.8, Cl = 3.0– ∆EN = 2.2– Bond is ionic; e– transferred from K to Cl
K1+ Cl1–