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Newton’s Laws of Motion and Free Body Analysis
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Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

Jan 19, 2016

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Joey Mitton
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Page 1: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

Newton’s Laws of Motion and Free Body Analysis

Page 2: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

1. M1= 2.5kg and M2=3.5kgAn external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration of the system, and (b) the tension force between m1 and m2.a)2.0m/s/s b) 7.0 N

Page 3: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

2. A Block of mass 0.50 kg travels with a speed of 2.0 m/s in the positive x direction on a flat frictionless surface. On passing through the origin, the block experiences a constant force of 3.0 newtons, at a 60 deg angle relative to the x axis for 1.50 seconds. Calculate the velocity of the block at the end of this time.V=(6.5m/s)i+(7.8m/s)j

Page 4: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

3. If m1=5.0kg, m2=1.5 kg, and theta is 20 degrees, what is the acceleration of the system. Make your own free body diagram for M2 and assume no friction.0.32 m/s/s

Page 5: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

Static and Kinetic Friction

Page 6: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

Table 4.1Approximate Values for Coefficients of Static and Kinetic

Friction between Certain Surfaces

Page 7: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

4. If the coefficient of static friction is between the 40 kg crate and the floor is 0.065. What is the magnitude of the horizontal applied force the worker must apply to keep the crate moving? If the worker maintains that force once the crate moves and the coefficient of kinetic friction is 0.500, what is the magnitude of the acceleration of the crate?

1.48 m/s/s

Page 8: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

A crate sits in the middle of a flat bed truck that is traveling at 80 km/hr on a level road. The coefficient of static friction between the crate and the truck is 0.40. What is the minimum stopping distance for the truck if the crate is not to slide?

62m

Page 9: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

5. If the coefficient of friction is 0.560, what should be the value of m3 if the system is not to accelerate? Given m1=0.150kg, m2=0.250 kg.if m3=0.100 kg, what is the acceleration of the system?0.179 kg, 0.862 m/s/s

Page 10: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

6. The Atwood’s machinewas invented by British scientist George Atwood to study motion . If m1=0.55 kg and M2=0.80 kg, calculate the acceleration of the system, and the tension in the string.

1.8m/s/s, 6.4 N

Page 11: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

7. In the frictionless system shown below (m1=2.0 kg), what is mass m2, if the system is to remain at rest?

1.2 kg

Page 12: Newton’s Laws of Motion and Free Body Analysis. 1. M1= 2.5kg and M2=3.5kg An external force F= 12 Newtons is applied to m1. Calculate (a) the acceleration.

8. The two blocks remain stuck together as they are pulled to the right by a force F=200N. The coefficient of kinetic friction between block b and the table top is 0.800. a) Calculate the acceleration of the system b) calculate the force of friction between the two blocks.

A) 5.5 m/s/s b) 173 N