Must show ALL steps and ALL work for credit Equations - Introduction
Jan 05, 2016
Must show ALL steps and ALL work for credit
Equations - Introduction
VocabularyVocabulary
Equation Equation
Solution Solution
Inverse OperationInverse Operation
Insert Lesson Title Here
Course 2
1-10 Equations and Their Solutions
Ella has 22 CDs. This is 9 more than her friend Kay has.
This situation can be written as an equation.An equation is a mathematical statement that two expressions are equal in value.
An equation is like a balanced scale.
Right expressionLeft expression
Number of CDs Ella has
22
is equalto=
9 more thanKay hasj + 9
Course 2
1-10 Equations and Their Solutions
Just as the weights on both sides of a balanced scale are exactly the same, the expressions on both sides of an equation represent exactly the same value.
When an equation contains a variable, a value of the variable that makes the statement true is called a solution of the equation.
22 = j + 9 j = 13 is a solution because 22 = 13 + 9.
22 = j + 9 j = 15 is not a solution because 22 15 + 9.
The symbol ≠ means “is not equal to.” Reading Math
Course 2
1-10 Equations and Their Solutions
Determine whether the given value of the variable is a solution of t + 9 = 17.
Additional Example 1A: Determining Whether a Number is a Solution of an Equation
26
26 + 9 = 17?
35 = 17?
26 is not a solution of t + 9 = 17.
Substitute 26 for t.
t + 9 = 17
Course 2
1-10 Equations and Their Solutions
Additional Example 1B: Determining Whether a Number is a Solution of an Equation
Determine whether the given value of the variable is a solution of t + 9 = 17.
8
8 + 9 = 17?
17 = 17?
8 is a solution of t + 9 = 17.
Substitute 8 for t.
t + 9 = 17
Course 2
1-10 Equations and Their Solutions
LearnLearn to solve one-step equations. to solve one-step equations.
Sections 1.11 and 1.12 in textbook.Sections 1.11 and 1.12 in textbook.
Course 2
12-1 Solving Two-Step Equations
How to solve one-step equations
1. Goal – Get the variable alone2. Use the inverse operation to undo
On BOTH sides of the equationAddition and Subtraction are inverse operationsMultiplication and Division are inverse
operations**Remember – Whatever you do to one side you MUST do
to the other side!!!
2-Column NotesExample #1b + 2 = 6 Step 1
-2 -2 Step 2
b = 4 Step 3
Check 4 + 2 = 6 Step 4
6 = 6 Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
2-Column NotesExample #2n – 36 = 17 Step 1
+36 +36 Step 2
n = 53 Step 3
Check 53–36 = 17 Step 4
17 = 17 Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
2-Column NotesExample #318 + j =94 Step 1
-18 -18 Step 2
j = 76 Step 3
Check 18+76=94 Step
4
94 = 94 Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
2-Column NotesExample #4
Step 1 Step 2
Step 3 Step 4
Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
9 108
9 108
9 912
9 12 108
108 108
q
q
q
check
2-Column NotesExample #5
Step 1 Step 2 Step 3 Step 4
Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
135
5 13 55
65
6513
513 13
z
z
z
check
2-Column NotesExample #6
Step 1 Step 2
Step 3 Step 4
Step 5
Instructions – STEPS
1) Copy Problem2) Inverse Operation
on BOTH sides*Do the Math!!!!
3) Solution – Box –in4) Check AnswerRewrite equation with Value substituted5) Do Math and check
BOTH sides
2211
11 22 1111242
24222
1122 22
w
w
w
check
When you solve equations that have one operation, you use an inverse operation toisolate the variable. You can also use inverseoperations to solve equations that have morethan one operation.
n + 7 = 15– 7 –7
n = 8
2x + 3 = 23
– 3 – 32x = 20 You need to use
another operationto isolate x.
It is often a good plan to follow the order of operations in reverse when solving equationsthat have more than one operation.
Course 2
12-1 Solving Two-Step Equations
LearnLearn to solve two-step equations. to solve two-step equations.
Course 2
12-1 Solving Two-Step Equations
Write down the directions to get to Pope High School from Hightower Trail MS parking lot.Directions to the
HSExplain how to
return to Hightower Trail MS.
Can you think of any other situations where you have to work backwards??????
How can the order of operations help us solve equations????List the order of
operations1.
2.
3.
4.
Now list it going backwards
1.
2.
3.
4.
Solve. Check each answer.
Additional Example 1A: Solving Two-Step Equations Using Division
9c + 3 = 39
9c + 3 = 39
– 3 –39c = 36
c = 4
Subtract 3 from both sides.
Divide both sides by 9.9c9
= 36 9
Course 2
12-1 Solving Two-Step Equations
Check.
Additional Example 1A Continued
9c + 3 = 39
9(4) + 3 39?=
?=
?=
36 + 3 39
39 39
Substitute 4 for c.
4 is a solution.
Course 2
12-1 Solving Two-Step Equations
Course 2
12-1 Solving Two-Step Equations
Reverse the order of operations when solving equations that have more than one operation.
Helpful Hint
Solve. Check the answer.
7c + 6 = 48
7c + 6 = 48
– 6 –67c = 42
c = 6
Subtract 6 from both sides.
Divide both sides by 7.7c7
= 42 7
Check It Out: Example 1A
Course 2
12-1 Solving Two-Step Equations
Check It Out: Example 1A Continued
Insert Lesson Title Here
Check.
7c + 6 = 48
7(6) + 6 48?=
?=
?=
42 + 6 48
48 48
Substitute 6 for c.
6 is a solution.
Course 2
12-1 Solving Two-Step Equations
Solve.
Additional Example 2A: Solving Two-Step Equations Using Multiplication
6 + y5 = 21y5 = 216 +
– 6 –6y5
= 15
y5
= (5)15(5)
y = 75
Subtract 6 from both sides.
Multiply both sides by 5.
Course 2
12-1 Solving Two-Step Equations
Solve.
Additional Example 2B: Solving Two-Step Equations Using Multiplication
x7 – 11 = 9
x7 – 11 = 9
x7 = 20
x7 = (7)20(7)
x = 140
Add 11 to both sides.
Multiply both sides by 7.
+11 +11
Course 2
12-1 Solving Two-Step Equations
Check It Out: Example 2A
Insert Lesson Title Here
Solve.
8 + y2 = 48y2 = 488 +
– 8 –8y2 = 40
y2
= (2)40(2)
y = 80
Subtract 8 from both sides.
Multiply both sides by 2.
Course 2
12-1 Solving Two-Step Equations
Check It Out: Example 2B
Insert Lesson Title Here
Solve.
x5 – 31 = 19
x5 – 31 = 19
+31 +31x5 = 50
x5 = (5)50(5)
x = 250
Add 31 to both sides.
Multiply both sides by 5.
Course 2
12-1 Solving Two-Step Equations
Out ticket Show each step and number each stepSolve and Check
1. 4w – 3 = 25 2.
2 123
x