Multiplying and Dividing Polynomials Chapter 5 Sections 5.4-5.7.

Multiplying and Dividing Polynomials

Chapter 5 Sections 5.4-5.7

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Multiplication of Monomials5.4

• In the expression 24, the number 2 is called the base, and 4 is called the exponent.

• The expression may also be called the fourth power of 2.In x3, the letter x is called the base and 3 is called the exponent.

Multiplication of Monomials

• a. x3 x2 = (x x x)(x x)

• b. a4 a2 = (a a a a)(a a)

• c. c5 c3 = (c c c c c)(c c c)

= x5

= a6

= c8

Rule 1 for Exponents: Multiplying Powers

am an = am+n

That is, to multiply powers with the same base, add the exponents.

• To multiply two monomials, multiply their numerical coefficients and combine their variable factors according to Rule 1 for exponents.

• Multiply: (2x3)(5x4)

• (2x3)(5x4) = 2 5 x3 x4 = 10x3 +

4

• = 10x7

Multiplication of Monomials

Add the exponents.

• Rule 2 for Exponents: Raising a Power to a Power

• (am)n = amn

• That is, to raise a power to a power, multiply the exponents.

• (x3)5 = x3

5 = x15

• Rule 3 for Exponents: Raising a Product to a Power

• (ab)m = ambm

• That is, to raise a product to a power, raise each factor to that same power.

• Example 6• (xy)3 (xy)3 = x3y3

• Example 7 • (-2h3 k6 m2 )5 = (-2)5 (h3 )5 (k6 )5 (m2 )5 = -32h15 k30 m10

Multiplication of Monomials

A special note about the meaning of – x2 is needed here. Note that x is squared, not – x. That is,

– x2 = – (x x)

If – x is squared, we have (– x)2 = (– x)(– x) = x2.

Multiplication of Monomials

(-3x4 )4 = (-3)4 (x4 )4 = 81 x16

-(3xy)2 = - 9 x2 y2

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Multiplication of Polynomials5.5

• To multiply a polynomial by a monomial, multiply each term of the polynomial by the monomial, and then add the products as shown in the following example.

Multiplication of Polynomials

Multiply: 3a(a2 – 2a + 1).

3a(a2 – 2a + 1) = 3a(a2) + 3a(–2a) + 3a(1)

= 3a3 – 6a2 + 3a

Multiplying Two Polynomials

• To multiply one polynomial by another simply distribute both the terms of the first to the terms of the second, then combine like terms.

• (5x – 3) (2x + 4) =• (5x)(2x) + (5x)(+4) + (-3)(2x) + (-3)(+4) =• 10x2 + 20x + (-6x) + (-12) = • 10 x2 + 14x -12• Some people think of this as FOIL meaning multiply First terms,

Outer terms, Inner terms, then Last terms. Then combine all like terms.

FOIL• Some people think of this as FOIL meaning

multiply First terms, Outer terms, Inner terms, then Last terms. Then combine all like terms.

• (2x + 5 ) ( x + 3) • First terms: (2x)(x) Outer terms: (2x)(3)• Inner terms: (5)(x) Last terms (5)(3)• 2x2 + 6x + 5x + 15 = • 2x2 + 11x + 15

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Division by a Monomial5.6

• To divide a monomial by a monomial, first write the quotient in fraction form.

1. Write the problem in fraction form.

2. Reduce to lowest terms by dividing both the numerator and the denominator by their common factors.

3. Subtract any exponents of like terms.

4. Write your final answers.

Division by a Monomial

Examples

• 6a2 : 2a = 6a2 = 3 a2-1 = 3a• 2a

• 6a2 b c3 = 3 a2-1 b1-2 c3-1 = 3 a b-1 c2

10 a b2 c 5 5

Note: negative exponents should be placed in the denominator so final answer would be 3 a c2

5 b

• Divide:

Example 4

Divide each term of the polynomial by 3x.

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Division by a Polynomial5.7

• Dividing a polynomial by a polynomial of more than one term is very similar to long division in arithmetic. We use the same names, as shown below.

Division by a Polynomial

• Step:• 1. Divide the first term of the dividend, 2x2, by the first• term of the divisor, x. Write the result, 2x, above the• dividend in line 1.

Example 1 cont’d

• 2. Multiply the divisor, x + 3, by 2x and write the result,

• 2x2 + 6x, in line 3 as shown.

• 3. Subtract this result, 2x2 + 6x, from the first two terms

• of the dividend, leaving –5x. Bring down the last

• term of the dividend, –14, as shown in line 4.

• 4. Divide the first term in line 4, –5x, by the first term

• of the divisor, x. Write the result, –5, to the right of 2x

• above the dividend in line 1.

Example 1 cont’d

• 5. Multiply the divisor, x + 3, by –5 and write the result,

–5x – 15, in line 5 as shown.

• 6. Subtract line 5 from line 4, leaving 1 as the remainder.

• Since the remainder, 1, is of a lower degree than the

• divisor, x + 3, the problem is finished. The quotient is

• 2x – 5 with remainder 1.

Example 1 cont’d

• As a check, you may use the relationship

• dividend = divisor quotient + remainder.

Division by a Polynomial

• The dividend should always be arranged in decreasing order of degree.

• Any missing powers of x should be filled in by using zeros as coefficients.

• For example, x3 – 1 = x3 + 0x2 + 0x – 1.

Division by a Polynomial

Resources for Practice

• Pg. 234 29, 31, 33, 37-38• Pg. 236 1, 13, 27, 40, 50• Pg. 238 1-2

• Video resource:• http://www.youtube.com/watch?v=Il5JgYl4R2

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