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Multiplexing in
Communication SystemBHAVIN V KAKANI
IT, NU
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Multiplexing
Multiplexing is the set of techniques thatallows the simultaneous transmission ofmultiple signals across a single data link.
A Multiplexer(MUX) is a device thatcombines several signals into a singlesignal.
A Demultiplexer(DEMUX) is a device thatperforms the inverse operation.
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Categories of Multiplexing
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Frequency-division Multiplexing (FDM)
FDM is an analog technique that can be applied whenthe bandwidth of a link is greater than the combinedbandwidths of the signals to be transmitted.
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Frequency-division Multiplexing (FDM)
In FDM signalsgenerated by eachdevice modulatedifferent carrierfrequencies. These
modulated signals arecombined into asingle compositesignal that can betransported by the
link.
FDM is an analog mul tiplexing technique
that combines signals.
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Modulating (Modulation)
In analog transmission, the sendingdevice produces a high frequency signal(a sine wave) that acts as a basis for the
information signal. This base signal iscalled the carrier signal.
Digital information is then modulated onthe carrier signal by modifying one or
more of its characteristics (amplitude,frequency, phase). This kind ofmodification is called modulation andthe information signal is called amodulating signal.
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Modulation (Amplitude Shift keyingASK)
Time-domain description
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Modulation (Amplitude Shift keyingASK)
Frequency-domain description
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Frequency-division Multiplexing (FDM)
In FDM signals generated by each device modulate
different carrier frequencies. These modulated
signals are combined into a single composite signal
that can be transported by the link.
Carrier frequencies are separated by enoughbandwidth to accommodate the modulated signal.
These bandwidth ranges arte the channels through
which various signals travel.
Channels must separated by strips of unusedbandwidth (guard bands) to prevent signal
overlapping.
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Frequency-division Multiplexing (FDM)
In FDM, signals are modulated onto separatecarrier frequencies using either AM or FMmodulation.
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Example 1
Assume that a voice channel occupies a bandwidth of 4
KHz. We need to combine three voice channels into a link
with a bandwidth of 12 KHz, from 20 to 32 KHz. Show
the configuration using the frequency domain without the
use of guard bands.
Solution
Shift (modulate) each of the three voice channels to adifferent bandwidth, as shown in Figure 6.6.
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Example 1
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Example 2
Five channels, each with a 100-KHz bandwidth, are to be
multiplexed together. What is the minimum bandwidth of
the link if there is a need for a guard band of 10 KHz
between the channels to prevent interference?
Solution
For five channels, we need at least four guard bands.
This means that the required bandwidth is at least
5 x 100 + 4 x 10 = 540 KHz,
as shown in Figure 6.7.
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Example 2
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Wave-division Multiplexing (WDM)
Wave-division multiplexing isconceptually the same as FDM, exceptthat multiplexing and demultiplexing
involve light signals transmitted throughfiber-optic channels.
The purpose is to combine multiple lightsources into one single light at the
multiplexer and do the reverse at thedemultiplexer.
Combining and splitting of light sourcesare easily handled by a prism.
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The only difference with electrical FDM is that onoptical system is completely passive and thushighly reliable.
Due to its enormous bandwidth of around 25KGHz, there is a potential of multiplexing manychannels together over long routes.
Potential application of WDM is in the FTTC (FiberTo The Curb) systems.
Important application of WDM is the SONETnetworks in which multiple optical fiber lines aremultiplexed.
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Time-division Multiplexing (TDM)
Time-division multiplexing (TDM) is a digital process thatcan be applied when the data rate capacity of thetransmission medium is greater than the data raterequired by the sending and receiving devices.
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Data Rate
For T DM, the data rate of the multiplexed signal isalways n times the data rate of the individualsources, where n is the number of sources.
If 3 sources are multiplexed, then the data rate ofthe TDM signal is 3 times higher than the individualdata rate.
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TDM
TDM is a digital mul tiplexing technique to
combine data.
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Time-division Multiplexing (TDM)
TDM can be implemented in two ways:synchronous TDM and asynchronous TDM.
In synchronous time-division multiplexing, the
term synchronous means that the multiplexerallocates exactly the same time slot to eachdevice at all times, whether or not a devicehas anything to transmit.
Frames
Time slots are grouped into frames. A frameconsists of a one complete cycle of timeslots, including one or more slots dedicatedto each sending device.
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TDM frames
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Example 5
Four 1-Kbps connections are multiplexed together. A unit
is 1 bit. Find (1) the duration of 1 bit before multiplexing,
(2) the transmission rate of the link, (3) the duration of a
time slot, and (4) the duration of a frame?
Solution
We can answer the questions as follows:
1. The duration of 1 bit is 1/1 Kbps, or 0.001 s (1 ms).2. The rate of the l ink is 4 Kbps.
3. The duration of each time slot 1/4 ms or 250 s.
4. The duration of a frame 1 ms.
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I nter leaving
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Example 6
Four channels are multiplexed using TDM. If each
channel sends 100 bytes/s and we multiplex 1 byte per
channel, show the frame traveling on the link, the size of
the frame, the duration of a frame, the frame rate, and the
bit rate for the link.
Solution
The multiplexer is shown in Figure 6.15.
E l 6
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Example 6
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Example 7
A multiplexer combines four 100-Kbps channels using a
time slot of 2 bits. Show the output with four arbitrary
inputs. What is the frame rate? What is the frame
duration? What is the bit rate? What is the bit duration?
Solution
Figure 6.16 shows the output for four arbitrary inputs.
E l 7
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Example 7
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Time-division Multiplexing (TDM)
Framing Bits
Because the time slot order in a synchronous
TDM system does not vary from frame to
frame, very little overhead information needs
to be included in each frame. However, one
or more synchronization bits are usually
added to the beginning of each frame.
These bits, called framing bits, allows thedemultiplexer to synchronize with the
incoming stream so that it can separate the
time slot accurately.
F i bit
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Framing bits
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Example
Suppose that we have four input devices on a synchronous TDM
link, where the transmissions are interleaved by character. If
each device is generating 250 characters per second, and each
frame is carrying 1 character from each device, what is the
minimum data rate of this link?
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The link must be able to carry250 frames per second.
If we assume that eachcharacter consists of 8bits, then each frame has4x8 + 1= 33 bits ( 32 bits forthe four characters plus 1framing bit).
On the other hand, eachdevice is creating2000bps, because 250characters per second x 8bits =2000 bits per second,and the link is carrying8250 bps, because 250frames per second x33 bitsis 8250 bps.
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Example 8
We have four sources, each creating 250 characters persecond. If the interleaved unit is a character and 1
synchronizing bit is added to each frame, find (1) the data
rate of each source, (2) the duration of each character in
each source, (3) the frame rate, (4) the duration of each
frame, (5) the number of bits in each frame, and (6) the
data rate of the link.
Solution
See next slide.
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Solution (continued)
We can answer the questions as follows:
1. The data rate of each source is 2000 bps = 2 Kbps.
2. The duration of a character is 1/250 s, or 4 ms.
3. The link needs to send 250 frames per second.4. The duration of each frame is 1/250 s, or 4 ms.
5. Each frame is 4 x 8 + 1 = 33 bits.
6. The data rate of the link is 250 x 33, or 8250 bps.
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Example 9
Two channels, one with a bit rate of 100 Kbps and
another with a bit rate of 200 Kbps, are to be multiplexed.How this can be achieved? What is the frame rate? What
is the frame duration? What is the bit rate of the link?
Solution
We can allocate one slot to the first channel and two slots
to the second channel. Each frame carries 3 bits. The
frame rate is 100,000 frames per second because itcarries 1 bit from the first channel. The frame duration is
1/100,000 s, or 10 ms. The bit rate is 100,000 frames/s x
3 bits/frame, or 300 Kbps.
DS hierarchy
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DS hierarchy
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Table 6.1 DS and T l ines rates
Service LineRate
(Mbps)
Voice
Channels
DS-1 T-1 1.544 24
DS-2 T-2 6.312 96
DS-3 T-3 44.736 672
DS-4 T-4 274.176 4032
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Table 6.2 E line rates
E LineRate
(Mbps)
Voice
Channels
E-1 2.048 30
E-2 8.448 120
E-3 34.368 480
E-4 139.264 1920
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Asynchronous TDM
Synchronous TDM does not guarantee that the full
capacity of a link is used. Because the time slots arepreassigned and fixed, whenever a connected device
is not transmitting, the corresponding slot is empty.
Asynchronous time-division multiplexing, or statistical
time-division multiplexing, is designed to avoid thistype of waste.
Like synchronous TDM, asynchronous TDM allows a
number of lower-speed input lines to be multiplexed
to a single higher-speed line. However, in
asynchronous TDM the total speed of the input lines
can be greater than the capacity of the link.
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In an asynchronous system,
if we have n input lines, the
frame contains no more than
m slots, with m less than n.
The number of time slots in
an asynchronous TDM
frame (m) is based onstatistical analysis of the
number of input lines that
are likely to be transmitting
at any given time.
In this case any slot is
available to any of the
attached input lines that has
data to send.
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Asynchronous TDM
Addressing and Overhead
In asynchronous TDM each time slot mustcarry an address telling the demultiplexerhow direct the data. This address, forlocal use only, is attached by themultiplexer and discarded by the
demultiplexer once it has been read. Asynchronous TDM is efficient only when
the size of the time slots kept relativelylarge.
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Inverse Multiplexing
Inverse multiplexing takesthe data stream from onehigh-speed line andbreaks it into portions thatcan be sent across severallower-speed linessimultaneously, with noloss in the collective datarate.
Figure 6.21 Multiplexing and inverse mul tiplexing
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