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Mst541 Unit i

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  • Theory of Games

    Unit-I

    Prof. Narinder Verma

  • School of Business Management prof Narinder Verma2

    Strategic Behavior- Uncertain

    A lot of what we do, involves optimizing against various alternatives:

    What should I do after 10+2?

    Should I do MBA after graduation?

    What should be my major specialization?

    What kind of job be my dream job?

    Should I join family business?

  • School of Business Management prof Narinder Verma3

    Strategic Behavior- Uncertain

    Or at times against nature in general:

    Should I take an umbrella today?

    What crops should I plant this season?

    How do we treat this disease or injury?

    How do I fix my out of order car?

    We sometimes imagine it as a game against opponents

  • School of Business Management prof Narinder Verma4

    Prisoners DilemmaTwo suspects arrested for a crime were put into

    prison separately.

    prisoners decide whether to confess or not.

    If both confess, both sentenced to 5 years of jail

    If neither confesses, both will be sentenced to 1 year of jail

    If one confesses and the other does not, then the confessor goes free (no jail) and the non-

    confessor sentenced to 9 years of jail

    What should each prisoner do?

  • School of Business Management prof Narinder Verma5

    Battle of Seaes

    A couple deciding how to spend the evening

    Wife would like to go for a movie

    Husband would like to go for a cricket match

    Both however want to spend the time together

    Scope for strategic interaction

  • School of Business Management prof Narinder Verma6

    Understanding the Game

    Game refers to a situation of conflict

    and competition in which two or more

    competitors are involved in the

    decision-making process in anticipation

    of certain outcomes over a period of

    time.

    1. Competitors are called players

    2. Action is called Strategy

    3. Anticipated outcome is the payoff

  • School of Business Management prof Narinder Verma7

    Understanding the Game

    1. pricing of products is affected by

    the price of the competitor.

    2. Success of TV programme

    depends upon the presence of

    competing TV programmes in the

    same time slot.

    A basic feature here is that the final

    outcome depends primarily upon

    the combination of strategies

  • School of Business Management prof Narinder Verma8

    Game theory is a series of mathematical

    models that deal with interactive

    decision-making situations under the

    conditions of conflict and competition.

    The study of oligopolies

    The study of cartels; e.g. OPEC

    The study of military strategies.

    Study of effect of promotional campaigns

    Defining Game Theory

  • School of Business Management prof Narinder Verma9

    Game Theory

    Game theoretic notions go back thousands of years

    Talmud and Sun Tzu's writings.

    Modern theory credited to John von Neumann and Oskar Morgenstern 1944.

    Theory of Games and Economic Behavior.

    John Nash (A Beautiful Mind fame) generalized these results and provided the basis of the modern field.

  • School of Business Management prof Narinder Verma10

    Classification of Games

    2-person Game:

    A game that involves exactly two players

    n-person Game

    A game that involves exactly n players

    Zero-sum Game:

    When the sum of gains to one player is exactly equal to the losses to other player, so that the sum of the gains and the losses is equal to zero(0).

    Non-zero sum Game:

    A game whose sum is not equal to zero

  • School of Business Management prof Narinder Verma11

    Classification of Games

    Simultaneous Move Game:

    Each player has to take action simultaneously like Racing, Stone-paper-Scissors, Chidiya Ud etc

    Sequential Move Game

    One player moves

    Second player observes and then moves

    Like Chess, Tic-Tac-Toe (naughts and crosses), Discuss Throw, promotional campaigns by competitors

  • School of Business Management prof Narinder Verma12

    Elements of a Game

    A game consists of:

    A set of players

    A set of strategies for each player

    The payoffs to each player for every possible strategy

    Strategy is a course of action that a

    player adopts for every payoff

  • School of Business Management prof Narinder Verma13

    Strategies of Games

    Optimal Strategy:

    The particular strategy that optimizes a players gains or losses, without knowing the competitors courses of action

    Pure Strategy:

    A particular strategy that a player chooses

    to play again and again regardless of other

    players strategies

    It is a deterministic situation

  • School of Business Management prof Narinder Verma14

    Strategies of GamesMixed Strategy:

    A set of strategies that a player chooses on a particular move of the game with some fixed probabilities

    It is a probabilistic situation

    Value of the Game:

    It is the expected gain or loss in a game

    when a game is played a large number of

    times

    It is represented by V

  • School of Business Management prof Narinder Verma15

    payoff matrix to player A

    a11 a12 a1n

    a21 a22 ........ a2n

    .

    . aij

    am1 am2 . amn

    A1

    A2

    .

    .

    Am

    Two-person Zero-sum Game

    B1 B2 Bn

    Strategies of player BS

    tra

    teg

    ies

    of

    pla

    yer

    A

  • School of Business Management prof Narinder Verma16

    A1,A2,..,Am are the strategies of player A

    B1,B2,...,Bn are the strategies of player B

    aij is the payoff to player A (by B) when the player A plays strategy Aiand B plays Bj (aij is ve means B got |aij| from A)

    Two-person Zero-sum Game

  • School of Business Management prof Narinder Verma17

    Two boutiques A and B in Solan compete

    such that each gets 50% of clientele. As gain would be Bs loss. B moots an idea to gain market share by:

    1. Discount coupons - B1

    2. Decreasing price - B2

    3. TV Advertisement - B3

    4. 10% Cash Back - B4

    Two-person Zero-sum Game

  • School of Business Management prof Narinder Verma18

    A has an idea that B might do this. So A

    also moots an idea to gain market share

    by:

    1. Discount coupons - A1

    2. TV Advertisement - A2

    3. 10% Cash Back - A3

    The payoff matrix in Rupees for boutique

    A is given as:

    Two-person Zero-sum Game

  • School of Business Management prof Narinder Verma19

    8 -6 2 1

    4 9 4 5

    7 -5 3 -7

    B1 B2 B3 B4

    A1

    A2

    A3

    Strategies of player B

    Str

    ate

    gie

    s o

    f

    pla

    yer

    A

    1. Find the optimal strategies for both A and B.

    2. Find the value of the game.

  • School of Business Management prof Narinder Verma20

    Maximin and Minimax principle

    Maximin principle:

    For each row, find the minimum, then

    The maximum out of these minimums is the Maximin value for A

    Minimax principle:

    For each column, find the maximum, then

    The minimum out of these maximums is the Minimax value for B

  • School of Business Management prof Narinder Verma21

    Maximin and Minimax principle

    Saddle point:

    When Maximin value is equal to the Minimax value then the game is said to have an equilibrium point.

    Equilibrium point is called the Saddle point.

    The corresponding strategies are called optimal strategies. These are the pure ones.

    At saddle point,

    Maximin = Minimax = Value of Game (V)

  • School of Business Management prof Narinder Verma22

    Maximin and Minimax principleA game may have more than one saddle point.

    A game may not have a saddle point at all.

    In general,

    Maximin Value V Minimax Value

    A game is said to be a fair game if the

    Maximin = Minimax = 0 (zero)

    A game is said to be strictly determinable if

    the Maximin = Minimax = Value of the game (V)

  • School of Business Management prof Narinder Verma23

    8 -6 2 1

    4 9 4 5

    7 -5 3 -7

    B1 B2 B3 B4

    A1

    A2

    A3

    MaxCol 8 9 4 5

    Row min

    -6

    4

    -7

    minimax

    maximin

    Illustration Continues

  • School of Business Management prof Narinder Verma24

    Solution is based on the principle of securing

    the best of the worst for each player. If the

    player A plays strategy A1, then whatever

    strategy B plays, A will get at least -6 (loses

    at most Rs. 6).

    Thus to maximize its minimum returns, A

    should play strategy A2.

    If A plays strategy A2, then whatever B

    plays, will get at least 4. and if A plays

    strategy A3, then he will get at least -7(loses

    at most Rs. 7) whatever B plays.

  • School of Business Management prof Narinder Verma25

    Now if B plays strategy B1, then whatever

    A plays, he will lose a maximum of 8.

    Similarly for strategies B2,B3,B4. (These

    are the maximum of the respective

    columns).

    Maximin = Minimax = 4 = Saddle point

    Thus here, 4 is value of the game and

    appropriate strategies are A2, B3

    Thus to minimize this maximum

    loss, B should play strategy B3.

  • School of Business Management prof Narinder Verma26

    Two boutiques A and B in Solan compete

    such that each gets 50% of clientele. As gain would be Bs loss. B moots an idea to gain market share by:

    1. Discount coupons - B1 2. Decreasing price - B23. TV Advertisement - B34. 10% Cash Back - B45. Newspaper Inserts - B5

    Illustration 2

  • School of Business Management prof Narinder Verma27

    A has an idea that B might do this. A also

    moots an idea to gain market share by:

    1. Discount coupons - A12. Decrease price - A23. TV Advertisement - A34. 10% Cash Back - A4

    The payoff matrix in Rupees for boutique

    A is given as:

    Illustration 2

  • School of Business Management prof Narinder Verma28

    3 -1 4 6 7

    -1 8 2 4 12

    16 8 6 14 12

    1 11 -4 2 1

    B1 B2 B3 B4

    A1

    A2

    A3

    A4

    Strategies of player B

    Str

    ate

    gie

    s o

    f

    pla

    yer

    A

    1. Find the optimal strategies for both A and B.

    2. Find the value of the game.

    B5

  • School of Business Management prof Narinder Verma29

    maxCol 16 11 6 14 12

    Row min

    -1

    -1

    6

    -4

    minimax

    maximin

    Illustration 2

    3 -1 4 6 7

    -1 8 2 4 12

    16 8 6 14 12

    1 11 -4 2 1

    B1 B2 B3 B4 B5

    A1

    A2

    A3

    A4

  • School of Business Management prof Narinder Verma30

    Illustration 3

    The following game gives As payoff. Determine p, q that will make the entry a22 a saddle point.

    1 q 6

    p 5 10

    6 2 3

    A1

    A2

    A3

    B1 B2 B3

    Col max 6 5 10

    Row min

    1

    5

    2

  • School of Business Management prof Narinder Verma31

    Since a22 must be a saddle point,

    There for p has to be at least as large

    as 5, so

    And also q has to be at least as small

    as 5, so

    5p

    5q

    Illustration 3

    Find row minimums and column

    maximums with considering the

    values of unknowns

  • School of Business Management prof Narinder Verma32

    Specify the range for the value of the

    game in the following case assuming

    that the payoff is for player A.

    3 6 1

    5 2 3

    4 2 -5

    A1

    A2

    A3

    B1 B2 B3

    Col max 5 6 3

    Row min

    1

    2

    -5

    Illustration 4

  • School of Business Management prof Narinder Verma33

    maximin minimax (2 3)

    Hence the game has no saddle point.

    When there is no saddle point, then

    Maximin Value V Minimax Value i.e., 2 V 3.

    Thus the value of the game lies

    between 2 and 3.

    Illustration 4

  • School of Business Management prof Narinder Verma34

    Principles of DominanceThese are used to reduce the size of the payoff matrix by deleting certain inferior rows and or columns

    Dominance rules are especially used for the evaluation of the two-person zero-sum games without a saddle point

    1. For player B who is assumed to be a loser, if each element in a column Cr is greater than or epual to the corresponding element in another column Cs then the column Cr is said to be dominated by Cs (or inferior to) and there column Cr can be deleted

  • School of Business Management prof Narinder Verma35

    Principles of Dominance

    2. For player A who is assumed to be a gainer, if each element in a row Rr is less than or equal to the corresponding element in another row Rs then the row Rr is said to be dominated by Rs (or inferior to) and there row Rr can be deleted

    3. A strategy k can also be dominated if it is inferior to an average of two or more other pure strategies

    Dominance rules are framed assuming that the payoff matrix is a profit matrix for player A

  • School of Business Management prof Narinder Verma36

    8 6 2 8

    8 9 4 5

    7 5 3 5

    B1 B2 B3 B4

    A1

    A2

    A3

    Strategy A3 is dominated by the

    strategy A2 and so can be eliminated.

    Eliminating the strategy A3 , we get:

    Principles of Dominance:Ex1

  • School of Business Management prof Narinder Verma37

    8 6 2 8

    8 9 4 5

    B1 B2 B3 B4A1

    A2

    Eliminating the strategies B1 , B2, and

    B4 we get the reduced payoff matrix:

    For player B, strategies B1, B2, and B4 are

    dominated by the strategy B3.

    Principles of Dominance:Ex1

  • School of Business Management prof Narinder Verma38

    2

    4

    B3

    A1

    A2

    Now , for player A, strategy A1 is dominated

    by the strategy A2

    Eliminating the strategy A1

    Principles of Dominance:Ex1

  • School of Business Management prof Narinder Verma39

    4

    B3

    A2

    We thus see that A should always play A2 and B always B3 and the value of the game

    is 4 as before.

    Principles of Dominance:Ex1

  • School of Business Management prof Narinder Verma40

    -5 10 20 8

    5 -10 -10 6

    5 -20 -20 7

    B1 B2 B3 B4

    A1

    A2

    A3

    Strategy B3 is dominated by the

    Strategies B1 and B2 and so can be

    eliminated

    B4 is inferior to B1 so is deleted., we get:

    Principles of Dominance:Ex2

  • School of Business Management prof Narinder Verma41

    -5 10

    5 -10

    5 -20

    B1 B2A1

    A2

    Eliminating the strategy A3 we get the

    reduced payoff matrix:

    For player A, strategy A3 is dominated by

    the strategy A2.

    Principles of Dominance:Ex2

    A3

  • School of Business Management prof Narinder Verma42

    B1 B2A1

    A2

    The game has no saddle point as

    was the case originally.

    Principles of Dominance:Ex2

    -5 10

    5 -10

  • School of Business Management prof Narinder Verma43

    Used for (2 a n) or (m a 2) games, i.e.,

    for two-person zero-sum games where

    at least one player has only 2 strategies

    It is assumed that the player with two

    strategies, chooses a mixture of both

    the strategies with some fixed but

    unknown probabilities, to be calculated

    Mixed Strategies:

    Graphical Method

  • School of Business Management prof Narinder Verma44

    a11 a12 . a1n

    a21 a22 . a2n

    B1 B2 . Bn

    A1

    A2

    player A selects two strategies A1 and A2

    with probabilities p1 and p2 respectively

    Graphical Method: 2 x n Game

    Probability

    p1

    p2

    player Bplayer A

    Probability p1 p2 .. pn

  • School of Business Management prof Narinder Verma45

    Such that 1,2 0 and 1 + 2 = 1

    Graphical Method: 2 x n Game

    Expected Payoff for Player A

    Bs pure Strategies As Expected Payoff

    B1 + B2 + B3 + . .

    . .

    . .

    Bn +

  • School of Business Management prof Narinder Verma46

    Now plot probabilities on a- axis and

    Expected payoff on Y- axis

    Choose the lower envelope if initial

    payoff was for A, and

    player A has two strategies (as here)

    Graphical Method: 2 x n Game

  • School of Business Management prof Narinder Verma47

    Graphical: Illustration 1

    2 4 3 8 4

    5 6 3 7 8

    10 5 9 8 7

    4 2 8 4 3

    B1 B2 B3 B4 B5

    A1

    A2

    A3

    A4

    A1 and A4 are dominated by A3

  • School of Business Management prof Narinder Verma48

    Graphical: Illustration 1

    5 6 3 7 8

    10 5 9 8 7

    B1 B2 B3 B4 B5

    A2

    A3

    B1 is dominated by B3,so B1 gets deleted

  • School of Business Management prof Narinder Verma49

    Graphical: Illustration 1

    6 3 7 8

    5 9 8 7

    B2 B3 B4 B5

    A2

    A3

    Probability

    p1

    p2

    Assume that player A selects Strategies

    A2 and A3 with probabilities p1 and p2respectively

  • School of Business Management prof Narinder Verma50

    Such that 1,2 0 and 1 + 2 = 1

    Graphical : Illustration 1

    Expected Payoff for Player A

    Bs pure Strategies As Expected Payoff

    B2 + B3 + B4 + B5 +

  • School of Business Management prof Narinder Verma51

    M

    As Expected payoff, A1

    probability

    B2

    9

    8

    7

    6

    5

    4

    3

    2

    1

    0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1(0, 0)

    Graphical : Illustration 1

    9

    8

    7

    6

    5

    4

    3

    2

    1

    p1=1, p2=0 p1=0, p2=1

    (0, 0)

    As Exapected payoff, A2B3B4

    B5

    L

    N

  • School of Business Management prof Narinder Verma52

    Out of three points L, M and N; M

    represents Maximin, so M is the

    optimal mixed strategy

    Solve payoff equations for B2 and B3

    + = + , and

    + =

    Graphical : Illustration 1

  • School of Business Management prof Narinder Verma53

    + ( ) = + ( )

    = + = +

    = + = +

    = =

    There for =

    and =

    and =

    Graphical : Illustration 1

  • School of Business Management prof Narinder Verma54

    Illustration 1: Calculation for B

    6 3

    5 9

    B2 B3

    A2

    A3

    probability q2 q3

  • School of Business Management prof Narinder Verma55

    Such that 2, 3 0 and 2 + 3 = 1

    Graphical : Illustration 1

    Expected Payoff for Player B

    As pure Strategies Bs Expected Payoff

    A2 + A3 +

  • School of Business Management prof Narinder Verma56

    + ( ) = + ( )

    = + = +

    = + = +

    = =

    There for =

    and =

    and =

    Graphical : Illustration 1

  • School of Business Management prof Narinder Verma57

    Simplex Method

    a11 a12 a1n

    a21 a22 ........ a2n

    .

    . aij

    am1 am2 . amn

    A1

    A2

    .

    .

    Am

    B1 B2 Bn

    Strategies of player B

    Str

    ate

    gie

    s o

    f p

    layer

    AProbability

    1

    2

    Probability q1 q2 qn

  • School of Business Management prof Narinder Verma58

    = =

    = , , , . . ,

    Simplex Method

    ,

    :

  • School of Business Management prof Narinder Verma59

    Simplex Method

    a11 p1+ a21 p2+ ... + am1 pm V

    a12 p1 + a22 p2 + ... + am2 pm V

    :

    a1n p1 + a2n p2 + ... + amn pm V

    p1 + p2 + ... + pm = 1

    pi 0 (Non-negativity constraints) = 1,2, 3, . . ,

    , ,

  • School of Business Management prof Narinder Verma60

    Simplex MethodDivide all constraints by V

    a111

    + a21

    2

    + ... + am1

    1

    a121

    + a22

    2

    + ... + am2

    1

    :

    a1n1

    + a2n

    2

    + ... + amn

    1

    1

    + 2

    + ... +

    = 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma61

    Simplex Method

    Let

    = so that

    a11 1+ a21 2+ ... + am1 1

    a12 1+ a22 2+ ... + am2 1

    :

    a1n 1+ a2n 2+ ... + amn 1

    1+2+ ... += 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma62

    Simplex Method

    =

    , there for,

    =

    = 1+2+ ... + ,

    a11 1+ a21 2+ ... + am1 1

    a12 1+ a22 2+ ... + am2 1

    :

    a1n 1+ a2n 2+ ... + amn 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma63

    Simplex Method

    a11 a12 a1n

    a21 a22 ........ a2n

    .

    . aij

    am1 am2 . amn

    A1

    A2

    .

    .

    Am

    B1 B2 Bn

    Strategies of player B

    Str

    ate

    gie

    s o

    f p

    layer

    AProbability

    1

    2

    Probability q1 q2 qn

  • School of Business Management prof Narinder Verma64

    = =

    = , , , . . ,

    Simplex Method

    ,

    :

  • School of Business Management prof Narinder Verma65

    Simplex Method

    a11 q1+ a12 q2+ ... + a1n qn V

    a21 q1 + a22 q2 + ... + a2n qn V

    :

    am1 q1 + am1 q2 + ... + amn qn V

    q1 + q2 + ... + qn = 1

    qj 0 (Non-negativity constraints) = 1,2, 3, . . ,

    , ,

  • School of Business Management prof Narinder Verma66

    Simplex MethodDivide all constraints by V

    a111

    + a12

    2

    + ... + a1n

    1

    a211

    + a22

    2

    + ... + a2n

    1

    :

    am11

    + am2

    2

    + ... + amn

    1

    1

    + 2

    + ... +

    = 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma67

    Simplex Method

    Let

    = so that

    a11 1+ a12 2+ ... + a1n 1

    a21 1+ a22 2+ ... + a1n 1

    :

    am1 1+ am2 2+ ... + amn 1

    1+2+ ... += 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma68

    Simplex Method

    =

    , there for,

    =

    = 1+2+ ... + ,

    a11 1+ a12 2+ ... + a1n 1

    a21 1+ a22 2+ ... + a2n 1

    :

    am1 1+ am2 2+ ... + amn 1

    0 = 1,2, 3, . . ,

  • School of Business Management prof Narinder Verma69

    Solve for ys as there are only slack variables

    X values will be calculated from dual

    values of slack in the primal for y

    For x values, take the absolute value of

    (cj-zj), i.e., | cj -zj| against slack variables

    For x1 take | cj -zj| against s1, for x2 take

    | cj -zj| against s2 and like wise

    Simplex Method

  • School of Business Management prof Narinder Verma70

    Note: As

    = 0 and

    = 0

    For this, value must be non-negative, i. e., 0 ,there for all aij 0

    For this, add {| largest negative aij | +1}to all aij . If value of the game now is .

    Original value of the game ( ) now is

    = { | | +1}

    Simplex Method

  • School of Business Management prof Narinder Verma71

    1 -1 3

    3 5 -3

    6 2 -2

    B1 B2 B3

    A1

    A2

    A3

    MaxCol 6 5 3 5

    Row min

    -1

    -3

    -2

    minimax

    maximin

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma72

    Clearly there is no saddle point

    Value of the game follows

    Here V can be negative, so add

    {| largest negative aij | +1} i.e., {| -3| +1}= 4 to all aij

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma73

    Modified Payoff Matrix

    Probability 1 2 3

    5 4 7

    7 9 1

    10 6 2

    B1 B2 B3

    A1

    A2

    A3

    Probability

    1

    2

    3

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma74

    F ; ,, and + + =

    Simplex Method : Illustration

    Expected Payoff for Player A

    Bs pure Strategies As Expected Payoff

    B1 + + B2 + + B3 + +

  • School of Business Management prof Narinder Verma75

    Simplex Method

    5 p1+7 p2+ 10 p3 V

    3 p1+9 p2+ 6 p3 V

    7 p1 + p2 + 2 p3 V

    p1 + p2 + p3 = 1

    p1, p2 , p3 0

    , ,

  • School of Business Management prof Narinder Verma76

    Simplex MethodDivide all constraints by V

    5

    + 7

    + 10 1

    3

    + 9

    + 6 1

    7

    +

    + 2 1

    +

    +

    =

    ,

    , 0

  • School of Business Management prof Narinder Verma77

    Simplex Method

    Let

    = ,

    = and

    = so that

    5 + 7 + 10 1

    3 + 9 + 6 1

    7 + + 2 1

    ++ =

    ,, 0

  • School of Business Management prof Narinder Verma78

    Simplex Method

    =

    , there for,

    =

    = ++ ,

    5 + 7 + 10 1

    3 + 9 + 6 1

    7 + + 2 1

    ,, 0

  • School of Business Management prof Narinder Verma79

    F ; ,, and + + =

    Simplex Method : Illustration

    Expected Payoff for Player B

    As pure Strategies Bs Expected Payoff

    A1 + + A2 + + A3 + +

  • School of Business Management prof Narinder Verma80

    Simplex Method

    5 q1 + 3 q2 + 7 q3 V

    7 q1 + 9 p2 + q3 V

    10 q1 + 6 q2 + 2 q3 V

    q1 + q2 + q3 = 1

    q1, q2 , q3 0

    , ,

  • School of Business Management prof Narinder Verma81

    Simplex MethodDivide all constraints by V

    5

    + 3

    + 7 1

    7

    + 9

    + 1

    10

    + 6

    + 2 1

    +

    +

    =

    ,

    , 0

  • School of Business Management prof Narinder Verma82

    Simplex Method

    Let

    = ,

    = and

    = so that

    5 + 3 + 7 1

    7 + 9 + 1

    1 + 6 + 2 1

    ++ =

    ,, 0

  • School of Business Management prof Narinder Verma83

    Simplex Method

    =

    , there for,

    =

    = ++ ,

    5 + 3 + 7 1

    7 + 9 + 1

    1 + 6 + 2 1

    ,, 0

  • School of Business Management prof Narinder Verma84

    Simplex Method: Illustration

    The Standard form of LPP with constraints is:

    = 1+ 2 + + 01 + 02 + 03

    Subject to

    5 1+ 3 2+ 7 3+ 1 1+ 0 2+ 0 3 = 1

    7 1+ 9 2+ 3+ 0 1+ 1 2+ 0 3 = 1

    10 1+ 6 2+ 2 3+ 0 1+ 0 2+ 1 3 = 1

    1 0, 2 0, 3 0, 1 0, 2 0, 3 0

  • School of Business Management prof Narinder Verma85

    Final Tableau with optimal solution:

    Cj 1 1 1 0 0 0

    CB

    Basic

    Variable

    (B)

    Basic

    Soln(YB)y1 y2 y3 s1 s2 s3

    1 y3 1/10 2/5 0 1 3/20 -1/10 0

    1 y2 1/10 11/15 1 0 -1/60 7/60 0

    0 s3 1/5 24/5 0 0 -1/5 -3/5 1

    17/15 0 0 2/15 1/15 0

    -2/15 0 0 -2/15 -1/15 0

    Zj

    (Net Evaluation)Cj - Zj

    Simplex Method: Illustration

    Zq= 1/5

  • School of Business Management prof Narinder Verma86

    Optimal strategy for B:

    = , =

    =

    =

    There for =

    =

    = there for = = =

    = there for = =

    =

    = there for = =

    =

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma87

    As =

    =

    Original value of the game ( ) now is

    = { | | +1}

    = { } =

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma88

    X values will be calculated from dual

    values of slack in the primal for y

    For x values, take the absolute value of

    (cj-zj), i.e., | cj -zj| against slack variables

    For x1 take | cj -zj| against s1, for x2 take

    | cj -zj| against s2 and like wise

    =

    , =

    =

    Simplex Method

  • School of Business Management prof Narinder Verma89

    Optimal strategy for A:

    =

    , =

    =

    = there for = =

    =

    = there for = =

    =

    = there for = = =

    = (

    ,

    , ), = ,

    ,

    , = 1

    Simplex Method: Illustration

  • School of Business Management prof Narinder Verma90

    End of Unit - I