http://chemclass4spm.blogspot.com http://chemclass4spm.blogspot.com Exercise : Interconversion Mole and Number of Particle Avogadro Constant : 6.02 x 10 23 1. Calculate the number of particles in a. 1 mol atom of copper 1 x 6.02 x 10 23 atoms. b. 0.0625 mole of water, H 2 O 0.0625 x 6.02 x 1023 molecules c. 1.3 mole of Sodium ions, Na + 1.3 x 6.02 x 1023 ions. 2. Calculate the number of atoms in a. 0.012 mole of ethane gas, C 2 H 6 8 x 0.012 x 6.02 x 1023 atoms. b. 1.1 mole of sulphur trioxide, SO 3 4 x 1.1 x 6.02 x 1023 atoms. c. 0.25 mole of water, H 2 O 3 x 0.25 x 6.02 x 1023 atoms. 3. Calculate the number of moles of the following substances a. 3.02 x 10 23 sodium atom (3.02 x 1023) ÷ (6.02 x 1023 ) b. 1.8 x 10 24 H 2 S molecules (1.8 x 1024) ÷ (6.02 x 1023 ) 4. Calculate the number of moles of a. 7 g of Nitrogen gas, N 2 RMM of N2 = 14, Mole = 7÷14 = 0.5 mol b. 5.75 g of Sodium atom, Na RMM of Na = 23, Mole = 5.75 ÷23 = 0.25 mol c. 16 g of Oxygen gas, O 2 RMM of O2 = 32, Mole = 16 ÷ 32 = 0.5 mol d. 15 g of iron, Fe RMM of Fe = 56, Mole = 15÷56 = 0.27 mol 5. Calculate the number of molecules found in a. 14g of Nitrogen gas, N 2 RMM of N2 = 14, Mole = 14÷14 = 1 mol 1 x 6.02 x 1023 molecules b. 22g of Carbon dioxide gas, CO 2 RMM of CO2 = 44, Mole = 22÷44 = 0.5 mol 0.5 x 6.02 x 1023 molecules c. 1.6 g of Oxygen gas, O 2 RMM of O2 = 32, Mole = 1.6 ÷ 32 = 0.05 mol 0.05 x 6.02 x 1023 molecules 6. Calculate the number of atoms found in a. 14g of Nitrogen gas, N 2 RMM of N2 = 14, Mole = 14÷14 = 1 mol 1 x 6.02 x 1023 molecules 1 molecules of N2 consists of 2 mol N atom 2 x 1 x 6.02 x 1023 atom b. 1.6 g of Oxygen gas, O 2 RMM of O2 = 32, Mole = 1.6 ÷ 32 = 0.05 mol 0.05 x 6.02 x 1023 molecules 1 molecules of O2 consists of 2 mol O atom 2 x 0.05 x 6.02 x 1023 atom No of Mole No of Particle Mass x Avogadro Constant ÷ Avogadro Constant x Molar Mass ÷ Molar Mass Relative atomic mass: N, 14; O, 16; C, 12; H, 1; Fe, 56
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http://chemclass4spm.blogspot.com
http://chemclass4spm.blogspot.com
Exercise : Interconversion Mole and Number of Particle Avogadro Constant : 6.02 x 1023 1. Calculate the number of particles in a. 1 mol atom of copper
1 x 6.02 x 1023 atoms.
b. 0.0625 mole of water, H2O 0.0625 x 6.02 x 1023 molecules
c. 1.3 mole of Sodium ions, Na+
1.3 x 6.02 x 1023 ions.
2. Calculate the number of atoms in a. 0.012 mole of ethane gas, C2H6
8 x 0.012 x 6.02 x 1023 atoms.
b. 1.1 mole of sulphur trioxide, SO3 4 x 1.1 x 6.02 x 1023 atoms.
c. 0.25 mole of water, H2O 3 x 0.25 x 6.02 x 1023 atoms.
3. Calculate the number of moles of the following
substances a. 3.02 x 1023 sodium atom
(3.02 x 1023) ÷ (6.02 x 1023 )
b. 1.8 x 1024 H2S molecules (1.8 x 1024) ÷ (6.02 x 1023 )
4. Calculate the number of moles of a. 7 g of Nitrogen gas, N2
RMM of N2 = 14, Mole = 7÷14 = 0.5 mol
b. 5.75 g of Sodium atom, Na RMM of Na = 23, Mole = 5.75 ÷23 = 0.25 mol
c. 16 g of Oxygen gas, O2 RMM of O2 = 32, Mole = 16 ÷ 32 = 0.5 mol
d. 15 g of iron, Fe RMM of Fe = 56, Mole = 15÷56 = 0.27 mol
5. Calculate the number of molecules found in a. 14g of Nitrogen gas, N2
RMM of N2 = 14, Mole = 14÷14 = 1 mol 1 x 6.02 x 1023 molecules
b. 22g of Carbon dioxide gas, CO2 RMM of CO2 = 44, Mole = 22÷44 = 0.5 mol 0.5 x 6.02 x 1023 molecules
c. 1.6 g of Oxygen gas, O2 RMM of O2 = 32, Mole = 1.6 ÷ 32 = 0.05 mol 0.05 x 6.02 x 1023 molecules
6. Calculate the number of atoms found in a. 14g of Nitrogen gas, N2
RMM of N2 = 14, Mole = 14÷14 = 1 mol 1 x 6.02 x 1023 molecules 1 molecules of N2 consists of 2 mol N atom 2 x 1 x 6.02 x 1023 atom
b. 1.6 g of Oxygen gas, O2 RMM of O2 = 32, Mole = 1.6 ÷ 32 = 0.05 mol 0.05 x 6.02 x 1023 molecules 1 molecules of O2 consists of 2 mol O atom 2 x 0.05 x 6.02 x 1023 atom
No of Mole No of Particle Mass x Avogadro Constant
÷ Avogadro Constant
x Molar Mass
÷ Molar Mass
Relative atomic mass: N, 14; O, 16; C, 12; H, 1; Fe, 56
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