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IABLOKOV S.N. [1,2] and KUZNETSOV A.V. [1]
19.01.2021
Modified Fock-Schwinger method
[1] P.G. Demidov Yaroslavl State University, Yaroslavl, Russia
[2] A.A. Kharkevich Institute for Information Transmission Problems, Moscow, Russia
simplifies calculation of charged particle propagators in a constant magnetic field
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2 approaches to find propagators
Canonical quantization
βSum over solutionsβ
2
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2 approaches to find propagators
Canonical quantization Path integral formalism
βSum over solutionsβ Propagator equation
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Sum over solutions: main features
Obtain general form
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Orthogonalization & normalization
Sum over polarizations
Find polarizations vectors
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Propagator equation: main features
Obtain general form
Orthogonalization & normalization
Sum over polariations
Find polarizations vectors
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π» π₯, ππ₯ π π₯, π₯β² = πΏ4(π₯ β π₯β²)
π π₯, π₯β² = π π₯ β π₯β² = ΰΆ±π4π
2π 4πβπ π π₯βπ₯β²
π(π)
Translational invariance is assumed
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Propagator equation
Add external field
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πππ β ππ·π = πππ + πππ΄π(π₯)
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Propagator equation
Translational invariance is lostAdd external field
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πππ β ππ·π = πππ + πππ΄π(π₯) π π₯, π₯β² β π π₯ β π₯β²
β ΰΆ±π4π
2π 4πβπ π(π₯βπ₯β²) π(π)
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Fock-Schwinger (FS) method
Letβs solve this equation for S(x,xβ):
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π» π₯, ππ₯ π π₯, π₯β² = πΏ(π₯ β π₯β²)
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Fock-Schwinger (FS) method
Letβs solve this equation for S(x,xβ): Choose a parametrization:
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π» π₯, ππ₯ π π₯, π₯β² = πΏ(π₯ β π₯β²) π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ π(π₯, π₯β², π)
Ref: J.SchwingerPhys. Rev. 82, 664Published 1 June 1951
See also: FS method ina book on QFT byC. Itzykson, J.-B. Suber
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Fock-Schwinger (FS) method
Letβs solve this equation for S(x,xβ): Choose a parametrization:
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π» π₯, ππ₯ π π₯, π₯β² = πΏ(π₯ β π₯β²) π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ π(π₯, π₯β², π)
π» π₯, ππ₯ π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ π» π₯, ππ₯ π(π₯, π₯β², π) = πΏ(π₯ β π₯β²)
Ref: J.SchwingerPhys. Rev. 82, 664Published 1 June 1951
See also: FS method ina book on QFT byC. Itzykson, J.-B. Suber
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ π» π₯, ππ₯ π π₯, π₯β², π
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ π» π₯, ππ₯ π π₯, π₯β², π
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ ππ
πππ π₯, π₯β², π
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ ππ
πππ π₯, π₯β², π = π π₯, π₯β², 0 β π π₯, π₯β², ββ
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = π π₯, π₯β², 0 β π π₯, π₯β², ββ
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = π π₯, π₯β², 0 β π π₯, π₯β², ββ = πΏ(π₯ β π₯β²)
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
In the FS method we demand the following:
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π» π₯, ππ₯ π π₯, π₯β² = πΏ(π₯ β π₯β²)
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
Letβs check:
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Fock-Schwinger (FS) method
Solving this Schroedinger-type equationβ¦
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π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
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Fock-Schwinger (FS) method
Solving this Schroedinger-type equationβ¦
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π π₯, π₯β², π = eβiππ» π₯,ππ₯ + π πΏ(π₯ β π₯β²)
π» π₯, ππ₯ π π₯, π₯β², π = ππ
πππ π₯, π₯β², π
π π₯, π₯β², 0 = πΏ(π₯ β π₯β²) π π₯, π₯β², ββ = 0
β¦one obtains the following result:
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Fock-Schwinger (FS) method
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Finally, the solution of
is the following expression:
π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiππ»+ π πΏ(π₯ β π₯β²)
π» π₯, ππ₯ π π₯, π₯β² = πΏ(π₯ β π₯β²)
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Fock-Schwinger (FS) method
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Whatβs next?
π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiππ»+ π πΏ(π₯ β π₯β²)
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Fock-Schwinger (FS) method
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Whatβs next?
π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiππ»+ π πΏ(π₯ β π₯β²)
In the original FS method we actually usethis result to further βmassageβ theoriginal differential equation:
π― π, ππ πΌ π, πβ², π = ππ
πππΌ π, πβ², π
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Fock-Schwinger (FS) method
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Whatβs next?
π π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiππ»+ π πΏ(π₯ β π₯β²)
In the original FS method we actually usethis result to further βmassageβ theoriginal differential equation:
π― π, ππ πΌ π, πβ², π = ππ
πππΌ π, πβ², π
In the modified Fock-Schwinger (MFS)method one directly evaluates the actionof exponential operator on πΏ-function:
πβπππ―+πΊπ πΉ π β πβ² = β¦
Ref: S. N. IABLOKOV & A. V.KUZNETSOV, 2019 J. Phys.:Conf. Ser. 1390 012078
Ref: S. N. IABLOKOV & A. V.KUZNETSOV, Phys. Rev. D102, 096015 β Published 12November 2020
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Modified Fock-Schwinger (MFS) method
Assume the following decomposition of πΏ-function:
such that:
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Modified Fock-Schwinger (MFS) method
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Modified Fock-Schwinger (MFS) method
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Modified Fock-Schwinger (MFS) method
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Modified Fock-Schwinger (MFS) method
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Application of MFS
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Ξ πΞ π βπ2 πΏ ππβ 2ππππΉ π
πβ 1 β ΰ΅1 π Ξ πΞ π πΊ π
ππ₯, π₯β² = πΏ4 π₯ β π₯β² πΏ π
π
πΉ ππ=
0 0 0 00 0 π΅ 00 βπ΅ 0 00 0 0 0 π
π
Ξ π = πππ + πππ΄π(π₯)
π΄π = (0,0,βπ΅π₯, 0)
Vector charged boson in a constant magnetic field:
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Application of MFS
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Ξ πΞ π βπ2 πΏ ππβ 2ππππΉ π
πβ 1 β ΰ΅1 π Ξ πΞ π πΊ π
ππ₯, π₯β² = πΏ4 π₯ β π₯β² πΏ π
π
A B CπΉ ππ=
0 0 0 00 0 π΅ 00 βπ΅ 0 00 0 0 0 π
π
Ξ π = πππ + πππ΄π(π₯)
π΄π = (0,0,βπ΅π₯, 0)
A remarkable fact:
π΄, π΅ = 0
Vector charged boson in a constant magnetic field:
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Application of MFS
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Ξ πΞ π βπ2 πΏ ππβ 2ππππΉ π
πβ 1 β ΰ΅1 π Ξ πΞ π πΊ π
ππ₯, π₯β² = πΏ4 π₯ β π₯β² πΏ π
π
A B C
A remarkable fact:
πΉ ππ=
0 0 0 00 0 π΅ 00 βπ΅ 0 00 0 0 0 π
π
Ξ π = πππ + πππ΄π(π₯)
π΄π = (0,0,βπ΅π₯, 0)
π΄ + π΅, πΆ = 0
π΄, π΅ = 0
Vector charged boson in a constant magnetic field:
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According to the MFS method:
Application of MFS
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πΊ ππ
π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiππ»+ ππ
ππΏ4 π₯ β π₯β²
A B C= Ξ πΞ π βπ2 πΏ ππ
= β2ππππΉ ππ = β 1 β ΰ΅1 π Ξ πΞ π
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According to the MFS method:
Application of MFS
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πΊ ππ
π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiπ π΄+π΅+πΆ + ππ
ππΏ4 π₯ β π₯β²
A B C= Ξ πΞ π βπ2 πΏ ππ
= β2ππππΉ ππ = β 1 β ΰ΅1 π Ξ πΞ π
π΄ + π΅, πΆ = 0
π΄, π΅ = 0
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According to the MFS method:
Application of MFS
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πΊ ππ
π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiπ π΄+π΅+πΆ + ππ
ππΏ4 π₯ β π₯β²
A B C= Ξ πΞ π βπ2 πΏ ππ
= β2ππππΉ ππ = β 1 β ΰ΅1 π Ξ πΞ π
π΄ + π΅, πΆ = 0
π΄, π΅ = 0
eβiπ π΄+π΅+πΆ
Separating the exponentβ¦
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According to the MFS method:
Application of MFS
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πΊ ππ
π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiπ π΄+π΅+πΆ + ππ
ππΏ4 π₯ β π₯β²
A B C= Ξ πΞ π βπ2 πΏ ππ
= β2ππππΉ ππ = β 1 β ΰ΅1 π Ξ πΞ π
π΄ + π΅, πΆ = 0
π΄, π΅ = 0
eβiπ π΄+π΅+πΆ = eβiπ πΆeβiπ π΄+π΅
Separating the exponentβ¦
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According to the MFS method:
Application of MFS
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πΊ ππ
π₯, π₯β² = βπ ΰΆ±ββ
0
ππ eβiπ π΄+π΅+πΆ + ππ
ππΏ4 π₯ β π₯β²
A B C= Ξ πΞ π βπ2 πΏ ππ
= β2ππππΉ ππ = β 1 β ΰ΅1 π Ξ πΞ π
π΄ + π΅, πΆ = 0
π΄, π΅ = 0
eβiπ π΄+π΅+πΆ = eβiπ πΆeβiπ π΄+π΅ = eβiπ πΆeβiπ π΅eβiπ π΄
Separating the exponentβ¦
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
The expression has a nested structure:
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
Propagation of a scalar particle
The expression has a nested structure:
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
Propagation of a scalar particle
Accounting for a spin
The expression has a nested structure:
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
Propagation of a scalar particle
Accounting for a spin
Considering an arbitrary π-gauge
The expression has a nested structure:
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
What about πΏ-function?
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
What about πΏ-function?
πΏ4 π β πβ² =
π=0
β
ΰΆ±π3πβ₯,π¦2π 3
πβπ π πβπβ²
β₯,π¦ππ π₯ ππ(π₯β²)
here, ππ π₯ are simple harmonic oscillator eigenfunctions
Ξ π = πππ + πππ΄π(π₯)
π΄π = (0,0,βπ΅π₯, 0)
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
What about πΏ-function?
πΏ4 π₯ β π₯β² =
π=0
β
ΰΆ±π3πβ₯,π¦2π 3
πβπ π π₯βπ₯β²
β₯,π¦ππ π₯ ππ(π₯β²)
here, ππ π₯ are simple harmonic oscillator eigenfunctions
Ξ πΞ π βπ2 πβπ π π₯βπ₯β²
β₯,π¦ππ π₯ = πβ₯2 βπ2 + πππ΅ 2π + 1 π
βπ π π₯βπ₯β²β₯,π¦ππ(π₯)
Ξ π = πππ + πππ΄π(π₯)
π΄π = (0,0,βπ΅π₯, 0)An example of simplification:
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Application of MFS
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πΊ ππ= βπ ΰΆ±
ββ
0
ππ πΏ4 π₯ β π₯β²e+iπ 1β ΰ΅1 π Ξ πΞ π πβ2ππππΉ π
π
eβiπ Ξ πΞ πβπ2 πΏ π
π+ π
What about πΏ-function?
πΏ4 π₯ β π₯β² =
π=0
β
ΰΆ±π3πβ₯,π¦2π 3
πβπ π π₯βπ₯β²
β₯,π¦ππ π₯ ππ(π₯β²)
here, ππ π₯ are simple harmonic oscillator eigenfunctions
The rest of the calculations are boring straightforwardβ¦
Charged massive vector boson propagator in a constant magnetic field in arbitrary ΞΎ-gaugeobtained using the modified Fock-Schwinger method; S.βN. Iablokov and A.βV. KuznetsovPhys. Rev. D 102, 096015 β Published 12 November 2020
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Application of MFS
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Charged massive vector boson propagator in a constant magnetic field in arbitrary ΞΎ-gaugeobtained using the modified Fock-Schwinger method; S.βN. Iablokov and A.βV. KuznetsovPhys. Rev. D 102, 096015 β Published 12 November 2020
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Conclusions
MFS allows to obtain the solution of the propagator equation directly (almost) in momentum space.
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Conclusions
MFS allows to obtain the solution of the propagator equation directly (almost) in momentum space.
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MFS simplifies calculations and provides additional representations of the propagator.
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Conclusions
MFS allows to obtain the solution of the propagator equation directly (almost) in momentum space.
50
MFS simplifies calculations and provides additional representations of the propagator.
Drawback: MFS is as good as oneβs ability to obtain/guess the form of the wave-equationβs solution.
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Conclusions
MFS allows to obtain the solution of the propagator equation directly (almost) in momentum space.
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MFS simplifies calculations and provides additional representations of the propagator.
Drawback: MFS is as good as oneβs ability to obtain/guess the form of the wave-equationβs solution.
Can be applied for the constant electric field configuration, which is relevant for the Schwinger effect.
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Thank you for your attention
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