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Mixture & Money Problems Algebra Honors
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Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Dec 26, 2015

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Norman Gilmore
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Page 1: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Mixture & Money Problems

Algebra Honors

Page 2: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

John has $1.70, all in dimes and nickels. He has a total of 22 coins.

How many of each kind does he have?

Let d = number of dimes

Let n = number of nickels

Counting equation

d + n = 22

Value equation

.10d + .05n = 1.70BACK

Page 3: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

7.105.10.

22

nd

nd

170510 100 ndM-10

2201010 - nd

505 n10n12d

Page 4: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Tickets to a movie cost $5.00 for adults and $3.00 for children. If tickets were bought for 50 people for a total of $196 how many adult tickets were sold and how many children tickets were sold?

Let A = the number of Adult tickets sold.

Let C = the number of children tickets sold.

Counting Equation

A + C = 50

Value Equation

5A + 3C = 196BACK

Page 5: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

A + C = 50

5A + 3C = 196-3A – 3C = -150

-3

2A = 46

A = 23

23 + C = 50

C = 27

5(23) + 3(27) = 196

115 + 81 = 196

23 Adults and27 Children

Check

Page 6: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

How much 20% alcohol solution and 50% alcohol solution must be mixed to get 12 gallons of 30% alcohol solution?

Let x = amount of 20%

Let y = amount of 50%

Counting Equation

x + y = 12

Value Equation

.20x + .50y = .30(12).30(12)= 3.6

BACK

Page 7: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

x + y = 12

.20x + .50y = 3.62x + 5y = 36

10

-2x – 2y = -24

3y = 12

x + (4) = 12

x = 8

.2(8) + .5(4) = 3.6

1.6 + 2 = 3.6

8 gallons of 20%4 gallons of 50%

Check

-2

y = 4

BACK

Page 8: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

A typical mixture problem reads like this:Joe would like to mix 5 lbs of Columbian coffee costing $4.50 per pound with enough flavored coffee costing $3.00 per pound to make a mix worth $4.00 per pound. How many pounds of the flavored coffee should he take?

Let x = amount of flavored coffee in pounds

Mixture problems can be more easily solved by using a grid.

Page 9: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Joe would like to mix 5 lbs of Columbian coffee costing $4.50 per pound with enough flavored coffee costing $3.00 per pound to make a mix worth $4.00 per pound. How many pounds of the flavored coffee should he take?

Amt Cost Total

Colum

Flavor

Mix

Let’s fill in the chart with what we know.

5 4.50

x 3.00

4.00

BACK

Page 10: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Now we fill in the remaining cells. Since we are mixing the two types of coffee the mix Amt will be x + 5. For total multiply amt times cost and place in total column

Amt Cost Totals

Colum

Flavor

Mix

5 4.50

x 3.00

4.00x + 5

22.5

3x

Equation

The equation comes from the vertical and horizontal totals.BACK

Page 11: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

He will need 2.5 lbs of the flavored coffee.

5435.22 xx

20435.22 xx

205.22 x

x5.2

BACK

Page 12: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

An auto mechanic has 300 mL of battery acid solution that is 60% acid. He must add water to the solution to dilute it so that it is only 45% acid. How much water should he add?

Total Amount

% Acid Amnt of Acid

Original Solution

Water

New Solution

300 60%

x 0%

45%300 + x

180

0

Equation

Equation: 180 = 0.45 (300 + x)BACK

Page 13: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

A health food store sells a mixture of raisins and roasted nuts. Raisins sell for $3.50/kg and nuts sell for $4.75/kg. How many kilograms of each should be mixed to make 20 kg of this snack worth $4.00/kg? (Write Equation Only)

BACK

rRaisinsnNuts

20 nr

8075.45.3 nr

Page 14: Mixture & Money Problems Algebra Honors John has $1.70, all in dimes and nickels. He has a total of 22 coins. How many of each kind does he have? Let.

Mixture & Money Problems

Algebra Honors