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N AME : P RATIK K UMAR S INGHA C LASS : X S ECTION : B R OLL N O . : 29 S UBJECT : S CIENCE
17
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Page 1: MILLIKANS OIL EXPERIMENT

NAME : PRATIK KUMAR SINGHA

CLASS : X SECTION : BROLL NO. : 29

SUBJECT : SCIENCE

Page 2: MILLIKANS OIL EXPERIMENT

TOPIC : MILLIKAN’S OIL DROP EXPERIMENT

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In 19th century starting Rutherford had done his alpha scattering experiments. Nobody know the charge on an electron. Millikan modified experiments tried by others and did very careful work. Used nonvolatile oil rather than volatile water.

HISTORICAL SETTING

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To determine the charge of oil drop is an integral multiple of elemental electron charge.

AIM

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APPARATUS

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Plates can be charged. Charge can be varied. Oil drops fall through hole in

top plate.

Electrons are present in these oil drops

Microscope used for observing drops.

DESIGN OF THE EXPERIMENT

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Spray the oil drops into the oil drop box from the spraying hole by means of sprayer.

Ensure the change-over switch in the middle gear, measure the time tg required for falling motion (it looks as if rising motion) of the same oil drop as above mentioned in a certain distance.

Apply about 200V on the parallel polar plates to drive unnecessary oil drops until only several slow moving oil drops remain.

Measure the time t E required for rising motion of the oil drop (it looks as if falling motion) in the same distance.

PROCEDURE

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Free fall of the oil drop with mass m and charge Q

Oil drop falls down under the force of gravity. Then force of gravity will be balanced against air resistance.

mg=f1, f1 is the air resistance that is acting upward

PRINCIPLE

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Force due to E= QE

When the oil drop elevates at a uniform speed, the force of the electric field is balanced against gravityand resistance of air . The following relationship can be obtained:f2+mg=QE,f2 = Resistance of the air when oil drop is elevated

MOTION OF THE OIL DROP IN ELCTRIC FIELD E.

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So we get,

Since air is not a continuous medium,Applying a correction factor,We get the Total charge of Oil drop

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• Coefficient of viscosity for air: 5kg/ms

• Density of oil drop =981kg/m3

• Distance between two parallel polar plates d = 5 X 10-3m.

In this experiment the information that should be provided is,

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Tg(s)

Vg (*10-5) (m/s)

Radius(*10-5) (m)

Tp(s)

Ve(m/s)

ChargeOf drop(*10-17)

(C)

Charge/Charge of e-

22.41 4.46 3.48 7.15 1.39*10-

4

4.01 250.97

5.27 37.9 .17 13.36 1.48*10-

4

0.80 50.09

26.18 3.81 3.31 2.62 3.81*10-

4

8.54 534.02

4.08 40.91 0.20 15.09 1.32*10-

4

1.07 67.01

CONCLUSION

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Charge carried by an oil drop is an integral multiple of elementary electron charge i.e. 1.6*10-19 C

Found out the quantised nature of charges

RESULT

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Obtained Q/e ratios that are not always integer in this case . This might be due to manually aligning the scales, noting down rising and falling time that may caused the error.

Bigger and smaller oil drop give less accuracy.

DISCUSSION

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BIBLIOGRAPHYFor this project, I have taken help of a number of

resources . Some of them are: Internet (Wikipedia)

Google Images Reference Books

I want to thank our subject teacher to give us such a knowledgeable project. I also want to

thank my parents in helping me in a lot of way.

ACKNOWLEDGEMENT

Page 17: MILLIKANS OIL EXPERIMENT