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Midterm Exam ESE 232 October 8, 2008 Your Name: Your 10 #: You need to show all your work in order to get the full credit. There are 4 problems in this examination.
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Midterm Exam ESE 232 October 8, 2008

Apr 22, 2022

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Page 1: Midterm Exam ESE 232 October 8, 2008

Midterm Exam ESE 232

October 8, 2008

Your Name:

Your 10 #:

You need to show all your work in order toget the full credit. There are 4 problems inthis examination.

Page 2: Midterm Exam ESE 232 October 8, 2008

1.(25 pts) For the two stage amplifier shown below, find the gain va.Vs

Source Stage 1

+ l!.0kDV1

Stage 2

1 kD ~ /2 12kD!

Output

lkD

l0 K----~\0 \4'---t I 00 tc..

\\)$-- l \

Page 3: Midterm Exam ESE 232 October 8, 2008

2.(25 pts) Assuming that the op amp is ideal, find va. (Hint: Michigan football- Vs

says "when you are in doubt, punt." Or if you don't know what to do, create anextra variable.)

v~-~- G}l

R2'\I@

VS ~ _ ) ~.

, i v~G~ . R1

?+~£~~+ep ~

~. = '1.fs •

t")J~ =- '\J;.. ~ ~

(,t- -+ L~ 1" L=t =_ D ~ 0 + 'V, ;::-Q +~<..\

<VI ( RI -+R 2-) ~ \2-\ lY3 " "" (9

~tef ~ {c.C L CAt (jty,

?tep .~" ice L ~t CD. SIf' ~ w~ clov0\- Kt\OW +lL-

v" It •...&<- "'* ® c~ 0-"" e )(tl-CA.. V CAY I""bIe... '\J3,}

1J;-~~- -=.. 0

iC."'L

~ V\ -\- 0v - L.7: -::::-·0 -::0/ rV~- Uv -t- \Ji - 0R3. R4-

S0 b~:h+ute.~ ~~ 'n @ w;th G) ~~ \

Solve.. ti)y- '1f;; If' iertv\S +.~1h ¥' \::4 -t K>.J~·lt+ f:1 R.}.--+ 12,.he3i~.~E'f"'-- ....•.. --

'1)5> - R, r.~

Page 4: Midterm Exam ESE 232 October 8, 2008

3.(25 pts) Sketch Vin versus Vout for the circuit shown below (right). For thediode, use the i-v characteristics shown in the dotted box below (left).

r---------------------- IIIIIII

(whereRD = loon) I V.I If)

IIIIII

IIIIIIIIIIIIIIL _

0.5 V

1 kO

+

100('--

'ITo.A-~ 6h" - 1·5 \h~oO{L

-+ I_ 5"

/-~"W'\ t-~ ~ - V- datrlA<t",,~<.

air thL. 0 i'ooLs?. 1 TM d. Iu~.is. 1()!)'\ w~~~ 1h,,"'" 1'Jt~\j

"/ 0 ~\\.

1.5

Page 5: Midterm Exam ESE 232 October 8, 2008

4.(25 pts). With the Zener diodes (01 and 02) characteristics shown on the below(left), sketch Vout in the function of Vin for the circuit shown below (right). 01 and02 are identical.

--------------,Vinr- --

/0. +c>t-

IIII ~lkDI

/0 i III II+I

-2VIIVo I

02f lkD ~ VoutIlVI

I 01I I

+3..(---~-.~

,,,d L J-~() 6/:-3" /1 3Y:~_IIr-VI·,

~ -----.J.. II-3 v

@ W h.eY'!-]VL... ~ ~ (. 3 \!DI 4- P2- ~~

'Y1r--.

\K

CD W~eY\ 1J:n 7 3 VQ~ 0'" \- 0 I bU2.~k.d~

'11~~

Vn

IV' -L.

~ I/::..i2",1-

. ~I ~

\)0 :;. :; if

CD vJke'1 ~~ L. -3Vt> I 0 Y\ cl.. D L.. b \£.{) k:d.o!.Jr\

'VI'~

p=:::.

- 2-\J t1-t

.-L I"'- ~....t"'

_,v 1 - VOL\t -:: -3'/