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Methods of Analysis ELEC 202 Electric Circuit Analysis II
21

Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Jan 01, 2016

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Page 1: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Methods of Analysis

ELEC 202 Electric Circuit Analysis II

Page 2: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Nodal Analysis1. For an AC circuit, transform the

circuit into the phasor domain.2. Identify every node in the circuit.3. Label each node with a node

voltage. The node with the highest number of branches connected should be labeled as the ground node having zero potential.

Page 3: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Nodal Analysis (Cont’d)4. At a particular node of interest (except

ground), use Ohm’s law to express the current through any branch connected to that node as the difference between the two node voltages at both end of that branch divided by the branch impedance. The voltage at the node of interest is always considered to be at higher potential than the rest of the node voltages.

Page 4: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Nodal Analysis (Cont’d)5. Apply KCL to sum all currents at that

node of interest. The resulting algebraic equation (called nodal equation) has all node voltages as its unknowns.

6. Repeat steps 4 and 5 until all nodes except ground are accounted for. The number of equations must be equal to the number of node voltages.

Page 5: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Nodal Analysis (Cont’d)7. If a branch not connected to ground

contains a voltage source, the two nodes at both ends are collapsed into a single node called a supernode, and the voltage source and any elements connected in parallel with it removed. However, KCL must still be satisfied at a supernode using the old node voltage labels. Also, the removal of the voltage source provides another nodal equation.

Page 6: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Nodal Analysis (Cont’d)8. If a branch connected to ground contains

a voltage source, the non-ground node voltage is equal to the source voltage, and KCL is not applied to this node.

9. Solve the resulting simultaneous nodal equations to obtain the values of the unknown node voltages.

10. Use the values of node voltages above to find voltages and/or currents throughout the rest of the circuit.

Page 7: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 1

Find ix in the circuit using nodal analysis.

Page 8: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 1 (cont’d)

The resulting circuit in the phasor domain.

Page 9: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 2

Compute v1 and v2 in the circuit.

Page 10: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 3

Compute V1 and V2 in the circuit.

Page 11: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 3 (Cont’d)

Page 12: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 4Compute V1 and V2 in the circuit.

Page 13: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Mesh Analysis1. For an AC circuit, transform the circuit

into the phasor domain.2. Identify every mesh in the circuit.3. Label each mesh with a mesh current. It is recommended that all mesh

currents be labeled in the same direction (either clockwise (CW) or counter-clockwise (CCW)).

Page 14: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Mesh Analysis (Cont’d)4. Within a particular mesh of interest, use

Ohm’s law to express the voltage across any element within that mesh as the difference between the two mesh currents of contiguous meshes shared by the element times the element impedance. The current within the mesh of interest is always considered to be larger than the rest of the mesh currents.

Page 15: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Mesh Analysis (Cont’d)5. Apply KVL to sum all voltages in that

mesh of interest. The resulting algebraic equation (called mesh equation) has all mesh currents as its unknowns.

6. Repeat steps 4 and 5 until all meshes are accounted for. The number of equations must be equal to the number of mesh currents.

Page 16: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Mesh Analysis (Cont’d)7. If a current source exists between two

contiguous meshes, the two meshes are collapsed into a single mesh called a supermesh, and the current source and any elements connected in series with it removed. However, KVL must still be satisfied within a supermesh using the old mesh current labels. Also, the removal of the current source provides another mesh equation.

Page 17: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Mesh Analysis (Cont’d)8. If a current source exists only in one

mesh, the mesh current is equal to the source current, and KVL is not applied to this mesh.

9. Solve the resulting simultaneous mesh equations to obtain the values of the unknown mesh currents.

10. Use the values of mesh currents above to find voltages and/or currents throughout the rest of the circuit.

Page 18: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 5

Find I0 in the circuit using mesh analysis.

Page 19: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 6

Find I0 in the circuit using mesh analysis.

Page 20: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 7

Find V0 in the circuit using mesh analysis.

Page 21: Methods of Analysis ELEC 202 Electric Circuit Analysis II.

Example 7 (cont’d)