Tensile Test of A-36 Low Carbon Steel By Richard Balbuena ME 312 California State University Los Angeles 10-02-15
Feb 01, 2016
Tensile Test of A-36 Low Carbon Steel
By
Richard Balbuena
ME 312
California State University Los Angeles
10-02-15
ObjectiveThe purpose of this experiment was to conduct a tensile test on standard
structural steel in order to demonstrate Hooke’s Law.
Theory
Hooke’s Law is given by the equation F=-kx, where x is the extension of the
spring, being the extended length minus the unstretched length. Through relation, f,
the force used to compress or extend the spring a distance is directionally
proportional to its extension. K is the spring constant that may tell us how stiff a
spring is. The negative sign is there to act against the displacement of the spring in
order to restore the spring back to an equilibrium position.
Young’s Modulus is given by the equation
.
The point of this equation is to measure the how stiff a material is and can tell how
much a material can withstand a change in length when it is under compression or
tension.
Procedure
Before we began conducting the experiment, we first measured the diameter
of the steel sample using a dial caliper. After that was done we placed the sample
under a center punch fixture and aligned it in order to puncture the sample. After
this we placed the sample in the Tinius-Olsen UTM machine to begin the
experiment. Initially we placed a small load of around 100 lbs-200 lbs. but soon
after we increased the load to a bigger one. Gradually we began to increase the load
rate to up to 2000 lbs. when finally the load on the steel sample snapped it in half.
After removing the sample we measured the final diameter and completed our
experiment.
Diagrams
Tinius-Olsen UTM
A-36 Sample after the fracture
Results and Data
Proportional limit 47,000 psi
Yield Point 46,000 psi
Yield Strength 52,600 psi
Ultimate Strength 75,400 psi
Rupture Strength 15,110 psi
Modulus of Elasticity 31, 300psi
Modulus of Resilience 9,160 psi
Percent elongation in gauge length 0.072%
Percent reduction in area at fracture 64%
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.80
1020304050607080
9.1615.1
31.3
46 4752.6
75.4
Stress Vs Strain
Stress
Stra
in (
psi
in t
ho
usa
nd
s)
Discussion
Based on the numbers attained from this experiment, it was done decently
but not the best. When you compare the modulus of elasticity and resilience to the
actual publicized results listed on Matweb, they are somewhat similar. The ultimate
strength falls within the listed range however the yield strength is a bit off. Some
discrepancies of the test may be because the loading on the Tinius-Olsen machine
may have been done wrong or we could have attained a wrong reading on the
caliper while taking the diameter, resulting in wrong results in the percent
elongation and reduction. Other than that, the experiment went fairly okay. We may
use this steel sample with respect to its properties to use in structures because of its
calculated modulus of elasticity and yield point, which could compete with other
materials out there in the market. Most companies look for materials that will have
these things in order to get the best materials for their money that will insure a good
structure or item.
Conclusion
From this experiment, we have learned to calculate many things from a sample steel
bar. From using the Tinius-Olsen machine, we were able to determine the samples
fracture point as well as other things such as the modulus of elasticity and ultimate
strength.