May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law.
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May 1, 2013
AGENDA:1 – Bell Ringer & Part.
Log2 – Review HW3 – Demo: Boyle’s
Law4 - CN: Charles’ Law5 – Practice Problems6 – Demo: Charles’
Law7 – Work Time
Today’s Goal:Students will be able to
calculate using Charles’ Law.
Homework1. Charles’ Law2. Work from Week 32 is
due by Friday.3. Make up Week 32
Quiz by Friday.
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
5 minutes!
4 MINUTES REMAINING…
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
4 minutes!
3 MINUTES REMAINING…
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
3 minutes!
2 MINUTES REMAINING…
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
2 minutes!
1minute Remaining…
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
1 minute!!!
30 Seconds Remaining…
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
30 seconds!!!
BELL-RINGER TIME IS
UP!
May 1, 2013
AGENDA:1 – Bell Ringer & Part.
Log2 – Review HW3 – Demo: Boyle’s
Law4 - CN: Charles’ Law5 – Practice Problems6 – Demo: Charles’
Law7 – Work Time
Today’s Goal:Students will be able to
calculate using Charles’ Law.
Homework1. Charles’ Law2. Work from Week 32 is
due by Friday.3. Make up Week 32
Quiz by Friday.
Wednesday, May 1
Objective: Students will be able to calculate using Charles’ Law.
Bell Ringer:Use Boyle’s Law: P1V1 = P2V2 Oxygen gas, O2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container.
REVIEW
REVIEW HOMEWORK
Kinetic Molecular Theory and Boyle’s Law
Demonstrations of Boyle’s Law
Stay Puft Marshmallow Man in a vacuum… http://www.youtube.com/watch?v=27yqJ9vJ5kQ
What happens to lungs when diving underwater? Underwater demo:
http://www.youtube.com/watch?v=t8wFIMbMJvs Lab explanation demo:
http://www.youtube.com/watch?v=hXnkJNk45Ek
Discussion: How do yourlungs work?
Topic: Charles’ Law Date: 5/1/2013
Charles’ Law = For a given amount of gas at a constant pressure, the VOLUME of the gas is directly related to TEMPERATURE.
So if: T ↑ = V ↑ T ↓ = V ↓
T α V
1. Compare2. Formulat
e3. Support
Temperature
VolumeConsta
nt Pressur
e
Temper-ature
Volu
me
Topic: Charles’ Law Date: 5/1/2013
Variables & Units: V = Volume (mL, L) T = Temperature (K = Kelvin) You must convert °C to K before you calculate further!
To convert degrees Celsius to Kelvin: Temp. in K = °C + 273 Example: What is 25°C in K
temp.?Temp. in K = 25°C + 273Temp. in K = 298 K
1. Compare2. Formulat
e3. Support
Topic: Charles’ Law Date: 5/1/2013
Equation:1. Compare2. Formulat
e3. Support
V1 = V2
T1 T2
V1T2 = V2T1
Notice subscriptsare different on each
side!
Practice Problem
A balloon is at RT (25°C). The volume of the balloon is 2.0L. The balloon is then taken outside to a temperature of -5°C. What is the new volume of the balloon?
3rd Calculate:V1T2 = V2T1
(2)(268)=(V2)(298)
536 = V2(298) 298 298V2 = 536/298
V2 = 1.8L
2nd Determine Variables:V1 =T1 =V2 =T2 =
1st Predict: If T ↓, then V↓.
25°C2.0L
-5°C? = x
+273=298K
+273=268K
Convert to K!
Demonstrations of Charles’ Law Balloon fun with liquid nitrogen…
http://www.youtube.com/watch?v=ZgTTUuJZAFs
Balloon fun with boiling water… http://www.youtube.com/watch?v=GcCmalm
LTiU
Discussion: How do hot air balloons work?
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