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PARABOLA (horizontal) Center C(h,k) Vertices V(h±a,k) Foci F(h±c,k) Endpoints of the minor axis B(h,k±b) Directrices x = h±a/e ( 29 ( 29 1 b k y a h x 2 2 2 2 = - + - 1
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Page 1: M36 1.4 hyperbola

PARABOLA (horizontal)

Center C(h,k)

Vertices V(h±a,k)

Foci F(h±c,k)

Endpoints of the minor axis B(h,k±b)

Directrices x = h±a/e

( ) ( )1

b

ky

a

hx2

2

2

2=−+−

1

Page 2: M36 1.4 hyperbola

Center C(h,k)

Vertices V(h,k±a)

Foci F(h,k±c)

Endpoints of the minor axis B(h±b,k)

Directrices y = k±a/e

( ) ( )1

b

hx

a

ky2

2

2

2=−+−

2

PARABOLA (vertical)

Page 3: M36 1.4 hyperbola

1.4 Hyperbola

MATH 36

Page 4: M36 1.4 hyperbola

directrix

focus

P1

P2

F

Q1

Q2

Given the eccentricity e of a conic section, the conic is

parabola if e = 1;

ellipse if 0 < e < 1;

hyperbola if e > 1.

PQ

principal axis

vertex

Non-degenerate Conic

Page 5: M36 1.4 hyperbola

Objectives: At the end of this section students should be able to:

• give the standard equation of a hyperbola;

• identify parts of a hyperbola;

• sketch the graph of a hyperbola.

Hyperbola

Page 6: M36 1.4 hyperbola

1b

y

a

x2

2

2

2=−Standard Equation

( )0,a( )0,a−

( )b,0

( )b,0 −

centervertex

auxiliary rectangle

The line segment joining the vertices is called the transverse axis.

The line segment joining the points (0,b) and (0,-b) is called the conjugate axis.

vertex

focus( )0,c( )0,c−

focus

y=(b/a)xy=(-b/a)x

eccentricity: e = c/a

directrices:c

a

e

ax

2±=±=

222 bac +=

Page 7: M36 1.4 hyperbola

1b

x

a

y2

2

2

2=−Standard Equation

( )0,b( )0,b−

( )a,0

( )a,0 −

y=(a/b)xy=(-a/b)x

eccentricity: e = c/a

c

a

e

ay

2±=±=directrices:

Page 8: M36 1.4 hyperbola

Example 1. Given the hyperbola

14

y

9

x 22=−

Determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.

Page 9: M36 1.4 hyperbola

SOLUTION

center:

principal axis: x -axis

vertices:

(3,0) and (-3,0).

endpoints of conjugate axis: (0,2) and (0,-2)

3a =

2 2

19 4

x y− =

2 2 13c a b= + =2b =

(0,0)

Page 10: M36 1.4 hyperbola

SOLUTION

foci:

eccentricity:

equation of the directrices:

( )13 0,±

13

2

2ax

c= ±

9

13x = ±

3a = 2b =2 2 13c a b= + =

2 2

19 4

x y− =

Page 11: M36 1.4 hyperbola

Example 2. Given the hyperbola

19

x

16

y 22

=−

Determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.Tr

y Thiz

z on

your

own!!!

Page 12: M36 1.4 hyperbola

If the center of the hyperbola is at (h,k) and the line y = k as principal axis then the standard equation is given by

( ) ( ).1

b

ky

a

hx2

2

2

2=−−−

Hyperbola with center (h,k)

Page 13: M36 1.4 hyperbola

If the center of the hyperbola is at (h,k) and the line x = h as principal axis then the standard equation is given by

( ) ( ).1

b

hx

a

ky2

2

2

2=−−−

Hyperbola with center (h,k)

Page 14: M36 1.4 hyperbola

Example 3. Given the hyperbola

( ) ( )1

16

2x

4

1y 22=+−−

determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.

Page 15: M36 1.4 hyperbola

SOLUTION

center: (-2,1)

principal axis: x = -2

vertices:

(-2,-1) and (-2,3).

endpoints of conjugate axis: (2,1) and (-6,1)

2a =

( ) ( )1

16

2x

4

1y 22=+−−

52bac 22 =+=4b =

( )1,2( )1,6−

( )3,2−

( )1,2 −−

(-2,1)

Page 16: M36 1.4 hyperbola

SOLUTION

2a =

( ) ( )1

16

2x

4

1y 22=+−−

52bac 22 =+=4b =

foci:

eccentricity:

equation of the directrices:

( )521,2 ±−

5

c

a1y

2±=

52

41y ±=

(-2,1) ( )1,2( )1,6−

( )3,2−

( )1,2 −−

Page 17: M36 1.4 hyperbola

Example 4. Given the hyperbola

determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.

( ) ( )1

4

1

4

2 22

=+

−− yx

Try T

hizz o

n

your

own!!!

Page 18: M36 1.4 hyperbola

Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.

SOLUTION:

center: (1, 1)

vertical principal axis

h = 1 and k = 1.

( ) ( )2 2

2 2

y k x h1

a b

− −− =

Page 19: M36 1.4 hyperbola

Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.

SOLUTION:

length of the transverse axis: 4

b = 4

a = 2

length of the conjugate axis: 8

Page 20: M36 1.4 hyperbola

Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.

SOLUTION:

( ) ( )2 2y 1 x 1

14 16

− −− =

standard equation

Page 21: M36 1.4 hyperbola

Example 6. Determine the standard equation of the hyperbola with a vertex at ( 2,0), center at the origin and its eccentricity is 3/2.

Try T

hizz o

n

your

own!!!

Page 22: M36 1.4 hyperbola

CENTER C(h,k)

VERTICES V(h±a,k)

FOCI F(h±c,k)

ENDPTS OF CONJUGATE AXIS B(h,k±b)

DIRECTRICES x=h±a/e

( ) ( )1

b

ky

a

hx2

2

2

2

=−−−

HYPERBOLA (horizontal)

Page 23: M36 1.4 hyperbola

CENTER C(h,k)

VERTICES V(h,k±a)

FOCI F(h,k±c)

ENDPTS OF CONJUGATE AXIS B(h±b,k)

DIRECTRICES y=k±a/e

( ) ( )1

b

hx

a

ky2

2

2

2

=−−−

END

HYPERBOLA (vertical)